RE: [PHP-DB] Adding times in php
I would consider adding either: 1. a virtual column in the sql to add up the times 2. issue another sql statement to get a total 3. store a total in a cookie / session initially bastien From: Allan [EMAIL PROTECTED] Reply-To: Allan [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] Adding times in php Date: Sat, 4 Mar 2006 15:13:13 +0800 Hi All I have two tables with columns of times that it took to perform tasks eg: 8:40 6:50 8:30 10:55 - 34:55 total time taken to complete the tasks in hours and minutes I am able to add the times with sql however I need to add the totals to cone up with a grand total and because of the makeup of the tables I cant use sql. I am there for going to have to use php code and this is where the problem comes in because in sql there is SEC_TO_TIME and TIME_TO_SEC functions that allow easy addition of the times but I cant find an equivalent in php. Does any one know of a way that I can add to times together in php. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] MySQL update statement problem
Hi, Apologies if this isn't the right place to ask - but I'm banging my head against the wall with this one! I'm trying to update a record in the table (creation script below) using the following SQL statement: UPDATE shop_customer SET eu_vat_number = SK1234567890 AND vat_amount = 0 AND total_amount = 8.4925 WHERE customer_id = 7 AND hash=dcd5e751 Before running the query the value for eu_vat_number is 'null', vat_amount is 0.085 and total_amount = 8.5775. After I run the query (mysql_affected_rows = 1) the values for vat_amount and total_amount remain the same, but vat_number is changed to 0. I've been looking at this most of the afternoon, and it's probably something really simple but I just can't see it... Any ideas? Thanks in advance for your help... Cheers, Kev -- Server version: 3.23.58 -- PHP Version: 4.3.10 CREATE TABLE `shop_customer` ( `customer_id` int(11) NOT NULL auto_increment, `hash` varchar(8) NOT NULL default '', `first_name` varchar(255) NOT NULL default '', `last_name` varchar(255) NOT NULL default '', `email_address` varchar(255) NOT NULL default '', `member_id` int(11) default NULL, `address1` varchar(255) default NULL, `address2` varchar(255) default NULL, `town` varchar(255) default NULL, `county` varchar(255) default NULL, `postcode` varchar(255) default NULL, `country` int(11) NOT NULL default '0', `eu_vat_number` varchar(15) default NULL, `total_items` int(11) default '0', `net_amount` float default '0', `vat_amount` float default '0', `shipping_amount` float default '0', `total_amount` float default '0', `added` datetime NOT NULL default '-00-00 00:00:00', `payment_received` datetime default NULL, PRIMARY KEY (`customer_id`) ) TYPE=MyISAM AUTO_INCREMENT=8 ; -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] MySQL update statement problem
You need to separate the SET arguments with commas, not ANDs... It's really doing something like this: UPDATE shop_customer SET eu_vat_number = (SK1234567890 AND vat_amount = 0 AND total_amount = 8.4925) WHERE customer_id = 7 AND hash=dcd5e751 (SK1234567890 AND vat_amount = 0 AND total_amount = 8.4925) evaluates to false (0) , so that's what gets set. Kevin Davies - Bonhurst Consulting wrote: Hi, Apologies if this isn't the right place to ask - but I'm banging my head against the wall with this one! I'm trying to update a record in the table (creation script below) using the following SQL statement: UPDATE shop_customer SET eu_vat_number = SK1234567890 AND vat_amount = 0 AND total_amount = 8.4925 WHERE customer_id = 7 AND hash=dcd5e751 Before running the query the value for eu_vat_number is 'null', vat_amount is 0.085 and total_amount = 8.5775. After I run the query (mysql_affected_rows = 1) the values for vat_amount and total_amount remain the same, but vat_number is changed to 0. I've been looking at this most of the afternoon, and it's probably something really simple but I just can't see it... Any ideas? Thanks in advance for your help... Cheers, Kev -- Server version: 3.23.58 -- PHP Version: 4.3.10 CREATE TABLE `shop_customer` ( `customer_id` int(11) NOT NULL auto_increment, `hash` varchar(8) NOT NULL default '', `first_name` varchar(255) NOT NULL default '', `last_name` varchar(255) NOT NULL default '', `email_address` varchar(255) NOT NULL default '', `member_id` int(11) default NULL, `address1` varchar(255) default NULL, `address2` varchar(255) default NULL, `town` varchar(255) default NULL, `county` varchar(255) default NULL, `postcode` varchar(255) default NULL, `country` int(11) NOT NULL default '0', `eu_vat_number` varchar(15) default NULL, `total_items` int(11) default '0', `net_amount` float default '0', `vat_amount` float default '0', `shipping_amount` float default '0', `total_amount` float default '0', `added` datetime NOT NULL default '-00-00 00:00:00', `payment_received` datetime default NULL, PRIMARY KEY (`customer_id`) ) TYPE=MyISAM AUTO_INCREMENT=8 ; -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] MySQL update statement problem
Jenaro,
You're absolutely right (',' instead of 'and' - schoolboy error!). I've
obviously been staring at the screen too long! Strange that MySQL accepted
it as a valid statement though.
Many thanks for the quick reply.
I'm off to have a lie down! :)
Thanks and regards,
Kevin
-Original Message-
From: Jenaro Centeno Gómez [mailto:[EMAIL PROTECTED]
Sent: 04 March 2006 17:35
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL update statement problem
Maybe I am wrong, biut isn´this the rigth way to do this:
UPDATE shop_customer SET eu_vat_number = SK1234567890, vat_amount =
0,total_amount = 8.4925
WHERE customer_id = 7 AND hash=dcd5e751
Sorry, I've not used too much MySQL but this is the rigth way in Oracle,
PostgreSQL and SQLServer.
Hope this helps.
Kevin Davies - Bonhurst Consulting escribió:
Hi,
Apologies if this isn't the right place to ask - but I'm banging my head
against the wall with this one!
I'm trying to update a record in the table (creation script below) using
the
following SQL statement:
UPDATE shop_customer SET eu_vat_number = SK1234567890 AND vat_amount = 0
AND total_amount = 8.4925 WHERE customer_id = 7 AND hash=dcd5e751
Before running the query the value for eu_vat_number is 'null', vat_amount
is 0.085 and total_amount = 8.5775.
After I run the query (mysql_affected_rows = 1) the values for vat_amount
and total_amount remain the same, but vat_number is changed to 0.
I've been looking at this most of the afternoon, and it's probably
something
really simple but I just can't see it...
Any ideas?
Thanks in advance for your help...
Cheers,
Kev
-- Server version: 3.23.58
-- PHP Version: 4.3.10
CREATE TABLE `shop_customer` (
`customer_id` int(11) NOT NULL auto_increment,
`hash` varchar(8) NOT NULL default '',
`first_name` varchar(255) NOT NULL default '',
`last_name` varchar(255) NOT NULL default '',
`email_address` varchar(255) NOT NULL default '',
`member_id` int(11) default NULL,
`address1` varchar(255) default NULL,
`address2` varchar(255) default NULL,
`town` varchar(255) default NULL,
`county` varchar(255) default NULL,
`postcode` varchar(255) default NULL,
`country` int(11) NOT NULL default '0',
`eu_vat_number` varchar(15) default NULL,
`total_items` int(11) default '0',
`net_amount` float default '0',
`vat_amount` float default '0',
`shipping_amount` float default '0',
`total_amount` float default '0',
`added` datetime NOT NULL default '-00-00 00:00:00',
`payment_received` datetime default NULL,
PRIMARY KEY (`customer_id`)
) TYPE=MyISAM AUTO_INCREMENT=8 ;
--
L.A. Jenaro Centeno Gómez
Administración de Redes y Bases de Datos
Alimentos La Concordia, S.A. de C.V.
Loma de Prados No. 1332
Col. La Marimba
Lagos de Moreno, Jal.
C.P. 47470
Tel.- 01 474 741 92 00 Ext. 9280
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[PHP-DB] RE: Adding time in php
Hi,
All you need to do is run a query to your db to get the times.
than use something like this:
?php
// Multiplying with varaibles
$factorA = .01;
$factorB = number_format(system_value('usercount'), 0);
$product = $factorA * $factorB + .25;
echo $product;
?
What this one does is count a total number of user on the website, than use
factorA and multiplies that with factorB + a certain value.
But this won't bring it in-line to what you want, but you could run some code
to work it out. (just divide by .60?)
J
Hi AllI have two tables with columns of times that it took to perform tasks
eg: 8:406:508:30 10:55 - 34:55 total time taken to
complete the tasks in hours and minutesI am able to add the times with sql
however I need to add the totals to cone up with a grand total and because
of the makeup of the tables I cant use sql. I am there for going to have to
use php code and this is where the problem comes in because in sql there is
SEC_TO_TIME and TIME_TO_SEC functions that allow easy addition of the times
but I cant find an equivalent in php. Does any one know of a way that I can
add to times together in php.
