[libuv] Is it safe to use static or pre-allocated buffer when receiving data form a single loop?
Hi everyone, I'm working on a simple network application and I'm new to the libuv, so I have this noob question to ask If I have an application which use only one loop, with many tcp/udp handler registered on it, is it safe to use static buffer in uv_alloc_cb like this? static char buffer[65535] = {0}; void alloc_buffer(uv_handle_t *handle, size_t suggested_size, uv_buf_t *buf) { buf->base = (char*)buffer; buf->len = 65535; } In my imagine, the event loop of libuv would work in a SINGLE thread with the following way: 1. System polled an event 2. Invoke uv_alloc_cb 3. Invoke uv_recv_cb with the allocated buffer and other infomation 4. After #3 ends, back to #1 In this circuit, it's easy to point out that the allocated memory will be only used in uv_recv_cb and will not been overwritten before #3 ends, so in this situation I think use a static buffer here is possible, but I don't know whether the process I imagine is correct. If my imagine is correct, is it safe to use the static buffer? More questions if it's safe: 1. Does libuv has same behaviour on different platform? 2. Will thread-based handler (file or something else) change the behaviour? Thanks!!! -- You received this message because you are subscribed to the Google Groups "libuv" group. To unsubscribe from this group and stop receiving emails from it, send an email to libuv+unsubscr...@googlegroups.com. To post to this group, send email to libuv@googlegroups.com. Visit this group at https://groups.google.com/group/libuv. For more options, visit https://groups.google.com/d/optout.
[libuv] Is it safe for use a static or pre-allocated buffer when receiving data from loop
Hi, everyone, I'm working on a simple network application and I'm new to libuv, so I have a question about the buffer allocation. If I have only one event loop in application, and I registered many tcp and udp handlers on the event loop, does it safe for use the following code as uv_alloc_cb? static char buffer[65535] = {0}; void alloc_buffer(uv_handle_t *handle, size_t suggested_size, uv_buf_t *buf) { buf->base = (char*)buffer; buf->len = 65535; } In my imagine, the libuv will work like this in a single thread: system polled --> call allocator --> call uv_recv_cb --> anthoer system polled --> ..., so the memory allocated in uv_alloc_cb will only been used in the uv_recv_cb and will not been overwrite before uv_recv_cb end, it seems safe to use static memory in the loop in such situation, but I don't know whether libuv do it actually like this. And more question if libuv actually work like this: Will it have different behaviour in different platform? Will the behaviour changes in some special situation(like thread-based handler been added to loop)? Thanks! -- You received this message because you are subscribed to the Google Groups "libuv" group. To unsubscribe from this group and stop receiving emails from it, send an email to libuv+unsubscr...@googlegroups.com. To post to this group, send email to libuv@googlegroups.com. Visit this group at https://groups.google.com/group/libuv. For more options, visit https://groups.google.com/d/optout.