Re: [H] OT Inclined planes
Assume an 8 degree incline to the ramp. The tangent of an angle (in this case 8 degrees) equals the rise divided by the run or y/x. In this example, the rise is either 1 ft or 3 ft, so, tan(8 degrees) = rise_ft / run_ft = y_ft / x_ft or ... x_ft = (1 ft) / tan(8 degrees) = (1 ft) / (0.140541) = (7.11537 ft) and ... x_ft = (3 ft) / tan(8 degrees) = (3 ft) / (0.140541) = (21.3461 ft) y /y / y / y h/ y /y / y / y /) y x0 In the above drawing, x == y and the triangle is 9 y's rise by 9 x's run. The angle /) is 45 degrees (although it doesn't look right due to font dimensions), and tan(45 degrees) = 1.0 = 9/9. If you need the length of the inclined path (h = hypotenuse), use Pythagarus' theorem: h^2 = x^2 +y^2 or ... h = (x^2 +y^2)^(1/2) = 21.5559 ft or ... [sin(8 degrees) = h / rise_ft] h = 1 ft / sin(8 degrees) = 7.18530 ft ; sin(8 degrees) = 0.139173 h = 3 ft / sin(8 degrees) = 21.5559 ft ; sin(8 degrees) = 0.139173 hth, Jim -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Harvey Best Sent: Sunday, July 13, 2008 9:33 AM To: Alt Cpu Subject: [H] OT Inclined planes As a distraction form my network backup problems, a friend called me and asked this question. I am using google now to see if I can find the formula. Here is his question:This is about Inclined Planes. How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... Also would like the length to a hight of 3 feet, at the same degree of incline, if you can do it... Any help with formula and answer greatly appreciated. Why do I get myself in these situations. lol _ Need to know now? Get instant answers with Windows Live Messenger. http://www.windowslive.com/messenger/connect_your_way.html?ocid=TXT_TAGLM_WL _messenger_072008
[H] OT Inclined planes
As a distraction form my network backup problems, a friend called me and asked this question. I am using google now to see if I can find the formula. Here is his question:This is about Inclined Planes. How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... Also would like the length to a hight of 3 feet, at the same degree of incline, if you can do it... Any help with formula and answer greatly appreciated. Why do I get myself in these situations. lol _ Need to know now? Get instant answers with Windows Live Messenger. http://www.windowslive.com/messenger/connect_your_way.html?ocid=TXT_TAGLM_WL_messenger_072008
Re: [H] OT Inclined planes
On Sun, 13 Jul 2008 13:32:35 -0400 Harvey Best [EMAIL PROTECTED] wrote: How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... 8 degree = 1.67551608 inches per foot http://www.google.com/search?hl=enclient=firefox-arls=org.mozilla%3Aen-US%3Aofficialq=8+degree+%3D+%3F+inches+per+footbtnG=Search HTH Al
Re: [H] OT Inclined planes
On Sun, 13 Jul 2008 14:14:47 -0400 [EMAIL PROTECTED] wrote: On Sun, 13 Jul 2008 13:32:35 -0400 Harvey Best [EMAIL PROTECTED] wrote: How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... 8 degree = 1.67551608 inches per foot So to answer your question; 12 / 1.68 = 7.14285714 TotalRise / RisePerFoot = Total Feet 36 / 1.68 = 21.4285714 feet for 3 foot rise. Best, Al
Re: [H] OT Inclined planes
Thanks! I had been searching for a formula when I should have run a search like you did. Wind Date: Sun, 13 Jul 2008 14:14:47 -0400 From: [EMAIL PROTECTED] To: hardware@hardwaregroup.com Subject: Re: [H] OT Inclined planes On Sun, 13 Jul 2008 13:32:35 -0400 Harvey Best [EMAIL PROTECTED] wrote: How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... 8 degree = 1.67551608 inches per foot http://www.google.com/search?hl=enclient=firefox-arls=org.mozilla%3Aen-US%3Aofficialq=8+degree+%3D+%3F+inches+per+footbtnG=Search HTH Al _ Making the world a better place one message at a time. http://www.imtalkathon.com/?source=EML_WLH_Talkathon_BetterPlace
Re: [H] OT Inclined planes
It is a formula from trig, Sine of an angle equals the opposite side over the hypotenuse. So set your calculator in degree mode (vs radian) and then do rise/(sin 8) which gives the length. (where length and rise are both in the same units) -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Harvey Best Sent: Sunday, July 13, 2008 8:42 PM To: hardware@hardwaregroup.com Subject: Re: [H] OT Inclined planes Thanks! I had been searching for a formula when I should have run a search like you did. Wind Date: Sun, 13 Jul 2008 14:14:47 -0400 From: [EMAIL PROTECTED] To: hardware@hardwaregroup.com Subject: Re: [H] OT Inclined planes On Sun, 13 Jul 2008 13:32:35 -0400 Harvey Best [EMAIL PROTECTED] wrote: How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... 8 degree = 1.67551608 inches per foot http://www.google.com/search?hl=enclient=firefox-arls=org.mozilla%3Aen-US% 3Aofficialq=8+degree+%3D+%3F+inches+per+footbtnG=Search HTH Al _ Making the world a better place one message at a time. http://www.imtalkathon.com/?source=EML_WLH_Talkathon_BetterPlace
Re: [H] OT Inclined planes
At 20:42 07/13/08, Harvey Best wrote: Thanks! I had been searching for a formula when I should have run a search like you did. How long does a ramp have to be to raise a plane 8 degrees from horizontal to a hight of one foot... One shouldn't have to find a formula to solve this. It's simple trigonometry (the definition of the sine of an angle in a right triangle) from high school math. If X is the hypotenuse of a right triangle (call it X because this is what we're looking for), A is an angle, and L is the length of the side opposite from A, then sine of A is defined as opposite over hypotenuse. Sin A = L / X Use A = 8 degrees and L = 1 foot. We get Sin 8 = 1 / X or X = 1 / sin8 Get sin 8 = .13917 (using the calculator applet in Windows). Note: be sure your calculator is set for degrees and not radians. X = 1 foot / .13917 = 7.1853 feet The whole point is not to look for (and memorize) some formula but to use a concept learned (hopefully) long ago. Regards, Bill