RE: Unix Help
Title: Message DEST_DIR=your_desination_directory SOURCE_DIR=your_source_directory for file in `ls $SOURCE_DIR` do fn=basename $file if [ ! -f $DEST_DIR/$fn ] then cp $file $DEST_DIR/$fn fi done Hope it helps. Allan -Original Message-From: Sujatha Madan [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 07, 2003 10:24 PMTo: Multiple recipients of list ORACLE-LSubject: Unix Help Hi, Sorry for the slightly non-Oracle post. I am after a UNIX code snippet that will help me copy archive logs to another directory BUT not if they already exist. So if only 2 archive logs are generated between script runs only the two new ones should copy. I know I can do this using sysdate - "time interval" but I am trying to avoid that. Thanks in advance, Sujatha Madan. __ This email is intended solely for the person or entity to which it is addressed and may contain confidential and/or privileged information. Copying, forwarding or distributing this message by persons or entities other than the addressee is prohibited. If you have received this email in error, please contact the sender immediately and delete the material from any computer. This email may have been monitored for policy compliance. [021216]
RE: Unix help
Yawn... -Original Message- Sent: Tuesday, April 16, 2002 10:08 AM To: Multiple recipients of list ORACLE-L I have this unix script, please tell me how to change it so it also does the following: counts the time between start time and end time of the process(I mean time difference between Jobb startat(Job started) and Job Klart(Job Finished). loadbilbo.sh: #!/bin/sh . /usr/bin/orasetup.sh . /d31/appl/konto/bat/movefiles.sh echo Jobb startat :\c /d31/appl/konto/log/laddabilbo.txt date /d31/appl/konto/log/laddabilbo.txt sqlldr userid=konto/icakort control=/d31/appl/konto/bat/ehbgrupp.ctl log=/d31/appl/konto/log/ehbgrupp.log sqlldr userid=konto/icakort control=/d31/appl/konto/bat/kampanj.ctl log=/d31/appl/konto/log/kampanj.log sqlldr userid=konto/icakort control=/d31/appl/konto/bat/mxurval.ctl log=/d31/appl/konto/log/mxurval.log sqlldr userid=konto/icakort control=/d31/appl/konto/bat/load_arg.ctl log=/d31/appl/konto/log/load_arg.log sqlldr userid=konto/icakort control=/d31/appl/konto/bat/laddabsg.ctl log=/d31/appl/konto/log/laddabsg.log sqlplus -s konto/icakort ! set heading off set verify off set feedback off set termout off set pages 0 begin konto.fillbilbotables.anrop; END; / EXIT ! echo -- /d31/appl/konto/log/laddabilbo.txt echo ehbgrupp status /d31/appl/konto/log/laddabilbo.txt tail -11 /d31/appl/konto/log/ehbgrupp.log /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo kampanj status /d31/appl/konto/log/laddabilbo.txt tail -11 /d31/appl/konto/log/kampanj.log /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo mxurval status /d31/appl/konto/log/laddabilbo.txt tail -11 /d31/appl/konto/log/mxurval.log /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo load_arg status /d31/appl/konto/log/laddabilbo.txt tail -11 /d31/appl/konto/log/load_arg.log /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo laddabsg status /d31/appl/konto/log/laddabilbo.txt tail -11 /d31/appl/konto/log/laddabsg.log /d31/appl/konto/log/laddabilbo.txt echo -- /d31/appl/konto/log/laddabilbo.txt echo Jobb klart! :\c /d31/appl/konto/log/laddabilbo.txt date /d31/appl/konto/log/laddabilbo.txt cat /d31/appl/konto/log/laddabilbo.txt | mailx -s Konto - Statusrapport [EMAIL PROTECTED] [EMAIL PROTECTED] [EMAIL PROTECTED] IThis log file is also sent by mail to people. I would like this log file only to be sent if there is anything wrong with the script(for instance if the database is down) So if the script goes fine, then no email will be sent. The log file looks like this: Jobb startat :Sun Apr 14 18:06:23 MEST 2002 -- ehbgrupp status Total logical records skipped: 0 Total logical records read: 400 Total logical records rejected: 0 Total logical records discarded:0 Run began on Sun Apr 14 18:06:23 2002 Run ended on Sun Apr 14 18:11:51 2002 Elapsed time was: 00:05:28.15 CPU time was: 00:00:00.07 (Ma -- -- kampanj status Total logical records skipped: 0 Total logical records read:13 Total logical records rejected: 0 Total logical records discarded:0 Run began on Sun Apr 14 18:11:51 2002 Run ended on Sun Apr 14 18:12:44 2002 Elapsed time was: 00:00:52.52 CPU time was: 00:00:00.04 (Ma -- -- mxurval status Total logical records skipped: 0 Total logical records read: 4829 Total logical records rejected: 0 Total logical records discarded:0 Run began on Sun Apr 14 18:12:44 2002 Run ended on Sun Apr 14 18:12:50 2002 Elapsed time was: 00:00:05.90 CPU time was: 00:00:00.18 (Ma -- -- load_arg status Total logical records skipped: 0 Total logical records read:151613 Total logical records rejected: 0 Total logical records discarded:0 Run began on Sun Apr 14 18:12:50 2002
Re: UNIX help needed for sed multi-line pattern space
Alan,
What do you mean the file is to large for vi? If you are going to string the lines
together be sure that you don't overrun the linitations of the server input line
length. If you need to have continuations in the line I think that the \ tells the
server the command is continued on the next line.
Check the server manufacturer's site for support discussions.
ROR mª¿ªm
[EMAIL PROTECTED] 11/15/01 12:55PM
If I have the following two-line sql statement in a file:
SELECT A,B,C FROM TABLE1
WHERE A=1;
and want to create a single line, I could use the following sed script:
/[^;]$/{
N
s/\n/ /
}
which would produce:
SELECT A,B,C FROM TABLE1 WHERE A=1;
What would my sed script look like if there were 2, 3, or even 4
continuation lines (unknown number of lines)?
Note that the file is too large for vi.
Any good UNIX sites where I could post UNIX questions?
Thanx,
Alan Martin
Principal Consultant
Defense Logistics Information Service
[EMAIL PROTECTED]
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RE: UNIX help needed for sed multi-line pattern space
Title: UNIX help needed for sed multi-line pattern space
Alan,
Why not use awk?
cat filename | awk '{if (
substr($0,length($0),1) == ";") {print " " $0 } else {printf($0)
}}'
Hope this helps
Chris
-Original Message-From: Martin, Alan
[mailto:[EMAIL PROTECTED]]Sent: 15 November 2001
17:55To: Multiple recipients of list ORACLE-LSubject:
UNIX help needed for sed multi-line pattern space
If I have the following two-line sql statement in a
file:
SELECT A,B,C FROM TABLE1 WHERE A=1;
and want to create a single line, I could use the
following sed script:
/[^;]$/{ N s/\n/ /
}
which would produce:
SELECT A,B,C FROM TABLE1 WHERE A=1;
What would my sed script look like if there were 2,
3, or even 4 continuation lines (unknown number of lines)? Note that the file is too large for vi. Any good UNIX sites where I could post UNIX
questions?
Thanx,
Alan
Martin Principal Consultant Defense Logistics Information Service [EMAIL PROTECTED]
