Re: "Dynamyc" modells
hi guys, django-dynamo https://bitbucket.org/schacki/django-dynamo will let users create models dynamically on the fly through the admin. maybe this helps. regards, juergen Am Dienstag, 13. März 2012 08:48:03 UTC+1 schrieb airween: > > hi, > > On Mon, Mar 12, 2012 at 09:51:43PM -0400, Dennis Lee Bieber wrote: > > On Mon, 12 Mar 2012 22:14:27 +0100, Ervin Hegedüs> > declaimed the following in gmane.comp.python.django.user: > > > > > > > Some promotion has few millions of records, different promotions have > > > different format of codes, ... And general: I'm looking for an ultimate > > > solution, and may be the next time every ListRecord will have different > > > columns. > > > > > Strangely, your "ultimate solution" might mean implementing a > DBMS > > AS the application, rather than just USING a DBMS... > > > > That is: maintaining a data dictionary which contains "promotion > > format", "promotion field", "field type", (maybe field position too, > > along with fields to identify constraints on the valid values); > [...] > > yes, it's absolutely true. > > But :), I'm so far from there I implement full of these. > > > It's no problem, I'm just looking for a good solution, first it > could be enough to implement all() method (and filter()), and > there is an important invariant: in my (all) cases, the different > ListItems has an intersect of columns, I mean there are a few > columns, which exists in all ListItems object. > > > Any idea? > > > Thanks: > > > a. > > > -- > I � UTF-8 > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To view this discussion on the web visit https://groups.google.com/d/msg/django-users/-/NonOheQhNWUJ. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
This is so not what Django was built to do... I have a feeling that if you ever do manage to write it, it's going to be slower than slow and error prone... Sincerely, AT On Tue, Mar 13, 2012 at 4:59 AM, Ervin Hegedüswrote: > hello, > > On Tue, Mar 13, 2012 at 09:38:34AM +0200, Jani Tiainen wrote: > > > Ultimate solution sounds more like using document oriented > > databases, like CouchDB or MongoDB. (Just the few I happened to > > remember). > > okay, lets look an another example: I have a model, which > describes RDBMS connections: DBdesc, DBhost, DBuser, DBpassword, > DBdbname, DBtable, DBkeycolumn, DBvalcolumn, and so on... > > Now I can filter() a row by DBdesc, which gives me de full > description of DB connection - sometimes that DB exists on an > external host. As I wrote my previous email, all data model in > different data source have an intersect of columns, these columns > are stored in my model. > > (Security is important, usually I used this through VPN's, and > currently all stored connection has just select privilege - these > are not sensitive datas of course.) > > After I get the DB desc, I use "row" SQL connection, eg. when DB > is MySQL, I import the MySQLdb modul, create a mysql connection, > a cursor... > > This is different from marketing agencies example, but I can use > the "ultimate" solution at every cases. > > > Thanks: > > > a. > > > -- > I � UTF-8 > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-users@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
hello, On Tue, Mar 13, 2012 at 09:38:34AM +0200, Jani Tiainen wrote: > Ultimate solution sounds more like using document oriented > databases, like CouchDB or MongoDB. (Just the few I happened to > remember). okay, lets look an another example: I have a model, which describes RDBMS connections: DBdesc, DBhost, DBuser, DBpassword, DBdbname, DBtable, DBkeycolumn, DBvalcolumn, and so on... Now I can filter() a row by DBdesc, which gives me de full description of DB connection - sometimes that DB exists on an external host. As I wrote my previous email, all data model in different data source have an intersect of columns, these columns are stored in my model. (Security is important, usually I used this through VPN's, and currently all stored connection has just select privilege - these are not sensitive datas of course.) After I get the DB desc, I use "row" SQL connection, eg. when DB is MySQL, I import the MySQLdb modul, create a mysql connection, a cursor... This is different from marketing agencies example, but I can use the "ultimate" solution at every cases. Thanks: a. -- I � UTF-8 -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
hi, On Mon, Mar 12, 2012 at 09:51:43PM -0400, Dennis Lee Bieber wrote: > On Mon, 12 Mar 2012 22:14:27 +0100, Ervin Hegedüs> declaimed the following in gmane.comp.python.django.user: > > > > Some promotion has few millions of records, different promotions have > > different format of codes, ... And general: I'm looking for an ultimate > > solution, and may be the next time every ListRecord will have different > > columns. > > > Strangely, your "ultimate solution" might mean implementing a DBMS > AS the application, rather than just USING a DBMS... > > That is: maintaining a data dictionary which contains "promotion > format", "promotion field", "field type", (maybe field position too, > along with fields to identify constraints on the valid values); [...] yes, it's absolutely true. But :), I'm so far from there I implement full of these. It's no problem, I'm just looking for a good solution, first it could be enough to implement all() method (and filter()), and there is an important invariant: in my (all) cases, the different ListItems has an intersect of columns, I mean there are a few columns, which exists in all ListItems object. Any idea? Thanks: a. -- I � UTF-8 -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
13.3.2012 3:51, Dennis Lee Bieber kirjoitti: On Mon, 12 Mar 2012 22:14:27 +0100, Ervin Hegedüsdeclaimed the following in gmane.comp.python.django.user: Some promotion has few millions of records, different promotions have different format of codes, ... And general: I'm looking for an ultimate solution, and may be the next time every ListRecord will have different columns. Strangely, your "ultimate solution" might mean implementing a DBMS AS the application, rather than just USING a DBMS... Ultimate solution sounds more like using document oriented databases, like CouchDB or MongoDB. (Just the few I happened to remember). That is: maintaining a data dictionary which contains "promotion format", "promotion field", "field type", (maybe field position too, along with fields to identify constraints on the valid values); and a related data table in which each record holds just ONE field, with a foreign key referencing the specific "promotion format/field" pair along with a field containing the "record ID" (since any actual record will take more than one table entry). The data value itself is likely going to be a BLOB [unless you are using SQLite where you can store anything in a field], and you use the type information to determine how to interpret the value. That's doable but will be pain in the ass to maintain. Also performance is not that good since it wouldbe RDBMS on top of RDBMS. Also all database CRUD operations would be handcrafted still. I would definitely look using those document oriented databases which would allow doing all that fancy stuff without too much sweat. -- Jani Tiainen -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
Hello, 2012.03.12. 20:48, "Shawn Milochik"ezt írta: > > On 03/12/2012 03:34 PM, Ervin Hegedüs wrote: >> >> The main problem is the PromoList is _dynamyc_ - it means all >> administrator on admin site should add new PromoList, without me >> :), so I can't derivate all subclass in code... >> > > You can't dynamically create database tables on the fly. That's not true. Currently I'm using this way, which I described above, just I can't use Model methods. When admin creates a new record, Django creates a new table trough save hook. > > Why not make one model, give it an extra field for the description of what type of promo it is, and just add records to the same model for each "type" of promo code? Some promotion has few millions of records, different promotions have different format of codes, ... And general: I'm looking for an ultimate solution, and may be the next time every ListRecord will have different columns. Thanks: a -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
On 03/12/2012 03:34 PM, Ervin Hegedüs wrote: The main problem is the PromoList is _dynamyc_ - it means all administrator on admin site should add new PromoList, without me :), so I can't derivate all subclass in code... You can't dynamically create database tables on the fly. That would require real-time schema migrations, which would be a bad idea even if you got it to work. Why not make one model, give it an extra field for the description of what type of promo it is, and just add records to the same model for each "type" of promo code? -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
Hello, thanks for the reply. On Mon, Mar 12, 2012 at 03:20:10PM -0400, Shawn Milochik wrote: > First, I would avoid using the word 'list' for describing anything > in your own data, since it's a Python built-in. Maybe CodeList or > PromoList or something, if they're going to be promotion codes. Or > maybe just Promo, since a model should be a singular name, and each > instance of your model will be a single item, not actually a list. well, you're right, using "list" should misleading - thanks. > I think you can do what you want my making a class that subclasses > models.Model, then subclassing that with all of your other classes. > > As long as you don't make the base class "abstract," adding > instances to any subclass will create an instance of the base class. > > I think that answers your question, but I don't understand your > description well enough to claim that this is the best approach to > the problem you're trying to solve. umm, no, sorry, I've wrote my problem incomplete. The main problem is the PromoList is _dynamyc_ - it means all administrator on admin site should add new PromoList, without me :), so I can't derivate all subclass in code... May be this would be clear Thanks: a. -- I � UTF-8 -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: "Dynamyc" modells
First, I would avoid using the word 'list' for describing anything in your own data, since it's a Python built-in. Maybe CodeList or PromoList or something, if they're going to be promotion codes. Or maybe just Promo, since a model should be a singular name, and each instance of your model will be a single item, not actually a list. I think you can do what you want my making a class that subclasses models.Model, then subclassing that with all of your other classes. As long as you don't make the base class "abstract," adding instances to any subclass will create an instance of the base class. I think that answers your question, but I don't understand your description well enough to claim that this is the best approach to the problem you're trying to solve. Shawn -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
"Dynamyc" modells
Hello, I don't know how can I tell you my question :) There are many lists - lists contains items (in this case those items are promotion codes for marketing agencies, but it doesn't matter). I need (I want) to store every lists in different table. I can make a List model, which describes name of list, table which contains items, and so on. But then, I want to use every lists as List model - is it possible? I mean, I can use get(), filter() and other methods of model. If yes, what should I read to know this? Thanks: a. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.