[PHP-DB] Re: Passing multiple form variable in PHP
Cheers - query Answered
"Stephen Rhodes" <[EMAIL PROTECTED]> wrote in message
news:20021112162930.65021.qmail@;pb1.pair.com...
> HELLO - this is probably a simple problem !!
>
> Wanting to use in a html form and pass multiple
value
> into a php variable but does
> not work. I only get a single value. Can you tell me what I am doing wrong
> ?
>
> Does the multiple value get passed correctly in php
>
> if ($task=="check")
> {
> printf("$icon");
> }
> else
> {
> print '
> Multiple Check:
>
> False
> True
>
>';
> }
>
> Thanks
> Steve R
>
>
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[PHP-DB] Passing multiple form variable in PHP
HELLO - this is probably a simple problem !!
Wanting to use in a html form and pass multiple value
into a php variable but does
not work. I only get a single value. Can you tell me what I am doing wrong
?
Does the multiple value get passed correctly in php
if ($task=="check")
{
printf("$icon");
}
else
{
print '
Multiple Check:
False
True
';
}
Thanks
Steve R
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[PHP-DB] Using a variable as a variable name
Hi I am wanting to use the value in a variable as a variable name. I know it is possible but do not remember how to do it - what function to call. Example $section1 = "SECTION 1"; $section2 = "SECTION 2"; // I want to have a for loop that will call these variables. eg for ($i=1;$i<3;$i++) //Now I want to call $section1, and $section2 by using $i which will first equal 1 and then 2. Cheers Steve -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: intercative selection menu
You could have if statements for every option.
May be better if you have a for loop for some of the options -- SEE BELOW.
e.g
:
%s",$i);
}
printf(" 1916");
printf(" volta");
printf(" scatt11");
?>
Cheers
Steve
"Walid Dib" <[EMAIL PROTECTED]> wrote in message
6EDD9DC298BF9C48AC3EF66EA92596BC0463AF25@frbucmsx03medge">news:6EDD9DC298BF9C48AC3EF66EA92596BC0463AF25@frbucmsx03medge...
> Hello, I need to get back the present value in the data base and to
> post(show) it in the menu of selection. somebody has an idea??
>
> Thank you in advance.
> :
>
>1904
>1905
>1906
>1907
>1908
>1909
>1910
>1911
>1916
>volta
>scatt11
>
>
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[PHP-DB] Re: how can i get field-informationof a table?
use the function mysql_list_fields in url http://www.php.net/manual/en/function.mysql-list-fields.php Cheers Steve "Hermann Otteneder" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > hi, > i'm using a mssql-database. now i want update a record with the information > given in a form. i want use the following sql statement: > $SQL = "update set '' = > 'HTTP_POST_VARS[$index]' WHERE PKID = 'HTTP_POST_VARS[0]'"; > mssql_query($SQL); > > my problem is i cannot find a function which gives me an array of the fields > of a table -> > > I guess this is for sure very simple - haves anyone the solution? i would be > very thankfuly for this! > > lg hermann > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Working with dates
Forget my last email. Similar but before I told you how to do it from todays
date. You need to parse the $effdate. Below would only work for 1 number
months. (i.e not Oct,Nov,Dec)
Find where / occurs in the string and you will be laughing. Once you have
those numbers in $day,$month,$year you will be able to use the bottom two
lines of below to add three months on.
$effdate= "1/15/2002";
$day = substr($effdate,2,2);
$month = substr($effdate,0,1);
$year = substr($effdate,5,4);
$threeMonthsAhead = mktime(0,0,0,$month+3,$day,$year);
$dateInYourForm = date("m/d/Y",$threeMonthsAhead);
Cheers
Steve
"Manuel" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>
> Can anybody help me with this?
>
> How do you take a known date and add three month to it?
>
> Example:
>
> $effdate= "1/15/2002"
>
>
>
> -
> Do You Yahoo!?
> LAUNCH - Your Yahoo! Music Experience
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[PHP-DB] Re: output problem
When you write the SQL statement write it as:
select count(user) AS count from log_request where date='$date' and
status = 'open'
(note i have added 'AS count' in there so it stores the value in
'count')
Now when you output the result write it as $line->count
Cheers
Steve
"Chris Grigor" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
Howdi Alll
some of you might laugh at this but I cant get this to work
Im doing a count on a field and want to diplay the result here is an
example...
");
print (" $line->user\n");
print ("");
}
?>
what am I missing as it returns no value at all from $line->user, should I
be
doing this differently??
Thankyou
Chris
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[PHP-DB] Re: Working with dates
Use this: ($dateInYourForm gives the date in three months time in the form
you gave below.
$threeMonths = mktime(0,0,0,date("m")+3,date("d"),date("Y"));
$dateInYourForm = date("d/m/Y",$threeMonths);
Cheers
Steve
"Manuel" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
>
> Can anybody help me with this?
>
> How do you take a known date and add three month to it?
>
> Example:
>
> $effdate= "1/15/2002"
>
>
>
> -
> Do You Yahoo!?
> LAUNCH - Your Yahoo! Music Experience
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[PHP-DB] Using the ALTER statement
When i use the alter statement in the PHP function mysql_db_query( ) I get a permission error. I can CREATE tables, DROP them etc so there are no permission problems as far as I know. Can anyone help ? Steve -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
