Re: How do I check if this field is of this template struct?
On Saturday, 20 March 2021 at 00:16:06 UTC, Steven Schveighoffer
wrote:
On 3/19/21 12:41 PM, Jack wrote:
On Friday, 19 March 2021 at 08:54:50 UTC, Paul Backus wrote:
On Friday, 19 March 2021 at 07:14:46 UTC, Jack wrote:
give below template struct, how can I list the members x, y
and z? I've tried something with OriginalType and TemplateOf
but no luck... it seems if I do foo!"str1" the "str1" became
"part of type"? give .stringof from
typeof(__traits(getMember, foo, field)) I thought the type
would be foo!string or something.
You want std.traits.isInstanceOf:
static if(!isType!m && isInstanceOf!(foo, typeof(m)))
thanks this works fine outside a method but not in a static
method. what am I missing?
void main()
{
// doesn't print anything
Foo.list();
}
alias Foo = foo!();
template foo(string s = null)
{
@nogc
struct foo
{
int n;
enum x = foo!"str1"(10);
enum y = foo!"str2"(20);
enum z = foo!"str3"(30);
enum myEnum { none }
void someMethod() { }
static void list()
{
//writeln("members = ", [__traits(allMembers,
foo!())]);
static foreach(field; __traits(allMembers,
foo!()))
{{
alias m = __traits(getMember, foo!(), field);
static if(!isType!m && isInstanceOf!(foo,
typeof(m)))
foo in this context is the *instantiated* foo (i.e. the struct
foo above). What you want is `isIsntanceOf!(.foo, typeof(m))`
-Steve
Thank you Steve, that what I was looking for. Funny thing, I
totally forget about the . operator
Re: How do I check if this field is of this template struct?
On Friday, 19 March 2021 at 17:40:39 UTC, frame wrote: On Friday, 19 March 2021 at 16:41:11 UTC, Jack wrote: thanks this works fine outside a method but not in a static method. what am I missing? Reading the manual ;) To use isInstanceOf to check the identity of a template while inside of said template, use TemplateOf. indeed, it shwos an example on how to use that in a static function
Can I make this work?
there's a value passed as template parameter which is know at
compile time (can be used with static if) but I don't know how
can I pass it around and use in a property. Obviously enum
deosn't work because it would be a local to the function.
immutable would result in compiler can't read it at compile time.
version doesn't work either because it isn't at module scope but
a function.
full code:
struct S
{
enum x = init!(false, 10);
enum y = init!(true, 20);
this(string s)
{
type = Type.type1;
}
this(int n)
{
type = Type.type2;
}
static auto init(bool v, int val)()
{
auto s = S();
static if(v)
{
s.type = Type.type1;
}
else
{
s.type = Type.type2;
}
s.n = val;
return s;
}
int value()
{
// would to use static if here or just
// get rid of that check if type is Type.type1,
// information which is available at init()
// template function.
if(type == Type.type2) {
// do something
}
return n;
}
Type type;
int n;
}
enum Type
{
type1,
type2,
type3
}
Re: How do I check if this field is of this template struct?
On 3/19/21 12:41 PM, Jack wrote:
On Friday, 19 March 2021 at 08:54:50 UTC, Paul Backus wrote:
On Friday, 19 March 2021 at 07:14:46 UTC, Jack wrote:
give below template struct, how can I list the members x, y and z?
I've tried something with OriginalType and TemplateOf but no luck...
it seems if I do foo!"str1" the "str1" became "part of type"? give
.stringof from typeof(__traits(getMember, foo, field)) I thought the
type would be foo!string or something.
You want std.traits.isInstanceOf:
static if(!isType!m && isInstanceOf!(foo, typeof(m)))
thanks this works fine outside a method but not in a static method. what
am I missing?
void main()
{
// doesn't print anything
Foo.list();
}
alias Foo = foo!();
template foo(string s = null)
{
@nogc
struct foo
{
int n;
enum x = foo!"str1"(10);
enum y = foo!"str2"(20);
enum z = foo!"str3"(30);
enum myEnum { none }
void someMethod() { }
static void list()
{
//writeln("members = ", [__traits(allMembers, foo!())]);
static foreach(field; __traits(allMembers, foo!()))
{{
alias m = __traits(getMember, foo!(), field);
static if(!isType!m && isInstanceOf!(foo, typeof(m)))
foo in this context is the *instantiated* foo (i.e. the struct foo
above). What you want is `isIsntanceOf!(.foo, typeof(m))`
-Steve
Re: How to delete dynamic array ?
On Thursday, 18 March 2021 at 17:57:30 UTC, Patrick Schluter wrote: It's important to understand that [] is just a practical syntax for a fat pointer. Thinking of [] just as a fancy pointer helps imho to clarify that the pointed to memory nature is independant of the pointer itself. I think they are arrays alright. What's missing is expression of ownership, because D follows traditional language design approach, and traditionally ownership wasn't expressed in language and was done by convention.
Re: How do I check if this field is of this template struct?
On Friday, 19 March 2021 at 16:41:11 UTC, Jack wrote: thanks this works fine outside a method but not in a static method. what am I missing? Reading the manual ;) To use isInstanceOf to check the identity of a template while inside of said template, use TemplateOf.
Re: How do I check if this field is of this template struct?
On Friday, 19 March 2021 at 08:54:50 UTC, Paul Backus wrote:
On Friday, 19 March 2021 at 07:14:46 UTC, Jack wrote:
give below template struct, how can I list the members x, y
and z? I've tried something with OriginalType and TemplateOf
but no luck... it seems if I do foo!"str1" the "str1" became
"part of type"? give .stringof from typeof(__traits(getMember,
foo, field)) I thought the type would be foo!string or
something.
You want std.traits.isInstanceOf:
static if(!isType!m && isInstanceOf!(foo, typeof(m)))
thanks this works fine outside a method but not in a static
method. what am I missing?
void main()
{
// doesn't print anything
Foo.list();
}
alias Foo = foo!();
template foo(string s = null)
{
@nogc
struct foo
{
int n;
enum x = foo!"str1"(10);
enum y = foo!"str2"(20);
enum z = foo!"str3"(30);
enum myEnum { none }
void someMethod() { }
static void list()
{
//writeln("members = ", [__traits(allMembers, foo!())]);
static foreach(field; __traits(allMembers, foo!()))
{{
alias m = __traits(getMember, foo!(), field);
static if(!isType!m && isInstanceOf!(foo,
typeof(m)))
{
writefln("field = [%s]", field);
}
}}
}
}
}
Re: How do I check if this field is of this template struct?
On Friday, 19 March 2021 at 07:56:26 UTC, Panke wrote:
On Friday, 19 March 2021 at 07:14:46 UTC, Jack wrote:
give below template struct, how can I list the members x, y
and z? I've tried something with OriginalType and TemplateOf
but no luck... it seems if I do foo!"str1" the "str1" became
"part of type"? give .stringof from typeof(__traits(getMember,
foo, field)) I thought the type would be foo!string or
something.
Template parameter cannot only be types but also values,
including strings. If you instantiate a template with different
values you get different types.
that design is a bit different but may be worth, gonna get used
to it
--
struct foo(T) { }
struct bar(string s) {}
alias a = foo!string; // type of a is foo!string
alias b = bar!"str1"; // type of b is bar!"str1"
alias c = bar!"str2"; // typo of c is bar!"str2"
static assert (!is(typeof(c) == typeof(b)));
--
Re: Using YMM registers causes an undefined label error
On Tuesday, 9 March 2021 at 20:33:01 UTC, z wrote: On Tuesday, 9 March 2021 at 20:23:48 UTC, z wrote: On Friday, 5 March 2021 at 12:57:43 UTC, z wrote: ... Then it seems the only way to get AVX-compatible inline assembly(ldc.llvmasm excluded) is to use an external assembler. For example : ... But i'm not really sure how to integrate that into a dub project, it seems «lflags "filename.obj"» and preGenerateCommands/preBuildCommands would work but i haven't tested that.(«dflags "filename.obj"» doesn't work for sure) In dub.sdl : lflags "source/asmfunctions.obj" preGenerateCommands " cd source && *command or bat/sh file that builds the asm object file(s)*" It works, but if the package is being imported by another then it will fail because the way lflags work mean that the linker will try to find source/asmfunctions.obj from the working directory of the importer. This is circumventable with relative paths(if possible). lflags "../importedpackagesname/source/asmfunctions.obj"
Re: How do I check if this field is of this template struct?
On Friday, 19 March 2021 at 07:14:46 UTC, Jack wrote: give below template struct, how can I list the members x, y and z? I've tried something with OriginalType and TemplateOf but no luck... it seems if I do foo!"str1" the "str1" became "part of type"? give .stringof from typeof(__traits(getMember, foo, field)) I thought the type would be foo!string or something. You want std.traits.isInstanceOf: static if(!isType!m && isInstanceOf!(foo, typeof(m)))
Re: noobie question, dub or meson?
On Thursday, 18 March 2021 at 06:02:03 UTC, Elronnd wrote: Meson doesn't track dependencies properly for d, so your dirty builds will be wrong if you go that route. You might consider keeping the c and d code in the same repository, but with separate build systems; using dub to build the d code and and whatever tool you prefer for c. Or try reggae. Hi Elronnd You might be right. Since Visual D is highly spoken of on these forums I decided to give it a go. I don't usually write software on Windows, and I have to say that once I stepped outside the D ecosystem the experience was not good. There's no standard locations for anything. Meson worked well on Linux, but I can't figure out how to get it to find vcpkg dependencies on Windows. Outside Visual D, the one thing that worked great on windows was: dub I know everyone knocks the idea of downloading your dependencies off the web, but when starting from scratch you have to get them from somewhere and dub comes to the rescue, and "add-path" is there for local packages. Has there ever been talk of adding C source code support to dub, or is that a forbidden topic? I know if dub supported C, all my C libs and all my necessary dependencies (openssl, expat, etc.) would have dub.json files before the weekend was over.
Re: How do I check if this field is of this template struct?
On Friday, 19 March 2021 at 07:14:46 UTC, Jack wrote:
give below template struct, how can I list the members x, y and
z? I've tried something with OriginalType and TemplateOf but no
luck... it seems if I do foo!"str1" the "str1" became "part of
type"? give .stringof from typeof(__traits(getMember, foo,
field)) I thought the type would be foo!string or something.
Template parameter cannot only be types but also values,
including strings. If you instantiate a template with different
values you get different types.
--
struct foo(T) { }
struct bar(string s) {}
alias a = foo!string; // type of a is foo!string
alias b = bar!"str1"; // type of b is bar!"str1"
alias c = bar!"str2"; // typo of c is bar!"str2"
static assert (!is(typeof(c) == typeof(b)));
--
How do I check if this field is of this template struct?
give below template struct, how can I list the members x, y and
z? I've tried something with OriginalType and TemplateOf but no
luck... it seems if I do foo!"str1" the "str1" became "part of
type"? give .stringof from typeof(__traits(getMember, foo,
field)) I thought the type would be foo!string or something.
Here's the code:
template foo(string s = null)
{
@nogc
struct foo
{
int n;
enum x = foo!"str1"(10);
enum y = foo!"str2"(20);
enum z = foo!"str3"(30);
enum myEnum { none }
void someMethod() { }
}
}
not working listener:
void list()
{
static foreach(field; __traits(allMembers, foo!()))
{{
alias m = __traits(getMember, foo!(), field);
static if(!isType!m && __traits(isSame,
OriginalType!(typeof(m)), foo))
{
writefln("field = [%s]", field);
}
}}
}
