Re: graphics card

2012-10-23 Thread Polytropon
On Mon, 22 Oct 2012 15:56:56 -0500, ajtiM wrote:
 Hi!
 
 I have an old computer but it works good still :). I use KDE and GIMP and I 
 like to use Krita more but a problem is graphics card and it is slow (Gimp is 
 okay).
 I have ASUS P4P800 mother board and ATI Radeon 9000 AGP graphics card. I look 
 for some Nvidia AGP cards (opengl 2.0) but the problem is because my 
 motherboard AGP supports +1.5V only.
 Which gr. card would be better than my but I could use on my motherboard, 
 please?

I've been using an ATI Radeon 9200 (RV250) with XFree86's
and later X.org's ati driver without any problems. Even
shooters did play very well. I've also been using Krita and
Gimp on that system (Pentium 4 based mainboard), running
FreeBSD 4, 5 and 7.

There are several options for X you can tweak, and the
native ati driver is excellent for the older ATI models.
Make sure you have DRM/DRI working, and check for GL
support (glxinfo, glxgears, xvinfo; install xlockmore
and see xlock -nolock -mode fire).


-- 
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
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Re: way way off topic

2012-10-23 Thread Polytropon
On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
 Gary,
 
 On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
 
  apologies up front for this math type quandary. I had it in a std C program,
  but 3+ hours of grepping havent found it.  I would have bet my last cent 
  that I
  had a summary Somewhere, but cant find that either.
 
  here is the problem as best I can remember it.
 
 
  let's say that john is 8 and his older friend, jim, is 22.
  how much older is exact percentage terms is jim?
 
 That should be 22/8=2.75
 Jim is 275% older than John

Jim is 175% _older_. Why? Because 100% older means 16 years,
as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
Percentage is always a reference to something else, in this
question, Jim's age in relation to John's. The word older
means adding percentage, refering to the base value of 8,
divided in 100 parts (floating point considerations aside),
to finally reach the value 22.

If the question would be different, say, What's the percentage
of John's age regarding Jim's age? In that case, it would be
8/22=0.3636 being 36%. Obvious: John's age is approximately
1/3 of Jim's age.

The easiest way for creating the proper calculation is to refer
to the equation

   percentage * 100
percentage value = 
 base value

and resolve it to whatever is required.

-- 
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
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Re: way way off topic

2012-10-23 Thread perryh
Olivier Nicole olivier.nic...@cs.ait.ac.th wrote:
 On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
  apologies up front for this math type quandary. I had it in
  a std C program, but 3+ hours of grepping havent found it.
  I would have bet my last cent that I had a summary Somewhere,
  but cant find that either.
 
  here is the problem as best I can remember it.
 
  let's say that john is 8 and his older friend, jim, is 22.
  how much older is exact percentage terms is jim?

 That should be 22/8=2.75
 Jim is 275% older than John

No, a subtraction is needed if we wish to use the term older.
Suppose Jim were 9; the above approach would give 9/8 = 1.125
so Jim is 113% older than John, which is clearly wrong (although
one could correctly say in that case that John's age is 113% of
Jim's age).

I think the OP is probably looking for

  ((22 - 8) * 100 + (8/2)) / 8

which will give the answer directly as a correctly-rounded
integral percentage.  (For a fractional percentage, use floats
instead of ints and omit the (8/2) part -- but in that case
you probably also want to express the ages in something other
than whole years.)
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Re: license

2012-10-23 Thread Polytropon
On Mon, 22 Oct 2012 16:01:03 -0500, ajtiM wrote:
 Again me
 
 Last time I try to make some T-shirts which I have on my redbubble page. It 
 is 
 not a big nmoney, I didn't sell anything just one card :) but I like to make 
 a 
 T-shirt design with Beastie on it too. Do I need a permission for using 
 Beastie or it is free or I cannot use.

The required information (including the proper copyright and
useful contact information) can be found here:

http://www.freebsd.org/copyright/daemon.html

http://www.mckusick.com/beastie/index.html
http://www.mckusick.com/beastie/mainpage/images.html


-- 
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
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nanobsd configuration

2012-10-23 Thread Jack Mc Lauren
hi 

i have a problem with nanobsd. there are somethings which don't have WITHOUT 
knobs, how can i control these directories manually ? how can i add a costume 
function to nanobsd.sh to do this ??

thanks ...
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mfi driver at FreeBSD 8.2

2012-10-23 Thread Omer Faruk SEN
Hi,

I remember someone sending a bug report about mfi driver on FreeBSD 8.2

Can I see the list of these bugs? Couldn't find any email about it. (I
remember i have read but can't find it )

Regards.
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Re: mfi driver at FreeBSD 8.2

2012-10-23 Thread Matthew Seaman
On 23/10/2012 09:37, Omer Faruk SEN wrote:
 I remember someone sending a bug report about mfi driver on FreeBSD 8.2
 
 Can I see the list of these bugs? Couldn't find any email about it. (I
 remember i have read but can't find it )

Sure.  Like this you mean?:

http://www.freebsd.org/cgi/query-pr-summary.cgi?category=severity=priority=class=state=sort=nonetext=mfiresponsible=multitext=originator=release=

To get that, use the form here:

http://www.freebsd.org/cgi/query-pr-summary.cgi

and enter 'mfi' into the 'Text in single-line fields' box and then click
on the 'Query PRs' button.  You might need to play with some of the
other fields in that form in order to find exactly the right PR.

Cheers,

Matthew

-- 
Dr Matthew J Seaman MA, D.Phil.
PGP: http://www.infracaninophile.co.uk/pgpkey




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Bug in LAGG driver at 9.0 ?

2012-10-23 Thread Frank Bonnet

Hello

I cannot get the lagg driver to work properly at 9.0

the Cisco switch is well configured to support LACP no problem
on that side it supports another Linux server with two aggregated
eth ports that works well.

here is the config of the FreeBSD 9.0-P3 server

ifconfig_bce0=up
ifconfig_bce1=up
ifconfig_bce2=up
cloned_interfaces=lagg0
ifconfig_lagg0=laggproto lacp laggport bce0 laggport bce1 laggport bce2
ipv4_addrs_lagg0=147.215.201.21/24
defaultrouter=147.215.201.1


showing the lagg configuration give the following , only one ethernet 
port is active.



ifconfig lagg0
lagg0: flags=8843UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST metric 0 mtu 1500
options=c01bbRXCSUM,TXCSUM,VLAN_MTU,VLAN_HWTAGGING,JUMBO_MTU,VLAN_HWCSUM,TSO4,VLAN_HWTSO,LINKSTATE
ether 00:9c:02:9a:97:b0
inet 147.215.201.21 netmask 0xff00 broadcast 147.215.201.255
nd6 options=29PERFORMNUD,IFDISABLED,AUTO_LINKLOCAL
media: Ethernet autoselect
status: active
laggproto lacp
laggport: bce2 flags=0
laggport: bce1 flags=0
laggport: bce0 flags=1cACTIVE,COLLECTING,DISTRIBUTING



Thanks for any info/idea


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Re: nanobsd configuration

2012-10-23 Thread Arthur Chance

On 10/23/12 09:28, Jack Mc Lauren wrote:

hi

i have a problem with nanobsd. there are somethings which don't have WITHOUT 
knobs,
 how can i control these directories manually ? how can i add a 
costume function to

 nanobsd.sh to do this ??

How about something along the lines of

cust_clean () {
rm -rf ${NANO_WORLDIR}/path/to/unwanted
}

customize_cmd cust_clean

in your nanobsd config file?

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Re: nanobsd configuration

2012-10-23 Thread Jack Mc Lauren





 From: Arthur Chance free...@qeng-ho.org
To: Jack Mc Lauren jack.mclau...@yahoo.com 
Cc: freebsd-questions@freebsd.org freebsd-questions@freebsd.org 
Sent: Tuesday, October 23, 2012 2:54 PM
Subject: Re: nanobsd configuration
 
On 10/23/12 09:28, Jack Mc Lauren wrote:
 hi
 
 i have a problem with nanobsd. there are somethings which don't have WITHOUT 
 knobs,
 how can i control these directories manually ? how can i add a costume 
 function to
 nanobsd.sh to do this ??

How about something along the lines of

cust_clean () {
    rm -rf ${NANO_WORLDIR}/path/to/unwanted
}

customize_cmd cust_clean

in your nanobsd config file?


===
thanks 
you mean after building image, this function remove unwanted from WORLDDIR ?
i suppose this will not effect the image, because the image had been built 
before removing unwanted directories ...
did i get your point correctly ? 
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Samba and handbook

2012-10-23 Thread Leslie Jensen


According to

http://www.se.freebsd.org/doc/en_US.ISO8859-1/books/handbook/network-samba.html

One can use

samba_enable=YES

Or, for fine grain control:

nmbd_enable=YES

smbd_enable=YES


20121022:
  AFFECTS: users of net/samba36
  AUTHOR: ti...@freebsd.org

  Startup rc.d/samba script was modified to address some problems with the
  fine control of supplimentary daemons. As a side effect now it's always
  necessary to specify in rc.conf:

  samba_enable=YES

  to get the script working. You can still control each of the daemons
  individualy, by disabling/enabling them with:

  nmbd_enable=NO
  smbd_enable=NO
  winbindd_enable=YES





The Handbook information is out of date because of this and should be 
corrected.



thanks :-)


/Leslie



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Re: ipfw headers

2012-10-23 Thread Polytropon
On Tue, 23 Oct 2012 17:35:45 +0330, s m wrote:
 thanks for your quick reply. you know, i want to add studio.h header but
 the below error occurs: no such file or directory. i am sure that
 studio.h locates in usr/src/include but that error occured. if i write the
 full path of studio.h in ipfw file and then compile it, another error
 happened. do you know how i could fix it? thanks

The normal inclusion

#include stdio.h

should be sufficient. However, if you make your change to
ipfw in the /usr/src tree, calling make might default to
a different path for obtaining headers, i. e. use them from
within the src/ tree.

The system defaults to several paths, in one of them stdio.h
should be defined no matter what build command you use.

/usr/include/stdio.h is the default file. /usr/include will
be automatically used unless you change a compiler option
(-I).

/usr/src/include/stdio.h the file used when building stuff
from source. This would be the case (if I remember correctly)
when you call make from /usr/src/sbin/ipfw directly. As
ipfw (unaltered) also includes headers next to stdio.h,
it shouldn't be a problem. You can compare this to other
#include preprocessor commands found in ipfw's main.c.

Final note: If you did actually use the name studio.h - that
is a typo. There is no u in standard I/O. :-)





-- 
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...
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Re: how many memory is needed for FreeBSD 9 ?

2012-10-23 Thread Patrick Lamaiziere
Le Mon, 22 Oct 2012 03:49:50 +1100,
andrew clarke m...@ozzmosis.com a écrit :

Hello,

  I'm updating an old laptop running FreeBSD 8.1 with 64 MB ram (44MB
  available) but now FreeBSD 9.1 panics at boot time:
  
  panic: kmem_malloc(4194304): kmem_map too small: 24584192 allocated?
 
 That's one very old laptop. I think you'll need to install more memory
 or downgrade FreeBSD to an earlier version.

1998, I think (HP Omnibook 900). I use it for small network testing and
serial console access. It works well for this.

Well I've put 8-STABLE on it (two days to make buildworld/buildkernel).
Looks good.

 From my limited testing under VirtualBox, 96 MB RAM is about the lower
 limit that will allow FreeBSD 9.1-RC2 to boot before the swap
 partition is enabled. Any less and the kernel will freeze or panic at
 boot. This was with the amd64 version though, not i386.

Thanks for this, regards.

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Re: Bug in LAGG driver at 9.0 ?

2012-10-23 Thread dweimer

On 2012-10-23 06:02, Frank Bonnet wrote:

Hello

I cannot get the lagg driver to work properly at 9.0

the Cisco switch is well configured to support LACP no problem
on that side it supports another Linux server with two aggregated
eth ports that works well.

here is the config of the FreeBSD 9.0-P3 server

ifconfig_bce0=up
ifconfig_bce1=up
ifconfig_bce2=up
cloned_interfaces=lagg0
ifconfig_lagg0=laggproto lacp laggport bce0 laggport bce1 laggport 
bce2

ipv4_addrs_lagg0=147.215.201.21/24
defaultrouter=147.215.201.1


showing the lagg configuration give the following , only one ethernet
port is active.


ifconfig lagg0
lagg0: flags=8843UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST metric 0 
mtu 1500


options=c01bbRXCSUM,TXCSUM,VLAN_MTU,VLAN_HWTAGGING,JUMBO_MTU,VLAN_HWCSUM,TSO4,VLAN_HWTSO,LINKSTATE
ether 00:9c:02:9a:97:b0
inet 147.215.201.21 netmask 0xff00 broadcast 147.215.201.255
nd6 options=29PERFORMNUD,IFDISABLED,AUTO_LINKLOCAL
media: Ethernet autoselect
status: active
laggproto lacp
laggport: bce2 flags=0
laggport: bce1 flags=0
laggport: bce0 flags=1cACTIVE,COLLECTING,DISTRIBUTING



Thanks for any info/idea


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Can you post your Cisco Switch port configuration?  I have a two port 
LAGG using lacp on two separate Dell PowerEdge servers running 
9.0-RELEASEp3, below is my config in FreeBSD the only differences I see 
apart form 2 instead of three ports, is that I named the interface, and 
used a different syntax to specify the ip addresses, but yours should be 
correct as well.


uname -v
FreeBSD 9.0-RELEASE-p3 #0: Tue Jun 26 10:27:21 CDT 2012

ifconfig_bce0=up
ifconfig_bce1=up
cloned_interfaces=lagg6
ifconfig_lagg6_name=DMZ
ifconfig_DMZ=laggproto lacp laggport bce0 laggport bce1
ifconfig_DMZ_alias0=inet 10.50.20.5 netmask 0x
ifconfig_DMZ_alias1=inet 10.52.20.5 netmask 0x
defaultrouter=10.50.110.4

DMZ: flags=8843UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST metric 0 mtu 
1500

options=c01bbRXCSUM,TXCSUM,VLAN_MTU,VLAN_HWTAGGING,JUMBO_MTU,VLAN_HWCSUM,TSO4,VLAN_HWTSO,LINKSTATE

ether 78:2b:cb:68:9f:1e
inet 10.50.20.5 netmask 0x broadcast 10.50.255.255
inet 10.52.20.5 netmask 0x broadcast 10.52.255.255
nd6 options=29PERFORMNUD,IFDISABLED,AUTO_LINKLOCAL
media: Ethernet autoselect
status: active
laggproto lacp
laggport: bce1 flags=1cACTIVE,COLLECTING,DISTRIBUTING
laggport: bce0 flags=1cACTIVE,COLLECTING,DISTRIBUTING




--
Thanks,
   Dean E. Weimer
   http://www.dweimer.net/
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Re: graphics card

2012-10-23 Thread ajtiM
On Tuesday 23 October 2012 01:34:33 Polytropon wrote:
 On Mon, 22 Oct 2012 15:56:56 -0500, ajtiM wrote:
  Hi!

 There are several options for X you can tweak, and the
 native ati driver is excellent for the older ATI models.
 Make sure you have DRM/DRI working, and check for GL
 support (glxinfo, glxgears, xvinfo; install xlockmore
 and see xlock -nolock -mode fire).

I had this computer about 12 years and it works very good still. I didn't have 
problem with slow Krita before but now is not the same. IMO all graphics 
programs are more hungry for better gr. cards but GIM works still very good.
I have ati native drivers, I have dr/drm installed but I don't use xorg.conf 
and it works.
I ran glxgears -info in the small size windows and I got:
glxgears -info
GL_RENDERER   = Mesa DRI R200 (RV250 4966) 20090101 AGP 4x x86/MMX/SSE2 TCL
GL_VERSION= 1.3 Mesa 7.6.1
GL_VENDOR = Tungsten Graphics, Inc.
GL_EXTENSIONS = GL_ARB_draw_buffers GL_ARB_imaging GL_ARB_multisample 
GL_ARB_multitexture GL_ARB_point_parameters GL_ARB_point_sprite 
GL_ARB_texture_border_clamp GL_ARB_texture_compression GL_ARB_texture_cube_map 
GL_ARB_texture_env_add GL_ARB_texture_env_combine GL_ARB_texture_env_crossbar 
GL_ARB_texture_env_dot3 GL_ARB_texture_mirrored_repeat 
GL_ARB_texture_rectangle GL_ARB_transpose_matrix GL_ARB_vertex_buffer_object 
GL_ARB_vertex_program GL_ARB_window_pos GL_EXT_abgr GL_EXT_bgra 
GL_EXT_blend_color GL_EXT_blend_equation_separate GL_EXT_blend_func_separate 
GL_EXT_blend_logic_op GL_EXT_blend_minmax GL_EXT_blend_subtract 
GL_EXT_compiled_vertex_array GL_EXT_convolution GL_EXT_copy_texture 
GL_EXT_draw_range_elements GL_EXT_fog_coord GL_EXT_histogram 
GL_EXT_multi_draw_arrays GL_EXT_packed_depth_stencil GL_EXT_packed_pixels 
GL_EXT_point_parameters GL_EXT_polygon_offset GL_EXT_rescale_normal 
GL_EXT_secondary_color GL_EXT_separate_specular_color GL_EXT_stencil_wrap 
GL_EXT_subtexture GL_EXT_texture GL_EXT_texture3D GL_EXT_texture_edge_clamp 
GL_EXT_texture_env_add GL_EXT_texture_env_combine GL_EXT_texture_env_dot3 
GL_EXT_texture_filter_anisotropic GL_EXT_texture_lod_bias 
GL_EXT_texture_mirror_clamp GL_EXT_texture_object GL_EXT_texture_rectangle 
GL_EXT_vertex_array GL_APPLE_packed_pixels GL_ATI_blend_equation_separate 
GL_ATI_texture_env_combine3 GL_ATI_texture_mirror_once GL_ATI_fragment_shader 
GL_IBM_multimode_draw_arrays GL_IBM_rasterpos_clip 
GL_IBM_texture_mirrored_repeat GL_INGR_blend_func_separate GL_MESA_pack_invert 
GL_MESA_window_pos GL_NV_blend_square GL_NV_light_max_exponent 
GL_NV_texture_rectangle GL_NV_texgen_reflection GL_OES_read_format 
GL_SGI_color_matrix GL_SGI_color_table GL_SGIS_generate_mipmap 
GL_SGIS_texture_border_clamp GL_SGIS_texture_edge_clamp GL_SGIS_texture_lod 
GL_SUN_multi_draw_arrays
9632 frames in 5.0 seconds = 1926.316 FPS
10262 frames in 5.0 seconds = 2052.362 FPS
10254 frames in 5.0 seconds = 2050.631 FPS
10262 frames in 5.0 seconds = 2052.296 FPS
10262 frames in 5.0 seconds = 2052.253 FPS
10262 frames in 5.0 seconds = 2052.279 FPS
10261 frames in 5.0 seconds = 2052.143 FPS
10262 frames in 5.0 seconds = 2052.282 FPS
10260 frames in 5.0 seconds = 2051.818 FPS
10261 frames in 5.0 seconds = 2052.118 FPS

glxgears -fullscreen I got:

glxgears -fullscreen
1453 frames in 5.0 seconds = 290.501 FPS
1490 frames in 5.0 seconds = 297.973 FPS
1490 frames in 5.0 seconds = 297.976 FPS
1490 frames in 5.0 seconds = 297.981 FPS
1490 frames in 5.0 seconds = 297.975 FPS
1490 frames in 5.0 seconds = 297.981 FPS
1490 frames in 5.0 seconds = 297.990 FPS
1490 frames in 5.0 seconds = 297.989 FPS
1490 frames in 5.0 seconds = 297.985 FPS
1490 frames in 5.0 seconds = 297.982 FPS
1490 frames in 5.0 seconds = 297.989 FPS
1490 frames in 5.0 seconds = 297.913 FPS

glxinfo shows:
name of display: :0
display: :0  screen: 0
direct rendering: Yes
server glx vendor string: SGI
server glx version string: 1.2
server glx extensions:
GLX_ARB_multisample, GLX_EXT_visual_info, GLX_EXT_visual_rating, 
GLX_EXT_import_context, GLX_EXT_texture_from_pixmap, GLX_OML_swap_method, 
GLX_SGI_make_current_read, GLX_SGIS_multisample, GLX_SGIX_hyperpipe, 
GLX_SGIX_swap_barrier, GLX_SGIX_fbconfig, GLX_SGIX_pbuffer, 
GLX_MESA_copy_sub_buffer
client glx vendor string: Mesa Project and SGI
client glx version string: 1.4
client glx extensions:
GLX_ARB_get_proc_address, GLX_ARB_multisample, GLX_EXT_import_context, 
GLX_EXT_visual_info, GLX_EXT_visual_rating, GLX_MESA_allocate_memory, 
GLX_MESA_copy_sub_buffer, GLX_MESA_swap_control, 
GLX_MESA_swap_frame_usage, GLX_OML_swap_method, GLX_OML_sync_control, 
GLX_SGI_make_current_read, GLX_SGI_swap_control, GLX_SGI_video_sync, 
GLX_SGIS_multisample, GLX_SGIX_fbconfig, GLX_SGIX_pbuffer, 
GLX_SGIX_visual_select_group, GLX_EXT_texture_from_pixmap
GLX version: 1.2
GLX extensions:
GLX_ARB_get_proc_address, GLX_ARB_multisample, GLX_EXT_import_context, 
GLX_EXT_visual_info, GLX_EXT_visual_rating, GLX_MESA_allocate_memory, 

Re: way way off topic

2012-10-23 Thread Gary Kline
On Tue, Oct 23, 2012 at 11:31:18AM +0700, Olivier Nicole wrote:
 Gary,
 
 On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
 
  apologies up front for this math type quandary. I had it in a std C program,
  but 3+ hours of grepping havent found it.  I would have bet my last cent 
  that I
  had a summary Somewhere, but cant find that either.
 
  here is the problem as best I can remember it.
 
 
  let's say that john is 8 and his older friend, jim, is 22.
  how much older is exact percentage terms is jim?
 
 That should be 22/8=2.75
 Jim is 275% older than John
 
 Olivier
 

thanks.  but this wasn't the formula I remember mousing 
down.  I'll keep looking.

gary

ps:  it was involved; something with three or more steps.
things that I had crammed together in one line of C... 


  to find the answer I had to find the relative difference {22 - 8} and then
  do something with the difference.  this isn't any kind of trick or
  advanced-cognition; I just thought it was clever [and exact].  it 
  obviously
  works for finding the abs() results in subtraction.  it's something I found 
  on
  the web and swipes and save the prose discussion.  BZZT: Lost, :-(
 
  if this seems dumb, I plead guilty!
 
  im asking here because -questions is the sharpest list on the net.
 
  --
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Twenty-six years of service to the Unix community.
 
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Re: way way off topic

2012-10-23 Thread Gary Kline
On Tue, Oct 23, 2012 at 11:34:36AM +0700, Erich Dollansky wrote:
 Hi,
 
 On Mon, 22 Oct 2012 21:20:07 -0700
 Gary Kline kl...@thought.org wrote:
 
  
  apologies up front for this math type quandary. I had it in a std C
  program, but 3+ hours of grepping havent found it.  I would have bet
  my last cent that I had a summary Somewhere, but cant find that
  either.
  
  here is the problem as best I can remember it.
  
  
  let's say that john is 8 and his older friend, jim, is 22.  
  how much older is exact percentage terms is jim?
  
  to find the answer I had to find the relative difference {22 - 8} and
  then do something with the difference.  this isn't any kind of trick
  or advanced-cognition; I just thought it was clever [and exact].
  it obviously works for finding the abs() results in subtraction.
  it's something I found on the web and swipes and save the prose
  discussion.  BZZT: Lost, :-(
  
 It seems that I am also lost. What should abs() do here?
 
 I would multiply the age of john and the difference with 100 and then
 divide the result to get the percentage.
 
 Or did I get lost here?
 
  if this seems dumb, I plead guilty!
  
  im asking here because -questions is the sharpest list on the net.
  
 
 Are you sure?
 
 Erich

LOL.  yes!  

it's been years since I used the steps to find the accurant amount of
difference.  it may not have involved a %.  I can only think of one
concrete example.

lets say that x == 15 and y == 16.  Q:  how much less is x than y?
it is not just 1; there was some other way of finding the answer.  


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Re: Music production on FreeBSD

2012-10-23 Thread Allen
I know this is old, but I just saw it. Anyway, I make all of my music on 
LMMS. It's made for Linux as the name implies, but it works jut fine on 
FreeBSD.


http://www.myspace.com/farmacyofhorror



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Re: way way off topic

2012-10-23 Thread Gary Kline
On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
 On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
  Gary,
  
  On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
  
   apologies up front for this math type quandary. I had it in a std C 
   program,
   but 3+ hours of grepping havent found it.  I would have bet my last cent 
   that I
   had a summary Somewhere, but cant find that either.
  
   here is the problem as best I can remember it.
  
  
   let's say that john is 8 and his older friend, jim, is 22.
   how much older is exact percentage terms is jim?
  
  That should be 22/8=2.75
  Jim is 275% older than John
 
 Jim is 175% _older_. Why? Because 100% older means 16 years,
 as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
 Percentage is always a reference to something else, in this
 question, Jim's age in relation to John's. The word older
 means adding percentage, refering to the base value of 8,
 divided in 100 parts (floating point considerations aside),
 to finally reach the value 22.
 
 If the question would be different, say, What's the percentage
 of John's age regarding Jim's age? In that case, it would be
 8/22=0.3636 being 36%. Obvious: John's age is approximately
 1/3 of Jim's age.
 
 The easiest way for creating the proper calculation is to refer
 to the equation
 
  percentage * 100
   percentage value = 
base value
 
 and resolve it to whatever is required.
 


I just took a cup's worth of coffee/caffeine to bring me back up! but
it seems to me that your logic is about the same as I remember 
otherwise stated in getting the true differences in ages or speeds
[say or cars. x == 200clicks/hr, y == 400 clicks/hour.] or 
*whatever*.  it isn't as easy as it would seem at first thought.



 -- 
 Polytropon
 Magdeburg, Germany
 Happy FreeBSD user since 4.0
 Andra moi ennepe, Mousa, ...

-- 
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Re: way way off topic

2012-10-23 Thread Gary Kline
On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
 On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
  Gary,
  
  On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
  
   apologies up front for this math type quandary. I had it in a std C 
   program,
   but 3+ hours of grepping havent found it.  I would have bet my last cent 
   that I
   had a summary Somewhere, but cant find that either.
  
   here is the problem as best I can remember it.
  
  
   let's say that john is 8 and his older friend, jim, is 22.
   how much older is exact percentage terms is jim?
  
  That should be 22/8=2.75
  Jim is 275% older than John
 
 Jim is 175% _older_. Why? Because 100% older means 16 years,
 as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
 Percentage is always a reference to something else, in this
 question, Jim's age in relation to John's. The word older
 means adding percentage, refering to the base value of 8,
 divided in 100 parts (floating point considerations aside),
 to finally reach the value 22.
 
 If the question would be different, say, What's the percentage
 of John's age regarding Jim's age? In that case, it would be
 8/22=0.3636 being 36%. Obvious: John's age is approximately
 1/3 of Jim's age.
 
 The easiest way for creating the proper calculation is to refer
 to the equation
 
  percentage * 100
   percentage value = 
base value
 
 and resolve it to whatever is required.
 
 -- 
 Polytropon
 Magdeburg, Germany
 Happy FreeBSD user since 4.0
 Andra moi ennepe, Mousa, ...


yo; I THInk this is it. around line 4542 in my ~/.HowTo file::



%%% find percent inc/dec [increase/decrease] between two numbers.

Always figure the percentage of change relative to the original value!
For instance: * Suppose a certain item used to sell for seventy-five
cents a pound, you see that it's been marked up to eighty-one cents a
pound. What is the percent increase?

First, I have to find the absolute
increase:
Reserved 81 - 75 = 6

The price has gone up six cents. Now I can find the
percentage increase over the original price.

This percentage increase is the relative change: 6/75 = 0.08
...or an 8% increase in price per pound.



So I was wrong about ages or speed; it's the % betwen two ints;
here, the inc/dec [or change] between 75 cents as compared to
an inflated increase of 81 cents.

1.  find abs increase:  81-75 = 6;
2   find the % increase over the *original* value. 6.0/75.0
3.  percent increase using doubles is 0.08;  so a markup of six
cents is an 8% rate.


so: going back to the ages example with john bein 8, jim, 22.
22-8 is 14.
14.0/8.0 = 1.75

175%.  jim is 175% times older than john.  which is what you found,
polyt.  {I'll have to re-read your logic now that im awake..}

Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%.
etc,  etc.

Hm.  that's 0 for gary, 729 for polytrop!!

Ah, life:: accept no substitutes.




-- 
 Gary Kline  kl...@thought.org  http://www.thought.org  Public Service Unix
  Twenty-six years of service to the Unix community.

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Re: 9.1 and gmirror with GPT?

2012-10-23 Thread Warren Block

On Tue, 23 Oct 2012, free...@johnea.net wrote:


In recent years I've just been creating a swap partition and one big root 
partition. It just seems as soon as I make all the traditional partitions, one 
runs out of room.

Do you feel there are any major disadvantages of this approach?


Backup of split filesystems can be easier.  The traditional 
split-filesystem approach kind of separates things by use, and some 
people create a separate /home also.  The advantage of one big root is 
efficient use of free space on small drives.



To create a swap and then a root that fills the rest of the disk, must the swap 
be created first, like this:

gpart add -t freebsd-swap -a 4k -s 4g mirror/gm0s1
gpart add -t freebsd-ufs  -a 4k   mirror/gm0s1

Is there any other way to tell gpart to create the / partition using all space 
except 4G?


I'm afraid it requires one to Use Math(tm).  gpart show will at least 
show the real capacity of a drive, instead of the diagonally-measured 
inflated units used by drive vendors.

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Re: way way off topic

2012-10-23 Thread Gezeala M . Bacuño II
% change = ( (present - past) / past ) * 100


On Tue, Oct 23, 2012 at 5:07 PM, Gary Kline kl...@thought.org wrote:
 On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
 On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
  Gary,
 
  On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
  
   apologies up front for this math type quandary. I had it in a std C 
   program,
   but 3+ hours of grepping havent found it.  I would have bet my last cent 
   that I
   had a summary Somewhere, but cant find that either.
  
   here is the problem as best I can remember it.
  
  
   let's say that john is 8 and his older friend, jim, is 22.
   how much older is exact percentage terms is jim?
 
  That should be 22/8=2.75
  Jim is 275% older than John

 Jim is 175% _older_. Why? Because 100% older means 16 years,
 as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
 Percentage is always a reference to something else, in this
 question, Jim's age in relation to John's. The word older
 means adding percentage, refering to the base value of 8,
 divided in 100 parts (floating point considerations aside),
 to finally reach the value 22.

 If the question would be different, say, What's the percentage
 of John's age regarding Jim's age? In that case, it would be
 8/22=0.3636 being 36%. Obvious: John's age is approximately
 1/3 of Jim's age.

 The easiest way for creating the proper calculation is to refer
 to the equation

  percentage * 100
   percentage value = 
base value

 and resolve it to whatever is required.

 --
 Polytropon
 Magdeburg, Germany
 Happy FreeBSD user since 4.0
 Andra moi ennepe, Mousa, ...


 yo; I THInk this is it. around line 4542 in my ~/.HowTo file::



 %%% find percent inc/dec [increase/decrease] between two numbers.

 Always figure the percentage of change relative to the original value!
 For instance: * Suppose a certain item used to sell for seventy-five
 cents a pound, you see that it's been marked up to eighty-one cents a
 pound. What is the percent increase?

 First, I have to find the absolute
 increase:
 Reserved 81 - 75 = 6

 The price has gone up six cents. Now I can find the
 percentage increase over the original price.

 This percentage increase is the relative change: 6/75 = 0.08
 ...or an 8% increase in price per pound.



 So I was wrong about ages or speed; it's the % betwen two ints;
 here, the inc/dec [or change] between 75 cents as compared to
 an inflated increase of 81 cents.

 1.  find abs increase:  81-75 = 6;
 2   find the % increase over the *original* value. 6.0/75.0
 3.  percent increase using doubles is 0.08;  so a markup of six
 cents is an 8% rate.


 so: going back to the ages example with john bein 8, jim, 22.
 22-8 is 14.
 14.0/8.0 = 1.75

 175%.  jim is 175% times older than john.  which is what you found,
 polyt.  {I'll have to re-read your logic now that im awake..}

 Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%.
 etc,  etc.

 Hm.  that's 0 for gary, 729 for polytrop!!

 Ah, life:: accept no substitutes.




 --
  Gary Kline  kl...@thought.org  http://www.thought.org  Public Service Unix
   Twenty-six years of service to the Unix community.

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Re: way way off topic

2012-10-23 Thread Gary Kline
On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuño II wrote:
 % change = ( (present - past) / past ) * 100
 


yeah, this is exactly it for my how much more is 16 than 15
problem. or the ages example. 

It's 6.6[bar-over .6]%  this is probably close to or exactly
what was the core of my C [argc, *srgv[]] program.   my error was in
not understanding the logic that polttropon has given below.  if/when
I ever find that v short exercise, THIS time, il'l remember to
'splain stuff in

/*
 * comments
 */


 
 On Tue, Oct 23, 2012 at 5:07 PM, Gary Kline kl...@thought.org wrote:
  On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote:
  On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote:
   Gary,
  
   On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline kl...@thought.org wrote:
   
apologies up front for this math type quandary. I had it in a std C 
program,
but 3+ hours of grepping havent found it.  I would have bet my last 
cent that I
had a summary Somewhere, but cant find that either.
   
here is the problem as best I can remember it.
   
   
let's say that john is 8 and his older friend, jim, is 22.
how much older is exact percentage terms is jim?
  
   That should be 22/8=2.75
   Jim is 275% older than John
 
  Jim is 175% _older_. Why? Because 100% older means 16 years,
  as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24).
  Percentage is always a reference to something else, in this
  question, Jim's age in relation to John's. The word older
  means adding percentage, refering to the base value of 8,
  divided in 100 parts (floating point considerations aside),
  to finally reach the value 22.
 
  If the question would be different, say, What's the percentage
  of John's age regarding Jim's age? In that case, it would be
  8/22=0.3636 being 36%. Obvious: John's age is approximately
  1/3 of Jim's age.
 
  The easiest way for creating the proper calculation is to refer
  to the equation
 
   percentage * 100
percentage value = 
 base value
 
  and resolve it to whatever is required.
 
  --
  Polytropon
  Magdeburg, Germany
  Happy FreeBSD user since 4.0
  Andra moi ennepe, Mousa, ...
 
 
  yo; I THInk this is it. around line 4542 in my ~/.HowTo file::
 
 
 
  %%% find percent inc/dec [increase/decrease] between two numbers.
 
  Always figure the percentage of change relative to the original value!
  For instance: * Suppose a certain item used to sell for seventy-five
  cents a pound, you see that it's been marked up to eighty-one cents a
  pound. What is the percent increase?
 
  First, I have to find the absolute
  increase:
  Reserved 81 - 75 = 6
 
  The price has gone up six cents. Now I can find the
  percentage increase over the original price.
 
  This percentage increase is the relative change: 6/75 = 0.08
  ...or an 8% increase in price per pound.
 
 
 
  So I was wrong about ages or speed; it's the % betwen two ints;
  here, the inc/dec [or change] between 75 cents as compared to
  an inflated increase of 81 cents.
 
  1.  find abs increase:  81-75 = 6;
  2   find the % increase over the *original* value. 6.0/75.0
  3.  percent increase using doubles is 0.08;  so a markup of six
  cents is an 8% rate.
 
 
  so: going back to the ages example with john bein 8, jim, 22.
  22-8 is 14.
  14.0/8.0 = 1.75
 
  175%.  jim is 175% times older than john.  which is what you found,
  polyt.  {I'll have to re-read your logic now that im awake..}
 
  Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%.
  etc,  etc.
 
  Hm.  that's 0 for gary, 729 for polytrop!!
 
  Ah, life:: accept no substitutes.
 
 
 
 
  --
   Gary Kline  kl...@thought.org  http://www.thought.org  Public Service Unix
Twenty-six years of service to the Unix community.
 
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Re: way way off topic

2012-10-23 Thread Erich Dollansky
Hi,

On Tue, 23 Oct 2012 18:13:05 -0700
Gary Kline kl...@thought.org wrote:

 On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuño II wrote:
 if/when I ever find that v short exercise, THIS time, il'l remember to
   'splain stuff in
 
   /*
* comments
*/
 
your programs are not self-explanatory?

Erich
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Re: Strange system messages in 8.3

2012-10-23 Thread Olivier Nicole
Hi,

 Two night ago, I upgraded my main server to FreeBSD 8.3 and since, I
 get those messages:

 Message from syslogd@banyan at Oct 19 01:15:32 ...
 banyan kernel: )
[...]
 I have all my servers running the same release, and this is the only
 on exibiting such behavious.

 FreeBSD banyan.cs.ait.ac.th 8.3-RELEASE-p4 FreeBSD 8.3-RELEASE-p4 #5:
 Wed Oct 17 18:32:54 ICT 2012
 r...@banyan.cs.ait.ac.th:/usr/obj/usr/src/sys/CSIM amd64

 The custom kernel only includes quota, nothing fancy, rest is generic.

 What these messages could be?

I have updated to Samba 3.6 and still get the following errors.

Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.566992,  1,
pid=17753, effective(7186, 97), real(0, 0)]
printing/printer_list.c:94(printer_list_get_printer)
Oct 24 09:49:45 banyan smbd[17753]:   Failed to fetch record!
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.606964,  0,
pid=17753, effective(7186, 97), real(0, 0)]
lib/fault.c:51(fault_report)
Oct 24 09:49:45 banyan smbd[17753]:
===
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.606994,  0,
pid=17753, effective(7186, 97), real(0, 0)]
lib/fault.c:52(fault_report)
Oct 24 09:49:45 banyan smbd[17753]:   INTERNAL ERROR: Signal 11 in pid
17753 (3.6.7)
Oct 24 09:49:45 banyan smbd[17753]:   Please read the Trouble-Shooting
section of the Samba3-HOWTO
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.607020,  0,
pid=17753, effective(7186, 97), real(0, 0)]
lib/fault.c:54(fault_report)
Oct 24 09:49:45 banyan kernel: pid
Oct 24 09:49:45 banyan kernel: 53O
Oct 24 09:49:45 banyan kernel: ct6 2
Oct 24 09:49:45 banyan kernel: (1s18mbd4
Oct 24 09:49:45 banyan kernel: 9:),
Oct 24 09:49:45 banyan kernel: uid11 80:4
Oct 24 09:49:45 banyan kernel: :4 e
Oct 24 09:49:45 banyan syslogd: /dev/ttyp4: No such file or directory
Oct 24 09:49:45 banyan syslogd: /dev/olivier:: No such file or directory
Oct 24 09:49:45 banyan kernel: xi1te18d o5
Oct 24 09:49:45 banyan kernel: 6bann
Oct 24 09:49:45 banyan kernel: s1i1g8nay
Oct 24 09:49:45 banyan kernel: an6 l
Oct 24 09:49:45 banyan kernel: 61
Oct 24 09:49:45 banyan kernel: 18smbd[17753]: [2012/10/24
09:49:45.607020,  0, pid=17753, effective(7186, 97), real(0, 0)]
lib/fault.c:54(fault_report)
Oct 24 09:49:45 banyan smbd[17753]:
Oct 24 09:49:45 banyan smbd[17753]:   From:
http://www.samba.org/samba/docs/Samba3-HOWTO.pdf
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.607044,  0,
pid=17753, effective(7186, 97), real(0, 0)]
lib/fault.c:55(fault_report)
Oct 24 09:49:45 banyan smbd[17753]:
===
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.607068,  0,
pid=17753, effective(7186, 97), real(0, 0)] lib/util.c:1117(smb_panic)
Oct 24 09:49:45 banyan smbd[17753]:   PANIC (pid 17753): internal error
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.607142,  0,
pid=17753, effective(7186, 97), real(0, 0)]
lib/util.c:1221(log_stack_trace)
Oct 24 09:49:45 banyan smbd[17753]:   BACKTRACE: 0 stack frames:
Oct 24 09:49:45 banyan smbd[17753]: [2012/10/24 09:49:45.607191,  0,
pid=17753, effective(0, 0), real(0, 0)] lib/fault.c:416(dump_core)
Oct 24 09:49:45 banyan smbd[17753]:   dumping core in /var/log/samba/cores/smbd
Oct 24 09:49:45 banyan smbd[17753]:
Oct 24 09:49:45 banyan smbd[57965]: [2012/10/24 09:49:45.678295,  0,
pid=57965, effective(0, 0), real(0, 0)]
smbd/server.c:433(smbd_accept_connection)
Oct 24 09:49:45 banyan smbd[57965]:   open_sockets_smbd: accept:
Software caused connection abort

Help will be highly welcome.

Best regards,

Olivier


 Best regards,

 Olivier
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