Re: [PHP-DB] SQL question!

2004-05-03 Thread Larry E . Ullman
I have these tables.
Users ( id,name,etc )
Coments : ( id , comment )
How do I do this kind of query:
I thought in one thing like this but I cant figure it out.
Example: Select * from users order by id desc in (select count (id) 
from
comments)
Expected result:
List of users:
* User1
  See comments ( 32 comment in database )

* User2
  See coments (13 comments in database )
You need to add a user_id column to comments, which records what user 
entered each comment. Then you can do
SELECT u.name, COUNT(c.id) FROM users u, comments c WHERE 
u.id=c.user_id GROUP BY (c.user_id)

The syntax may not be exactly right but that's the basic idea. Adding a 
user ID foreign key to the comments table is the important part.

Hope that helps,
Larry
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[PHP-DB] SQL question!

2004-05-03 Thread Bruno Braga
Hey.

 

I have these tables.

 

Users ( id,name,etc )

Coments : ( id , comment )

 

 

How do I do this kind of query:

I thought in one thing like this but I cant figure it out.

Example: Select * from users order by id desc in (select count (id) from
comments)

 

 

Expected result:

 

List of users:

 

* User1

  See comments ( 32 comment in database )

 

* User2

  See coments (13 comments in database )

 

*   etc.

 

 

thanks in advanced.

Bruno



[PHP-DB] SQL question

2003-12-11 Thread Constantin Brinzoi
I know it is  possible to search a database like this:

SELECT * FROM x_table WHERE name=%part_of_name%

but I don't know for sure the correct command.

Could you tell me the right syntax?

TIA
Aurel.

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Re: [PHP-DB] SQL question

2003-12-11 Thread Muhammed Mamedov
It should be as follows:
SELECT * FROM x_table WHERE name Like = %part_of_name%

Hope this helps,
M.Mamedov

- Original Message - 
From: Constantin Brinzoi [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, December 11, 2003 1:51 PM
Subject: [PHP-DB] SQL question


 I know it is  possible to search a database like this:
 
 SELECT * FROM x_table WHERE name=%part_of_name%
 
 but I don't know for sure the correct command.
 
 Could you tell me the right syntax?
 
 TIA
 Aurel.
 
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RE: [PHP-DB] SQL question

2003-12-11 Thread brettking
try 

SELECT * FROM x_table WHERE name LIKE %part_of_name%

-Original Message-
From: Constantin Brinzoi [mailto:[EMAIL PROTECTED]
Sent: 11 December 2003 11:52
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SQL question


I know it is  possible to search a database like this:

SELECT * FROM x_table WHERE name=%part_of_name%

but I don't know for sure the correct command.

Could you tell me the right syntax?

TIA
Aurel.

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Email has been scanned for viruses by www.emf-systems.com

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Re: [PHP-DB] SQL question

2003-12-11 Thread Muhammed Mamedov
I am sorry without equal = sign

SELECT * FROM x_table WHERE name Like %part_of_name%

there are actually three ways to do this:
%part_of_name%  part_of_name appears anywhere
%part_of_namepart_of_name appears at the end
art_of_name%   part_of_name appears at the begining
 
M.Mamedov


- Original Message - 
From: Muhammed Mamedov [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, December 11, 2003 2:00 PM
Subject: Re: [PHP-DB] SQL question


 It should be as follows:
 SELECT * FROM x_table WHERE name Like = %part_of_name%
 
 Hope this helps,
 M.Mamedov
 
 - Original Message - 
 From: Constantin Brinzoi [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Thursday, December 11, 2003 1:51 PM
 Subject: [PHP-DB] SQL question
 
 
  I know it is  possible to search a database like this:
  
  SELECT * FROM x_table WHERE name=%part_of_name%
  
  but I don't know for sure the correct command.
  
  Could you tell me the right syntax?
  
  TIA
  Aurel.
  
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  To unsubscribe, visit: http://www.php.net/unsub.php
  
 
 
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[PHP-DB] SQL question!

2002-06-27 Thread Bruno Gimenes Pereti

Hi,

I need a sql query to join multiple lines into only one line. Ok, I wouldn´t
understand this question so I´ll give an example (I´m doing it on mysql but
I need it to mssql). Supose I have 3 tables:

mysql select * from test1;
++---+
| id| nome   |
++---+
|  1| Bruno  |
|  2| Jorge   |
++---+

mysql select * from test2;
++-+---+
| id| request   | value |
++-+---+
|  1|   1  | 100,00  |
|  1|   2  | Mercedes  |
|  2|   1  | 50,00|
|  2|   3  | Sparc Sun |
++-+---+

mysql select * from test3;
++--+
| id| value|
++--+
|  1| money  |
|  2| car   |
|  3| computer |
++--+

test1.id - test2.id
test3.id - test2.request


When I execute:

select test1.nome, test3.value, test2.value
from test1, test2, test3
where test1.id = test2.id AND test2.request = test3.id

I get:

+---+--+---+
| nome| value   | value |
+---+--+---+
| Bruno  | money  | 100,00  |
| Bruno  | car   | Mercedes  |
| Jorge   | money | 50,00|
| Jorge   | computer | Sparc Sun |
+---+--+---+

But I need this result:

+---+--+---++
| nome| money | car| computer|
+---+--+---++
| Bruno  | 100,00 | Mercedes  | NULL|
| Jorge   | 50,00   | NULL   | Sparc Sun  |
+---+--+---++

Is it possible in Microsoft SQL Server? I´d like to know if it can be
executed on mysql and, if not, if there is some way to do it in mysql.

Sorry for the big e-mail but it´s something I really need to know.

Thank´s

Bruno Gimenes Pereti.


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[PHP-DB] SQL Question

2002-03-13 Thread Kevin Diffily

Hello,

I have a simple SQL Question.  I would like to take the column city in database 
addresses and find out which cities are available in it.  In other words if the 
following values are in there:

city
El Paso
Burlington
New York
New York
El Paso
Burlington

I would like it to return
El Paso
New York
Burlington

I know that it would something like
SELECT `city`
FROM `addresses` 
WHERE ??


Thanks

Kevin Diffily
InterNetWorkingSolutions
Enterprise Class Solutions for All Enterprises

318 Last Road, Cabot, VT 05647 USA
VOICE: 1.866.inetws.net (Toll Free)
FAX:   1.888.726.9030?  (Toll Free)

Sales:  [EMAIL PROTECTED]
General Information:[EMAIL PROTECTED]
Website Hosting:[EMAIL PROTECTED]
Systems Administration Services:   [EMAIL PROTECTED]
Technical Support  Training Services:  [EMAIL PROTECTED]
Shop For it On Amazon:http://kevin.inetws.net/amazon
Instant Messaging Username:
AIM, IRC, Jabber, MSN, Yahoo:  inetwsnet
ICQ: 120778694




RE: [PHP-DB] SQL Question

2002-03-13 Thread Rick Emery

SELECT DISTINCT city FROM addresses;

-Original Message-
From: Kevin Diffily [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 13, 2002 1:05 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SQL Question


Hello,

I have a simple SQL Question.  I would like to take the column city in
database addresses and find out which cities are available in it.  In other
words if the following values are in there:

city
El Paso
Burlington
New York
New York
El Paso
Burlington

I would like it to return
El Paso
New York
Burlington

I know that it would something like
SELECT `city`
FROM `addresses` 
WHERE ??


Thanks

Kevin Diffily
InterNetWorkingSolutions
Enterprise Class Solutions for All Enterprises

318 Last Road, Cabot, VT 05647 USA
VOICE: 1.866.inetws.net (Toll Free)
FAX:   1.888.726.9030?  (Toll Free)

Sales:  [EMAIL PROTECTED]
General Information:[EMAIL PROTECTED]
Website Hosting:[EMAIL PROTECTED]
Systems Administration Services:   [EMAIL PROTECTED]
Technical Support  Training Services:  [EMAIL PROTECTED]
Shop For it On Amazon:http://kevin.inetws.net/amazon
Instant Messaging Username:
AIM, IRC, Jabber, MSN, Yahoo:  inetwsnet
ICQ: 120778694


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RE: [PHP-DB] SQL Question

2002-03-13 Thread Gurhan Ozen

you can do it by using distinct function ..
Do:
SELECT DISTINCT(city) FROM addresses;


Gurhan


-Original Message-
From: Kevin Diffily [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 13, 2002 2:05 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] SQL Question


Hello,

I have a simple SQL Question.  I would like to take the column city in
database addresses and find out which cities are available in it.  In other
words if the following values are in there:

city
El Paso
Burlington
New York
New York
El Paso
Burlington

I would like it to return
El Paso
New York
Burlington

I know that it would something like
SELECT `city`
FROM `addresses`
WHERE ??


Thanks

Kevin Diffily
InterNetWorkingSolutions
Enterprise Class Solutions for All Enterprises

318 Last Road, Cabot, VT 05647 USA
VOICE: 1.866.inetws.net (Toll Free)
FAX:   1.888.726.9030?  (Toll Free)

Sales:  [EMAIL PROTECTED]
General Information:[EMAIL PROTECTED]
Website Hosting:[EMAIL PROTECTED]
Systems Administration Services:   [EMAIL PROTECTED]
Technical Support  Training Services:  [EMAIL PROTECTED]
Shop For it On Amazon:http://kevin.inetws.net/amazon
Instant Messaging Username:
AIM, IRC, Jabber, MSN, Yahoo:  inetwsnet
ICQ: 120778694



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