Re: should cxx11 1.1 PortGroup also blacklist older clangs (< 600, say) during libc++ builds?

[Ken Cunningham]

I’m sorry - retract this. I see there is already a section where this is done 
that I had glossed past before.

I’ll have to look into why I still need to fiddle with this sometimes.

Sorry for noise.

Ken


> On Aug 12, 2017, at 3:02 PM, Ken Cunningham  
> wrote:
> 
> The libstdc++ section of this portgroup forces clang 4.0, and the PPC section 
> forces gcc6. Those cover almost all current port compiler requirements.
> 
> But there is still a hole in the libc++ section, and it happens often enough 
> that older clangs (< 600 or so) have to be blacklisted on older systems 
> separately.
> 
> It would seem consistent with the purpose of the Portgroup that this might be 
> included in the libc++ section to save this coming into each Portfile 
> separately.
> 
> Something like this:
> 
> 
> 
> } else {
># GCC compilers can not use libc++
>compiler.blacklist-append   *gcc*
> 
>compiler.blacklist-append   { clang < 600 }
> 
> }
> 
> ==
> 
> would probably do it for now. (That could be bumped to 800 - or more - rather 
> easily in the future when that is needed).
> 
> 
> Ken

should cxx11 1.1 PortGroup also blacklist older clangs (< 600, say) during libc++ builds?

[Ken Cunningham]

The libstdc++ section of this portgroup forces clang 4.0, and the PPC section 
forces gcc6. Those cover almost all current port compiler requirements.

But there is still a hole in the libc++ section, and it happens often enough 
that older clangs (< 600 or so) have to be blacklisted on older systems 
separately.

It would seem consistent with the purpose of the Portgroup that this might be 
included in the libc++ section to save this coming into each Portfile 
separately.

Something like this:



} else {
# GCC compilers can not use libc++
compiler.blacklist-append   *gcc*

compiler.blacklist-append   { clang < 600 }

}

==

would probably do it for now. (That could be bumped to 800 - or more - rather 
easily in the future when that is needed).


Ken