switch statement exiting a void function

[Jonathan via Digitalmars-d-learn]

Here's the setup, I have a function

void main { ... }

The main method parses input (via std.getopt) and calls one of 
three void-return-type functions.  The program's three options 
correspond to significantly different initialization options.


In the code we then have:

enum RunOpt {opt1, opt2, opt3};

And the body of the function wants to do:

RunOpt option;
//parsing that results in, among other things option being 
initialized

switch(option){
case RunOpt.opt1: fun1(...);
case RunOpt.opt2: fun2(...);
default: fun3(...);
}

When compiling, the error I get is

Error: switch case fallthrough - use 'goto case;' if intended

This is not intended.  Note that calling return; after 
funi(...) makes everything work.  However, it feels like I'm 
doing something wrong here?

Re: switch statement exiting a void function

[bearophile via Digitalmars-d-learn]

Jonathan:

This is not intended.  Note that calling return; after 
funi(...) makes everything work.  However, it feels like I'm 
doing something wrong here?


Try:

enum RunOpt { opt1, opt2, opt3 } // No semicolon here

final switch (option) with (RunOpt) {
case opt1: fun1(...); break;
case opt2: fun2(...); break;
case opt3: fun3(...); break;
}

Bye,
bearophile

Re: switch statement exiting a void function

[Jonathan via Digitalmars-d-learn]

Try:

enum RunOpt { opt1, opt2, opt3 } // No semicolon here

final switch (option) with (RunOpt) {
case opt1: fun1(...); break;
case opt2: fun2(...); break;
case opt3: fun3(...); break;
}

Bye,
bearophile


My hero.