Re: Setting up my application
Just put those other one urls before the catch-all, for example:
...
(r'^aboutus/', 'views.aboutus'),
(r'^history/', 'views.history'),
(r'^contactinfo/', 'views.contactinfo'),
(r'(?P\w+)/', 'views.whatever),
...
Greg wrote:
> Duc,
> Because sometimes the word will be be a manufacturer. Some example
> possible url's of my site could be:
>
> www.mysites.com/milliken/
> www.mysites.com/mohawk/
> www.mysites.com/aboutus/
> www.mysites.com/history/
> www.mysites.com/contactinfo/
>
> So sometimes it wouldn't be a manufacturer. How would I solve that
> problem?
>
>
> On May 19, 11:55 pm, Duc Nguyen <[EMAIL PROTECTED]> wrote:
>> Why can't it just be a "catch-all" url like:
>>
>> (r'(?P\w+)/', 'theview')
>>
>> and then in your view:
>>
>> def theview(request, manufacturer):
>> if manufacturer in my_manufacturers:
>>do_something()
>> else:
>># error out with unknown manufacturer msg?
>>
>>
>>
>> Greg wrote:
>>> I'm working on creating an e-commerce site in Django. I have a
>>> website that sells area rugs from 20 different manufacturers. I am
>>> wondering what the best way to configure my urls.py file. I've been
>>> thinking of a couple of different ways to accomplish this.
>>> 1) Contained all in one url line
>>> (r'^(mohawk|milliken|shaw|sphinx|etc...))/$', 'theview'),
>>> My 'theview' function would then find out what variable was passed to
>>> it. And then query that manufacturer table. So my url can get
>>> pretty long depending on how many manufacturers I have. Also, if I
>>> did it this way how would I setup my view? Would it be something like
>>> this
>>> def theview(request, manufacturer):
>>>rec = manufacturer.objects.all()
>>>return render_to_response('dispaly_manu.html', {'manu_records':
>>> rec})
>>> 2) Creating a separate url for each manufacturer
>>> (r'^/mohawk/$', 'django.views.generic.list_detail.object_list',
>>> mohawk_dict),
>>> (r'^/milliken/$', 'django.views.generic.list_detail.object_list',
>>> milliken_dict),
>>> (r'^/shaw/$', 'django.views.generic.list_detail.object_list',
>>> shaw_dict),
>>> (r'^/sphinx/$', 'django.views.generic.list_detail.object_list',
>>> sphinx_dict),
>>> This way seems like a waste. Would I need to create a unique
>>> dictionary for each manufacturer? Is there a way I can use the same
>>> dictionary for every manufacturer?
>>> Or does somebody have a better solution than what I came up with
>>> above?
>>> Thanks- Hide quoted text -
>> - Show quoted text -
>
>
> >
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Re: Setting up my application
Duc,
Because sometimes the word will be be a manufacturer. Some example
possible url's of my site could be:
www.mysites.com/milliken/
www.mysites.com/mohawk/
www.mysites.com/aboutus/
www.mysites.com/history/
www.mysites.com/contactinfo/
So sometimes it wouldn't be a manufacturer. How would I solve that
problem?
On May 19, 11:55 pm, Duc Nguyen <[EMAIL PROTECTED]> wrote:
> Why can't it just be a "catch-all" url like:
>
> (r'(?P\w+)/', 'theview')
>
> and then in your view:
>
> def theview(request, manufacturer):
> if manufacturer in my_manufacturers:
>do_something()
> else:
># error out with unknown manufacturer msg?
>
>
>
> Greg wrote:
> > I'm working on creating an e-commerce site in Django. I have a
> > website that sells area rugs from 20 different manufacturers. I am
> > wondering what the best way to configure my urls.py file. I've been
> > thinking of a couple of different ways to accomplish this.
>
> > 1) Contained all in one url line
> > (r'^(mohawk|milliken|shaw|sphinx|etc...))/$', 'theview'),
>
> > My 'theview' function would then find out what variable was passed to
> > it. And then query that manufacturer table. So my url can get
> > pretty long depending on how many manufacturers I have. Also, if I
> > did it this way how would I setup my view? Would it be something like
> > this
>
> > def theview(request, manufacturer):
> >rec = manufacturer.objects.all()
> >return render_to_response('dispaly_manu.html', {'manu_records':
> > rec})
>
> > 2) Creating a separate url for each manufacturer
> > (r'^/mohawk/$', 'django.views.generic.list_detail.object_list',
> > mohawk_dict),
> > (r'^/milliken/$', 'django.views.generic.list_detail.object_list',
> > milliken_dict),
> > (r'^/shaw/$', 'django.views.generic.list_detail.object_list',
> > shaw_dict),
> > (r'^/sphinx/$', 'django.views.generic.list_detail.object_list',
> > sphinx_dict),
>
> > This way seems like a waste. Would I need to create a unique
> > dictionary for each manufacturer? Is there a way I can use the same
> > dictionary for every manufacturer?
>
> > Or does somebody have a better solution than what I came up with
> > above?
>
> > Thanks- Hide quoted text -
>
> - Show quoted text -
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Re: Setting up my application
Why can't it just be a "catch-all" url like:
(r'(?P\w+)/', 'theview')
and then in your view:
def theview(request, manufacturer):
if manufacturer in my_manufacturers:
do_something()
else:
# error out with unknown manufacturer msg?
Greg wrote:
> I'm working on creating an e-commerce site in Django. I have a
> website that sells area rugs from 20 different manufacturers. I am
> wondering what the best way to configure my urls.py file. I've been
> thinking of a couple of different ways to accomplish this.
>
> 1) Contained all in one url line
> (r'^(mohawk|milliken|shaw|sphinx|etc...))/$', 'theview'),
>
> My 'theview' function would then find out what variable was passed to
> it. And then query that manufacturer table. So my url can get
> pretty long depending on how many manufacturers I have. Also, if I
> did it this way how would I setup my view? Would it be something like
> this
>
> def theview(request, manufacturer):
>rec = manufacturer.objects.all()
>return render_to_response('dispaly_manu.html', {'manu_records':
> rec})
>
> 2) Creating a separate url for each manufacturer
> (r'^/mohawk/$', 'django.views.generic.list_detail.object_list',
> mohawk_dict),
> (r'^/milliken/$', 'django.views.generic.list_detail.object_list',
> milliken_dict),
> (r'^/shaw/$', 'django.views.generic.list_detail.object_list',
> shaw_dict),
> (r'^/sphinx/$', 'django.views.generic.list_detail.object_list',
> sphinx_dict),
>
> This way seems like a waste. Would I need to create a unique
> dictionary for each manufacturer? Is there a way I can use the same
> dictionary for every manufacturer?
>
> Or does somebody have a better solution than what I came up with
> above?
>
> Thanks
>
>
> >
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Setting up my application
I'm working on creating an e-commerce site in Django. I have a
website that sells area rugs from 20 different manufacturers. I am
wondering what the best way to configure my urls.py file. I've been
thinking of a couple of different ways to accomplish this.
1) Contained all in one url line
(r'^(mohawk|milliken|shaw|sphinx|etc...))/$', 'theview'),
My 'theview' function would then find out what variable was passed to
it. And then query that manufacturer table. So my url can get
pretty long depending on how many manufacturers I have. Also, if I
did it this way how would I setup my view? Would it be something like
this
def theview(request, manufacturer):
rec = manufacturer.objects.all()
return render_to_response('dispaly_manu.html', {'manu_records':
rec})
2) Creating a separate url for each manufacturer
(r'^/mohawk/$', 'django.views.generic.list_detail.object_list',
mohawk_dict),
(r'^/milliken/$', 'django.views.generic.list_detail.object_list',
milliken_dict),
(r'^/shaw/$', 'django.views.generic.list_detail.object_list',
shaw_dict),
(r'^/sphinx/$', 'django.views.generic.list_detail.object_list',
sphinx_dict),
This way seems like a waste. Would I need to create a unique
dictionary for each manufacturer? Is there a way I can use the same
dictionary for every manufacturer?
Or does somebody have a better solution than what I came up with
above?
Thanks
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