Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Allowee 
Hi,

Where do you get $info2 from?
I only see $info in this function.

.: Allowee

 function scan_dir($dir)
 {
 $info = New mphp3(2);

 $handle = @opendir($dir);
 while ($file = @readdir ($handle))
 {
 if (eregi(^\.{1,2}$,$file))
 {
 continue;
 }

 if(is_dir($dir.$file))
 {
 scan_dir($dir.$file./);
 }
 else
 {
 $info-load(/.$dir.$file);

 $query =insert into mp3 (
   file,
   path,
   artist,
   title,
   album)
 values (
  '$info2-filename',
  '$dir',
  '$info2-v2_artist',
  '$info2-v2_title',
  '$info2-v2_album');;

 mysql_query($query);
 }
 }
 @closedir($handle);
 }
 scan_dir(mp3/);
 ?

 but all it does is to put the path ($dir) into the database. everything
 else is ignored. an error does not occur. since the simple demo works
 fine i think its a problem with the validity of variables.
 i'm new to php, so could anybody give me a hint on what mightbe wrong
 with my code please?

 thanx a lot


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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Ole Hornauer 
hi allowee,

sorry, this was not meant to be. $info2 is supposed to be $info. my 
fault. but that is not the actual problem.

 Hi,
 
 Where do you get $info2 from?
 I only see $info in this function.
 
 .: Allowee
 
  function scan_dir($dir)
  {
  $info = New mphp3(2);
 
  $handle = @opendir($dir);
  while ($file = @readdir ($handle))
  {
  if (eregi(^\.{1,2}$,$file))
  {
  continue;
  }
 
  if(is_dir($dir.$file))
  {
  scan_dir($dir.$file./);
  }
  else
  {
  $info-load(/.$dir.$file);
 
  $query =insert into mp3 (
file,
path,
artist,
title,
album)
  values (
   '$info2-filename',
   '$dir',
   '$info2-v2_artist',
   '$info2-v2_title',
   '$info2-v2_album');;
 
  mysql_query($query);
  }
  }
  @closedir($handle);
  }
  scan_dir(mp3/);
  ?
 
  but all it does is to put the path ($dir) into the database. everything
  else is ignored. an error does not occur. since the simple demo works

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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Allowee 
hmmm,
maybe this code..

$info-load(/.$dir.$file);

if $dir = mp3s and $file = test.mp3
then it will load '/mp3s/test.mp3'

you got that directory?
I've seen the class and you are hiding the fopen error message, which could be 
the problem.

.: Allowee

On Saturday 07 June 2003 11:11, Ole Hornauer wrote:
 hi allowee,

 sorry, this was not meant to be. $info2 is supposed to be $info. my
 fault. but that is not the actual problem.

  Hi,
 
  Where do you get $info2 from?
  I only see $info in this function.
 
  .: Allowee
 
   function scan_dir($dir)
   {
   $info = New mphp3(2);
  
   $handle = @opendir($dir);
   while ($file = @readdir ($handle))
   {
   if (eregi(^\.{1,2}$,$file))
   {
   continue;
   }
  
   if(is_dir($dir.$file))
   {
   scan_dir($dir.$file./);
   }
   else
   {
   $info-load(/.$dir.$file);
  
   $query =insert into mp3 (
 file,
 path,
 artist,
 title,
 album)
   values (
'$info2-filename',
'$dir',
'$info2-v2_artist',
'$info2-v2_title',
'$info2-v2_album');;
  
   mysql_query($query);
   }
   }
   @closedir($handle);
   }
   scan_dir(mp3/);
   ?
  
   but all it does is to put the path ($dir) into the database. everything
   else is ignored. an error does not occur. since the simple demo works


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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Ruprecht Helms 
Hi,

 Where do you get $info2 from?
 I only see $info in this function.

I guess that the $info-values are formfieldvalues.
$info-[db-field] is normaly used within a whileloop for
outputing a select-statement.

In the case of formfieldvalues you can use $formfieldname.

 .: Allowee

  function scan_dir($dir)
...
  $query =insert into mp3 (
file,
path,
artist,
title,
album)
  values (
   '$info2-filename',
   '$dir',
   '$info2-v2_artist',
   '$info2-v2_title',
   '$info2-v2_album');;
 
  mysql_query($query);
...

Regards,
Ruprecht

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Tel./Fax  +49[0]7621 16 99 16
email:  [EMAIL PROTECTED]
Homep.http://www.rheyn.de

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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Allowee 
On Saturday 07 June 2003 11:20, Allowee wrote:
 hmmm,
 maybe this code..

 $info-load(/.$dir.$file);

 if $dir = mp3s and $file = test.mp3
 then it will load '/mp3s/test.mp3'

 you got that directory?
 I've seen the class and you are hiding the fopen error message, which could
 be the problem.

 .: Allowee


hmmm.
that won't work..

you can try
$info-load(./.$dir./.$file);

or simple..
$info-load($dir./.$file);

.: Allowee

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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Ole Hornauer 
well, you are right. the dir '/mp3' does not exist. 'mp3' is a subdir 
from my htdocs dir. so i think the right path should be 
'mp3/someartist/somesong', right?
i fixed that, but the original problem is still the same :(

 hmmm,
 maybe this code..
 
 $info-load(/.$dir.$file);
 
 if $dir = mp3s and $file = test.mp3
 then it will load '/mp3s/test.mp3'
 
 you got that directory?
 I've seen the class and you are hiding the fopen error message, which could be 
 the problem.
 
 .: Allowee
 
 On Saturday 07 June 2003 11:11, Ole Hornauer wrote:
  hi allowee,
 
  sorry, this was not meant to be. $info2 is supposed to be $info. my
  fault. but that is not the actual problem.
 
   Hi,
  
   Where do you get $info2 from?
   I only see $info in this function.
  
   .: Allowee
  
function scan_dir($dir)
{
$info = New mphp3(2);
   
$handle = @opendir($dir);
while ($file = @readdir ($handle))
{
if (eregi(^\.{1,2}$,$file))
{
continue;
}
   
if(is_dir($dir.$file))
{
scan_dir($dir.$file./);
}
else
{
$info-load(/.$dir.$file);
   
$query =insert into mp3 (
  file,
  path,

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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Ole Hornauer 
moin,

sorry, my php-knowledge is not the best.
what do you mean with formfieldvalues?
i think $info-value is used to get the id3-tag info from the class, 
right? this worked for me in a more simple way without the recursive 
scan:

?
  include(mphp3.php);
  $info = New mphp3(2);

  mysql_connect(192.168.100.12,user,password);
  mysql_select_db(music);

  $info-load(test.mp3);

  $abfrage =insert into mp3 (
  file,
  artist,
  title,
  album)
   values (
 '$info-filename',
 '$info-v2_artist',
 '$info-v2_title',
 '$info-v2_album');;
  mysql_query($abfrage);
?

 Hi,
 
  Where do you get $info2 from?
  I only see $info in this function.
 
 I guess that the $info-values are formfieldvalues.
 $info-[db-field] is normaly used within a whileloop for
 outputing a select-statement.
 
 In the case of formfieldvalues you can use $formfieldname.
 
  .: Allowee
 
   function scan_dir($dir)
 ...
   $query =insert into mp3 (
 file,
 path,
 artist,
 title,
 album)
   values (
'$info2-filename',
'$dir',
'$info2-v2_artist',
'$info2-v2_title',
'$info2-v2_album');;
  
   mysql_query($query);
 ...
 
 Regards,
 Ruprecht
 
 --
 Ruprecht Helms IT-Service und Softwareentwicklung
 
 Tel./Fax  +49[0]7621 16 99 16
 email:  [EMAIL PROTECTED]
 Homep.http://www.rheyn.de
 

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