[PHP-DB] FWD: Hey there!!
phey.brI wanted to prove I could amount to something I knew I had to take advantage of this now a weight is lifted off my shoulders you could be living the dreambra href=http://www.aqa.ru/forum/redirect.php?http://home72solutions.net/esubmit/bizopp_main.php/%3Fcimedamp;95ler=facebook.comamp;95baco=google.com;http://www.aqa.ru/forum/redirect.php?http://home72solutions.net/esubmit/bizopp_main.php/%3Fcimedamp;95ler=facebook.comamp;95baco=google.com/abrtalk to you later./p
[PHP-DB] Look what i found...
pwhats up!brit was important for me to prove I could amount to something I was so lucky to have found this it proved that miracles can happen you are definitely cut out for thisbra href=http://powen.home.pl/DanielEvans13.html;http://powen.home.pl/DanielEvans13.html/abrsee you./p
[PHP-DB] Bulk Insert from text file
Hi All, I have bulk data store in text file, which is attached with this email. Could any 1 please help on how to insert using phpMyAdmin?? I tried using below code but getting Error in SQL Syntax: BULK INSERT venue FROM 'c:\venues.txt' WITH ( FIELDTERMINATOR = ',') Any help will be appreciated. Regards, Nasreen
[PHP-DB] Import Excel sheet into SQL
Hi, How can I import Excel sheet into MS-SQL. The data I have saved in excel sheet is in cells, snapshot is attached in this email. I am using sqlmyAdmin. and tried using import but getting error Invalid Count on line1 Help required!!! Nasreen -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Run SQL query when click on OK button of warning message
Hi All, I am printing a _javascript_warning message. On pressing OK button, I want to run an sql query. Below is the way I have tried but sql query is running either press OK or Cancel button on warning message or even refresh the page (F5). Also redirection, when press OK, also not working. Am I using the right approach? Could any 1 please help me to sort this problem. Regards, Nasreen trtd input type="button" DELETE FROM artist where aid = '$id'";mysql_query($sqldel) or die(mysql_error());//header("Location: artist.php");//window.location="http://www.yahoo.com/"?}else{window.location='index.php' }" value="DELETE" /td/tr
[PHP-DB] Create Search engine with multiple form fields
Hi, I have an HTML form which has more then one fields. User can precise its search using one or more input fields E.g GigName,Date, Genre,Venue. The data is coming from 3 tables. Below Query brings one tables record with each and every row of other two tables. Could any one please help me sort out the query. select * FROM gig g, venue v, genre ge WHERE g.gigName LIKE '%.$gig_name.%' OR g.gig_date LIKE '%.$sdate.%' OR ge.name LIKE '%.$genre.%' OR g.ticket_price LIKE '%.$ticket_price1.%' OR g.ticket_price LIKE '%.$ticket_price2.%' OR v.venueName LIKE '%.$vname.%' If I replace OR with AND I dont get any result. Regards Nasreen
[PHP-DB] Help in concatenation
Hi, I need to change PHP embeded in HTML to HTML embeded in PHP as trying to use modularity approach. I'm stuck on below these lines where concatenation is the big issue. I have researched, read but couldnt sort this out after try really hard. Could any one please help me to change this code to HTML embeded in PHP please. Mostly i'm getting confuse where text is written in red I know it is very basic question but this concatenation is confusing me so much. I have spended my whole day in sorting this out but :( 1. a class=?php print($class);? href=?php print($thispage.($y0?(?start=).$y:));??php print($pg);?/a 2. a href=?php print($thispage.($next0?(?start=).$next:));?/a Thank you
[PHP-DB] Navigation Help
Hi, Could any one please help me with Page Navigation. I have done Next and Previous page Navigation but confused on printing page numbers (1,2,3,4) and hyperlink them. Below is the code which i'm halfway on but it only prints 1 with no hyperlink where as I have 11 pages, if i print $noPages. Could you please correct where i'm mistaking. $result = safe_query(select count(*) FROM gig g, venue v WHERE g.gigName LIKE '%.$gig_name.%' ); $noEntries = mysql_num_rows($result); $noPages = ceil($noEntries / $limit); $currentPage = 0; if(isset($_GET['pag']) is_numeric($_GET['pag']) $_GET['pag'] 0 $_GET['pag'] $noPages){ $currentPage = $_GET['pag']; } $start = $currentPage * $pageLimit; $sqlTotal = select * FROM gig g, venue v WHERE g.gigName LIKE '%.$gig_name.%' .$start.,.$limit; for($a = 0; $a $noPages; $a++){ if($currentPage == $a){ echo($a+1); }else{ echo 'a href='.$_SERVER['PHP_SELF'].'?spag='.$a.''.($a+1).'/a'; } if($a $noPages - 1){ echo '-'; } }
[PHP-DB] How to do a Newsletter
Hi, Does any one know a better way of doing Newsletter. I have to run a query and send that data to clients. Regards Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
Re: [PHP-DB] How to do a Newsletter
I have to email it. Basically I have run a query according to user criteria of newsletter and send it via email - Original Message From: Jason Pruim [EMAIL PROTECTED] To: Nasreen Laghari [EMAIL PROTECTED] Cc: php-db@lists.php.net Sent: Thursday, May 1, 2008 5:03:43 PM Subject: Re: [PHP-DB] How to do a Newsletter That's not an awful lot to go off of.. I'm assuming the actual newsletter is already produced probably in a PDF? Are you looking to e-mail it out? Post it to a website? Get e-mail addresses to e-mail it to? Get postal addresses to postal mail it to? More info I think would definitely help. On May 1, 2008, at 11:59 AM, Nasreen Laghari wrote: Hi, Does any one know a better way of doing Newsletter. I have to run a query and send that data to clients. Regards Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 3251 132nd ave Holland, MI, 49424-9337 www.raoset.com [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
[PHP-DB] Why $row is EMPTY
Hi, Why my program is not going in while loop? When I run the same query in SQL cmd, it brings result but here when I print $result gives Resouce ID number means $result has data then why $row is empty. $query = 'SELECT * FROM `gig` LEFT JOIN genre ON gig.genreId=genre.genreId LEFT JOIN venue ON gig.venueID = venue.vid where gig.gigid = '.$gigDetail.' ORDER BY gig.gigid'; $result = mysql_query($query) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { echo Program is in While loop; $g_name = $row[gig.gigName]; $vname = $row[venue.venueName]; $genre = $row[genre.name]; echo(Gig Name: .$g_name); } Regards Nasreen Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
[PHP-DB] Query Criteria
Hi All, I need help in below coding as it is not working. What I'm trying to do here, if $type contains today value then bring all record which has today's date, If $type contains tomorrow bring all tomorrow's record. Do you think below coding is correct? becuase when I run this query I get exception but if I place only one $query and outside of if.. else the same query runs without errors. Thank you for your help Regards $query; $date = date(d/m/y); if($type==today) { $query = SELECT * FROM gig where gig_Date= $date; } else if($type==tomorrow) { $tomorrow = mktime(0, 0, 0, date(m) , date(d)+1, date(Y)); $query = SELECT * FROM gig where gig_Date= $tomorrow; } else if($type==week) { $week = mktime(0, 0, 0, date(m) , date(d)+6, date(Y)); $query = SELECT * FROM gig WHERE g.gig_Date = .$date. OR g.gig_Date =.$week.; } $result = mysql_query($query)or die(mysql_error()); return $result; } Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
[PHP-DB] A very basic PHP question
Hi, I have some confusion with Variables scope. I searched but couldn't figure it out :( The question is: one variable which changes according to if... else statment, how do you change the value of that variable? Actually $query is changing on $type variable so I tried doing using if.. else statment. Please clarify me. function select_entries_quick ($offset=0,$location,$type) { global $limit; $query; $date = date(d/m/y); if (empty($offset)) { $offset = 0; } if($type==today) { $query = SELECT * FROM gig where gig_Date= $date; } else if($type==tomorrow) { $tomorrow = mktime(0, 0, 0, date(m) , date(d)+1, date(Y)); $query = SELECT * FROM gig where gig_Date= $tomorrow; } else if($type==week) { $week = mktime(0, 0, 0, date(m) , date(d)+6, date(Y)); $query = SELECT * FROM gig WHERE g.gig_Date = .$date. OR g.gig_Date =.$week.; } $result = safe_query($query); return $result; } - Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now.
[PHP-DB] Select query with Forein key Relation
Hi, I have a table which contains 2 foreign key relation columns. I'm trying to get all columns from main table as well as all column from those 2 foreign key relation tables. The query i'm using is : select * from gig where gig.gigid = $gigDetail LEFT JOIN genre ON gig.genreId=genre.genreId LEFT JOIN venue ON gig.venueID = venue.vid ORDER BY gig.gigid; is this query OK? I know how to get value from gig table colums but how could i get value of columns from venue table? Regards Nasreen Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
[PHP-DB] Dynamic Navigation with Limit
Hi, I'm trying to put limit of data fetch as well as dynamic navigation. Below is the try which I did but something is going wrong as $screen value is not increasing so when I click on NEXt button it refreshes the same page and Previous button does even show. Could you kindly have look on the coding and help me where i'm mistaking. Regards Nasreen ?php $rows_per_page = 10; $i=0; if (!isset($screen)) $screen=0; $start = $screen * $rows_per_page; $sql = SELECT * FROM gig g, venue v WHERE g.gigName LIKE '%.$gig_name.%' OR g.gig_date LIKE '%.$sdate.%' OR g.genre LIKE '%.$genre.%' OR g.ticket_price LIKE '%.$ticket_price1.%' OR g.ticket_price LIKE '%.$ticket_price2.%' OR v.venueName LIKE '%.$vname.%' OR v.vCity LIKE '%.$city.%' order by gig_Date LIMIT $start,$rows_per_page; $result = mysql_query($sql) or die(Query error: . mysql_error()); $num_rows = mysql_num_rows($result) ; $pages = ceil($num_rows / $rows_per_page); $j=0; while ($row = mysql_fetch_array($result)) { global $limit; $j = $j+1; $gigid = $row['gigid']; $gigname = $row['gigName']; $sdate = $row['gig_fdate']; $fdate =$row['gig_tdate']; $genre = $row['genre']; $ticket_price = $row['ticket_price']; $gigdetail= $gigid; echo(br $gigid a href='detail.php?gigDetail=$gigid' $gigname/a); } } if ($screen 0) { print a href=\view.php?$screen=.( $screen+1).\lt;lt;Previous Entries/a nbsp; ; } else if ($screen $pages) { $screen = $screen+1; print a href=\view.php?screen=.($screen).\Next Entriesgt;gt;/a nbsp; ; } ? You rock. That's why Blockbuster's offering you one month of Blockbuster Total Access, No Cost. http://tc.deals.yahoo.com/tc/blockbuster/text5.com
[PHP-DB] SELECT query with multiple WHERE Clause
Hi All, Thank you for increasing my knowledge about PHP/MYSQL. I am creating a SEARCH, by only using one table. The search form is same as Inserting item (search has form of all fields in table ), difference is SEARCH page doesnt have validation . Therefore user can enter information in any of field. I would like to know how to write a SELECT query which has multiple where clause with OR operator. shall we write: $query = mysql_query(SELECT * from gig WHERE Name='$name' || WHERE gig_fdate='$sdate'); OR $query = mysql_query(SELECT * from gig WHERE gigName='$gig_name' OR WHERE gig_fdate='$sdate'); OR $query = mysql_query(SELECT * from gig WHERE gigName='$gig_name' || gig_fdate='$sdate'); Regards Nasreen Looking for last minute shopping deals? Find them fast with Yahoo! Search. http://tools.search.yahoo.com/newsearch/category.php?category=shopping
[PHP-DB] Password Reset
Hi, I have encrypted password in database and I encrypted using MD5(). As it is a one-way Hash so I cant get password back to original text !!! What encrypting technique I used to encrypt password so if user forget, I can decrypt password and email it. Regards Nasreen Looking for last minute shopping deals? Find them fast with Yahoo! Search. http://tools.search.yahoo.com/newsearch/category.php?category=shopping
[PHP-DB] INSERT query with Primary and foreign key
Hi, I need help to insert date into two tables when tables have primary and foreign key relationship using php. I tried simple INSERT query but foreign key colum is storing NULL. Regards Nasreen Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
[PHP-DB] Uploading Image using PHP and mySQL
Hi All, First of all A very big thank you to all of you for solving my Password() encryption problem. Now I'm stuck on new problem which is image not uploading. I'm using the following code. Regards Nasreen ?php include (header.php); include (dbconnect.php); $submit=$_REQUEST[submit] ; $aname=$_REQUEST[aname]; $aboutu=$_REQUEST[urself]; $file=$_REQUEST[file]; $url_provided = $_REQUEST[url_provided]; echo($aname); if ($submit == Sign!) { function getImageFile($file){ $takeFile = fopen($file, r); $file = fread($takeFile, filesize($file)); fclose($takeFile); return $file; } function getfileType( $name ){ $name = explode(., $name); $name = array_reverse($name); $name = $name[0]; return $name; } $allowedImageTypes = array(gif,jpg,png); if(empty($_FILES['image_file']['tmp_name'])){ echo File not uploaded; } else { $fileType = $_FILES['file']['name']; if(in_array(getfileType($fileType), $allowedImageTypes)){ $fileContent = getImageFile($_FILES['file']['tmp_name']); $uploadedImage = chunk_split(base64_encode($fileContent)); $query = INSERT INTO artist (name,about_u,imgdata, profile_url) VALUES('$aname','$aboutu','$uploadedImage','$url_provided'); $result = mysql_query($query); if(mysql_affected_rows() 0){ echo Image has been inserted succesfully; } else { echo Image can not be inserted check your submission; } } else { echo This is not a true image type; } } } ? div align=center class=style1 h1Artist Profile Form/h1 pnbsp;/p form action=artist.php method=post enctype=multipart/form-data table width=397 border=0 tr th width=221 scope=colh4 align=rightName:/h4/th th width=166 scope=coldiv align=left input name=aname type=text id=username3 /div/th /tr tr th scope=rowdiv align=rightAbout Yourself /div/th tddiv align=left textarea name=urself/textarea /div/td /tr tr th scope=rowdiv align=right Profile export from myspace/face book /div/th tddiv align=left input name=url_provided type=text id=repass /div/td /tr tr th scope=rowdiv align=rightUpload Photo /div/th tddiv align=left input type=file name=file /div/td /tr tr th scope=rownbsp;/th td input type=submit name=submit value=Sign! input type=reset name=Reset value=Reset/td /tr /table /form pstrong/strong/p /div Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ
[PHP-DB] Uploading Image using PHP and mySQL
Hi All, First of all A very big thank you to all of you for solving my Password() encryption problem. Now I'm stuck on new problem which is image not uploading. I'm using the following code. Regards Nasreen ?php include (header.php); include (dbconnect.php); $submit=$_REQUEST[submit] ; $aname=$_REQUEST[aname]; $aboutu=$_REQUEST[urself]; $file=$_REQUEST[file]; $url_provided = $_REQUEST[url_provided]; echo($aname); if ($submit == Sign!) { function getImageFile($file){ $takeFile = fopen($file, r); $file = fread($takeFile, filesize($file)); fclose($takeFile); return $file; } function getfileType( $name ){ $name = explode(., $name); $name = array_reverse($name); $name = $name[0]; return $name; } $allowedImageTypes = array(gif,jpg,png); if(empty($_FILES['image_file']['tmp_name'])){ echo File not uploaded; } else { $fileType = $_FILES['file']['name']; if(in_array(getfileType($fileType), $allowedImageTypes)){ $fileContent = getImageFile($_FILES['file']['tmp_name']); $uploadedImage = chunk_split(base64_encode($fileContent)); $query = INSERT INTO artist (name,about_u,imgdata, profile_url) VALUES('$aname','$aboutu','$uploadedImage','$url_provided'); $result = mysql_query($query); if(mysql_affected_rows() 0){ echo Image has been inserted succesfully; } else { echo Image can not be inserted check your submission; } } else { echo This is not a true image type; } } } ? div align=center class=style1 h1Artist Profile Form/h1 pnbsp;/p form action=artist.php method=post enctype=multipart/form-data table width=397 border=0 tr th width=221 scope=colh4 align=rightName:/h4/th th width=166 scope=coldiv align=left input name=aname type=text id=username3 /div/th /tr tr th scope=rowdiv align=rightAbout Yourself /div/th tddiv align=left textarea name=urself/textarea /div/td /tr tr th scope=rowdiv align=right Profile export from myspace/face book /div/th tddiv align=left input name=url_provided type=text id=repass /div/td /tr tr th scope=rowdiv align=rightUpload Photo /div/th tddiv align=left input type=file name=file /div/td /tr tr th scope=rownbsp;/th td input type=submit name=submit value=Sign! input type=reset name=Reset value=Reset/td /tr /table /form pstrong/strong/p /div Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. Never miss a thing. Make Yahoo your home page. http://www.yahoo.com/r/hs
[PHP-DB] Password decryption
Hi, I'm junior in PHP and stuck on Encryption. I have encrypted password using SQL : $query = insert into user (userid,password,) values ('$username',Password('$pass'));; Which is working perfect. Now I'm working on Login page where I have to compare passwords.. As password in database is encrypted so I need to decrypt it back for compression. I have tried the flowing but not working. if ($pwd != Password($info['password'])) { echo(-); //header(Location: abuse.php); } and if ($pwd != $info(Password(['password'])) { echo(-); //header(Location: abuse.php); } Could any one please help.. Thank you Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ