Re: [PHP] Strange Numeric Conversion...
trim will not work, try something like: $id = preg_replace(/^0+(.*)$/,//1,$id); instead Monty wrote: I tried removing the zeros, but, I get the same result: $id = 11; $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ??? This didn't work either: $id = 11; settype($id, 'string'); $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ??? No matter what I do, $id=11 is seen as 9. Only way is to pass the number without the zeros ($id=11), but, because this data is being read from a database, I can't change the format because PHP seems to be converting it immediately to a 9 instead of reading it as 11 or even 11. If PHP sees this as an octal, then why does gettype(11) = INTEGER? This makes no sense. Monty. From: [EMAIL PROTECTED] (Jay Blanchard) Newsgroups: php.general Date: Fri, 2 Apr 2004 15:38:03 -0600 To: Monty [EMAIL PROTECTED], [EMAIL PROTECTED] Subject: RE: [PHP] Strange Numeric Conversion... [snip] Why is this happening??? $id = 11; echo $id; // Displays: 9 $id = 11; echo $id; // Displays: 11 How do I make the first number (00011) display as 11? Why is it showing 9? [/snip] First of all you have naked numbers. The first one, 11, looks like a binary number (which actually should be 3). You are going to have to trim the leading zero's from the number to have it display as 11. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
sry... it's \\1 instead of //1 ... guess i had one to many beers :) Red Wingate wrote: trim will not work, try something like: $id = preg_replace(/^0+(.*)$/,//1,$id); instead Monty wrote: I tried removing the zeros, but, I get the same result: $id = 11; $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ??? This didn't work either: $id = 11; settype($id, 'string'); $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ??? No matter what I do, $id=11 is seen as 9. Only way is to pass the number without the zeros ($id=11), but, because this data is being read from a database, I can't change the format because PHP seems to be converting it immediately to a 9 instead of reading it as 11 or even 11. If PHP sees this as an octal, then why does gettype(11) = INTEGER? This makes no sense. Monty. From: [EMAIL PROTECTED] (Jay Blanchard) Newsgroups: php.general Date: Fri, 2 Apr 2004 15:38:03 -0600 To: Monty [EMAIL PROTECTED], [EMAIL PROTECTED] Subject: RE: [PHP] Strange Numeric Conversion... [snip] Why is this happening??? $id = 11; echo $id; // Displays: 9 $id = 11; echo $id; // Displays: 11 How do I make the first number (00011) display as 11? Why is it showing 9? [/snip] First of all you have naked numbers. The first one, 11, looks like a binary number (which actually should be 3). You are going to have to trim the leading zero's from the number to have it display as 11. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Image output (Newb question)
you should have script, call it image.php or something like that, the
only thing that should be in that script is this:
?php
$link = mysql_connect(localhost, root, );
if ($link){
header(Content-type: image/png);
$im = imagecreatefrompng(images/map/map-15x9.png);
imagepng($im); //,images/.session_id()..png
imagedestroy($im);
mysql_close($link);
}
else{
//probably want to have another way to handle this error
echo(Not connected.);
}
?
no html tags in there, no whitespace.
to see the image you could call the page like this
http://www.yourdomain.whatever/image.php . you could call it in a
iumage tag like this
img src=http://www.yourdomain.whatever/image.php; /
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RE: [PHP] Image output (Newb question)
This way works fine!!
Thank you very much.
-Original Message-
From: Matt Matijevich [mailto:[EMAIL PROTECTED]
Sent: Friday, April 02, 2004 2:10 PM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP] Image output (Newb question)
you should have script, call it image.php or something like that, the
only thing that should be in that script is this:
?php
$link = mysql_connect(localhost, root, );
if ($link){
header(Content-type: image/png);
$im = imagecreatefrompng(images/map/map-15x9.png);
imagepng($im); //,images/.session_id()..png
imagedestroy($im);
mysql_close($link);
}
else{
//probably want to have another way to handle this error
echo(Not connected.);
}
?
no html tags in there, no whitespace.
to see the image you could call the page like this
http://www.yourdomain.whatever/image.php . you could call it in a
iumage tag like this
img src=http://www.yourdomain.whatever/image.php; /
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[PHP] Session hell: register_globals off
Had a previous thread on this issue. Started working on it again and am running into new bugs, so thought I'd start a new thread. Read thoroughly through session examples in docs and here's how I tried to pass an object from one page to another: page 1 __ // include class definition file include_once order_classes.php; // start session session_start(); // create instance of class Order $order = New Order(); // assign class instance to $SESSION[] $_SESSION['order'] = $order; page 2 __ // include class definition file include_once order_classes.php; // start session session_start(); // assign $_SESSION['order'] object to variable $order = $_SESSION['order']; I'm getting the following error when page 2 loads: [error] PHP Notice: Undefined variable: _SESSION Any ideas? Pertinent PHP vars: ___ Darwin systame.cniweb.net 7.2.0 Darwin Kernel Version 7.2.0: Thu Dec 11 16:20:23 PST 2003; root:xnu/xnu-517.3.7.obj~1/RELEASE_PPC Power Macintosh Build Date Apr 2 2004 12:58:17 Configure Command './configure' '--with-apxs=/usr/sbin/apxs' '--with-pgsql' '--with-xml' '--with-openssl=/usr/local/ssl' '--with-pear' '--with-curl=/usr/lib' Apache/1.3.29 (Darwin) DAV/1.0.3 mod_perl/1.29 PHP/4.3.5 mod_jk/1.2.4 mod_ssl/2.8.16 OpenSSL/0.9.7c register_globalsOff Off -- Randall Perry sysTame Xserve Web Hosting/Co-location Website Development/Promotion Mac Consulting/Sales http://www.systame.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
Thanks Red, but, still the same problem: $id = 11; $id2 = preg_replace(/^0+(.*)$/,\\1,$id); echo $id2; // Displays 9 echo $id; // Displays 9 as well. If the number begins with a zero, there seems to be no way to tell PHP this is an integer, not an octal. The conversion happens as soon as the number is stored in the variable, it appears, which is why everything done afterwards makes no difference, because $id=11; seems to be stored as $id=9 by PHP. From: [EMAIL PROTECTED] (Red Wingate) Organization: ErisX Development Reply-To: [EMAIL PROTECTED] Newsgroups: php.general Date: Sat, 03 Apr 2004 00:01:43 +0200 To: [EMAIL PROTECTED] Cc: Monty [EMAIL PROTECTED], [EMAIL PROTECTED] Subject: Re: [PHP] Strange Numeric Conversion... sry... it's \\1 instead of //1 ... guess i had one to many beers :) Red Wingate wrote: trim will not work, try something like: $id = preg_replace(/^0+(.*)$/,//1,$id); instead -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
Doesn't putting and x11 tell PHP it's a decimal format? $id = 11; $id2 = preg_replace(/^0+(.*)$/,\\1,$id); echo $id2; // Displays 9 echo $id; // Displays 9 as well. If the number begins with a zero, there seems to be no way to tell PHP this is an integer, not an octal. The conversion happens as soon as the number is stored in the variable, it appears, which is why everything done afterwards makes no difference, because $id=11; seems to be stored as $id=9 by PHP. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
hm ever tryed telling PHP to display the variable as an integer? echo (integer) $id ; -- red Daniel Clark wrote: Doesn't putting and x11 tell PHP it's a decimal format? $id = 11; $id2 = preg_replace(/^0+(.*)$/,\\1,$id); echo $id2; // Displays 9 echo $id; // Displays 9 as well. If the number begins with a zero, there seems to be no way to tell PHP this is an integer, not an octal. The conversion happens as soon as the number is stored in the variable, it appears, which is why everything done afterwards makes no difference, because $id=11; seems to be stored as $id=9 by PHP. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
Found this: $a = 1234; # decimal number $a = -123; # a negative number $a = 0123; # octal number (equivalent to 83 decimal) $a = 0x1A; # hexadecimal number (equivalent to 26 decimal) http://www.phpbuilder.com/manual/language.types.integer.php#language.types.integer.casting hm ever tryed telling PHP to display the variable as an integer? echo (integer) $id ; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
* Thus wrote Daniel Clark ([EMAIL PROTECTED]): Found this: $a = 1234; # decimal number $a = -123; # a negative number $a = 0123; # octal number (equivalent to 83 decimal) $a = 0x1A; # hexadecimal number (equivalent to 26 decimal) $a is integer in all these cases, the only difference is the last two are set using different base notation. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
* Thus wrote Monty ([EMAIL PROTECTED]): I tried removing the zeros, but, I get the same result: $id = 11; $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ??? This didn't work either: $id = 11; settype($id, 'string'); $id = ltrim($id, '0'); echo $id; // Displays: 9 instead of 11 ??? This is expected, $id becomes 9 as soon as you assign it. the ltrim() function's dont see any 0. this will work however: $id = 011; echo (int)$id; - or $id = 011; echo ltrim($id, '0'); No matter what I do, $id=11 is seen as 9. Only way is to pass the number without the zeros ($id=11), but, because this data is being read from a database, I can't change the format because PHP seems to be converting it immediately to a 9 instead of reading it as 11 or even 11. This shouldn't be happening. A variable that contains a value of '11' will not be seen as on octal value. If PHP sees this as an octal, then why does gettype(11) = INTEGER? This makes no sense. Thats because 11 is an integer in octal notation. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
Red Wingate wrote: ever tryed telling PHP to display the variable as an integer? echo (integer) $id ; Ever tryed realizing 0x09, 011, and 9 are all integers (just different bases)? ;) ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Strange Numeric Conversion...
Monty wrote: Thanks Red, but, still the same problem: $id = 11; $id2 = preg_replace(/^0+(.*)$/,\\1,$id); echo $id2; // Displays 9 echo $id; // Displays 9 as well. If the number begins with a zero, there seems to be no way to tell PHP this is an integer, not an octal. The conversion happens as soon as the number is stored in the variable, it appears, which is why everything done afterwards makes no difference, because $id=11; seems to be stored as $id=9 by PHP. 011 and 9 are the exact same number, but represented in different bases! Maybe this is the concept you're not grasping. When you say $id = 11, then you're telling PHP to assign the value of 9 to $id, plain and simple. Can we take a step back here and ask where you're getting 11 from? ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] $this variable reference question
I was trying to bend my mind around the concept of the reference
operator () today and came across an article at
http://www.onlamp.com/pub/a/php/2002/09/12/php_foundations.html where
the author gave the following example:
?php
class test {
function test($val) {
global $myref;
$myref = $this;
$this-value = $val;
}
function printval() {
echo The value of this class is '{$this-value}' br;
}
function setval($val) {
$this-value = $val;
}
}
?
My question is actually regarding the line $myref = $this;. The
author states that this is a reference to the class/object itself.
Isn't this like saying outside the class $myref = new test;? What
would be the point of referring to itself inside the class in this
manner? Thanks for your help in advance!
-Adam Reiswig
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[PHP] Directories function opendir() - how to open an URL
The Directories function opendir(string path) As of PHP 4.3.0 path can also be any URL which supports directory listing This returns false eventhough the URL supports directory listing? opendir (http://www.fu.bar/images/); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Directories function opendir() - how to open an URL
* Thus wrote Dave ([EMAIL PROTECTED]): The Directories function opendir(string path) As of PHP 4.3.0 path can also be any URL which supports directory listing , however only the file:// URL wrapper supports this in PHP 4.3. As of PHP 5.0.0, support for the ftp:// URL wrapper is included as well. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: problem about php
the browser always shows like this: brbFatal error/b: Call to undefined function: domxml_open_mem() in bc:\apache\htdocs\svg_dom_xml_php_bsp.php/b on line b76/bbr. What is wrong here? In php 4 the dom xml extension is NOT loaded by default. So you can't just call these functions until you load the extension. http://us2.php.net/domxml I also looked through the web site www.php.net. But I was confused with so much information.Should I download GNOME XML library? Should domxml run only under linux, not windows?Should domxml run above the version php4.0.x? If possible under windows, how can I get the GNOME XML library and then how to install it? At last,how can I configurate php again after installing it? Windows users don't need the GNOME library for domxml, and I wouldn't recommend building it yourself. However, depending on your version of php you need to have a file in your include path. Directly from the manual: Note to Win32 Users: In order to enable this module on a Windows environment, you must copy one additional file from the DLL folder of the PHP/Win32 binary package to the SYSTEM32 folder of your Windows machine (Ex: C:\WINNT\SYSTEM32 or C:\WINDOWS\SYSTEM32). For PHP = 4.2.0 copy libxml2.dll, for PHP = 4.3.0 copy iconv.dll from the DLL folder to your SYSTEM32 folder. For windows 98, I think you can put the relevant file into C:\WINDOWS\SYSTEM -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Directories function opendir() - how to open an URL
Is http:// URL wrapper support included in PHP 4.3.4 ? or is this included in PHP 5.0.0? Curt Zirzow [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] * Thus wrote Dave ([EMAIL PROTECTED]): The Directories function opendir(string path) As of PHP 4.3.0 path can also be any URL which supports directory listing , however only the file:// URL wrapper supports this in PHP 4.3. As of PHP 5.0.0, support for the ftp:// URL wrapper is included as well. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] opening cash register drawer
Greetings, I am working on a Point of Sale Program for PHP. I need to find out how to open a cash register drawer. Could anyone give me any info? Do I need to do this with a javascript section? Thanks, Leonard Burton -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Directories function opendir() - how to open an URL
* Thus wrote Dave ([EMAIL PROTECTED]): Is http:// URL wrapper support included in PHP 4.3.4 ? or is this included in PHP 5.0.0? I wouldn't expect the http wrapper to ever support opendir functionality. Its virtually impossilble to read directoy listings from a web server. Curt Zirzow [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] * Thus wrote Dave ([EMAIL PROTECTED]): The Directories function opendir(string path) As of PHP 4.3.0 path can also be any URL which supports directory listing , however only the file:// URL wrapper supports this in PHP 4.3. As of PHP 5.0.0, support for the ftp:// URL wrapper is included as well. Curt -- I used to think I was indecisive, but now I'm not so sure. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: $this variable reference question
It's not the same thing. When an variable references an object then you
can change either the original object or the new variable and you will
be changing the *same* object, not a new one. Maybe this example helps?
?php
class test {
function test($val) {
global $myref;
$myref = $this;
$this-value = $val;
}
function printval() {
echo The value of this class is '{$this-value}' br;
}
function setval($val) {
$this-value = $val;
}
}
$a = new test();
$b = $a;
$c = new test();
$a-setval(22);
$b-setval(321);
$c-setval('A weird comment');
$a-printval(); // should see 321
$b-printval(); // should see 321
$c-printval(); // should see A weird comment
?
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[PHP] Re: $this variable reference question
My question is actually regarding the line $myref = $this;. The author states that this is a reference to the class/object itself. Isn't this like saying outside the class $myref = new test;? What would be the point of referring to itself inside the class in this manner? Thanks for your help in advance! -Adam Reiswig The exact class that the author wrote isn't too useful, although it makes its point well. However, a reference to $this inside a class can be useful, for example, if you were using the observer pattern. http://www.phppatterns.com/index.php/article/articleview/27/1/1/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Session hell: register_globals off
page 1 __ // include class definition file include_once order_classes.php; // start session session_start(); // create instance of class Order $order = New Order(); // assign class instance to $SESSION[] $_SESSION['order'] = $order; page 2 __ // include class definition file include_once order_classes.php; // start session session_start(); // assign $_SESSION['order'] object to variable $order = $_SESSION['order']; I'm getting the following error when page 2 loads: [error] PHP Notice: Undefined variable: _SESSION Any ideas? Are you passing the session id between the pages? E.g. are you setting session cookies, or passing the session id as part of the url? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Why does session ID sometimes show appeneded to url and sometimes not?
Boot wrote: Thanks to those who helped with my last post on session vars. My question now is why does my server seem to randomly choose whether or not to show the session ID appended to the browser URL? Sometimes it is there, sometimes not. All pages session_start();. Thanks! Check your browser's cookies... do you have the session id there? If so then you don't need to append the id as part of the url. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: opening cash register drawer
You probably need to check out OPOS, but I haven't looked at it in a while and can't really tell you what to do. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] opening cash register drawer
Leonard B Burton wrote: Greetings, I am working on a Point of Sale Program for PHP. I need to find out how to open a cash register drawer. Could anyone give me any info? Do I need to do this with a javascript section? You will be hard pressed to do anything like this with php. the reason is that php is designed primarily as a language for building web applications. Not at all suitable for desktop applications or smart devices. Hardware control certainly is not recommended. Having said all that if you have a C library that handles the functionality you can invoke it's methods via php. Thanks, Leonard Burton -- Raditha Dissanayake. - http://www.radinks.com/print/upload.php SFTP, FTP and HTTP File Upload solutions -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Session hell: register_globals off
on 4/2/04 8:24 PM, Jason Barnett at [EMAIL PROTECTED] wrote: Are you passing the session id between the pages? E.g. are you setting session cookies, or passing the session id as part of the url? Doesn't php default to using cookies? I'm not doing anything other than using the code I showed. page 1 __ // include class definition file include_once order_classes.php; // start session session_start(); // create instance of class Order $order = New Order(); // assign class instance to $SESSION[] $_SESSION['order'] = $order; page 2 __ // include class definition file include_once order_classes.php; // start session session_start(); // assign $_SESSION['order'] object to variable $order = $_SESSION['order']; -- Randall Perry sysTame Xserve Web Hosting/Co-location Website Development/Promotion Mac Consulting/Sales http://www.systame.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] opening cash register drawer
Leonard B Burton wrote: I am working on a Point of Sale Program for PHP. I need to find out how to open a cash register drawer. Could anyone give me any info? Do I need to do this with a javascript section? Uhmm... I to am interested in PHP scripts that open cash register drawers. Yeah... can you, ah, let me know what you find out?? John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] opening cash register drawer
On Fri, 2004-04-02 at 20:40, Raditha Dissanayake wrote: Leonard B Burton wrote: Greetings, I am working on a Point of Sale Program for PHP. I need to find out how to open a cash register drawer. Could anyone give me any info? Do I need to do this with a javascript section? You will be hard pressed to do anything like this with php. the reason is that php is designed primarily as a language for building web applications. Not at all suitable for desktop applications or smart devices. Hardware control certainly is not recommended. Having said all that if you have a C library that handles the functionality you can invoke it's methods via php. Or a command line interface that can be invoked with exec, or system, or backticks :) Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: How to retrieve dir file list from an internet server folder?
Yes, you'll need to parse the output of the page. Dave [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Is it possible to retrieve dir file list from an internet server folder from within a php program? In the browser, the http:// page displays Index of and a list of files. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Session hell: register_globals off
Randall Perry wrote:
on 4/2/04 8:24 PM, Jason Barnett at [EMAIL PROTECTED] wrote:
Are you passing the session id between the pages? E.g. are you setting
session cookies, or passing the session id as part of the url?
Doesn't php default to using cookies? I'm not doing anything other than
using the code I showed.
Hmmm, I misunderstood the problem... OK, just try this and see if the
session is starting and any errors starting it:
?php
error_reporting(E_ALL);
if (session_start()) {
echo Session started;
} else {
echo No session;
}
?
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Re: [PHP] Re: $this variable reference question
Jason, thanks. Yes, I understand your example here very well. My
question actually had more to do with understanding what value was added
to the class by $myref = $this;. Perhaps it is some misunderstanding
I have of classes but, since a class is just a pattern and not an
actual, usable object in and of itself, what is the value in equating a
member variable with the class. Almost seems recursive. Even though
$myref is set to global it is still a member variable, right? Does
$this refer to the class pattern or is it creating an object of itself
inside the class, sort of an object inside an object? I guess my
problem in understanding this is not so much where this sort of coding
should be used but rather what is really going on here. Thanks again!
-Adam Reiswig
Jason Barnett wrote:
It's not the same thing. When an variable references an object then you
can change either the original object or the new variable and you will
be changing the *same* object, not a new one. Maybe this example helps?
?php
class test {
function test($val) {
global $myref;
$myref = $this;
$this-value = $val;
}
function printval() {
echo The value of this class is '{$this-value}' br;
}
function setval($val) {
$this-value = $val;
}
}
$a = new test();
$b = $a;
$c = new test();
$a-setval(22);
$b-setval(321);
$c-setval('A weird comment');
$a-printval(); // should see 321
$b-printval(); // should see 321
$c-printval(); // should see A weird comment
?
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Re: [PHP] Global $_FILEs
On Saturday 03 April 2004 05:50, Bruno Santos wrote: i've tried to pass the global array $_FILES to a function $_FILES is a superglobal and hence available everywhere (including the inside of functions) without any work on your part. but still no sucess... Please elaborate. can someone help me ?? Only if you can provide some details: 1) State what you're trying to do 2) Show the code that you're using 3) State what you expect the code to do 4) State what the code is actually doing If (3) and (4) are different then: i) Enable full error reporting and study any error messages you get ii) Use print_r() and var_dump() to examine all your variables. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* A king's castle is his home. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem sending with mail()
On Saturday 03 April 2004 03:35, Matt MacLeod wrote: I'm stumped. I have a script to send a simple email using the mail() function in PHP. For some reason I can only receive the email if I send it to my hotmail account. If I send to my regular email ([EMAIL PROTECTED]) I can't get it. I've also tried sending to other non-hotmail addresses with no luck. What does the php error logs say? And your mail logs? -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* If the human brain were so simple that we could understand it, we would be so simple we couldn't. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php email functionality
On Saturday 03 April 2004 00:59, Shawn Beard wrote: I just tried downgrading to version 4.3.4 and it still does not work. And presumably it had worked before you did the upgrade? The tone of your original post suggested that the upgrade broke the mail functionality? Again: Are you positive you have made no other changes to your setup whilst upgrading php? -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Murphy's Law is recursive. Washing your car to make it rain doesn't work. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] I can't view files uploaded with PHP
On Saturday 03 April 2004 03:04, Linux Zero wrote: I write some PHP scripts for a system's module that allows the user to upload a file from his computer to the host. It works fine in a server with Linux Apache MySQL PHP (LAMP) environment. I based on the examples of this page: http://www.php.net/manual/en/features.file-upload.php Las week we transfer the whole system to another server with the same environment, but now the uploaded files can't be viewed in the browser. That's because the file is uploaded with 640 permissions and can't be opened by the browser with a wwwrun user. We check in the old server and find that these uploaded files with 644 permissions. I check the httpd.conf and php.ini files looking for something like a umask option, but I find nothing like that. umask() and/or chmod() However it is odd, files uploaded via HTTP should be owned by the webserver, which in your case ought to be 'wwwrun'? What is the user that the webserver is running under and who is the owner of the uploaded files? -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Your temporary financial embarrassment will be relieved in a surprising manner. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Apache version... 1.3.29 vs 2.0.
On Saturday 03 April 2004 01:28, Chris Shiflett wrote: --- Frano ILICIC [EMAIL PROTECTED] wrote: I just wonder what is the best apache version to run PHP 4.35? Just wondering if there is an obvious choice? Maybe not obvious, but I think the best choice is the latest Apache 1.3.x. But presumably one still has to wait for PHP 4.35 to be released ;-) -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Nothing is as simple as it seems at first Or as hopeless as it seems in the middle Or as finished as it seems in the end. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Relative Url
I'm using this on Apache. You need to include 'inc/globals.php' in your
script.
inc/globals.php
?
require_once('functions.php');
define('RELPATH', GetRelativePath());
?
inc/functions.php
function GetRelativePath() {
$RELPATH = str_replace(UpDirectory(__FILE__), '',
dir_name($_SERVER['SCRIPT_NAME]));
$RELPATH = substr_count($RELPATH, '/');
if ( $RELPATH0 )
$RELPATH = str_repeat('../', $RELPATH);
else
$RELPATH = '/';
return ConvertSlashes($RELPATH);
}
function UpDirectory($directory, $level=1) {
while ( $level-- 0 )
$directory = dirname(dirname($directory));
return ConvertSlashes($directory);
}
function ConvertSlashes($st) {
$st = str_replace('', '/', $st);
$st = str_replace('\\', '/', $st);
return $st;
}
function dir_name($directory) {
return ConvertSlashes(dirname($directory));
}
Chris Thomas wrote:
Is there anyway that i can get a url relative to my server for a script that
is being run??
The script is being included in mulitple files and $_SERVER['SCRIPT_NAME']
just gives me the name of the file that is including the other scripts.
Also $_SERVER['SCRIPT_FILENAME'] is returning nothing.
Thanks
Chris
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Re: [PHP] Configuration Variable user_agent
Bernhard Kraft wrote: Hallo ! I run PHP 4.1.2. I want to set the user_agent which gets sent along when fetching file via the fopen(...) call. Normally this is PHP/VERISON in my case PHP/4.1.2 I want to set a different user_agent. I *believe* you can set this via header(), but its still early here. A sure-fire way to find out is to see how snoopy (snoopy.sf.net) does it. -- Burhan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php email functionality
Shawn Beard wrote: I just upgraded to PHP 4.3.5 and now my email functionality does not work. I do have the SMTP setting in the php.ini set up and did restart Apache. We are running a Windows 2000 server and Apache 2.0.49. Any ideas? A few ideas/suggestions : Does your smtp server require authentication before sending? If so, the default mail() function in PHP can't handle SMTP authentication. Could be that it changed since your upgrade. Does turning up the error_reporting level (E_ALL) print any warnings/notices? Can you ping the smtp server from your web server? Do other (non-PHP) mail applications work? Can you send mail using the same smtp server from a mail client running from the webserver? Is it possible to scan the logs of the smtp server to see what is going on? Hopefully these can lead you in the right direction. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
