Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
On Fri, Jun 23, 2000 at 08:51:44PM -0400, Peter Kovacs wrote: On Sat, 24 Jun 2000, Mark Phillips wrote: for f in $(cd From man 1 bash: Command Substitution Command substitution allows the output of a command to replace the command name. There are two forms: $(command) or `command` That's why I had the backticks in there. I've never seen the $() construct either. The key difference is that $( command list ) is nestable without quoting, backticks are not. If you've ever written: $ foo `bar \`baz qux\` ` ...nested to several levels, you'll appreciate: $ foo $( bar $( baz qux ) ) ...it becomes trivial to build complex expressions interatively on the command line with command-line editing, without having to worry about quoting backticks and such. The functionality is common in a number of shells other than bash, though I'm not quite sure which. I believe the Unix posix-compliant (bastardized korn) and possibly korn shells support it. -- Karsten M. Self kmself@ix.netcom.com http://www.netcom.com/~kmself Evangelist, Opensales, Inc. http://www.opensales.org What part of Gestalt don't you understand? Debian GNU/Linux rocks! http://gestalt-system.sourceforge.net/ K5: http://www.kuro5hin.org GPG fingerprint: F932 8B25 5FDD 2528 D595 DC61 3847 889F 55F2 B9B0 pgpjLcEuXwtaX.pgp Description: PGP signature
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
kmself@ix.netcom.com wrote: The key difference is that $( command list ) is nestable without quoting, backticks are not. [snip] The functionality is common in a number of shells other than bash, though I'm not quite sure which. I believe the Unix posix-compliant (bastardized korn) and possibly korn shells support it. Looking through the shells I have installed, ash and zsh support it too. As I remember, it only appeared in bash as of version 2. -- Colin Watson [EMAIL PROTECTED]
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
Peter Kovacs [EMAIL PROTECTED] writes: On Sat, 24 Jun 2000, Mark Phillips wrote: From man 1 bash: Command Substitution Command substitution allows the output of a command to replace the command name. There are two forms: $(command) or `command` That's why I had the backticks in there. I've never seen the $() construct either. You can use it for kill -9 $(pidof netscape) to get rid of all processes that have the string netscape in their names ;) Andre
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
** On Jun 24, Mark Phillips scribbled: Corey Popelier [EMAIL PROTECTED] wrote: Yes I have this problem also. I assume we shall await a fix. And use Mozilla in the meantime :) [snip] And the problem seems to be with a syntax error at the line for f in (cd $d;ls -1 . | sort); do According to man bash, the (cd $d;ls -1 . | sort) is a compound You shouldn't rely on what bash supports or not. The Debian shell scripts are supposed to be POSIX-compatible, and not everything bash implements is POSIX. command where the stuff in brackets is executed in its own shell. So what this line seems to be trying to do, is to go to a certain directory, get a sorted listing of the files there and then go through them one by one, executing . $d/$f for each of them. What is the . command??? I thought it was the current directory? It's the 'source' command. It takes its argument and interprets the file as a shell code - you might think of it as sort of dynamic linking for scripts. Anyway, the reason for the syntax error is with the definition of a for loop in bash. From man bash: for name [ in word ] ; do list ; done Again, don't rely on bash being the /bin/sh. Debian scripts cannot do that. Now word is a list of blank separated words I believe, so it does not allow the (cd $d;ls -1 . | sort) construction to be used here. So somehow we need to find an alternative. I don't use that script, but I think adding $ before the first bracket would do the trick. Any ideas? Upgrade :)) - it will have been fixed when you read those words most probably :)) marek pgp8wKXz6IzN9.pgp Description: PGP signature
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
** On Jun 24, Mark Phillips scribbled: Peter Kovacs [EMAIL PROTECTED] wrote: On Fri, 23 Jun 2000, Peter Kovacs wrote: I'm sure that a fix has already been posted, but this works for me (replace the code above with this): for d in /usr/lib/netscape/base-4/wrapper.d ; do cd $d; for f in `find -maxdepth 1 -type f`; do . $d/$f done done Wow. I just realized how incredibly incorrect the code is. Well, it works for me. YMMV though. I'd wait for an official fix, or fix it yourself if the above doesn't work. What does YMMV stand for? Your Mileage May Vary for f in $(cd It seems to work sort of, but I don't understand why! The $(...) construct is a replacement for the old `...` construct which means execute the comands between the single quotes (or the $(...) sequence) and replace the expression with the output of the command sequence. The command sequence is executed by a subshell, that is no side effects occur to the current shell (pwd, environment etc.) And what is the . $d/$f supposed to do?? Read my previous posting. marek pgpfE5R1srHJ7.pgp Description: PGP signature
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
Andre Berger [EMAIL PROTECTED] writes: Sorry, use kill -9 $(pidof communicator-smotif.real) or something like that. Andre Peter Kovacs [EMAIL PROTECTED] writes: On Sat, 24 Jun 2000, Mark Phillips wrote: From man 1 bash: Command Substitution Command substitution allows the output of a command to replace the command name. There are two forms: $(command) or `command` That's why I had the backticks in there. I've never seen the $() construct either. You can use it for kill -9 $(pidof netscape) to get rid of all processes that have the string netscape in their names ;) Andre
Bash script question (was: Re: Netscape 4.73 wrapper broken)
Corey Popelier [EMAIL PROTECTED] wrote: Yes I have this problem also. I assume we shall await a fix. And use Mozilla in the meantime :) Or we could try to fix it... the error is with the code: for d in \ /usr/lib/netscape/base-4/wrapper.d \ /usr/lib/netscape/$VER \ /usr/lib/netscape/$VER/$BIN ;do for f in (cd $d;ls -1 . | sort); do . $d/$f done done And the problem seems to be with a syntax error at the line for f in (cd $d;ls -1 . | sort); do According to man bash, the (cd $d;ls -1 . | sort) is a compound command where the stuff in brackets is executed in its own shell. So what this line seems to be trying to do, is to go to a certain directory, get a sorted listing of the files there and then go through them one by one, executing . $d/$f for each of them. What is the . command??? I thought it was the current directory? Anyway, the reason for the syntax error is with the definition of a for loop in bash. From man bash: for name [ in word ] ; do list ; done Now word is a list of blank separated words I believe, so it does not allow the (cd $d;ls -1 . | sort) construction to be used here. So somehow we need to find an alternative. Any ideas? Thanks, Mark. P.S. For any replies, please cc a copy directly to me. On Fri, 23 Jun 2000, Mark Phillips wrote: I've just updated my system to the current frozen, and included in this update was the installation of netscape 4.73. When I now run netscape, it bombs out, complaining of: $ netscape /usr/bin/X11/netscape: line 277: syntax error near unexpected token `(c' /usr/bin/X11/netscape: line 277: ` for f in (cd $d;ls -1 . | sort); do' Has anyone else had this problem? Does anyone else know the fix? Thanks, Mark. P.S. Please cc a copy of any reply directly to me as I currently read the list only via the archives --- and I can't even do that now that netscape is not working. -- _/\___/~~\ /~~\_/~~\__/~~\__Mark_Phillips /~~\_/[EMAIL PROTECTED] /~~\HE___/~~\__/~~\APTAIN_ /~~\__/~~\ __ They told me I was gullible ... and I believed them! -- Unsubscribe? mail -s unsubscribe [EMAIL PROTECTED] /dev/null -- _/\___/~~\ /~~\_/~~\__/~~\__Mark_Phillips /~~\_/[EMAIL PROTECTED] /~~\HE___/~~\__/~~\APTAIN_ /~~\__/~~\ __ They told me I was gullible ... and I believed them!
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
On Sat, 24 Jun 2000, Mark Phillips wrote: for d in \ /usr/lib/netscape/base-4/wrapper.d \ /usr/lib/netscape/$VER \ /usr/lib/netscape/$VER/$BIN ;do for f in (cd $d;ls -1 . | sort); do . $d/$f done done I'm sure that a fix has already been posted, but this works for me (replace the code above with this): for d in /usr/lib/netscape/base-4/wrapper.d ; do cd $d; for f in `find -maxdepth 1 -type f`; do . $d/$f done done Peter -- Peter D. Kovacs KnowPost.com LLC Lead Engineer [EMAIL PROTECTED] --
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
Peter Kovacs [EMAIL PROTECTED] wrote: On Fri, 23 Jun 2000, Peter Kovacs wrote: I'm sure that a fix has already been posted, but this works for me (replace the code above with this): for d in /usr/lib/netscape/base-4/wrapper.d ; do cd $d; for f in `find -maxdepth 1 -type f`; do . $d/$f done done Wow. I just realized how incredibly incorrect the code is. Well, it works for me. YMMV though. I'd wait for an official fix, or fix it yourself if the above doesn't work. What does YMMV stand for? An official fix has come through, and what it does is replace for f in (cd. by for f in $(cd It seems to work sort of, but I don't understand why! And what is the . $d/$f supposed to do?? Cheers, Mark. -- _/\___/~~\ /~~\_/~~\__/~~\__Mark_Phillips /~~\_/[EMAIL PROTECTED] /~~\HE___/~~\__/~~\APTAIN_ /~~\__/~~\ __ They told me I was gullible ... and I believed them!
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
On Sat, 24 Jun 2000, Mark Phillips wrote: What does YMMV stand for? YMMV = Your Mileage May Vary An official fix has come through, and what it does is replace for f in (cd. by for f in $(cd From man 1 bash: Command Substitution Command substitution allows the output of a command to replace the command name. There are two forms: $(command) or `command` That's why I had the backticks in there. I've never seen the $() construct either. And what is the . $d/$f supposed to do?? Again, from man 1 bash: . filename [arguments] source filename [arguments] Read and execute commands from filename in the cur rent shell environment and return the exit status of the last command executed from filename... It simply executes those files as a shell script. Peter -- Peter D. Kovacs KnowPost.com LLC Lead Engineer [EMAIL PROTECTED] --
Re: Bash script question (was: Re: Netscape 4.73 wrapper broken)
On Fri, Jun 23, 2000 at 08:51:44PM -0400, Peter Kovacs wrote On Sat, 24 Jun 2000, Mark Phillips wrote: What does YMMV stand for? YMMV = Your Mileage May Vary An official fix has come through, and what it does is replace for f in (cd. by for f in $(cd From man 1 bash: Command Substitution Command substitution allows the output of a command to replace the command name. There are two forms: $(command) or `command` That's why I had the backticks in there. I've never seen the $() construct either. And what is the . $d/$f supposed to do?? Again, from man 1 bash: . filename [arguments] source filename [arguments] Read and execute commands from filename in the cur rent shell environment and return the exit status of the last command executed from filename... It simply executes those files as a shell script. To be more accurate, it executes the contents of those files as if they had been included in the current script. No new shell, all the current parameters accessible, any parameters or functions defined in those files available in the current context. John P. -- [EMAIL PROTECTED] [EMAIL PROTECTED] http://www.mdt.net.au/~john Debian Linux admin support:technical services
