Re: [Matplotlib-users] a break in the y-axis

2011-01-24 Thread Paul Ivanov 
Eric Firing, on 2011-01-22 17:49,  wrote:
  Paul Ivanov, on 2011-01-22 18:28,  wrote:
 
 Paul,
 
 Your example below is nice, and this question comes up quite often.  If 
 we don't already have a gallery example of this, you might want to add 
 one.  (Probably better to use deterministic fake data rather than random.)
 
 
 import numpy as np
 import matplotlib.pylab as plt
 pts = np.random.rand(30)*.2
 pts[[7,11]] += .8
 f,(ax,ax2) = plt.subplots(2,1,sharex=True)
 
 ax.plot(pts)
 ax2.plot(pts)
 ax.set_ylim(.78,1.)
 ax2.set_ylim(0,.22)
 
 ax.xaxis.tick_top()
 ax.spines['bottom'].set_visible(False)
 ax.tick_params(labeltop='off')
 ax2.xaxis.tick_bottom()
 ax2.spines['top'].set_visible(False)

Done in r8935, see examples/pylab_examples/broken_axis.py

I documented the above, used deterministic fake data, as Eric
suggested, and added the diagonal cut lines that usually
accompany a broken axis. Here's the tail end of the script which
creates that effect (see updated attached image).

  # This looks pretty good, and was fairly painless, but you can
  # get that cut-out diagonal lines look with just a bit more
  # work. The important thing to know here is that in axes
  # coordinates, which are always between 0-1, spine endpoints
  # are at these locations (0,0), (0,1), (1,0), and (1,1).  Thus,
  # we just need to put the diagonals in the appropriate corners
  # of each of our axes, and so long as we use the right
  # transform and disable clipping.
  
  d = .015 # how big to make the diagonal lines in axes coordinates
  # arguments to pass plot, just so we don't keep repeating them
  kwargs = dict(transform=ax.transAxes, color='k', clip_on=False)
  ax.plot((-d,+d),(-d,+d), **kwargs)  # top-left diagonal
  ax.plot((1-d,1+d),(-d,+d), **kwargs)# top-right diagonal
  
  kwargs.update(transform=ax2.transAxes)  # switch to the bottom axes
  ax2.plot((-d,+d),(1-d,1+d), **kwargs)   # bottom-left diagonal
  ax2.plot((1-d,1+d),(1-d,1+d), **kwargs) # bottom-right diagonal
  
  # What's cool about this is that now if we vary the distance
  # between ax and ax2 via f.subplots_adjust(hspace=...) or
  # plt.subplot_tool(), the diagonal lines will move accordingly,
  # and stay right at the tips of the spines they are 'breaking'

best,
-- 
Paul Ivanov
314 address only used for lists,  off-list direct email at:
http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7 
attachment: broken_axis.png

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[Matplotlib-users] Find the RMS from a PSD

2011-01-24 Thread E 
Hello matplotlib users.

I'm new to signal processing and I've read that RMS could be found from
a PSD. I'm interested in as I would further like to know energy in a
signal through it's frequencies.
My problem is I don't find how to calculate the RMS from the PSD output.
It seems it's a matter of scale (frequencies bandwith is taken in
account already).

I wrote a test case with a simple sinus. I should be able to find the
same RMS value from the PSD method and direct RMS over signal method.

Could you please have a look and tell me how to find good RMS value from
PSD output?

Thanks

#!/usr/bin/python
# -*- coding: utf-8 -*-

import matplotlib, platform
if platform.system() == 'Linux' :
matplotlib.use(gtk)
import pylab
import scipy



## PSD vs RMS

#Parameters
samplerate = 48000
nfft = 1024*2
graph = False

#create 1 sec sinus signal
t = scipy.arange(0, 1 , 1/float(samplerate))
signal = .25*scipy.sin(2*scipy.pi*(samplerate/10.)*t)
print len(signal)


#RMS of an array
def RMS(data):
rms = data**2
rms = scipy.sqrt(rms.sum()/len(data))
return rms

#PSD of an array. I want this to return the RMS
def RMSfromPSD(data) :
y, x = pylab.psd(data, NFFT = nfft, Fs = samplerate)

##Calculate the RMS

#The energy returned by PSD depends on FFT size
freqbandwith = x[1]
y = y*freqbandwith

#The energy returned by PSD depends on Samplerate
y = y/float(samplerate)

#Summing the power in freq domain to get RMS
rms =  scipy.sqrt(y.sum())

return rms

print RMS method, RMS(signal)
print RMS using PSD method, RMSfromPSD(signal)



#Graph
if graph == True :
pylab.subplot(211)
pylab.plot(t,signal)
pylab.subplot(212)
pylab.psd(signal, nfft, samplerate)
pylab.show()
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Re: [Matplotlib-users] a break in the y-axis

2011-01-24 Thread Eric Firing 
On 01/23/2011 11:46 PM, Paul Ivanov wrote:
[...]
 Done in r8935, see examples/pylab_examples/broken_axis.py


Thank you.

 I documented the above, used deterministic fake data, as Eric
 suggested, and added the diagonal cut lines that usually
 accompany a broken axis. Here's the tail end of the script which
 creates that effect (see updated attached image).

Beautiful!

Eric


# This looks pretty good, and was fairly painless, but you can
# get that cut-out diagonal lines look with just a bit more
# work. The important thing to know here is that in axes
# coordinates, which are always between 0-1, spine endpoints
# are at these locations (0,0), (0,1), (1,0), and (1,1).  Thus,
# we just need to put the diagonals in the appropriate corners
# of each of our axes, and so long as we use the right
# transform and disable clipping.

d = .015 # how big to make the diagonal lines in axes coordinates
# arguments to pass plot, just so we don't keep repeating them
kwargs = dict(transform=ax.transAxes, color='k', clip_on=False)
ax.plot((-d,+d),(-d,+d), **kwargs)  # top-left diagonal
ax.plot((1-d,1+d),(-d,+d), **kwargs)# top-right diagonal

kwargs.update(transform=ax2.transAxes)  # switch to the bottom axes
ax2.plot((-d,+d),(1-d,1+d), **kwargs)   # bottom-left diagonal
ax2.plot((1-d,1+d),(1-d,1+d), **kwargs) # bottom-right diagonal

# What's cool about this is that now if we vary the distance
# between ax and ax2 via f.subplots_adjust(hspace=...) or
# plt.subplot_tool(), the diagonal lines will move accordingly,
# and stay right at the tips of the spines they are 'breaking'

 best,

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[Matplotlib-users] How to get a Mac OS X version of Tcl/Tk rather than X11 version.

2011-01-24 Thread Lou Pecora 
I have an installation of Python 2.6.4 on my MacBook Pro (OS X 10.6) that by 
default uses X11 windows and dialogs rather than the Mac version of those GUI 
items.  In my googling and exchanges on other support groups I've come down to 
the problem may be with the Tcl/Tk installation using the generic X11 GUI 
rather than the Mac version.  Does anyone know how I can change that in the Tk 
part of the python framework?
 
I think this problem came up in the iPython email list, but I didn't get enough 
info from the messages there.
 
More Info:  The python framework is part of the SAGE package which I installed 
from source.  I did this on my Mac Pro (system 10.4) and it works well with Mac 
windows for matplotlib and Mac open/save dialogs for Tk calls.  But on my 
MacBook Pro I get X11 windows and dialogs.  I want the Mac versions.
 
Even more info:
 
If you're interested, here's the original message I put up on the SAGE support 
group and was told it's a problem with the type of Tcl/Tk installed.

-- Lou Pecora

-

I have an installation of SAGE (from source) on my Mac laptop in which using 
the 
tcl/tk library to plot (using TKAgg backend) or call tk file open/save dialogs 
calls the X11 versions and not the native Mac versions of dialogs and windows.  
I want to get the Mac versions.
 
I posted about this on this list recently and now after a response here and 
much 
googling I have the sense that the problem is that I have a SAGE package with 
an 
X11 version of the tk library rather than the Mac one. I compiled SAGE from 
source on my Mac laptop. That went perfectly.  I don't know how I got the X11 
version since I also compiled SAGE from source on my Mac desktop where the 
plotting and file dialogs are the correct Mac versions, not X11. The only 
difference is that the laptop is Mac OS X 10.6 and the desktop is 10.4.  If 
that 
matters, I don't know.
 
Does anyone know how to get the Mac version installed in the SAGE 
source-compile 
installation?  I have not found an answer to this elsewhere.  I'm hoping 
someone 
here knows how this is done with the source installation.
 
Thanks for any help or pointers.
 
-- Lou Pecora



  

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[Matplotlib-users] X and Y label position in axes_grid1.AxesGrid/ImageGrid

2011-01-24 Thread Russell Hewett 
Hi All,

I can't get the x label on the top row of an ImageGrid to display if there
is more than one row in the grid.  I suspect that something is being clipped
somewhere, but have no idea what to do to fix it.  (Note, this also happens
on the right edge of a ride-sided y axis label.)

I have included some minimal sample code below.  I'd appreciate it if anyone
can point me in the right direction.


Cheers,
Russ

#---

import matplotlib.pyplot as plt
import matplotlib.cm as cm
import mpl_toolkits.axes_grid1 as ag

import numpy as np

fig1 = plt.figure()

grid1 = ag.AxesGrid( fig1, 111, nrows_ncols = (1,2), axes_pad = 0.5)

grid1[0].axes.xaxis.set_label_position('top')
grid1[0].axes.xaxis.set_label_text('foo')

grid1[1].axes.xaxis.set_label_position('top')
grid1[1].axes.xaxis.set_label_text('bar')

grid1[0].axes.yaxis.set_label_position('right')
grid1[0].axes.yaxis.set_label_text('foo')

grid1[1].axes.yaxis.set_label_position('right')
grid1[1].axes.yaxis.set_label_text('bar')


fig2 = plt.figure()

grid2 = ag.AxesGrid( fig2, 111, nrows_ncols = (2,1), axes_pad = 0.5)

grid2[0].axes.xaxis.set_label_position('top')
grid2[0].axes.xaxis.set_label_text('bar')

grid2[1].axes.xaxis.set_label_position('top')
grid2[1].axes.xaxis.set_label_text('bar')

grid2[0].axes.yaxis.set_label_position('right')
grid2[0].axes.yaxis.set_label_text('foo')

grid2[1].axes.yaxis.set_label_position('right')
grid2[1].axes.yaxis.set_label_text('bar')


plt.show()

#---

-- 
Russell J. Hewett
Ph.D. Candidate
Department of Computer Science
University of Illinois at Urbana-Champaign
www.russellhewett.com
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Re: [Matplotlib-users] X and Y label position in axes_grid1.AxesGrid/ImageGrid

2011-01-24 Thread Paul Ivanov 
Russell Hewett, on 2011-01-24 13:56,  wrote:
 Hi All,
 
 I can't get the x label on the top row of an ImageGrid to display if there
 is more than one row in the grid.  I suspect that something is being clipped
 somewhere, but have no idea what to do to fix it.  (Note, this also happens
 on the right edge of a ride-sided y axis label.)
 
 I have included some minimal sample code below.  I'd appreciate it if anyone
 can point me in the right direction.
 
 
 Cheers,
 Russ

Hi Russ, 

thanks for the report - at a glance, it appears to be a bug in
AxesGrid removing redundant labels for shared axis when they
align. I've included a temporary workaround for your script, but
don't have time to look into it further at the moment. By the
way, calling grid[0].axes is redundant, so I just modified it to
use grid[0].xaxis, which is equivalent.

#---
import matplotlib.pyplot as plt
import matplotlib.cm as cm
import mpl_toolkits.axes_grid1 as ag

import numpy as np

fig1 = plt.figure()

grid1 = ag.AxesGrid( fig1, 111, nrows_ncols = (1,2), axes_pad = 0.5)

grid1[0].xaxis.set_label_position('top')
grid1[0].xaxis.set_label_text('foo')

grid1[1].xaxis.set_label_position('top')
grid1[1].xaxis.set_label_text('bar')

grid1[0].yaxis.set_label_position('right')
grid1[0].yaxis.set_label_text('foo')

grid1[1].yaxis.set_label_position('right')
grid1[1].yaxis.set_label_text('bar')
grid1[1].yaxis.label.set_visible(True) # tmp workaround


fig2 = plt.figure()
grid2 = ag.AxesGrid( fig2, 111, nrows_ncols = (2,1), axes_pad = 0.5)

grid2[0].xaxis.set_label_position('top')
grid2[0].xaxis.set_label_text('bar')
grid2[0].xaxis.label.set_visible(True) # tmp workaround

grid2[1].xaxis.set_label_position('top')
grid2[1].xaxis.set_label_text('bar')

grid2[0].yaxis.set_label_position('right')
grid2[0].yaxis.set_label_text('foo')

grid2[1].yaxis.set_label_position('right')
grid2[1].yaxis.set_label_text('bar')

plt.show()
#---

best,
-- 
Paul Ivanov
314 address only used for lists,  off-list direct email at:
http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7 


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[Matplotlib-users] floating bar chart?

2011-01-24 Thread C M 
I looked through the gallery, but didn't see this one and am not sure
how to create it.  It would be a floating bar chart (or floating
column chart), like what is seen here:

http://peltiertech.com/Excel/pix1/BloodSugarFloater.gif

Thanks,
Che

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Re: [Matplotlib-users] labels in ax = Axes3D(fig) are not aligned in parallel

2011-01-24 Thread Paul Ivanov 
Daniel Mader, on 2011-01-24 20:55,  wrote:
 Hi,
 
 I have seen this ever since I use mpl_toolkits.mplot3d.Axes3D but it never
 bothered me too much until now: the labels are not aligned in paralled to
 the axes so that with longer labels or small figsizes, they run into the
 tick labels, besides looking odd.
 
Hi Daniel,

it does appear like a bug, though only for some views on the
axes, thanks for the report. I'm not very familiar with this
code, so I'll leave the bugfix for someone else, but here's the
temporary workaround:

 Is there anything I can do to change the angle manually?

# prevent the automatic rotation caused by view changes
ax.yaxis.set_rotate_label(False) 
ax.yaxis.label.set_rotation(45)

Beware that you'll have to adjust that angle on a per-view basis
to get things to look right.

best,
-- 
Paul Ivanov
314 address only used for lists,  off-list direct email at:
http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7 


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Re: [Matplotlib-users] floating bar chart?

2011-01-24 Thread Paul Ivanov 
C M, on 2011-01-24 16:27,  wrote:
 I looked through the gallery, but didn't see this one and am not sure
 how to create it.  It would be a floating bar chart (or floating
 column chart), like what is seen here:
 
 http://peltiertech.com/Excel/pix1/BloodSugarFloater.gif

Hi Che,

just specify the 'bottom' keyword argument to bar. Note that the
second parameter is height of the bar, *not* the top of the bar

plt.bar([1,2,3,4], [2,2.5,5,3], bottom=[0,-1,1,2])

best,
-- 
Paul Ivanov
314 address only used for lists,  off-list direct email at:
http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7 


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Re: [Matplotlib-users] X and Y label position in axes_grid1.AxesGrid/ImageGrid

2011-01-24 Thread Russell Hewett 
Worked great, thanks!

-r

On Mon, Jan 24, 2011 at 2:32 PM, Paul Ivanov pivanov...@gmail.com wrote:

 Russell Hewett, on 2011-01-24 13:56,  wrote:
  Hi All,
 
  I can't get the x label on the top row of an ImageGrid to display if
 there
  is more than one row in the grid.  I suspect that something is being
 clipped
  somewhere, but have no idea what to do to fix it.  (Note, this also
 happens
  on the right edge of a ride-sided y axis label.)
 
  I have included some minimal sample code below.  I'd appreciate it if
 anyone
  can point me in the right direction.
 
 
  Cheers,
  Russ

 Hi Russ,

 thanks for the report - at a glance, it appears to be a bug in
 AxesGrid removing redundant labels for shared axis when they
 align. I've included a temporary workaround for your script, but
 don't have time to look into it further at the moment. By the
 way, calling grid[0].axes is redundant, so I just modified it to
 use grid[0].xaxis, which is equivalent.

 #---
 import matplotlib.pyplot as plt
 import matplotlib.cm as cm
 import mpl_toolkits.axes_grid1 as ag

 import numpy as np

 fig1 = plt.figure()

 grid1 = ag.AxesGrid( fig1, 111, nrows_ncols = (1,2), axes_pad = 0.5)

 grid1[0].xaxis.set_label_position('top')
 grid1[0].xaxis.set_label_text('foo')

 grid1[1].xaxis.set_label_position('top')
 grid1[1].xaxis.set_label_text('bar')

 grid1[0].yaxis.set_label_position('right')
 grid1[0].yaxis.set_label_text('foo')

 grid1[1].yaxis.set_label_position('right')
 grid1[1].yaxis.set_label_text('bar')
 grid1[1].yaxis.label.set_visible(True) # tmp workaround


 fig2 = plt.figure()
 grid2 = ag.AxesGrid( fig2, 111, nrows_ncols = (2,1), axes_pad = 0.5)

 grid2[0].xaxis.set_label_position('top')
 grid2[0].xaxis.set_label_text('bar')
 grid2[0].xaxis.label.set_visible(True) # tmp workaround

 grid2[1].xaxis.set_label_position('top')
 grid2[1].xaxis.set_label_text('bar')

 grid2[0].yaxis.set_label_position('right')
 grid2[0].yaxis.set_label_text('foo')

 grid2[1].yaxis.set_label_position('right')
 grid2[1].yaxis.set_label_text('bar')

 plt.show()
 #---

 best,
 --
 Paul Ivanov
 314 address only used for lists,  off-list direct email at:
 http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7

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-- 
Russell J. Hewett
Ph.D. Candidate
Department of Computer Science
University of Illinois at Urbana-Champaign
www.russellhewett.com
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Re: [Matplotlib-users] labels in ax = Axes3D(fig) are not aligned in parallel

2011-01-24 Thread Daniel Mader 
Dear Paul,

thank you very much for the quick reply! Unfortunately, I don't seem to get
things right with your snippet of code:

# prevent the automatic rotation caused by view changes
 ax.yaxis.set_rotate_label(False)
 ax.yaxis.label.set_rotation(45)



Traceback (most recent call last):
  File example_mpl3D_spiral.py, line 41, in module
ax.yaxis.set_rotate_label(False)
AttributeError: 'YAxis' object has no attribute 'set_rotate_label'

Am I missing something?

Thanks in advance,
best regards from a snowed up Salzburg,

Daniel
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Re: [Matplotlib-users] floating bar chart?

2011-01-24 Thread C M 
On Mon, Jan 24, 2011 at 4:42 PM, Paul Ivanov pivanov...@gmail.com wrote:
 C M, on 2011-01-24 16:27,  wrote:
 I looked through the gallery, but didn't see this one and am not sure
 how to create it.  It would be a floating bar chart (or floating
 column chart), like what is seen here:

 http://peltiertech.com/Excel/pix1/BloodSugarFloater.gif

 Hi Che,

 just specify the 'bottom' keyword argument to bar. Note that the
 second parameter is height of the bar, *not* the top of the bar

 plt.bar([1,2,3,4], [2,2.5,5,3], bottom=[0,-1,1,2])

 best,
 --
 Paul Ivanov

Thanks, Paul!  Easy enough.

-Che

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Re: [Matplotlib-users] X and Y label position in axes_grid1.AxesGrid/ImageGrid

2011-01-24 Thread Benjamin Root 
On Monday, January 24, 2011, Russell Hewett rhewe...@illinois.edu wrote:
 Worked great, thanks!

 -r

 On Mon, Jan 24, 2011 at 2:32 PM, Paul Ivanov pivanov...@gmail.com wrote:

 Russell Hewett, on 2011-01-24 13:56,  wrote:
 Hi All,

 I can't get the x label on the top row of an ImageGrid to display if there
 is more than one row in the grid.  I suspect that something is being clipped
 somewhere, but have no idea what to do to fix it.  (Note, this also happens
 on the right edge of a ride-sided y axis label.)

 I have included some minimal sample code below.  I'd appreciate it if anyone
 can point me in the right direction.


 Cheers,
 Russ

 Hi Russ,

 thanks for the report - at a glance, it appears to be a bug in
 AxesGrid removing redundant labels for shared axis when they
 align. I've included a temporary workaround for your script, but
 don't have time to look into it further at the moment. By the
 way, calling grid[0].axes is redundant, so I just modified it to
 use grid[0].xaxis, which is equivalent.

 #---
 import matplotlib.pyplot as plt
 import matplotlib.cm as cm
 import mpl_toolkits.axes_grid1 as ag

 import numpy as np

 fig1 = plt.figure()

 grid1 = ag.AxesGrid( fig1, 111, nrows_ncols = (1,2), axes_pad = 0.5)

 grid1[0].xaxis.set_label_position('top')
 grid1[0].xaxis.set_label_text('foo')

 grid1[1].xaxis.set_label_position('top')
 grid1[1].xaxis.set_label_text('bar')

 grid1[0].yaxis.set_label_position('right')
 grid1[0].yaxis.set_label_text('foo')

 grid1[1].yaxis.set_label_position('right')
 grid1[1].yaxis.set_label_text('bar')
 grid1[1].yaxis.label.set_visible(True) # tmp workaround


 fig2 = plt.figure()
 grid2 = ag.AxesGrid( fig2, 111, nrows_ncols = (2,1), axes_pad = 0.5)

 grid2[0].xaxis.set_label_position('top')
 grid2[0].xaxis.set_label_text('bar')
 grid2[0].xaxis.label.set_visible(True) # tmp workaround

 grid2[1].xaxis.set_label_position('top')
 grid2[1].xaxis.set_label_text('bar')

 grid2[0].yaxis.set_label_position('right')
 grid2[0].yaxis.set_label_text('foo')

 grid2[1].yaxis.set_label_position('right')
 grid2[1].yaxis.set_label_text('bar')

 plt.show()
 #---

 best,
 --
 Paul Ivanov
 314 address only used for lists,  off-list direct email at:
 http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7

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 --
 Russell J. Hewett
 Ph.D. Candidate
 Department of Computer Science
 University of Illinois at Urbana-Champaign
 www.russellhewett.com



Isn't it a feature?  Axes_grid lets you choose the label mode which is
'L' by default.  This means that only the outer labels are shown.  Or
am I missing something in the description of the problem?

Ben Root

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Re: [Matplotlib-users] labels in ax = Axes3D(fig) are not aligned in parallel

2011-01-24 Thread Benjamin Root 
On Monday, January 24, 2011, Daniel Mader
danielstefanma...@googlemail.com wrote:
 Dear Paul,

 thank you very much for the quick reply! Unfortunately, I don't seem to get 
 things right with your snippet of code:



 # prevent the automatic rotation caused by view changes
 ax.yaxis.set_rotate_label(False)
 ax.yaxis.label.set_rotation(45)
 Traceback (most recent call last):
   File example_mpl3D_spiral.py, line 41, in module
     ax.yaxis.set_rotate_label(False)
 AttributeError: 'YAxis' object has no attribute 'set_rotate_label'

 Am I missing something?

 Thanks in advance,
 best regards from a snowed up Salzburg,

 Daniel


This problem with poorly rotated labels was fixed a couple of months
ago in the development branch and I believe it is also in 1.0.1.  Just
to make sure, what version are you running?

Ben Root

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[Matplotlib-users] Defining a precise x-axis max in plot()

2011-01-24 Thread Lionel (Lee) Brooks 3rd 
Hello Gentlepeople,

I am plotting an integer array using: matplotlib.pyplot.plot().
For my purposes it is imperative that the x-axis be explicitly defined.
I have tried to achieve this by using: matplotlib.pyplot.axis(v).
Where v is a list of integer values corresponding to the desired axes 
limits [xmin, xmax, ymin, ymax].
However, the x-axis that is displayed does not obey my explicit xmax 
declaration; the value is rounded up.

Here is the relevant portion of my code:

fig = pyplot.figure(figsize=(16,8))
ax1 = fig.add_axes([0.05, 0.15, 0.9, 0.8])
v = [0, len(myintvector), 0, max(myintvector, key=int)]
ax1.axis(v)
ax1.plot(myintvector, 'r--')

The reason that I need the x-axis to match the length of my integer 
vector is because I am also drawing a colorbar immediately below the 
plot, the values of which describe the same integer vector.  Therefore I 
need the colorbar coordinates to match the x-axis coordinates of my plot.

I hope that I have described my issue coherently.  Please be kind (N00b 
alert).
Any help is greatly appreciated!

Sincerely,
Lionel 'Lee' Brooks 3rd
Dartmouth Genetics Grad Student

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Re: [Matplotlib-users] X and Y label position in axes_grid1.AxesGrid/ImageGrid

2011-01-24 Thread Russell Hewett 
This is indeed correct.  Somehow I missed this.  Setting label_mode = 'all'
gets the behavior I wanted.

Though, the top and right side are technically on the outside too.  Perhaps
that should be an available or the default setting?  Perhaps the top row
should default to labeling on the top, the right column default to labeling
on the right, etc?

-r

On Mon, Jan 24, 2011 at 5:56 PM, Benjamin Root ben.r...@ou.edu wrote:



 Isn't it a feature?  Axes_grid lets you choose the label mode which is
 'L' by default.  This means that only the outer labels are shown.  Or
 am I missing something in the description of the problem?

 Ben Root




-- 
Russell J. Hewett
Ph.D. Candidate
Department of Computer Science
University of Illinois at Urbana-Champaign
www.russellhewett.com
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Re: [Matplotlib-users] Defining a precise x-axis max in plot()

2011-01-24 Thread Eric Firing 
On 01/24/2011 02:49 PM, Lionel (Lee) Brooks 3rd wrote:
 Hello Gentlepeople,

 I am plotting an integer array using: matplotlib.pyplot.plot().
 For my purposes it is imperative that the x-axis be explicitly defined.
 I have tried to achieve this by using: matplotlib.pyplot.axis(v).
 Where v is a list of integer values corresponding to the desired axes
 limits [xmin, xmax, ymin, ymax].
 However, the x-axis that is displayed does not obey my explicit xmax
 declaration; the value is rounded up.

 Here is the relevant portion of my code:

It is always better to provide a minimal but complete self-contained 
example illustrating the problem.


 fig = pyplot.figure(figsize=(16,8))
 ax1 = fig.add_axes([0.05, 0.15, 0.9, 0.8])
 v = [0, len(myintvector), 0, max(myintvector, key=int)]
 ax1.axis(v)
 ax1.plot(myintvector, 'r--')

I am not seeing the problem when I try what I think is a minimal 
example; what version of mpl are you using?  And have you tried calling 
axis after the call to plot?  This might have been necessary in some 
earlier versions; I don't recall.

(In ipython -pylab, my example was this:

ax1 = gca()
ax1.axis([0,9.9,0,9.9])
ax1.plot([1,2])
draw()

in which no rounding occurs.)

Eric


 The reason that I need the x-axis to match the length of my integer
 vector is because I am also drawing a colorbar immediately below the
 plot, the values of which describe the same integer vector.  Therefore I
 need the colorbar coordinates to match the x-axis coordinates of my plot.

 I hope that I have described my issue coherently.  Please be kind (N00b
 alert).
 Any help is greatly appreciated!

 Sincerely,
 Lionel 'Lee' Brooks 3rd
 Dartmouth Genetics Grad Student


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