[C++-sig] How to override a property setter?

[ilias]

I got a class:

class X
{
private:
  std::wstring text_;
public:
  std::wstring text() const { return text_; }
  void set_text(const std::string& text) { text_ = from_utf8(text); }
  void set_text(const std::wstring& text) { text_ = text; }
};

I'm trying to use it as a property:

BOOST_PYTHON_MODULE(test)
{
  class_("X")
.add_property("text", &X::text, )
  ;
}

What should I write to get following behavior:

>>> x = X()
>>> x.text = "abc" # I want X::set_text(const std::string&) to be invoked here
>>> x.text = u"abc" # Here I expect X::set_text(const std::wstring&) to be 
called

-- 
Ilya.
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[C++-sig] Weird function call results

[ilias]

I got an overloaded function:

void f(int n)
{
  std::clog << "invoked f(int n = " << n << ")" << std::endl;
}

void f(double d)
{
  std::clog << "invoked f(double d = " << d << ")" << std::endl;
}

If I put declarations in that order:

void (*f_int)(int) = &f;
void (*f_double)(double) = &f;

BOOST_PYTHON_MODULE(test)
{
  def("f", f_int);
  def("f", f_double);
}

No matter what I pass into the function f, f(double) is invoked every time. 
Even though I call f(int(1)) I will see "invoked f(double d = 1)".

But if I declare the function f in reversed order:

BOOST_PYTHON_MODULE(test)
{
  def("f", f_double);
  def("f", f_int);
}

I will see "invoked f(int n = 5)" when I call f(5) and "invoked f(double d = 
3.14)" when I call f(3.14) as it has to be. Why does it happen? Why does it 
depend on declaration order?

-- 
Ilya.
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Re: [C++-sig] Weird function call results

[ilias]

Alex,

> It's not a bug, it's as designed.  Boost.python tries function overloads
> in reverse registration order and picks the first one that works, in the
> sense that all the arguments convert.

Is that behavior specified somewhere in the documentation?
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