Re: Query Help
Thanks John! On Wednesday, February 8, 2023 at 1:08:59 PM UTC-6 John Wiegley wrote: > > "J" == Jasel17212 writes: > > J> I'm using zsh so entered: > > J> ledger reg ^exp and "(%tag1 | %tag2)" > > Sadly, it has to be more separated than this: > > > ledger reg ^exp and '(%tag1' '|' '%tag2)' > > It's a bug to me that the query parser interprets "(%tag1 | %tag2)" as if > you > had written "(%tag1 |" "%tag2)". > > John > -- --- You received this message because you are subscribed to the Google Groups "Ledger" group. To unsubscribe from this group and stop receiving emails from it, send an email to ledger-cli+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/ledger-cli/62db2fbb-a89d-4e65-90fb-b8cd70b5cdabn%40googlegroups.com.
Re: Query Help
> "J" == Jasel17212 writes: J> I'm using zsh so entered: J> ledger reg ^exp and "(%tag1 | %tag2)" Sadly, it has to be more separated than this: ledger reg ^exp and '(%tag1' '|' '%tag2)' It's a bug to me that the query parser interprets "(%tag1 | %tag2)" as if you had written "(%tag1 |" "%tag2)". John -- --- You received this message because you are subscribed to the Google Groups "Ledger" group. To unsubscribe from this group and stop receiving emails from it, send an email to ledger-cli+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/ledger-cli/m2o7q46kmi.fsf%40newartisans.com.
Re: Query Help
On 2/8/23 06:18, Jasel17212 wrote:
Two questions:
Is there a shorthand way to write the following query?
ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
"has_meta('tag2')"
This seems to work for me:
ledger reg ^exp and expr "has_meta('tag1') | has_meta('tag2')"
Sorry I don't have an answer to the second question. —Randy
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Re: Query Help
John,
I'm using zsh so entered:
ledger reg ^exp and "(%tag1 | %tag2)"
The results were for tag2 only.
I used the group-by tag as follows:
ledger reg ^exp and expr "(has_meta('tag1') or has_meta('tag2'))"
--group-by tag('tag1')
The results was:
zsh: missing delimiter for 'u' glob qualifier
Thoughts on either result?
On Tuesday, February 7, 2023 at 6:08:28 PM UTC-6 jwie...@gmail.com wrote:
> > "J" == Jasel17212 writes:
>
> J> Is there a shorthand way to write the following query?
>
> J> ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
> J> "has_meta('tag2')"
>
> You may need to escape it from your shell, but this should do it:
>
> ledger reg ^exp & (%tag1 | %tag2)
>
> J> ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
> J> "has_meta('tag2')" --group-by
>
> --group-by tag('tag1')
>
> John
>
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Re: Query Help
> "J" == Jasel17212 writes:
J> Is there a shorthand way to write the following query?
J> ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
J> "has_meta('tag2')"
You may need to escape it from your shell, but this should do it:
ledger reg ^exp & (%tag1 | %tag2)
J> ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
J> "has_meta('tag2')" --group-by
--group-by tag('tag1')
John
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Re: Query Help
On Tue, Feb 7, 2023 at 5:18 PM Jasel17212 wrote:
> Two questions:
>
> Is there a shorthand way to write the following query?
>
> ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
> "has_meta('tag2')"
>
>
Hi JL,
Maybe just a little shorter:
reg ^exp and expr "(has_meta('tag1') or has_meta('tag2'))"
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Query Help
Two questions:
Is there a shorthand way to write the following query?
ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
"has_meta('tag2')"
Is there a way to group the results of this query by tag?
ledger reg ^exp and expr "has_meta('tag1')" or ^exp and expr
"has_meta('tag2')" --group-by
Thanks
JL
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