[PHP-DB] re: PHP4

2003-06-21 Thread Jon Miller
Does anyone know if PHP 4 on the Red Hat distro is only available on RHL8 or better?

Thanks

Jon L. Miller, MCNE, CNS
Director/Sr Systems Consultant
MMT Networks Pty Ltd
http://www.mmtnetworks.com.au

I don't know the key to success, but the key to failure
 is trying to please everybody. -Bill Cosby





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[PHP-DB] Header, Directory, and SESSIONs

2003-06-21 Thread nabil
Hi all, wish u all a good weekend..
Guys I have a question as the following:

1- In my wwwroot I have two folders : folder1  and folder2 (actually I have
14 folders)
2- In the same two folders there are same PHP files do the same job, as db
jobs with different databases..
3- I log in the users by register a session, lab lab lab ... etc
4- the logging files in the two folders are different by registering a
different session value.
4- I want if any user jumped to the other directory and logged in with the
correct requested password TO HAVE THE FIRST SESSION UNREGISTERED
automatically, so he can't be logged in in both at same time.. and keep only
the new.. and ofcourse have to re logging if he jumped back to the first
one...
 (the reason that every folder has different DB connection, and the
interface of the two section are identical.. so I need to split it .to avoid
any problems with many users )

5- what I m trying to do is , if there is a possibility to control the
header.. by if { /folder1 go } else { unregister session whatever}
if {/ folder2 .. } else {.} etc

6- IS IT A GOOD WAY TO DO IT , OR NOT? of cource I need a security in the
first place..

I HOPE I WAS CLEAR, and thanks for your patient again...   :))
(sorry because it might be shouldn't in db list)
Regards
Nabil

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[PHP-DB] Re: test

2003-06-21 Thread fazla
:-))
David Robley [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
 In article [EMAIL PROTECTED], [EMAIL PROTECTED] says...
  login test
 Login/Password mismatch
 Connection failed

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[PHP-DB] connect to db with php?

2003-06-21 Thread David
Warning - beginner  :-)  I'm new at Linux, php and mysql, so please go slowly.

I have a test database with a couple of tables, etc., that I can connect to 
and run simple queries against, etc., all from the command line. I do most 
things as root, probably because I didn't set it up right and haven't fixed 
it.

I'm trying to put together a simple php script to connect to the database and 
learn about both at the same time. At the moment I have something like this:

?php
$conn = mysql_connect(127.0.0.1,root,password,databasename);
if (!$conn) die (Could not connect);
blah blah
?

which gives this result:
Warning: Access denied for user: '[EMAIL PROTECTED]' (Using password: 
YES) in /var/www/html/php/script1.php on line 9
 (line 9 is the $conn line, above)

I've tried a few variations but I'm not sure where to go from here.
Can anyone help out?
thanks
David

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[PHP-DB] How can I get the number of entries retrieved by a SELECT - FROM Thanks!

2003-06-21 Thread ed anderson
Dell 4500, mem 1g, disk 45g, mhz 2g, Mysql-3.23.54a-linux-i686, PHP-4.30,
httpd_2.0.44

Thanks to Paul DuBois, Roger Davis, Helen Sallee, Ronan Chilvers, and Edward
Dudlik
for thier response to my question.  I've included the a (one of many?)
snippit of code that
I've decided to use as a pattern for a (class) to be developed.

Thanks again:

Ed anderson

htmlheadtitlesample.php/title/head
body
sample.php BR
see page 405 msql cookbook for code used to develop $h_nrows BR
?php
#
$mysql_connect = mysql_connect(localhost, root)
   or die (mysql_connect $mysql_connect\n);
mysql_select_db(mysql, $mysql_connect)
or die (mysql_select_db $mysql_connect\n);
#
$h_id1 = 3; $h_id2 = 4; $h_id3 = 5;
$t = td; $tn = /td;
$r = tr; $rn =  /tr;
#
$h_query =  SELECT  *
FROM employees
  WHERE  id=$h_id1  OR  id=$h_id2  OR  id=$h_id3;
 printf(mysql_query: $h_querybr\n);
#
$h_result_id =  mysql_query($h_query, $mysql_connect);
 if(! $h_result_id)
  die ( mysql_query h $mysql_connect\n);
 $h_nrows = @mysql_num_rows ($h_result_id);
#
if ($h_nrows == 0)
 print (Note: h query has no result set\n);
  $dat_h_id  = mysql_result($h_result_id,$i,id);
  $dat_first = mysql_result($h_result_id,$i,first);
  $dat_last  = mysql_result($h_result_id,$i,last);
#
#
#
echo table border=1 cellspacing=0;
for ($i = 0; $i  $h_nrows; $i++)
{ echo $r;
   $dat_h_id  = mysql_result($h_result_id,$i,id);
echo $t  $dat_h_id$tn;
$dat_first = mysql_result($h_result_id,$i,first);
echo $t  $dat_first$tn;
$dat_last  = mysql_result($h_result_id,$i,last);
echo $t  $dat_last $tn;
echo $t  $i$tn;
echo $t  $h_nrows  $tn;
echo $rn;
} echo /table;
#
?
BR
sample.php end BRBR
/body
/html

using mozilla browser -http://127.0.0.1/sample.php

sample.php
see page 405 msql cookbook code used to develop $h_nrows
mysql_query: SELECT * FROM employees WHERE id=3 OR id=4 OR id=5
3 Brad   Johnson 0 3
4 aa   bb 1 3
5 WW   EE 2 3


sample.php end


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[PHP-DB] Re: test

2003-06-21 Thread JeRRy
Are we 'testing' something here?  Seems to be working,
but I guess I really don't know because I have NFI
what is being tested here.  Nor do I expect anyone to
care to explain! ;)



To: [EMAIL PROTECTED] 
From: fazla [EMAIL PROTECTED] 
Date: Sat, 21 Jun 2003 16:30:09 +0200 
Subject: Re: test 


:-))
David Robley [EMAIL PROTECTED] wrote in
message
news:[EMAIL PROTECTED]
 In article [EMAIL PROTECTED],
[EMAIL PROTECTED] says...
  login test
 Login/Password mismatch
 Connection failed

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Re: [PHP-DB] connect to db with php?

2003-06-21 Thread Doug Thompson
1. The default user table sets up root with no password.  Leave out the password and 
it will probably connect OK.  You really need to fix the user table, but as long as 
the system isn't accessible from outside, you can get by.

2.  You don't need to use host, in this case 127.0.0.1, when connecting from the 
same machine.  It doesn't hurt, but it may add confusion at some future point in your 
troubleshooting.

3.  All of this is really mysql specific and you would do better using that list, too.

Doug


On Sun, 22 Jun 2003 00:45:12 +1000, David wrote:

Warning - beginner  :-)  I'm new at Linux, php and mysql, so please go slowly.

I have a test database with a couple of tables, etc., that I can connect to 
and run simple queries against, etc., all from the command line. I do most 
things as root, probably because I didn't set it up right and haven't fixed 
it.

I'm trying to put together a simple php script to connect to the database and 
learn about both at the same time. At the moment I have something like this:

?php
$conn = mysql_connect(127.0.0.1,root,password,databasename);
if (!$conn) die (Could not connect);
blah blah
?

which gives this result:
Warning: Access denied for user: '[EMAIL PROTECTED]' (Using password: 
YES) in /var/www/html/php/script1.php on line 9
 (line 9 is the $conn line, above)

I've tried a few variations but I'm not sure where to go from here.
Can anyone help out?
thanks
David

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The arm folds in at the elbow, not out


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