[PHP-DB] Query syntax error?

2011-01-13 Thread Harvey
Hello,

I have a query on a page that used to work fine, but is now generating an
error.

I assume that the version of php or mysql was updated on the webhost server
or something like that?

Here is the query:

select count(places_data.place_id) as areacount, boroughs.borough_name as
boroname, area.area_name as areaname, area.area_id as areaid
from places_data a 
inner join boroughs b on a.area_fid = b.area_id
inner join area c on c.borough_fid = b.borough_id
where places_data.on_off_fid = 2
 . $cat_query . 
group by c.area_name 
order by b.borough_name ASC, c.area_name ASC

And here is the error message:

Unknown column 'places_data.place_id' in 'field list'

But place_id is a field in places_data table.

Any ideas?

Thanks!

Harvey


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RE: [PHP-DB] Query syntax error?

2011-01-13 Thread Harvey
Thanks, I got it working now, had to use the a/b/c thing a few times


-Original Message-
From: jose [mailto:jojap...@gmail.com] 
Sent: Thursday, January 13, 2011 9:52 AM
Cc: php-db@lists.php.net
Subject: Re: [PHP-DB] Query syntax error?

you have renamed places_data table to 'a'

2011/1/13 Harvey har...@harveyk.com:
 Hello,

 I have a query on a page that used to work fine, but is now generating an
 error.

 I assume that the version of php or mysql was updated on the webhost
server
 or something like that?

 Here is the query:

 select count(places_data.place_id) as areacount, boroughs.borough_name as
 boroname, area.area_name as areaname, area.area_id as areaid
 from places_data a
 inner join boroughs b on a.area_fid = b.area_id
 inner join area c on c.borough_fid = b.borough_id
 where places_data.on_off_fid = 2
  . $cat_query . 
 group by c.area_name
 order by b.borough_name ASC, c.area_name ASC

 And here is the error message:

 Unknown column 'places_data.place_id' in 'field list'

 But place_id is a field in places_data table.

 Any ideas?

 Thanks!

 Harvey


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Re: [PHP-DB] Hiding Admin Link

2009-05-01 Thread harvey

You can start by creating a login system
http://www.phpeasystep.com/workshopview.php?id=6
Then you can do an if/then statement to show the link only to people who 
have logged in...



On 4/30/2009 10:29 PM, Joey Hendricks wrote:

Hello,
I am very new at PHP so I will try to explain my question the best I can. I was wondering 
if there was a way to have a link show only to the owner of the site? Like having a 
Admin link for editing posts, but hidden to all users except the owner. Thank 
you very much for your time!!
  


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Re: [PHP-DB] php generators

2009-04-28 Thread harvey
Dreamweaver has some php generation. That's how I started to learn. I am 
not an expert by any means, and I am sure that experts will not like the 
code, but for a beginner, I found it totally fine



On 4/28/2009 12:40 PM, conor mahaney wrote:

Hello Everyone,

I am a beginner with PHP and Mysql and have dived into a project that may be to 
much for me right now.  I am still learning php and do not have enough 
knowledge to accomplish what I am trying to.

I have been looking into PHP code generators and was wondering if anyone has 
any thoughts or suggestions, also if anyone knows of any good resources for 
learning

 

Thanks 

 


_
Rediscover HotmailĀ®: Get e-mail storage that grows with you. 
http://windowslive.com/RediscoverHotmail?ocid=TXT_TAGLM_WL_HM_Rediscover_Storage2_042009
  


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Re: [PHP-DB] currency formating

2001-12-31 Thread Billy Harvey

On Tue, 2002-01-01 at 00:08, Webmaster wrote:
 Yea i have read that but did not think it was what i needed considering it
 is for an automated billing system and the customer may not like it if they
 are charged and extra .50 cents or so every month. Their has got to me
 another alternative.

Well, round wouldn't do that, but what you're looking for is
number_format().

Billy


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