Re: Copy a file one hundred times
Tzafrir Cohen wrote:
On Sun, Dec 21, 2008 at 04:45:21PM -0600, Ron Johnson wrote:
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
$ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
What's with the {}? An implied variable?
$ LANG=C man xargs | grep -C 2 '{}'
-i[replace-str]
This option is a synonym for -Ireplace-str if replace-str is
specified, and for -I{} otherwise. This option is deprecated;
use -I instead.
yes, {} was the default placeholder in the xargs command. According to the
man-page it should now be
$ seq -w 1 1 100 | xargs -I{} cp file.jpg file{}.jpg
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Re: Copy a file one hundred times
Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
ere is one without looping :-)
snip
$ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 cp file.jpg
And even shorter:
$ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
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Re: Copy a file one hundred times
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
ere is one without looping :-)
snip
$ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 cp file.jpg
And even shorter:
$ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
What's with the {}? An implied variable?
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Re: Copy a file one hundred times
On Sun, Dec 21, 2008 at 04:45:21PM -0600, Ron Johnson wrote:
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
$ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
What's with the {}? An implied variable?
$ LANG=C man xargs | grep -C 2 '{}'
-i[replace-str]
This option is a synonym for -Ireplace-str if replace-str is
specified, and for -I{} otherwise. This option is deprecated;
use -I instead.
--
example:
somecommand | xargs -s 5 echo | xargs -I '{}' -s 10 rm '{}'
Here, the first invocation of xargs has no input line length limit be-
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Re: Copy a file one hundred times
2008/12/14, Rodolfo Medina rodolfo.med...@gmail.com: I need the right syntax to copy file.jpg 100 times with one command so to get 100 files named file1.jpg, file2.jpg, ..., file100.jpg. Can anybody suggest how to achieve that? You could try something like: cat file.pdf | tee `seq -w 0 100 | sed 's+.*+file_.pdf+'` /dev/null (1) The cat command pipes the contents of the file file.pdf to the command tee which can dump the contents of the file to both a file (or files) and to stdout. (2) The `seq -w [...]` creates the file names. (3) The /dev/null is necessary unless you want the contents of the file to pollute your screen. -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of unsubscribe. Trouble? Contact listmas...@lists.debian.org
Re: Copy a file one hundred times
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
c=0; while [ $c -lt 100 ]; do c=$[c + 1]; n='000'$c; cp file.jpg file${n:
-3}.jpg; done
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Re: Copy a file one hundred times
Hi Rodolfo On Sat, Dec 13, 2008 at 8:12 PM, Rodolfo Medina rodolfo.med...@gmail.com wrote: I need the right syntax to copy file.jpg 100 times with one command so to get 100 files named file1.jpg, file2.jpg, ..., file100.jpg. #!/bin/bash for x in `seq 1 100`; do if [[ x -lt 10 ]]; then cp file.jpg file-00$x.jpg; elif [[ x -lt 100 ]]; then cp file.jpg file-0$x.jpg; else cp file.jpg file-$x.jpg; fi done Greetings, Manon. -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of unsubscribe. Trouble? Contact listmas...@lists.debian.org
Re: Copy a file one hundred times
On Sat, Dec 13, 2008 at 07:35:44PM +0100, Manon Metten wrote:
Hi Rodolfo
On Sat, Dec 13, 2008 at 8:12 PM, Rodolfo Medina
rodolfo.med...@gmail.com wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
#!/bin/bash
for x in `seq 1 100`; do
if [[ x -lt 10 ]]; then cp file.jpg file-00$x.jpg;
elif [[ x -lt 100 ]]; then cp file.jpg file-0$x.jpg;
else cp file.jpg file-$x.jpg;
fi
done
I forgot about seq. This is even better (the -w left pads with zero for
equal width):
for x in $(seq -w 1 100); do cp file.jpg file${c}.jpg; done
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Re: Copy a file one hundred times
Rodolfo writes:
I need the right syntax to copy file.jpg 100 times with one command so to
get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
for I in {1..100}; do cp file.jpg file$I.jpg ; done
But what are you actually trying to achieve?
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Re: Copy a file one hundred times
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote: I need the right syntax to copy file.jpg 100 times with one command so to get 100 files named file1.jpg, file2.jpg, ..., file100.jpg. Can anybody suggest how to achieve that? ere is one without looping :-) $ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 echo file.jpg -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of unsubscribe. Trouble? Contact listmas...@lists.debian.org
Re: Copy a file one hundred times
The Saturday 13 December 2008 20:12:32 Rodolfo Medina, you wrote :
I need the right syntax to copy file.jpg 100 times with one command so to
get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
Thanks for any reply
Rodolfo
filevar=file.jpg
basefile=${filevar%.[^.]*}
extension=${filevar##^.*.}
for i in `seq 100`
do
cp $filevar $basefile$i.$extension
done
with file the file to copy, basefile the file without the last extension and
extension the last extension (without the dot).
In a function it would be
function hundred-copy ()
{
filevar=$1 # The file to copy a hundred time
basefile=${filevar%.[^.]*} # We delete all the end from the last dot (eg
a dot followed by any others caracters)
extension=${filevar##^.*.} # We delete all the beginning until the last
dot included (biggest prefix with any caracters followed by a dot)
do
cp $filevar $basefile$i.$extension # file become
filenumber.extension
done
}
Regards,
Thomas Preud'homme
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Re: Copy a file one hundred times
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote: On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote: I need the right syntax to copy file.jpg 100 times with one command so to get 100 files named file1.jpg, file2.jpg, ..., file100.jpg. Can anybody suggest how to achieve that? ere is one without looping :-) $ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 echo file.jpg err.. does this work? -- Tzafrir Cohen | tzaf...@jabber.org | VIM is http://tzafrir.org.il || a Mutt's tzaf...@cohens.org.il || best ICQ# 16849754 || friend -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of unsubscribe. Trouble? Contact listmas...@lists.debian.org
Re: Copy a file one hundred times
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote: On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote: On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote: I need the right syntax to copy file.jpg 100 times with one command so to get 100 files named file1.jpg, file2.jpg, ..., file100.jpg. Can anybody suggest how to achieve that? ere is one without looping :-) $ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 echo file.jpg err.. does this work? I think he put an echo to show the lines echo file.jpg file1.jpg -- Tzafrir Cohen | tzaf...@jabber.org | VIM is http://tzafrir.org.il || a Mutt's tzaf...@cohens.org.il || best ICQ# 16849754 || friend -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of unsubscribe. Trouble? Contact listmas...@lists.debian.org -- President Musharraf, he's still tight with us on the war against terror, and that's what I appreciate. He's a -- he understands that we've got to keep Al Qaeda on the run, and that by keeping him on the run, it's more likely we will bring him to justice. - George W. Bush 08/22/2002 Ruch, OR signature.asc Description: Digital signature
Re: Copy a file one hundred times
Hi Rick,
On Sat, Dec 13, 2008 at 7:41 PM, Rick Pasotto r...@niof.net wrote:
I forgot about seq. This is even better (the -w left pads with zero for
equal width):
for x in $(seq -w 1 100); do cp file.jpg file${c}.jpg; done
Waw! Great one-liner.
BTW: Guess you meant file${x}.jpg;
Greetings, Manon.
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Re: Copy a file one hundred times
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote: On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote: On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote: I need the right syntax to copy file.jpg 100 times with one command so to get 100 files named file1.jpg, file2.jpg, ..., file100.jpg. Can anybody suggest how to achieve that? ere is one without looping :-) $ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 echo file.jpg err.. does this work? THIS DOES NOT WORK! Agh... This was my local test script :-) s/echo/cp/ is needed as you may have guessed. $ seq 1 100 | sed s/^\(.*\)$/file\1.jpg/ |xargs -n1 cp file.jpg This is one should do cp file.jpg file1.jpg cp file.jpg file2.jpg ... cp file.jpg file100.jpg Osamu -- To UNSUBSCRIBE, email to debian-user-requ...@lists.debian.org with a subject of unsubscribe. Trouble? Contact listmas...@lists.debian.org
Re: Copy a file one hundred times
Rick Pasotto wrote:
I forgot about seq. This is even better (the -w left pads with zero for
equal width):
for x in $(seq -w 1 100); do cp file.jpg file${x}.jpg; done
correction^
Nice! Something I have been looking for quite some time. I was using the
elseif statements before I saw this.
Thanks a ton.
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Re: Copy a file one hundred times
Thomas Preud'homme wrote:
The Saturday 13 December 2008 20:12:32 Rodolfo Medina, you wrote :
I need the right syntax to copy file.jpg 100 times with one command so to
get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
Thanks for any reply
Rodolfo
filevar=file.jpg
basefile=${filevar%.[^.]*}
extension=${filevar##^.*.}
for i in `seq 100`
do
cp $filevar $basefile$i.$extension
done
with file the file to copy, basefile the file without the last extension and
extension the last extension (without the dot).
In a function it would be
function hundred-copy ()
{
filevar=$1 # The file to copy a hundred time
basefile=${filevar%.[^.]*} # We delete all the end from the last dot (eg
a dot followed by any others caracters)
extension=${filevar##^.*.} # We delete all the beginning until the last
dot included (biggest prefix with any caracters followed by a dot)
do
cp $filevar $basefile$i.$extension # file become
filenumber.extension
done
}
Regards,
Thomas Preud'homme
Nice job of pattern matching and extraction without using sed! Gives me
a new tool to create new filesname based on input files. Usually I run
an experiment which takes filenames as input and produces multiple files
for each file to save results in.
Thanks.
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Re: Copy a file one hundred times
Thomas Preud'homme wrote:
filevar=$1 # The file to copy a hundred time
basefile=${filevar%.[^.]*} # We delete all the end from the last dot (eg
a dot followed by any others caracters)
extension=${filevar##^.*.} # We delete all the beginning until the last
Just for reference, this pattern matching and chopping is explained more
with examples here:
http://www.ibm.com/developerworks/library/l-bash.html#N1010B
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