Re: [ast-users] Raw command substitution $()
Can you exclude any character from your input data to be used as a separator?
Then you could redefine the read separator (in the example below I used X):
printf \n\n\n\n\n | IFS= read -dX FOO
Date: Mon, 16 Dec 2013 21:02:01 +
From: eschulm...@bloomberg.net
To: AST-USERS@LISTS.RESEARCH.ATT.COM
Subject: [ast-users] Raw command substitution $()
Hi guys,I'm looking for a method to do raw command substitution.
The issue:- Need a ksh93t+ / ksh93u facillity to be able to take the literal
output of a command with no substitutions or omissions, where the substitute
data is less than 1kB. Target platforms are RHEL 6.4, Solaris 11 AIX 7.1.
Examples. printf is used below for illustration only.- $(), command
substitution, i.e. FOO=$(printf \n\n\n\n\n); seems unsuitable as it modifies
the output by performing some whitespace handling, such as stripping newlines.
In this example, FOO returns zero-length.- $(), quoted, prevents the field
splitting and pathname expansions, but doesn't protect the trailing
whitespace.- Binary read, i.e. printf \n\n\n\n\n | read -N$length FOO;
works provided the $length of the read doesn't encounter the EOF, in this case
values 1-5. If $length5, in this example, FOO becomes zero-length. For an
input of unknown length, this feels impractical.- One possible workaround is
adding a suffix and then chopping it, i.e. FOO=$(printf
\n\n\n\n\nmysuffix); FOO=${FOO%mysuffix}
Any advice on the best way to acquire the literal command output?
Thanks!-G
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Re: [ast-users] Raw command substitution $()
Very usable. That looks like a winner.
Thanks!
-G
- Original Message -
From: janis_papanag...@hotmail.com
To: Eugene Schulman (BLOOMBERG/ 120 PARK), ast-users@lists.research.att.com
At: Dec 16 2013 16:28:54
Can you exclude any character from your input data to be used as a separator?
Then you could redefine the read separator (in the example below I used X):
printf \n\n\n\n\n | IFS= read -dX FOO
Date: Mon, 16 Dec 2013 21:02:01 +
From: eschulm...@bloomberg.net
To: AST-USERS@LISTS.RESEARCH.ATT.COM
Subject: [ast-users] Raw command substitution $()
Hi guys,
I'm looking for a method to do raw command substitution.
The issue:
- Need a ksh93t+ / ksh93u facillity to be able to take the literal output of a
command with no substitutions or omissions, where the substitute data is less
than 1kB. Target platforms are RHEL 6.4, Solaris 11 AIX 7.1.
Examples. printf is used below for illustration only.
- $(), command substitution, i.e. FOO=$(printf \n\n\n\n\n); seems unsuitable
as it modifies the output by performing some whitespace handling, such as
stripping newlines. In this example, FOO returns zero-length.
- $(), quoted, prevents the field splitting and pathname expansions, but
doesn't protect the trailing whitespace.
- Binary read, i.e. printf \n\n\n\n\n | read -N$length FOO; works
provided the $length of the read doesn't encounter the EOF, in this case values
1-5. If $length5, in this example, FOO becomes zero-length. For an input of
unknown length, this feels impractical.
- One possible workaround is adding a suffix and then chopping it, i.e.
FOO=$(printf \n\n\n\n\nmysuffix); FOO=${FOO%mysuffix}
Any advice on the best way to acquire the literal command output?
Thanks!-G
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Re: [ast-users] Raw command substitution $()
On 12/16/2013 1:02 PM, Eugene Schulman (BLOOMBERG/ 120 PARK) wrote:
Hi guys,
I'm looking for a method to do raw command substitution.
The issue:
- Need a ksh93t+ / ksh93u facillity to be able to take the literal
output of a command with no substitutions or omissions, where the
substitute data is less than 1kB. Target platforms are RHEL 6.4,
Solaris 11 AIX 7.1.
Examples. printf is used below for illustration only.
- $(), command substitution, i.e. FOO=$(printf \n\n\n\n\n); seems
unsuitable as it modifies the output by performing some whitespace
handling, such as stripping newlines. In this example, FOO returns
zero-length.
- $(), quoted, prevents the field splitting and pathname expansions,
but doesn't protect the trailing whitespace.
- Binary read, i.e. printf \n\n\n\n\n | read -N$length FOO; works
provided the $length of the read doesn't encounter the EOF, in this
case values 1-5. If $length5, in this example, FOO becomes
zero-length. For an input of unknown length, this feels impractical.
- One possible workaround is adding a suffix and then chopping it,
i.e. FOO=$(printf \n\n\n\n\nmysuffix); FOO=${FOO%mysuffix}
The possible workaround is the normal approach, in my experience the
mysuffix is often just a single period or lower case x.
FOO=$(printf \n\n\n ; printf x ;) ; FOO=${FOO%x}
You can use 'echo x' rather than 'printf x' as the trailing newline that
echo produces will be removed by the command substitution.
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