[android-beginners] Re: remote app commands sent via http
The code worked perfectly. Thanks for the help.
On Sep 27, 2:46 pm, Jeffrey Blattman jeffrey.blatt...@gmail.com
wrote:
no, there's a default read timeout. the only thing i noticed wrong was
that you were writing to URL itself to the stream.
On 9/27/09 11:42 AM, HTN wrote:
Seems like I was on the right track as I had url.openconnection. Is
the ReadTimout portion what I was doing wrong?
I'll try the code out when I get back home tomorrow. Thanks for the
help.
On Sep 27, 2:21 pm, Jeffrey Blattmanjeffrey.blatt...@gmail.com
wrote:
nah. first, he said that the endpoint wants GET params, and you are
opening with POST method below. you don't need to write data to the
stream. the data is passed to the endpoint as GET params.
if you just want to pass the get params, it's enough to just call
openConnection(). depending on how the endpoint returns a response, you
can check the response code with getResponseCode(), or you can read a
data response (XML, JSON, etc) by calling getInputStream(). here's the
simplest case,
URL url = new URL(urlString);
HttpURLConnection uc = (HttpURLConnection)
url.openConnection();
uc.setReadTimeout(30 * 1000); // 30 seconds
if (uc.getResponseCode() != 200) {
//TODO: handle error and return
}
reader = new BufferedReader(new
InputStreamReader(uc.getInputStream(), ISO-8859-1), 8192);
while ((line = reader.readLine()) != null) {
result.append(line);
result.append('\n');
}
// result data is in result
On 9/27/09 11:07 AM, Alok Kulkarni wrote:
This works
URL url = new URL(serverURL);
// open the conncetion
HttpURLConnection connection =
(HttpURLConnection)url.openConnection();
// Let the run-time system (RTS) know that we want input.
connection.setDoInput(true);
// Let the RTS know that we want to do output
connection.setDoOutput(true);
// No caching, we want the real thing
connection.setUseCaches(false);
// set the content type property
connection.setRequestProperty(Content-type,strContenttype);
// set request method
connection.setRequestMethod(POST);
// create the post body to send
String content = credDevPair.toString();
Log.i(Request ... ,content);
DataOutputStream printout = new DataOutputStream (
connection.getOutputStream () );
// send the data
printout.writeBytes(content);
printout.flush();
printout.close();
On Sun, Sep 27, 2009 at 11:25 PM, HTNrevil...@gmail.com
mailto:revil...@gmail.com wrote:
It's through GET parameters. I can type in the following command in a
browser's URL box and it works:
http://192.168.0.12/output_format=xmlDeviceNum=13action=SetTargetn...
http://192.168.0.12/output_format=xmlDeviceNum=13action=SetTargetn...
I'm used to sending commands through TCP sockets so I'm sure what's
the best way to send a URL command. I'm guessing the opening a URL
part isn't adequate.
On Sep 26, 8:49 pm, Jeffrey Blattmanjeffrey.blatt...@gmail.com
mailto:jeffrey.blatt...@gmail.com
wrote:
you are opening a URL, then writing that URL to the stream you
open at
the URL. that's probably not what you wanted. what's the URL,
and what
is the command you are trying to pass? how does the endpoint
accept
the command? by reading POST data? through GET parameters?
On 9/25/09 7:31 PM, HTN wrote:
I'm developing a remote app that sends commands via http.
Normally I
type in a link in a browser and the command will work. With
Android, I
would like it to work with a press of a button. I tried the
following
code and it didn’t work:
URL url = new URL(urlString);
URLConnection connection = url.openConnection();
connection.setDoOutput(true);
OutputStreamWriter out = new OutputStreamWriter
(connection.getOutputStream());
out.write(urlString);
out.close();
urlstring is the http command link.
Any ideas? Am I on the wrong track? I'm confused because
technically I
don't need to write anything to the link. I would think it
would work
if I just open the connection.
Thanks.
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You received this message because you are subscribed
[android-beginners] Re: remote app commands sent via http
It's through GET parameters. I can type in the following command in a browser's URL box and it works: http://192.168.0.12/output_format=xmlDeviceNum=13action=SetTargetnewTargetValue=1 I'm used to sending commands through TCP sockets so I'm sure what's the best way to send a URL command. I'm guessing the opening a URL part isn't adequate. On Sep 26, 8:49 pm, Jeffrey Blattman jeffrey.blatt...@gmail.com wrote: you are opening a URL, then writing that URL to the stream you open at the URL. that's probably not what you wanted. what's the URL, and what is the command you are trying to pass? how does the endpoint accept the command? by reading POST data? through GET parameters? On 9/25/09 7:31 PM, HTN wrote: I'm developing a remote app that sends commands via http. Normally I type in a link in a browser and the command will work. With Android, I would like it to work with a press of a button. I tried the following code and it didn’t work: URL url = new URL(urlString); URLConnection connection = url.openConnection(); connection.setDoOutput(true); OutputStreamWriter out = new OutputStreamWriter (connection.getOutputStream()); out.write(urlString); out.close(); urlstring is the http command link. Any ideas? Am I on the wrong track? I'm confused because technically I don't need to write anything to the link. I would think it would work if I just open the connection. Thanks. -- --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Android Beginners group. To post to this group, send email to android-beginners@googlegroups.com To unsubscribe from this group, send email to android-beginners-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en -~--~~~~--~~--~--~---
[android-beginners] Re: remote app commands sent via http
Seems like I was on the right track as I had url.openconnection. Is
the ReadTimout portion what I was doing wrong?
I'll try the code out when I get back home tomorrow. Thanks for the
help.
On Sep 27, 2:21 pm, Jeffrey Blattman jeffrey.blatt...@gmail.com
wrote:
nah. first, he said that the endpoint wants GET params, and you are
opening with POST method below. you don't need to write data to the
stream. the data is passed to the endpoint as GET params.
if you just want to pass the get params, it's enough to just call
openConnection(). depending on how the endpoint returns a response, you
can check the response code with getResponseCode(), or you can read a
data response (XML, JSON, etc) by calling getInputStream(). here's the
simplest case,
URL url = new URL(urlString);
HttpURLConnection uc = (HttpURLConnection)
url.openConnection();
uc.setReadTimeout(30 * 1000); // 30 seconds
if (uc.getResponseCode() != 200) {
//TODO: handle error and return
}
reader = new BufferedReader(new
InputStreamReader(uc.getInputStream(), ISO-8859-1), 8192);
while ((line = reader.readLine()) != null) {
result.append(line);
result.append('\n');
}
// result data is in result
On 9/27/09 11:07 AM, Alok Kulkarni wrote:
This works
URL url = new URL(serverURL);
// open the conncetion
HttpURLConnection connection =
(HttpURLConnection)url.openConnection();
// Let the run-time system (RTS) know that we want input.
connection.setDoInput(true);
// Let the RTS know that we want to do output
connection.setDoOutput(true);
// No caching, we want the real thing
connection.setUseCaches(false);
// set the content type property
connection.setRequestProperty(Content-type,strContenttype);
// set request method
connection.setRequestMethod(POST);
// create the post body to send
String content = credDevPair.toString();
Log.i(Request ... ,content);
DataOutputStream printout = new DataOutputStream (
connection.getOutputStream () );
// send the data
printout.writeBytes(content);
printout.flush();
printout.close();
On Sun, Sep 27, 2009 at 11:25 PM, HTN revil...@gmail.com
mailto:revil...@gmail.com wrote:
It's through GET parameters. I can type in the following command in a
browser's URL box and it works:
http://192.168.0.12/output_format=xmlDeviceNum=13action=SetTargetn...
http://192.168.0.12/output_format=xmlDeviceNum=13action=SetTargetn...
I'm used to sending commands through TCP sockets so I'm sure what's
the best way to send a URL command. I'm guessing the opening a URL
part isn't adequate.
On Sep 26, 8:49 pm, Jeffrey Blattman jeffrey.blatt...@gmail.com
mailto:jeffrey.blatt...@gmail.com
wrote:
you are opening a URL, then writing that URL to the stream you
open at
the URL. that's probably not what you wanted. what's the URL,
and what
is the command you are trying to pass? how does the endpoint
accept
the command? by reading POST data? through GET parameters?
On 9/25/09 7:31 PM, HTN wrote:
I'm developing a remote app that sends commands via http.
Normally I
type in a link in a browser and the command will work. With
Android, I
would like it to work with a press of a button. I tried the
following
code and it didn’t work:
URL url = new URL(urlString);
URLConnection connection = url.openConnection();
connection.setDoOutput(true);
OutputStreamWriter out = new OutputStreamWriter
(connection.getOutputStream());
out.write(urlString);
out.close();
urlstring is the http command link.
Any ideas? Am I on the wrong track? I'm confused because
technically I
don't need to write anything to the link. I would think it
would work
if I just open the connection.
Thanks.
--
--
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google
Groups Android Beginners group.
To post to this group, send email to android-beginners@googlegroups.com
To unsubscribe from this group, send email to
android-beginners-unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/android-beginners?hl=en
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[android-beginners] remote app commands sent via http
I'm developing a remote app that sends commands via http. Normally I type in a link in a browser and the command will work. With Android, I would like it to work with a press of a button. I tried the following code and it didn’t work: URL url = new URL(urlString); URLConnection connection = url.openConnection(); connection.setDoOutput(true); OutputStreamWriter out = new OutputStreamWriter (connection.getOutputStream()); out.write(urlString); out.close(); urlstring is the http command link. Any ideas? Am I on the wrong track? I'm confused because technically I don't need to write anything to the link. I would think it would work if I just open the connection. Thanks. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Android Beginners group. To post to this group, send email to android-beginners@googlegroups.com To unsubscribe from this group, send email to android-beginners-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en -~--~~~~--~~--~--~---
