Seems like I was on the right track as I had url.openconnection. Is the ReadTimout portion what I was doing wrong?
I'll try the code out when I get back home tomorrow. Thanks for the help. On Sep 27, 2:21 pm, Jeffrey Blattman <[email protected]> wrote: > nah. first, he said that the endpoint wants GET params, and you are > opening with POST method below. you don't need to write data to the > stream. the data is passed to the endpoint as GET params. > > if you just want to pass the get params, it's enough to just call > openConnection(). depending on how the endpoint returns a response, you > can check the response code with getResponseCode(), or you can read a > data response (XML, JSON, etc) by calling getInputStream(). here's the > simplest case, > > URL url = new URL(urlString); > HttpURLConnection uc = (HttpURLConnection) > url.openConnection(); > uc.setReadTimeout(30 * 1000); // 30 seconds > > if (uc.getResponseCode() != 200) { > //TODO: handle error and return > } > > reader = new BufferedReader(new > InputStreamReader(uc.getInputStream(), "ISO-8859-1"), 8192); > while ((line = reader.readLine()) != null) { > result.append(line); > result.append('\n'); > } > > // result data is in "result" > > On 9/27/09 11:07 AM, Alok Kulkarni wrote: > > > > > > > This works > > URL url = new URL(serverURL); > > > // open the conncetion > > HttpURLConnection connection = > > (HttpURLConnection)url.openConnection(); > > > // Let the run-time system (RTS) know that we want input. > > connection.setDoInput(true); > > // Let the RTS know that we want to do output > > connection.setDoOutput(true); > > // No caching, we want the real thing > > connection.setUseCaches(false); > > // set the content type property > > connection.setRequestProperty("Content-type",strContenttype); > > > // set request method > > connection.setRequestMethod("POST"); > > // create the post body to send > > String content = credDevPair.toString(); > > Log.i("Request ====....... ",content); > > DataOutputStream printout = new DataOutputStream ( > > connection.getOutputStream () ); > > > // send the data > > printout.writeBytes(content); > > printout.flush(); > > printout.close(); > > > On Sun, Sep 27, 2009 at 11:25 PM, HTN <[email protected] > > <mailto:[email protected]>> wrote: > > > It's through GET parameters. I can type in the following command in a > > browser's URL box and it works: > > http://192.168.0.12/output_format=xml&DeviceNum=13&action=SetTarget&n... > > > > <http://192.168.0.12/output_format=xml&DeviceNum=13&action=SetTarget&n...> > > > I'm used to sending commands through TCP sockets so I'm sure what's > > the best way to send a URL command. I'm guessing the "opening" a URL > > part isn't adequate. > > > On Sep 26, 8:49 pm, Jeffrey Blattman <[email protected] > > <mailto:[email protected]>> > > wrote: > > > you are opening a URL, then writing that URL to the stream you > > open at > > > the URL. that's probably not what you wanted. what's the URL, > > and what > > > is the "command" you are trying to pass? how does the endpoint > > accept > > > the command? by reading POST data? through GET parameters? > > > > On 9/25/09 7:31 PM, HTN wrote: > > > > > I'm developing a remote app that sends commands via http. > > Normally I > > > > type in a link in a browser and the command will work. With > > Android, I > > > > would like it to work with a press of a button. I tried the > > following > > > > code and it didn’t work: > > > > > URL url = new URL(urlString); > > > > > URLConnection connection = url.openConnection(); > > > > connection.setDoOutput(true); > > > > > OutputStreamWriter out = new OutputStreamWriter > > > > (connection.getOutputStream()); > > > > out.write(urlString); > > > > out.close(); > > > > > "urlstring" is the http command link. > > > > > Any ideas? Am I on the wrong track? I'm confused because > > technically I > > > > don't need to write anything to the link. I would think it > > would work > > > > if I just open the connection. > > > > > Thanks. > > > > -- > > -- --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Beginners" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en -~----------~----~----~----~------~----~------~--~---
