2009/11/7 Stas K :
> Thank you, Josef
> It is exactly what I want:
>
> ar[:,None]**2 + ar**2
>
> Do you know something about performance of this? In my real program ar have
> ~ 10k elements, and expression for v more complicated (it has some
> trigonometric functions)
The construction of ar[:,Non
Thank you, Josef
It is exactly what I want:
ar[:,None]**2 + ar**2
Do you know something about performance of this? In my real program
ar have ~ 10k elements, and expression for v more complicated (it has
some trigonometric functions)
On 07.11.2009, at 21:57, josef.p...@gmail.com wrote:
On 11/7/2009 1:51 PM, Stas K wrote:
> Can I get rid of the loop in this example? And what is the fastest way
> to get v in the example?
>
> ar = array([1,2,3])
> for a in ar:
> for b in ar:
> v = a**2+b**2
>>> a2 = a*a
>>> np.add.outer(a2,a2)
array([[ 2, 5, 10],
[ 5, 8, 13
On Sat, Nov 7, 2009 at 1:51 PM, Stas K wrote:
> Can I get rid of the loop in this example? And what is the fastest way
> to get v in the example?
>
> ar = array([1,2,3])
> for a in ar:
> for b in ar:
> v = a**2+b**2
>>> ar[:,None]**2 + ar**2
array([[ 2, 5, 10],
[ 5, 8, 13],
Can I get rid of the loop in this example? And what is the fastest way
to get v in the example?
ar = array([1,2,3])
for a in ar:
for b in ar:
v = a**2+b**2
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