Ron Gallant [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I am querying a list with a date field. I want to order the list by the
date field and only show each days date once with the other fields
showing.
(row 1) 2001-08-19 - some text here.
(row 2)more text under same date. My date does
not
show.
(row 3) 2001-08-20 - Lots of text today.
(row 4)Even more text here today. My date does
not
show.
(row 5)Yes more text, date not showing.
This seems to be a recurrent question in various guises;
The idea is simple: sort by date (so all equal dates are together),
then keep a temporary variable set to the last-seen date. When the
date changes, output a new date value.
== example.php
?php
mysql_connect(host, user, pwd)
or die(Error connecting: .mysql_error());
// return the 20 most recent items
$query =
SELECT mydate,mytext
.FROM table
.ORDER BY mydate DESC
.LIMIT 20;
$result = mysql_db_query(dbase, $query)
or die(Error querying: .mysql_error());
// show results in a table
$lastdate = ;
echo \ntable;
while ($row = mysql_fetch_array($result)) {
extract($row);
if ($lastdate == $mydate)
$t = ;
else
$t = $lastdate = $mydate;
echo \n\ttrtd$t/tdtd$mytext/td/tr;
}
echo \n\table;
?
===
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