[PHP] REALLY NEWB QUESTION - include issue

[TS]

Trying to include() a script from another domain on my server and it won't
let me do it.

I'm getting this error.

open_basedir restriction in effect. Operation not permitted etc...

Please help and stop laughing at me.

Thanks ahead, T


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RE: [PHP] REALLY NEWB QUESTION - include issue

[TS]

Code segment?
Exact error message? (Is there more context?)

Include (/file);

Function.include/a]: open_basedir restriction in effect.
File(/var/www/vhosts/domain/httpdocs/file.php) is not within the allowed
path(s): (/var/www/vhosts/differentdomain/httpdocs:/tmp) in
/var/www/vhosts/samedifferentdomain/httpdocs/custom-template.php on line 151

It's my server and it makes perfect security sense because the package I'm
using allows me to resell but, I don't care about that particular security
issue since I'm not reselling. I'm assuming it's something in php.ini. It's
a linux machine. I'm not sure what else there is to tell. 

Thanks, T





-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, July 01, 2008 1:08 AM
To: TS
Subject: RE: [PHP] REALLY NEWB QUESTION - include issue

Code segment?
Exact error message? (Is there more context?)

I probably don't have the answer to answer you, but make like a little
easier
for those who might by giving them some information to work with.

David

-- Original Message --
From: TS [EMAIL PROTECTED]
To: php-general@lists.php.net
Date: Tue, 1 Jul 2008 00:50:50 -0600
Subject: [PHP] REALLY NEWB QUESTION - include issue


Trying to include() a script from another domain on my server and it
won't
let me do it.

I'm getting this error.

open_basedir restriction in effect. Operation not permitted etc...

Please help and stop laughing at me.

Thanks ahead, T


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To unsubscribe, visit: http://www.php.net/unsub.php



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RE: [PHP] REALLY NEWB QUESTION - include issue

[Thijs Lensselink]

Quoting TS [EMAIL PROTECTED]:


Code segment?
Exact error message? (Is there more context?)


Include (/file);

Function.include/a]: open_basedir restriction in effect.
File(/var/www/vhosts/domain/httpdocs/file.php) is not within the allowed
path(s): (/var/www/vhosts/differentdomain/httpdocs:/tmp) in
/var/www/vhosts/samedifferentdomain/httpdocs/custom-template.php on line 151

It's my server and it makes perfect security sense because the package I'm
using allows me to resell but, I don't care about that particular security
issue since I'm not reselling. I'm assuming it's something in php.ini. It's
a linux machine. I'm not sure what else there is to tell.

Thanks, T





-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 01, 2008 1:08 AM
To: TS
Subject: RE: [PHP] REALLY NEWB QUESTION - include issue

Code segment?
Exact error message? (Is there more context?)

I probably don't have the answer to answer you, but make like a little
easier
for those who might by giving them some information to work with.

David


-- Original Message --
From: TS [EMAIL PROTECTED]
To: php-general@lists.php.net
Date: Tue, 1 Jul 2008 00:50:50 -0600
Subject: [PHP] REALLY NEWB QUESTION - include issue


Trying to include() a script from another domain on my server and it

won't

let me do it.

I'm getting this error.

open_basedir restriction in effect. Operation not permitted etc...

Please help and stop laughing at me.

Thanks ahead, T




Looks like your hosting is blocking files included outside of the  
webroot. If you have root access you could change this. If you wanted  
to. But security is not a bad thing :)


To allow opening of remote url's you can enable 'allow_url_fopen' in php.ini.


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Re: [PHP] Simple array problem

[Thijs Lensselink]

Quoting Brian Dunning [EMAIL PROTECTED]:


I'm trying to add a number to a value in an array. Pretend I have this:

$new_value = array('orange', 2);
$arr = array(
array('blue', 4),
array('orange', 5),
array('green', 6));

I want to add the new value to the existing matching array element, so
I end up with this:

$arr = array(
array('blue', 4),
array('orange', 7),
array('green', 6));

Seems like it should be really simple but all the ways I can figure out
to do it are too kludgey.





Just loop through the array to update. And use in_array to check if  
the key to update exists. Then you can do $array[$key][1] = $newValue.


Something like this maybe:

function updateArray($array, $update)
{
list($updateKey, $updateValue) = $update;
foreach ($array as $key = $subArray) {
if (in_array($updateKey, $subArray)) {
$array[$key][1] = $updateValue;
}
}
}

updateArray($arr, $new_value);
var_dump($arr);

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Re: [PHP] Simple array problem

[Richard Heyes]

Brian Dunning wrote:

I'm trying to add a number to a value in an array. Pretend I have this:

$new_value = array('orange', 2);
$arr = array(
array('blue', 4),
array('orange', 5),
array('green', 6));

I want to add the new value to the existing matching array element, so I 
end up with this:


$arr = array(
array('blue', 4),
array('orange', 7),
array('green', 6));

Seems like it should be really simple but all the ways I can figure out 
to do it are too kludgey.


It's rather easy:

for ($i=0; $icount($arr); $i++) {
if ($arr[$i][0] == $new_array[0]) {
$arr[$i][1] += $new_array[1];
break; // Optional - means the first orange found will be
   // updated only
}
}

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Employ me:
http://www.phpguru.org/cv

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FW: [PHP] REALLY NEWB QUESTION - include issue

[TS]

 To allow opening of remote url's you can enable 'allow_url_fopen' in
php.ini.

This isn't a remote url though. It's a local path.

Looking for something similar to crossdomain.xml file for Flash if anyone is
familiar with that.

Thanks, T


-Original Message-
From: Thijs Lensselink [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, July 01, 2008 1:58 AM
To: php-general@lists.php.net
Subject: RE: [PHP] REALLY NEWB QUESTION - include issue

Quoting TS [EMAIL PROTECTED]:

 Code segment?
 Exact error message? (Is there more context?)

 Include (/file);

 Function.include/a]: open_basedir restriction in effect.
 File(/var/www/vhosts/domain/httpdocs/file.php) is not within the allowed
 path(s): (/var/www/vhosts/differentdomain/httpdocs:/tmp) in
 /var/www/vhosts/samedifferentdomain/httpdocs/custom-template.php on line
151

 It's my server and it makes perfect security sense because the package I'm
 using allows me to resell but, I don't care about that particular security
 issue since I'm not reselling. I'm assuming it's something in php.ini.
It's
 a linux machine. I'm not sure what else there is to tell.

 Thanks, T





 -Original Message-
 From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 01, 2008 1:08 AM
 To: TS
 Subject: RE: [PHP] REALLY NEWB QUESTION - include issue

 Code segment?
 Exact error message? (Is there more context?)

 I probably don't have the answer to answer you, but make like a little
 easier
 for those who might by giving them some information to work with.

 David

 -- Original Message --
 From: TS [EMAIL PROTECTED]
 To: php-general@lists.php.net
 Date: Tue, 1 Jul 2008 00:50:50 -0600
 Subject: [PHP] REALLY NEWB QUESTION - include issue


 Trying to include() a script from another domain on my server and it
 won't
 let me do it.

 I'm getting this error.

 open_basedir restriction in effect. Operation not permitted etc...

 Please help and stop laughing at me.

 Thanks ahead, T



Looks like your hosting is blocking files included outside of the  
webroot. If you have root access you could change this. If you wanted  
to. But security is not a bad thing :)

To allow opening of remote url's you can enable 'allow_url_fopen' in
php.ini.


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Re: FW: [PHP] REALLY NEWB QUESTION - include issue

[Chris]

 -Original Message-
 From: Thijs Lensselink [mailto:[EMAIL PROTECTED] 
 Sent: Tuesday, July 01, 2008 1:58 AM
 To: php-general@lists.php.net
 Subject: RE: [PHP] REALLY NEWB QUESTION - include issue
 
 Quoting TS [EMAIL PROTECTED]:
 
 Code segment?
 Exact error message? (Is there more context?)
 Include (/file);

 Function.include/a]: open_basedir restriction in effect.
 File(/var/www/vhosts/domain/httpdocs/file.php) is not within the allowed
 path(s): (/var/www/vhosts/differentdomain/httpdocs:/tmp) in
 /var/www/vhosts/samedifferentdomain/httpdocs/custom-template.php on line
 151


/var/www/vhosts/domain/httpdocs/file.php is not in the paths you allowed:

/var/www/vhosts/differentdomain/httpdocs

or

/tmp

So you'll need to adjust it through your apache config or you can
disable it just for that domain as well.

See
http://www.php.net/manual/en/configuration.changes.php#configuration.changes.apache


and

http://www.php.net/manual/en/features.safe-mode.php#ini.open-basedir


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Re: FW: [PHP] REALLY NEWB QUESTION - include issue

[Thijs Lensselink]

Quoting TS [EMAIL PROTECTED]:


To allow opening of remote url's you can enable 'allow_url_fopen' in

php.ini.

This isn't a remote url though. It's a local path.

Looking for something similar to crossdomain.xml file for Flash if anyone is
familiar with that.

Thanks, T


-Original Message-
From: Thijs Lensselink [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 01, 2008 1:58 AM
To: php-general@lists.php.net
Subject: RE: [PHP] REALLY NEWB QUESTION - include issue

Quoting TS [EMAIL PROTECTED]:


Code segment?
Exact error message? (Is there more context?)


Include (/file);

Function.include/a]: open_basedir restriction in effect.
File(/var/www/vhosts/domain/httpdocs/file.php) is not within the allowed
path(s): (/var/www/vhosts/differentdomain/httpdocs:/tmp) in
/var/www/vhosts/samedifferentdomain/httpdocs/custom-template.php on line

151


It's my server and it makes perfect security sense because the package I'm
using allows me to resell but, I don't care about that particular security
issue since I'm not reselling. I'm assuming it's something in php.ini.

It's

a linux machine. I'm not sure what else there is to tell.

Thanks, T





-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 01, 2008 1:08 AM
To: TS
Subject: RE: [PHP] REALLY NEWB QUESTION - include issue

Code segment?
Exact error message? (Is there more context?)

I probably don't have the answer to answer you, but make like a little
easier
for those who might by giving them some information to work with.

David


-- Original Message --
From: TS [EMAIL PROTECTED]
To: php-general@lists.php.net
Date: Tue, 1 Jul 2008 00:50:50 -0600
Subject: [PHP] REALLY NEWB QUESTION - include issue


Trying to include() a script from another domain on my server and it

won't

let me do it.

I'm getting this error.

open_basedir restriction in effect. Operation not permitted etc...

Please help and stop laughing at me.

Thanks ahead, T




Looks like your hosting is blocking files included outside of the
webroot. If you have root access you could change this. If you wanted
to. But security is not a bad thing :)

To allow opening of remote url's you can enable 'allow_url_fopen' in
php.ini.




In your first post you mentioned something about a remote domain. So i  
assumed you were including a remote page. But Chris already answered  
your question. Just add the paths so they are accessible.



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Re: [PHP] Encription

[Stefano Esposito]

On Mon, 30 Jun 2008 14:39:04 -0500
Will Fitch [EMAIL PROTECTED] wrote:

 Have you considered mcrypt then base64?

Thanks, i was completely forgetting mcrypt... that's what i need :)
 
 
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[PHP] Re: can you give me example of website using postgresql database?

[paragasu]

paragasu wrote:
 I develop a relatively
 large, in-house application using PostgreSQL that I can't wait to convert to
 MySQL.

 well, you should give me a reason why you want to do this.

 What exactly scares you about Sun/MySQL?
 personally, it is not about i am scared. i am still continue to use
 mysql for several
 project i did few years ago and continue support and upgrade it.

 for the moment, after making internet survey for few month i found out
 it might be
 worth my time trying to explore the concept of trigger etc.

 don't get me wrong. it is not about mysql vs postgresql. it is just
 something i believe
 worth to explore..

opps...

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Re: [PHP] Strategy to protect images

[Stefano Esposito]

On Sun, 15 Jun 2008 13:48:28 +0200
Stefano Esposito [EMAIL PROTECTED] wrote:

 Hi all,
 
 i have to forbid users of my site to view images directly (i.e.
 writing the image URL in the address bar) but they'd be able viewing
 them from the pages of the site. What's the best way of doing it, or
 something similar? Is there a common strategy using PHP? Thank you for
 any hint :-)
 
 Ciao,
 Stefano

Thanks for all of your hints :)
Here's my solution:

1) disable contextmenu on the images to protect using javascript (just
to discourage less determined people)

2) for other purposes, the page containing images to protect, is
brought to users through an ajax request, so they can't so-easily
look at the source (not with browser's normal 'view source'
anyway... they would need something like firebug).

3) use a script to get image data (as someone on the list suggested),
checking for the right $_SERVER['HTTP_REFERER'] (i know... it's not so
trustworthy... if anyone has a better idea, i'll be glad to listen
to :))

4) encrypt the relative path of the image on the fly, using mcrypt with
a key generated on the login and then pass it encoded whit
base64_encode (with a little workaround for '+', '/' and '=' chars) to
the image-reading script. So, even if someone can get to the source,
they'll end up whit an encrypted id of which they don't know neither
the key nor the encryption method nor even what it's supposed to
represent (if some database id or a path).

I think that's a good way to prevent image theft... well, unless the
thief uses the print screen key...

What's your point of view?

Ciao,
Stefano
 
 
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Re: [PHP] Strategy to protect images

[Nitsan Bin-Nun]

Umm have you ever thought about watermark-ing it? (In case its not a part of
your website or something..)

On 01/07/2008, Stefano Esposito [EMAIL PROTECTED] wrote:

 On Sun, 15 Jun 2008 13:48:28 +0200

 Stefano Esposito [EMAIL PROTECTED] wrote:


  Hi all,
 
  i have to forbid users of my site to view images directly (i.e.
  writing the image URL in the address bar) but they'd be able viewing
  them from the pages of the site. What's the best way of doing it, or
  something similar? Is there a common strategy using PHP? Thank you for
  any hint :-)
 
  Ciao,
  Stefano


 Thanks for all of your hints :)
 Here's my solution:

 1) disable contextmenu on the images to protect using javascript (just
 to discourage less determined people)

 2) for other purposes, the page containing images to protect, is
 brought to users through an ajax request, so they can't so-easily
 look at the source (not with browser's normal 'view source'
 anyway... they would need something like firebug).

 3) use a script to get image data (as someone on the list suggested),
 checking for the right $_SERVER['HTTP_REFERER'] (i know... it's not so
 trustworthy... if anyone has a better idea, i'll be glad to listen
 to :))

 4) encrypt the relative path of the image on the fly, using mcrypt with
 a key generated on the login and then pass it encoded whit
 base64_encode (with a little workaround for '+', '/' and '=' chars) to
 the image-reading script. So, even if someone can get to the source,
 they'll end up whit an encrypted id of which they don't know neither
 the key nor the encryption method nor even what it's supposed to
 represent (if some database id or a path).

 I think that's a good way to prevent image theft... well, unless the
 thief uses the print screen key...

 What's your point of view?


 Ciao,
 Stefano


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Re: [PHP] Simple array problem

[tedd]

At 9:35 AM +0100 7/1/08, Richard Heyes wrote:

Brian Dunning wrote:
Seems like it should be really simple but all the ways I can figure 
out to do it are too kludgey.


It's rather easy:

for ($i=0; $icount($arr); $i++) {
if ($arr[$i][0] == $new_array[0]) {
$arr[$i][1] += $new_array[1];
break; // Optional - means the first orange found will be
   // updated only
}
}

--
Richard Heyes


Small correction:

for ($i=0; $icount($arr); $i++)
   {
if ($arr[$i][0] == $new_value [0])
  {
$arr[$i][1] += $new_value [1];
break; // Optional - means the first orange found will be
   // updated only
   }
   }

See here:

http://www.webbytedd.com/b1/array/

But, I'm not sure as to why you (Brian) would want to do that anyway.

tedd
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Re: [PHP] Simple array problem

[Richard Heyes]

Small correction:


Which is...?

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Re: [PHP] Simple array problem

[Eric Butera]

On Tue, Jul 1, 2008 at 8:50 AM, Richard Heyes [EMAIL PROTECTED] wrote:
 Small correction:

 Which is...?

 --
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Look at the link he sent.

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Re: [PHP] Simple array problem

[Wolf]

Brian Dunning wrote:

I'm trying to add a number to a value in an array. Pretend I have this:

$new_value = array('orange', 2);
$arr = array(
array('blue', 4),
array('orange', 5),
array('green', 6));

I want to add the new value to the existing matching array element, so I 
end up with this:


$arr = array(
array('blue', 4),
array('orange', 7),
array('green', 6));

Seems like it should be really simple but all the ways I can figure out 
to do it are too kludgey.



What have you tried so far?

Wolf


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Re: [PHP] Simple array problem

[Roberto Costumero Moreno]

I think the problem is easier... and also the solutions doing a for
instead of foreach are not good solutions because if the array is not
index-consecutive the loop fails.

So, if you has an array with the colors as indexes and the integer value X
as the value for that position of the array, updating is very easy.

You have an array such as:

$array = array( );

$array['blue'] = 4;

$array['orange'] = 5;

$array['green'] = 6;



So if you want to update the key 'orange' with a new value $new_value is as
easy as:

$array['orange'] += $new_value;

As the new value is being passed as an array so as to update it, it should
be like:

$new_value = array('orange',2);

So you have to do a foreach in the $new_value array like:

foreach ($new_value as $key = $value){

   if(in_array($key,$array)){

  $array[$key] += $value;

   }

}

I think that solution works and is the easiest way to do it.

Cheers,

Roberto

On 01/07/2008, tedd [EMAIL PROTECTED] wrote:

 At 9:35 AM +0100 7/1/08, Richard Heyes wrote:

 Brian Dunning wrote:

 Seems like it should be really simple but all the ways I can figure out
 to do it are too kludgey.


 It's rather easy:

 for ($i=0; $icount($arr); $i++) {
if ($arr[$i][0] == $new_array[0]) {
$arr[$i][1] += $new_array[1];
break; // Optional - means the first orange found will be
   // updated only
}
 }

 --
 Richard Heyes


 Small correction:

 for ($i=0; $icount($arr); $i++)
   {
if ($arr[$i][0] == $new_value [0])
  {
$arr[$i][1] += $new_value [1];
break; // Optional - means the first orange found will be
   // updated only
   }
   }

 See here:

 http://www.webbytedd.com/b1/array/

 But, I'm not sure as to why you (Brian) would want to do that anyway.

 tedd
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Re: [PHP] unset in foreach breaks recrusion

[Roberto Costumero Moreno]

That's true. My fault. I forgot the recrusion call ;-)

I think that is the better solution so far, and it is far far away (better)
that the one you posted at first

On 01/07/2008, David Sky [EMAIL PROTECTED] wrote:

 Hey,

 Can't use your example, as you check weather
 $sorted is empty, if it is - run the foreach and return,
 but on next recursion when it's not empty - do nothing :)

 Though I found how to cut a few seconds (on very big array),
 removing the first if, and adding a $return=true to functions'
 parameters, and in future calls set it to false:

 function recur($array, $sorted=array(), $pid=0, $level=0, $return=true)

 {
 foreach($array as $id=$parent)
 {
 if($pid===$parent)
 {
 $sorted[$id]= $level;
 unset($array[$id]);
 if(in_array($id,$array)){

 recur($array, $sorted, $id,
 $level+1, false);
 }
 }
 }
 if($return){return $sorted;}
 }


 Well, I guess that's it, I'm sure I can think of
 another way to cut execution time, but, well,
 I don't have much time for it :)


 Thanks all!

 David.


 On Mon, Jun 30, 2008 at 8:24 AM, Roberto Costumero Moreno

 [EMAIL PROTECTED] wrote:
  Hi David,
 
  That's good work ;-)
 
  You are right that my example would only return one entry for each
 parent.
  Didn't realized of that.
 
  I know the local copies you create in the recursive calls is not the best
  solution in efficiency, but lots of times it is better to have local
 copies
  of the array (in time of execution of the foreach) that the reference to
 it,
  and the loss is not so big.
 
  I think i would not be able to improve that function a lot, but if I come
 up
  a solution I will tell you.
 
  One little advice, you can get the same functionality saving a little bit
 of
  code, and having one variable less, so the function should look like this
  (avoiding the use of $return variable and makes the code clearer for
 later
  revisions):
 
  /**
   * Recursion
   * @array as ( id = parent )
   * return array as ( id = level ) maintaining arrays' initial order
   */
  function recur($array, $sorted=array(), $pid=0, $level=0)
  {
 if(empty($sorted)){
foreach($array as $id=$parent)
{
 if($pid===$parent)
 {
 $sorted[$id]= $level;
 unset($array[$id]);
 if(in_array($id,$array)){
 recur($array, $sorted, $id, $level+1);
 }
 }
}
return $sorted;
 }
  }
 
  Note that return $sorted is inside the if so as to avoid returning an
 empty
  array. If you don't mind returning an empty array put it down the
 bracket.
 
  And thanks to you. I signed up to the mailing list only two days ago
  (although I've been working with PHP for at least 3 years), and you are
 the
  first person I help successfully (or almost). Don't ever regret of asking
  problems in the mailing list and always wait about 24 hours for someone
 to
  answer ;-)
 
  There are lots of people from all over the world so if the one helping
 your
  case is in the opposite part of the world and is asleep... it takes time
 ;-)
 
  Cheers,
 
  Roberto
 
 
 
 
  On Mon, Jun 30, 2008 at 17:38, David Sky [EMAIL PROTECTED] wrote:
 
  Hey Robero,
 
  Thanks for the answer, the none recursion function is a good idea,
  although as provided in your example if would only return one
  entry from each parent it can get to and it only can get to few,
  depends on how the array is sorted.
 
  Basically you can make it work if you would sort the array from
  small to high by parent value, but in my case I will get this array
  pre-sorted by date, so I can't change the order.
 
  Now, about your other suggestion, yes, it will work without the
 reference.
  I used the reference to avoid creating local copies of the array.
 
  I solved the problem by removing the reference just as you said, but
 then
  there would be to many recursions, so I ended up with this function:
 
  /**
   * Recursion
   * @array as ( id = parent )
   * return array as ( id = level ) maintaining arrays' initial order
   */
  function recur($array, $sorted=array(), $pid=0, $level=0)
  {
 if(empty($sorted)){$return=true;}else{$return=false;}
 foreach($array as $id=$parent)
 {
 if($pid===$parent)
 {
 $sorted[$id]= $level;
 unset($array[$id]);
 if(in_array($id,$array)){
 recur($array, $sorted, $id, $level+1);
 }
 }
 }
 if($return){return $sorted;}
  }
 
 

RE: [PHP] Re: can you give me example of website using postgresql database?

[Will Fitch]

Then in that case I agree.  I develop an inherited, large-scale, in-house
system that utilizes PostgreSQL.  It does the job, but I can't wait until I
get the time to convert it to MySQL.

As with any RDMS, Postgres has its advantages:  controlling sequences,
aggregates, custom operators,  custom types, etc.  MySQL has focused on
performance while PostgreSQL primarily focused on features.  Now it seems
both are going in each other's starting direction.

-Original Message-
From: paragasu [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, July 01, 2008 4:51 AM
To: php-general@lists.php.net
Subject: [PHP] Re: can you give me example of website using postgresql
database?

paragasu wrote:
 I develop a relatively
 large, in-house application using PostgreSQL that I can't wait to convert
to
 MySQL.

 well, you should give me a reason why you want to do this.

 What exactly scares you about Sun/MySQL?
 personally, it is not about i am scared. i am still continue to use
 mysql for several
 project i did few years ago and continue support and upgrade it.

 for the moment, after making internet survey for few month i found out
 it might be
 worth my time trying to explore the concept of trigger etc.

 don't get me wrong. it is not about mysql vs postgresql. it is just
 something i believe
 worth to explore..

opps...

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Re: [PHP] can you give me example of website using postgresql database?

[Lester Caine]

Will Fitch wrote:

The purchase of MySQL by Sun should actually give you more comfort.  They
will be able to attach more money and developers to the project. Remember,
the advantage of open-source is not just that it's free, but that you may
freely modify it for your purpose (keeping in mind the restrictions of
individual licenses). 


I'm not sure what you're looking for in a RDMS, but the simple fact that you
are having a hard time finding a robust, live site that uses PostgreSQL
should scare you more than Sun's purchase of MySQL.  I develop a relatively
large, in-house application using PostgreSQL that I can't wait to convert to
MySQL.


WHY?
What a waste of time.
More big MySQL sites have had problems in the past that Postgres, but the only 
reason to change TO MySQL is if it is going to give something in return. What 
do you think it will give you?
Personally I'll stick with Firebird even though switching between engines is 
very simple in my case, using ADOdb ;)


paragasu - http://www.bitweaver.org/wiki/bitweaver_sites see if you can spot 
which engine is being used for which site :) MySQL is somewhat low on the list 
when it comes to testing :)


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Re: [PHP] Simple array problem

[tedd]

At 1:50 PM +0100 7/1/08, Richard Heyes wrote:

Small correction:


Which is...?

--
Richard Heyes


You missed it a second time?  :-)

It's not, new_array[], but new_value[].

Cheers,

tedd

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RE: [PHP] can you give me example of website using postgresql database?

[Will Fitch]

Assuming that a system should switch RDBMSs is a waste of time without
knowing the reason is asinine.  Using NDB clustering is a primary reason for
switching.  PostgreSQL is only currently PLANNING built-in replication, much
less clustering.  Not to mention that the existing system is not taking
advantage of ANY PostgreSQL functionality that is not already present in
MySQL.  So gaining performance and clustering is reason enough for me.


-Original Message-
From: Lester Caine [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, July 01, 2008 8:53 AM
To: php-general@lists.php.net
Subject: Re: [PHP] can you give me example of website using postgresql
database?

Will Fitch wrote:
 The purchase of MySQL by Sun should actually give you more comfort.  They
 will be able to attach more money and developers to the project. Remember,
 the advantage of open-source is not just that it's free, but that you may
 freely modify it for your purpose (keeping in mind the restrictions of
 individual licenses). 
 
 I'm not sure what you're looking for in a RDMS, but the simple fact that
you
 are having a hard time finding a robust, live site that uses PostgreSQL
 should scare you more than Sun's purchase of MySQL.  I develop a
relatively
 large, in-house application using PostgreSQL that I can't wait to convert
to
 MySQL.

WHY?
What a waste of time.
More big MySQL sites have had problems in the past that Postgres, but the
only 
reason to change TO MySQL is if it is going to give something in return.
What 
do you think it will give you?
Personally I'll stick with Firebird even though switching between engines is

very simple in my case, using ADOdb ;)

paragasu - http://www.bitweaver.org/wiki/bitweaver_sites see if you can spot

which engine is being used for which site :) MySQL is somewhat low on the
list 
when it comes to testing :)

-- 
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-
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L.S.Caine Electronic Services - http://lsces.co.uk
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Re: [PHP] unset in foreach breaks recrusion

[Jim Lucas]

David Sky wrote:

Hey,

Can't use your example, as you check weather
$sorted is empty, if it is - run the foreach and return,
but on next recursion when it's not empty - do nothing :)

Though I found how to cut a few seconds (on very big array),
removing the first if, and adding a $return=true to functions'
parameters, and in future calls set it to false:

function recur($array, $sorted=array(), $pid=0, $level=0, $return=true)
{
foreach($array as $id=$parent)
{
if($pid===$parent)
{   
$sorted[$id]= $level;
unset($array[$id]);
if(in_array($id,$array)){
recur($array, $sorted, $id, $level+1, 
false);
}
}
}
if($return){return $sorted;}
}


Well, I guess that's it, I'm sure I can think of
another way to cut execution time, but, well,
I don't have much time for it :)



Why are you returning anything at all?  I mean, you are making your 
function call like this right?


$dataOut = recur($dataIn, array(), 3);

You are passing the second argument as a reference already, why not keep 
it that way at the top level.  Do this instead.


recur($dataIn, $dataOut, 3);


Now, from what you function looks like, it would return $sorted through 
the reference $dataOut.


Then you can get rid of the extra if($return){return $sorted;} thing. 
Remove the last argument from the function definition and you should now 
be a little faster also.




Thanks all!

David.



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Re: [PHP] Simple array problem

[Jim Lucas]

Roberto Costumero Moreno wrote:

I think the problem is easier... and also the solutions doing a for
instead of foreach are not good solutions because if the array is not
index-consecutive the loop fails.

So, if you has an array with the colors as indexes and the integer value X
as the value for that position of the array, updating is very easy.

You have an array such as:

$array = array( );

$array['blue'] = 4;

$array['orange'] = 5;

$array['green'] = 6;



So if you want to update the key 'orange' with a new value $new_value is as
easy as:

$array['orange'] += $new_value;

As the new value is being passed as an array so as to update it, it should
be like:

$new_value = array('orange',2);

So you have to do a foreach in the $new_value array like:

foreach ($new_value as $key = $value){

   if(in_array($key,$array)){

  $array[$key] += $value;

   }

}

I think that solution works and is the easiest way to do it.

Cheers,

Roberto

On 01/07/2008, tedd [EMAIL PROTECTED] wrote:

At 9:35 AM +0100 7/1/08, Richard Heyes wrote:


Brian Dunning wrote:


Seems like it should be really simple but all the ways I can figure out
to do it are too kludgey.


It's rather easy:

for ($i=0; $icount($arr); $i++) {
   if ($arr[$i][0] == $new_array[0]) {
   $arr[$i][1] += $new_array[1];
   break; // Optional - means the first orange found will be
  // updated only
   }
}

--
Richard Heyes


Small correction:

for ($i=0; $icount($arr); $i++)
  {
   if ($arr[$i][0] == $new_value [0])
 {
   $arr[$i][1] += $new_value [1];
   break; // Optional - means the first orange found will be
  // updated only
  }
  }

See here:

http://www.webbytedd.com/b1/array/

But, I'm not sure as to why you (Brian) would want to do that anyway.

tedd
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All of that is fine and dandy, but what if he can't change the structure 
of the array?


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Re: [PHP] Simple array problem

[Richard Heyes]

You missed it a second time?  :-)


My sight is awful - if you don't point it out, chances are I won't see it.

--
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Employ me:
http://www.phpguru.org/cv

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Re: [PHP] unset in foreach breaks recrusion

[David Sky]

Jim,

Read the first emails, your idea was my initial design, eg.
$sorted= array();
recrusion($array, $sorted);
var_dump( $sorted );

It's not a nice solution due to a need to create variable before the call.
Using my final function it will return sorted array into new variable eg
$sorted = recur($array);

It's easier to use and understand :)


Thanks for your reply!


On Tue, Jul 1, 2008 at 6:34 AM, Jim Lucas [EMAIL PROTECTED] wrote:
 David Sky wrote:

 Hey,

 Can't use your example, as you check weather
 $sorted is empty, if it is - run the foreach and return,
 but on next recursion when it's not empty - do nothing :)

 Though I found how to cut a few seconds (on very big array),
 removing the first if, and adding a $return=true to functions'
 parameters, and in future calls set it to false:

 function recur($array, $sorted=array(), $pid=0, $level=0, $return=true)
 {
foreach($array as $id=$parent)
{
if($pid===$parent)
{
$sorted[$id]= $level;
unset($array[$id]);
if(in_array($id,$array)){
recur($array, $sorted, $id,
 $level+1, false);
}
}
}
if($return){return $sorted;}
 }


 Well, I guess that's it, I'm sure I can think of
 another way to cut execution time, but, well,
 I don't have much time for it :)


 Why are you returning anything at all?  I mean, you are making your function
 call like this right?

 $dataOut = recur($dataIn, array(), 3);

 You are passing the second argument as a reference already, why not keep it
 that way at the top level.  Do this instead.

 recur($dataIn, $dataOut, 3);


 Now, from what you function looks like, it would return $sorted through the
 reference $dataOut.

 Then you can get rid of the extra if($return){return $sorted;} thing. Remove
 the last argument from the function definition and you should now be a
 little faster also.


 Thanks all!

 David.



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Re: [PHP] can you give me example of website using postgresql database?

[Lester Caine]

Will Fitch wrote:

Assuming that a system should switch RDBMSs is a waste of time without
knowing the reason is asinine.  Using NDB clustering is a primary reason for
switching.  PostgreSQL is only currently PLANNING built-in replication, much
less clustering.  Not to mention that the existing system is not taking
advantage of ANY PostgreSQL functionality that is not already present in
MySQL.  So gaining performance and clustering is reason enough for me.


You gave no reasons initially ... and with facilities being added all the 
time, the reason to change may evaporate before a change is made?
Have you looked at the alternatives as well since you seem to have some work 
to do rather than simply changing the data source?


I'm being told I have to switch to MSSQL or Oracle but the customers can't 
provide justification to do that as yet and since we are only up to a couple 
of gigabytes of data replicated across machines I am always looking for 
informed explanations of why a switch is necessary ;) i.e. why one database 
may be more appropriate than another.


The lack of proper comparison information does make it difficult at times :(

--
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-
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L.S.Caine Electronic Services - http://lsces.co.uk
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[PHP] V4 Vs V5 Issue

[Neil]

Hi

First Post here, I hope this is the right place for this post.

This is probably not a php problem,  I think it may a configuration 
issue, but sorry I just dont know where to look


I have a V4 site the calls an on line editor and part of the process 
is by window.onload. If I had to explain how it all works I could'nt 
JS is not my thing and this is a fairly old piece of code.


anyways

-- Have a bit of code that looks like this

.
.
body  leftmargin=2 marginwidth=2 topmargin=2 marginheight=2 
onResize=blockDefault();

content;

include($settings['app_dir'].'/js/core_js.php');

echo  content
script LANGUAGE=Javascript
  window.onload=initEditor
/script

table border=0 cellpadding=5 cellspacing=0 width=100% 
height=100% class=framed

.
.
.
--

Under My V4 Sever it works fine .the Java script loads and an all is fine.

On my V5 Sever

I get the following Errors

Line: 68
Char: 21
Error: Syntax error
Code: 0
URL: ..
and then

Line: 600
Char: 11
Error 'initEditor' is undefined
Code 0
URL

Now the thing is, when I view source code in IE off both servers the 
the core_js.php is being read and is visible, the initEditor function 
is there for all the world to see.


If I rename the initEditor function on the V5 version and add a new 
empty function I still get the same error messages.


I dont have much hair and I am tearing out the rest as we speak 
:).I have no idea where to look so I am just hoping someone can 
point me in the right direction.


Like I said in the beginning I think it must be a configuration issue 
but I just dont know what or where.


Anyways TIA

Cheers

Neil



 



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RE: [PHP] can you give me example of website using postgresql database?

[Will Fitch]

Touché, salesman.

-Original Message-
From: Lester Caine [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, July 01, 2008 10:21 AM
To: php-general@lists.php.net
Subject: Re: [PHP] can you give me example of website using postgresql
database?

Will Fitch wrote:
 Assuming that a system should switch RDBMSs is a waste of time without
 knowing the reason is asinine.  Using NDB clustering is a primary reason
for
 switching.  PostgreSQL is only currently PLANNING built-in replication,
much
 less clustering.  Not to mention that the existing system is not taking
 advantage of ANY PostgreSQL functionality that is not already present in
 MySQL.  So gaining performance and clustering is reason enough for me.

You gave no reasons initially ... and with facilities being added all the 
time, the reason to change may evaporate before a change is made?
Have you looked at the alternatives as well since you seem to have some work

to do rather than simply changing the data source?

I'm being told I have to switch to MSSQL or Oracle but the customers can't 
provide justification to do that as yet and since we are only up to a couple

of gigabytes of data replicated across machines I am always looking for 
informed explanations of why a switch is necessary ;) i.e. why one database 
may be more appropriate than another.

The lack of proper comparison information does make it difficult at times :(

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-
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Re: [PHP] V4 Vs V5 Issue

[Wolf]

 Neil [EMAIL PROTECTED] wrote: 
 Hi
 
 First Post here, I hope this is the right place for this post.
 
 This is probably not a php problem,  I think it may a configuration 
 issue, but sorry I just dont know where to look

Configuration issue of what?

 
 I have a V4 site the calls an on line editor and part of the process 
 is by window.onload. If I had to explain how it all works I could'nt 
 JS is not my thing and this is a fairly old piece of code.
 
 anyways
!-- SNIP --

 Line: 68
 Char: 21
 Error: Syntax error
 Code: 0

It's probably all JS, but if this is a PHP page that you've actually cut/pasted 
from, look at lines 67 and 68 and check to make sure you have a ; at the end of 
line 67.  Or a ) or a } or some other closing brace that you could be using 
previously.

Otherwise, check with a javascript list to see what the javascript errors are.

HTH,
Wolf

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Re: [PHP] V4 Vs V5 Issue

[Eric Butera]

On Tue, Jul 1, 2008 at 11:27 AM, Neil [EMAIL PROTECTED] wrote:
 Hi

 First Post here, I hope this is the right place for this post.

 This is probably not a php problem,  I think it may a configuration issue,
 but sorry I just dont know where to look

 I have a V4 site the calls an on line editor and part of the process is by
 window.onload. If I had to explain how it all works I could'nt JS is not my
 thing and this is a fairly old piece of code.

 anyways

 -- Have a bit of code that looks like this

 .
 .
 body  leftmargin=2 marginwidth=2 topmargin=2 marginheight=2
 onResize=blockDefault();
 content;

 include($settings['app_dir'].'/js/core_js.php');

 echo  content
 script LANGUAGE=Javascript
  window.onload=initEditor
 /script

 table border=0 cellpadding=5 cellspacing=0 width=100% height=100%
 class=framed
 .
 .
 .
 --

 Under My V4 Sever it works fine .the Java script loads and an all is
 fine.

 On my V5 Sever

 I get the following Errors

 Line: 68
 Char: 21
 Error: Syntax error
 Code: 0
 URL: ..
 and then

 Line: 600
 Char: 11
 Error 'initEditor' is undefined
 Code 0
 URL

 Now the thing is, when I view source code in IE off both servers the the
 core_js.php is being read and is visible, the initEditor function is there
 for all the world to see.

 If I rename the initEditor function on the V5 version and add a new empty
 function I still get the same error messages.

 I dont have much hair and I am tearing out the rest as we speak :).I
 have no idea where to look so I am just hoping someone can point me in the
 right direction.

 Like I said in the beginning I think it must be a configuration issue but I
 just dont know what or where.

 Anyways TIA

 Cheers

 Neil





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Compare your rendered output from the v4 and the v5.  You might see
something in the php5 version that has some sort of error displaying
to screen that causes a parse error inside your JS block that wasn't
there before.

Something might have changed about the way your settings variable
works too.  Do a var_dump($settings['app_dir'].'/js/core_js.php') and
see if it actually prints out a real path to a file that exists.

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Re: [PHP] V4 Vs V5 Issue

[Neil]

Thanks Wolf

I have replied  to all, I hope that is the correct way here.

A configuration issue on the PHP V5 Server . thats my 
problem, I dont know where I should be looking.


The source code, php and JS is absolutely identical on both machines.

Cheers

Neil

At 01:36 AM 2/07/2008, Wolf wrote:


 Neil [EMAIL PROTECTED] wrote:
 Hi

 First Post here, I hope this is the right place for this post.

 This is probably not a php problem,  I think it may a configuration
 issue, but sorry I just dont know where to look

Configuration issue of what?


 I have a V4 site the calls an on line editor and part of the process
 is by window.onload. If I had to explain how it all works I could'nt
 JS is not my thing and this is a fairly old piece of code.

 anyways
!-- SNIP --

 Line: 68
 Char: 21
 Error: Syntax error
 Code: 0

It's probably all JS, but if this is a PHP page that you've actually 
cut/pasted from, look at lines 67 and 68 and check to make sure you 
have a ; at the end of line 67.  Or a ) or a } or some other closing 
brace that you could be using previously.


Otherwise, check with a javascript list to see what the javascript errors are.

HTH,
Wolf

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Re: [PHP] V4 Vs V5 Issue

[Neil]

Hi Thanks

I have tested the path, that works fine. I set up a dummy file on the 
same path just to check that,  it found that and printed out some 
echo'd text from that file.


I can see the content of core_js.php file  in the the IE view source view.

At 01:43 AM 2/07/2008, Eric Butera wrote:

On Tue, Jul 1, 2008 at 11:27 AM, Neil [EMAIL PROTECTED] wrote:
 Hi

 First Post here, I hope this is the right place for this post.

 This is probably not a php problem,  I think it may a configuration issue,
 but sorry I just dont know where to look

 I have a V4 site the calls an on line editor and part of the process is by
 window.onload. If I had to explain how it all works I could'nt JS is not my
 thing and this is a fairly old piece of code.

 anyways

 -- Have a bit of code that looks like this

 .
 .
 body  leftmargin=2 marginwidth=2 topmargin=2 marginheight=2
 onResize=blockDefault();
 content;

 include($settings['app_dir'].'/js/core_js.php');

 echo  content
 script LANGUAGE=Javascript
  window.onload=initEditor
 /script

 table border=0 cellpadding=5 cellspacing=0 width=100% 
height=100%

 class=framed
 .
 .
 .
 --

 Under My V4 Sever it works fine .the Java script loads and an all is
 fine.

 On my V5 Sever

 I get the following Errors

 Line: 68
 Char: 21
 Error: Syntax error
 Code: 0
 URL: ..
 and then

 Line: 600
 Char: 11
 Error 'initEditor' is undefined
 Code 0
 URL

 Now the thing is, when I view source code in IE off both servers the the
 core_js.php is being read and is visible, the initEditor function is there
 for all the world to see.

 If I rename the initEditor function on the V5 version and add a new empty
 function I still get the same error messages.

 I dont have much hair and I am tearing out the rest as we speak :).I
 have no idea where to look so I am just hoping someone can point me in the
 right direction.

 Like I said in the beginning I think it must be a configuration issue but I
 just dont know what or where.

 Anyways TIA

 Cheers

 Neil





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Compare your rendered output from the v4 and the v5.  You might see
something in the php5 version that has some sort of error displaying
to screen that causes a parse error inside your JS block that wasn't
there before.

Something might have changed about the way your settings variable
works too.  Do a var_dump($settings['app_dir'].'/js/core_js.php') and
see if it actually prints out a real path to a file that exists.

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Re: [PHP] Simple array problem

[tedd]

At 3:44 PM +0100 7/1/08, Richard Heyes wrote:

You missed it a second time?  :-)


My sight is awful - if you don't point it out, chances are I won't see it.

--
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I'm just as bad, I only saw the error after I tried to get your code to run.

I thought I had another way, but your's was better.

Cheers,

tedd

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[PHP] Execute command line as a different user

[Matt palermo]

My PHP is running as a user with limited rights.  I'd like to execute a 
command line as a different user.  I'm trying to delete a file and the PHP 
user doesn't have access to do this.  I know the username and password for 
the admin user that has rights to delete a file.  Is there a command I can 
use to make PHP run a delete command as the admin user?  If so, how can I do 
this?


Thanks,

Matt 



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Re: [PHP] Execute command line as a different user

[Dan Joseph]

On Tue, Jul 1, 2008 at 1:17 PM, Matt palermo [EMAIL PROTECTED] wrote:

 My PHP is running as a user with limited rights.  I'd like to execute a
 command line as a different user.  I'm trying to delete a file and the PHP
 user doesn't have access to do this.  I know the username and password for
 the admin user that has rights to delete a file.  Is there a command I can
 use to make PHP run a delete command as the admin user?  If so, how can I do
 this?

 Thanks,

 Matt

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I did a quick check on php.net, there is a post on there that talks about
using sudo:


@exec(echo 'apache' | /usr/bin/sudo -u mail -S /var/www/html/mailset.sh
$name);

You may want to read thru it, php.net/exec, go to the user notes.

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Light a man on fire, and will be warm for the rest of his life.

[PHP] Re: Execute command line as a different user

[Shawn McKenzie]

Matt palermo wrote:
My PHP is running as a user with limited rights.  I'd like to execute a 
command line as a different user.  I'm trying to delete a file and the 
PHP user doesn't have access to do this.  I know the username and 
password for the admin user that has rights to delete a file.  Is there 
a command I can use to make PHP run a delete command as the admin user?  
If so, how can I do this?


Thanks,

Matt


There are several ways on *nix systems. I would probably write a shell 
script to do the deletions and setuid of the script to root or a user 
with rights to delete the files.  Then just exec() the shell script.


On winbloze you can use the runas command.

-Shawn

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[PHP] Re: Execute command line as a different user

[Matt Palermo]

Okay, I'll have to look into that.  I have very limited knowledge with shell 
scripts.  You wouldn't have an example of one that can do what I need do 
you?


Thanks,

Matt


Shawn McKenzie [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]

Matt palermo wrote:
My PHP is running as a user with limited rights.  I'd like to execute a 
command line as a different user.  I'm trying to delete a file and the 
PHP user doesn't have access to do this.  I know the username and 
password for the admin user that has rights to delete a file.  Is there a 
command I can use to make PHP run a delete command as the admin user?  If 
so, how can I do this?


Thanks,

Matt


There are several ways on *nix systems. I would probably write a shell 
script to do the deletions and setuid of the script to root or a user with 
rights to delete the files.  Then just exec() the shell script.


On winbloze you can use the runas command.

-Shawn 



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Re: [PHP] Strategy to protect images

[Børge Holen]

On Tuesday 01 July 2008 13:34:28 Nitsan Bin-Nun wrote:
 Umm have you ever thought about watermark-ing it? (In case its not a part
 of your website or something..)

heh, this dude got way to much time on his hands... ;D


 On 01/07/2008, Stefano Esposito [EMAIL PROTECTED] wrote:
  On Sun, 15 Jun 2008 13:48:28 +0200
 
  Stefano Esposito [EMAIL PROTECTED] wrote:
   Hi all,
  
   i have to forbid users of my site to view images directly (i.e.
   writing the image URL in the address bar) but they'd be able viewing
   them from the pages of the site. What's the best way of doing it, or
   something similar? Is there a common strategy using PHP? Thank you for
   any hint :-)
  
   Ciao,
   Stefano
 
  Thanks for all of your hints :)
  Here's my solution:
 
  1) disable contextmenu on the images to protect using javascript (just
  to discourage less determined people)
 
  2) for other purposes, the page containing images to protect, is
  brought to users through an ajax request, so they can't so-easily
  look at the source (not with browser's normal 'view source'
  anyway... they would need something like firebug).
 
  3) use a script to get image data (as someone on the list suggested),
  checking for the right $_SERVER['HTTP_REFERER'] (i know... it's not so
  trustworthy... if anyone has a better idea, i'll be glad to listen
  to :))
 
  4) encrypt the relative path of the image on the fly, using mcrypt with
  a key generated on the login and then pass it encoded whit
  base64_encode (with a little workaround for '+', '/' and '=' chars) to
  the image-reading script. So, even if someone can get to the source,
  they'll end up whit an encrypted id of which they don't know neither
  the key nor the encryption method nor even what it's supposed to
  represent (if some database id or a path).
 
  I think that's a good way to prevent image theft... well, unless the
  thief uses the print screen key...
 
  What's your point of view?
 
 
  Ciao,
  Stefano
 
 
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[PHP] Re: Execute command line as a different user

[Shawn McKenzie]

Shawn McKenzie wrote:

Matt palermo wrote:
My PHP is running as a user with limited rights.  I'd like to execute 
a command line as a different user.  I'm trying to delete a file and 
the PHP user doesn't have access to do this.  I know the username and 
password for the admin user that has rights to delete a file.  Is 
there a command I can use to make PHP run a delete command as the 
admin user?  If so, how can I do this?


Thanks,

Matt


There are several ways on *nix systems. I would probably write a shell 
script to do the deletions and setuid of the script to root or a user 
with rights to delete the files.  Then just exec() the shell script.


On winbloze you can use the runas command.

-Shawn


Actually, a quick search shows that many *nix may not let you setuid on
a executable script, so sudo would be an approach.  You should be able 
to setup the apache user in the sudoers file so that it can only run a 
very specif command, such as 'rm /path/to/file/to/delete'.  Then just 
use that:


exec('sudo rm /path/to/file/to/delete');


-Shawn

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Re: [PHP] Strategy to protect images

[Stefano Esposito]

On Tue, 01 Jul 2008 19:59:20 +0200
Børge Holen [EMAIL PROTECTED] wrote:

 On Tuesday 01 July 2008 13:34:28 Nitsan Bin-Nun wrote:
  Umm have you ever thought about watermark-ing it? (In case its not
  a part of your website or something..)
 
 heh, this dude got way to much time on his hands... ;D
 

This dude has commitments, and watermark is not an option.


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[PHP] Splitting up long URLs

[Brian Dunning]

I have a web page that lists most recent comments in a left margin.  
Sometimes people post long URLs, or even just really really long  
words, that force that margin to display way too wide, screwing up the  
page layout. Is there a way to make sure URLs or other text in a  
string gets split up so this doesn't happen?


If there's a CSS solution that's better than a PHP solution I'll take  
that too.   :-)


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Re: [PHP] Splitting up long URLs

[Robert Cummings]

On Tue, 2008-07-01 at 13:26 -0700, Brian Dunning wrote:
 I have a web page that lists most recent comments in a left margin.  
 Sometimes people post long URLs, or even just really really long  
 words, that force that margin to display way too wide, screwing up the  
 page layout. Is there a way to make sure URLs or other text in a  
 string gets split up so this doesn't happen?
 
 If there's a CSS solution that's better than a PHP solution I'll take  
 that too.   :-)

You need to manually chop them. The wordwrap() function should be able
to do it for you. Although, you'll have issues with HTML if I recall
correctly. CSS will not do it for you unless you want to have overflow
and either hide the overflow or have scrollbars appear.

Cheers,
Rob.
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Application and Templating Framework for PHP


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RE: [PHP] Splitting up long URLs

[Boyd, Todd M.]

 -Original Message-
 From: Brian Dunning [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 01, 2008 3:27 PM
 To: php-general@lists.php.net
 Subject: [PHP] Splitting up long URLs
 
 I have a web page that lists most recent comments in a left margin.
 Sometimes people post long URLs, or even just really really long
 words, that force that margin to display way too wide, screwing up the
 page layout. Is there a way to make sure URLs or other text in a
 string gets split up so this doesn't happen?
 
 If there's a CSS solution that's better than a PHP solution I'll take
 that too.   :-)

STFW: http://www.w3.org/TR/css3-text/#white-space

...doesn't say much in the article about whether or not it will break up
words rather than lines, but it's worth a shot.


Todd Boyd
Web Programmer




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[PHP] Re: Execute command line as a different user

[Matt Palermo]

I'm using the following command and I'm not getting any feedback:

exec(echo 'adminPass' | sudo -u adminAccount -S whoami, $f, $r);

Both $f and $r don't contain any data.  This leads me to believe that the 
command is not being run for whatever reason.  Is there something wrong with 
this command?  Is there a different way to do it?


Thanks,

Matt


Matt palermo [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]
My PHP is running as a user with limited rights.  I'd like to execute a 
command line as a different user.  I'm trying to delete a file and the PHP 
user doesn't have access to do this.  I know the username and password for 
the admin user that has rights to delete a file.  Is there a command I can 
use to make PHP run a delete command as the admin user?  If so, how can I 
do this?


Thanks,

Matt 



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[PHP] Re: Execute command line as a different user

[Jon Drukman]

Matt Palermo wrote:

I'm using the following command and I'm not getting any feedback:

exec(echo 'adminPass' | sudo -u adminAccount -S whoami, $f, $r);

Both $f and $r don't contain any data.  This leads me to believe that 
the command is not being run for whatever reason.  Is there something 
wrong with this command?  Is there a different way to do it?


set up sudo to run that particular command for that particular user with 
no password.


adminAccountALL = NOPASSWD: /usr/bin/whoami


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[PHP] Re: V4 Vs V5 Issue

[Jon Drukman]

Neil wrote:


Hi Thanks

I have tested the path, that works fine. I set up a dummy file on the 
same path just to check that,  it found that and printed out some echo'd 
text from that file.


I can see the content of core_js.php file  in the the IE view source view.


debugging javascript in IE is about as much fun as slamming your head in 
a car door.


try it in firefox with firebug installed, it should give you much better 
feedback about what is going on.


-jsd-


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Re: [PHP] CURL de-bugging: So why am I not getting the results page on the target site?

[ioannes]

I didn't get any brave response on this, but given the other thread on 
'encription' I was wondering could anyone decrypt the __VIEWSTATE string 
at the end of this message.  It is part of the input page whose results 
page I am trying to retrieve back onto my server for further php work.  
I replicated the source from that input page onto a page on my server, 
and when I click the submit button it correctly goes to the target 
results page, on the other site though, however it did not work without 
the whole of the string below.  The experiment proved though that 
without the __VIEWSTATE the results page will not return.  So I am just 
wondering, as I have not been able to repeat this using curl, what the 
 is included in that string. There's a challenge for anyone with 
whatever resources it takes.


John


ioannes wrote:

For those that like CURL and calendars.
...

VIEWSTATE

curl_setopt($ch, 

Re: [PHP] Splitting up long URLs

[Nate Tallman]

If you want to do it on the php side, I would do something like this:

a href=$fullURLsubstr($fullURL, 0, 9)/a

It would provide a valid link using the full url, but chop off everything
after the 10th character and replace with a 

Nate

On Tue, Jul 1, 2008 at 3:45 PM, Boyd, Todd M. [EMAIL PROTECTED] wrote:

  -Original Message-
  From: Brian Dunning [mailto:[EMAIL PROTECTED]
  Sent: Tuesday, July 01, 2008 3:27 PM
  To: php-general@lists.php.net
  Subject: [PHP] Splitting up long URLs
 
  I have a web page that lists most recent comments in a left margin.
  Sometimes people post long URLs, or even just really really long
  words, that force that margin to display way too wide, screwing up the
  page layout. Is there a way to make sure URLs or other text in a
  string gets split up so this doesn't happen?
 
  If there's a CSS solution that's better than a PHP solution I'll take
  that too.   :-)

 STFW: http://www.w3.org/TR/css3-text/#white-space

 ...doesn't say much in the article about whether or not it will break up
 words rather than lines, but it's worth a shot.


 Todd Boyd
 Web Programmer




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[PHP] FIFO files on PHP?

[Waynn Lue]

I'm trying to build a queue out using FIFO files (someone on the MySQL
list suggested checking them out instead of using the database), but
I'm running into a problem because of the synchronous fwrite call.
Here's the code:

  $fifoFile = '/tmp/fifo';
  if (!file_exists($fifoFile)) {
posix_mkfifo($fifoFile, 0600);
  }
  $fp = fopen($fifoFile, w);
  fwrite($fp, content);
  fclose($fp);

But this will block until something actually reads the pipe.  Is there
any way to write to the pipe, then go away as opposed to waiting until
something consumes it?  Otherwise, I may just go back to a database
table.

Thanks,
Waynn

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Re: [PHP] Re: V4 Vs V5 Issue

[Neil]

Hi

Unfortunately this editor does not run in any other browsers. however 
I do not believe that it is the java script that is the problem 
because it runs and works and has done so for years on the current 
and earlier V4 servers.


Cheers

Neil
At 07:10 AM 2/07/2008, Jon Drukman wrote:

Neil wrote:

Hi Thanks
I have tested the path, that works fine. I set up a dummy file on 
the same path just to check that,  it found that and printed out 
some echo'd text from that file.

I can see the content of core_js.php file  in the the IE view source view.


debugging javascript in IE is about as much fun as slamming your 
head in a car door.


try it in firefox with firebug installed, it should give you much 
better feedback about what is going on.


-jsd-


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Re: [PHP] V4 Vs V5 Issue

[Jim Lucas]

Neil wrote:

Hi

First Post here, I hope this is the right place for this post.

This is probably not a php problem,  I think it may a configuration 
issue, but sorry I just dont know where to look


I have a V4 site the calls an on line editor and part of the process is 
by window.onload. If I had to explain how it all works I could'nt JS is 
not my thing and this is a fairly old piece of code.


anyways

-- Have a bit of code that looks like this

.
.
body  leftmargin=2 marginwidth=2 topmargin=2 marginheight=2 
onResize=blockDefault();

content;

include($settings['app_dir'].'/js/core_js.php');

echo  content
script LANGUAGE=Javascript
  window.onload=initEditor
/script

table border=0 cellpadding=5 cellspacing=0 width=100% 
height=100% class=framed

.
.
.
--

Under My V4 Sever it works fine .the Java script loads and an all is 
fine.


On my V5 Sever

I get the following Errors

Line: 68
Char: 21
Error: Syntax error
Code: 0
URL: ..
and then

Line: 600
Char: 11
Error 'initEditor' is undefined
Code 0
URL

Now the thing is, when I view source code in IE off both servers the the 
core_js.php is being read and is visible, the initEditor function is 
there for all the world to see.


If I rename the initEditor function on the V5 version and add a new 
empty function I still get the same error messages.


I dont have much hair and I am tearing out the rest as we speak :).I 
have no idea where to look so I am just hoping someone can point me in 
the right direction.


Like I said in the beginning I think it must be a configuration issue 
but I just dont know what or where.


Anyways TIA

Cheers

Neil



 






Two things come to mind.

1) Is their any PHP inside you javascript file that needs to be parsed?  And if 
so, is the new V5 install configured in such a way that it parses/processes 
javascript files? where the old install was processing javascript files.  This 
would be a configuration issue from the actual web server POV.  i.e.  Apache, 
lighttpd, etc...   Once reconfigured, make sure you restart your web server.


2) Is your code using short tags in php?  This allows the programmer to use ? 
instead of ?php   .   In this case you might want to enable short tags in the 
new version of PHP.  I think php 5 comes with short tags disabled and version 4 
had it enabled by default.  This setting would be found in your php.ini file on 
the server.  If you need to change the setting, make sure you restart your httpd 
server before testing.


Just a couple of thoughts

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Re: [PHP] Re: V4 Vs V5 Issue

[Chris]

Neil wrote:
 Hi
 
 Unfortunately this editor does not run in any other browsers. however I
 do not believe that it is the java script that is the problem because it
 runs and works and has done so for years on the current and earlier V4
 servers.

http://www.microsoft.com/downloads/details.aspx?familyid=e59c3964-672d-4511-bb3e-2d5e1db91038displaylang=en

Not as powerful as firebug but it gives you a lot more help than the IE
script debugger.

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Re: [PHP] can you give me example of website using postgresql database?

[paragasu]

i agree, salesman can make a lot of difference influence costumer.
sometimes they are really a headache because salesman not really a
technical person and know nothing about technical info. always
suggesting something complicated and
irrelevant feature to costumer. wtf



On 7/1/08, Will Fitch [EMAIL PROTECTED] wrote:
 Touché, salesman.

 -Original Message-
 From: Lester Caine [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, July 01, 2008 10:21 AM
 To: php-general@lists.php.net
 Subject: Re: [PHP] can you give me example of website using postgresql
 database?

 Will Fitch wrote:
 Assuming that a system should switch RDBMSs is a waste of time without
 knowing the reason is asinine.  Using NDB clustering is a primary reason
 for
 switching.  PostgreSQL is only currently PLANNING built-in replication,
 much
 less clustering.  Not to mention that the existing system is not taking
 advantage of ANY PostgreSQL functionality that is not already present in
 MySQL.  So gaining performance and clustering is reason enough for me.

 You gave no reasons initially ... and with facilities being added all the
 time, the reason to change may evaporate before a change is made?
 Have you looked at the alternatives as well since you seem to have some work

 to do rather than simply changing the data source?

 I'm being told I have to switch to MSSQL or Oracle but the customers can't
 provide justification to do that as yet and since we are only up to a couple

 of gigabytes of data replicated across machines I am always looking for
 informed explanations of why a switch is necessary ;) i.e. why one database
 may be more appropriate than another.

 The lack of proper comparison information does make it difficult at times :(

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[PHP] Re: FIFO files on PHP?

[Al]

Why not simply maintain an array as a file.

$fifoArray= unserialize(file_get_contents($fifoFile));

$oldValue= array_pop($fifoArray);//To pop off old value

array_unshift($fifoArray, $newValue);//To push in new value

$fifoStr= serialize($fifoArray);

file_put_contents($fifoArray, $fifoStr, LOCK_EX);

You can do the same thing by just using:
$fifoArray= file($fifoFile);

..same array_pop() and array_unshift() stuff

file_put_contents($fifoFile, $fifoArray, LOCK_EX);

You'll need to check for an empty array, etc.

Waynn Lue wrote:

I'm trying to build a queue out using FIFO files (someone on the MySQL
list suggested checking them out instead of using the database), but
I'm running into a problem because of the synchronous fwrite call.
Here's the code:

  $fifoFile = '/tmp/fifo';
  if (!file_exists($fifoFile)) {
posix_mkfifo($fifoFile, 0600);
  }
  $fp = fopen($fifoFile, w);
  fwrite($fp, content);
  fclose($fp);

But this will block until something actually reads the pipe.  Is there
any way to write to the pipe, then go away as opposed to waiting until
something consumes it?  Otherwise, I may just go back to a database
table.

Thanks,
Waynn


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Re: [PHP] V4 Vs V5 Issue

[Neil]

Thanks Jim






Two things come to mind.

1) Is their any PHP inside you javascript file that needs to be 
parsed?  And if so, is the new V5 install configured in such a way 
that it parses/processes javascript files? where the old install was 
processing javascript files.  This would be a configuration issue 
from the actual web server POV.  i.e.  Apache, lighttpd, 
etc...   Once reconfigured, make sure you restart your web server.


Yes there is PHP inside the javascript that is being passed. As an 
exorcise  I was just looking at deleting it all out of the code and 
seeing what happens, however it is everywhere.


The Webserver with the V5 PHP is Apache 2.2.4, but I can not really 
see where I would make the changes you are suggesting.


The older server with V4 is Apache 1.34.4

2) Is your code using short tags in php?  This allows the programmer 
to use ? instead of ?php   .   In this case you might want to 
enable short tags in the new version of PHP.  I think php 5 comes 
with short tags disabled and version 4 had it enabled by 
default.  This setting would be found in your php.ini file on the 
server.  If you need to change the setting, make sure you restart 
your httpd server before testing.


Short tags is enabled and working most of the application is short tagged.

Cheers

Neil


Just a couple of thoughts

--
Jim Lucas

   Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them.

Twelfth Night, Act II, Scene V
by William Shakespeare



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[PHP] PHP-CLI and the less command (kubuntu)

[Mattias Thorslund]

Hi everyone,

I have a CLI application that produces lots of output to the terminal, 
so I like to send the output along to the less command. This has 
always worked very nicely. Moving to the top or bottom of the output 
used to require just hitting the home or end key, and the up and 
down arrows as well as page up and page down worked nicely.


After upgrading to Hardy on Kubuntu, the behavior changed. Now, it seems 
to preempt the navigation and instead print ugly codes for each press on 
a navigational key (one of those mentioned above), such as ^[OF. When 
I press enter, the desired scroll is executed. Scrolling up and down 
is one thing, but it's particularly a pain when trying to search through 
the output, as it would no longer look up previous search arguments.


I thought at first it's a problem with Konsole, my terminal program, or 
with less itself. But I've now tried in different terminal programs, 
and reading output other than output from PHP, and the ONLY time it 
happens is when I pipe output from PHP to less. I have added a small 
test script that exhibits the problem on my system. It may work well the 
first time, but when repeating the same command a second time, the 
weird behavior starts.


It could very well be some kind of problem with less, but since I can 
only reproduce the problem with output from PHP CLI, I thought it's 
worth asking here.


Did something about PHP CLI output change lately?

My test script:

?php

$count = 0;
while ($count  100){

   echo This is line number $count\n;
   $count++;
}

?

Execute like so:
$ php test.php | less

First time might work without problem, but subsequent times not.

Thanks for any feedback and observations.

Mattias

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Re: [PHP] Strategy to protect images

[Bastien Koert]

On Tue, Jul 1, 2008 at 2:16 PM, Stefano Esposito [EMAIL PROTECTED] wrote:

 On Tue, 01 Jul 2008 19:59:20 +0200
 Børge Holen [EMAIL PROTECTED] wrote:

  On Tuesday 01 July 2008 13:34:28 Nitsan Bin-Nun wrote:
   Umm have you ever thought about watermark-ing it? (In case its not
   a part of your website or something..)
 
  heh, this dude got way to much time on his hands... ;D
 

 This dude has commitments, and watermark is not an option.


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since the image is sent to the client browser, anyone with enough brains to
look in the cache will be able to access the image. What about setting the
image to show only inside a flash viewer with ming?
-- 

Bastien

Cat, the other other white meat

Re: [PHP] CURL de-bugging: So why am I not getting the results page on the target site?

[Chris]

ioannes wrote:
 I didn't get any brave response on this, but given the other thread on
 'encription' I was wondering could anyone decrypt the __VIEWSTATE string
 at the end of this message.  It is part of the input page whose results
 page I am trying to retrieve back onto my server for further php work. 
 I replicated the source from that input page onto a page on my server,
 and when I click the submit button it correctly goes to the target
 results page, on the other site though, however it did not work without
 the whole of the string below.  The experiment proved though that
 without the __VIEWSTATE the results page will not return.  So I am just
 wondering, as I have not been able to repeat this using curl, what the
  is included in that string. There's a challenge for anyone with
 whatever resources it takes.

echo base64_decode($view_state_string);

viewstate in asp.net is like sessions in php (I believe, I could be
completely wrong :P).

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Re: [PHP] CURL de-bugging: So why am I not getting the results page on the target site?

[Chris]

Chris wrote:
 ioannes wrote:
 I didn't get any brave response on this, but given the other thread on
 'encription' I was wondering could anyone decrypt the __VIEWSTATE string
 at the end of this message.  It is part of the input page whose results
 page I am trying to retrieve back onto my server for further php work. 
 I replicated the source from that input page onto a page on my server,
 and when I click the submit button it correctly goes to the target
 results page, on the other site though, however it did not work without
 the whole of the string below.  The experiment proved though that
 without the __VIEWSTATE the results page will not return.  So I am just
 wondering, as I have not been able to repeat this using curl, what the
  is included in that string. There's a challenge for anyone with
 whatever resources it takes.
 
 echo base64_decode($view_state_string);

or maybe

print_r(base64_decode($view_state_string));

I don't know if it will return a string or an array or something else.

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Re: [PHP] CURL de-bugging: So why am I not getting the results page on the target site?

[Andrew Ballard]

On Tue, Jul 1, 2008 at 5:23 PM, ioannes [EMAIL PROTECTED] wrote:
 I didn't get any brave response on this, but given the other thread on
 'encription' I was wondering could anyone decrypt the __VIEWSTATE string at
 the end of this message.  It is part of the input page whose results page I
 am trying to retrieve back onto my server for further php work.  I
 replicated the source from that input page onto a page on my server, and
 when I click the submit button it correctly goes to the target results page,
 on the other site though, however it did not work without the whole of the
 string below.  The experiment proved though that without the __VIEWSTATE the
 results page will not return.  So I am just wondering, as I have not been
 able to repeat this using curl, what the  is included in that string.
 There's a challenge for anyone with whatever resources it takes.

 John


 ioannes wrote:

 For those that like CURL and calendars.
 ...

 VIEWSTATE

 curl_setopt($ch,
 

Re: [PHP] V4 Vs V5 Issue

[Neil]

Thanks Jim

Will add some more to this.

The PHP that is parsed inside this file and the JS is I think working 
correctly because the values are populated in the JavaScript output 
that is being displayed in the IE source viewer.


For instance there is a stack of variable that are defined up front, 
these get information from PHP, these have the same information as 
the V4 server and I can therefore only presume the correct information.


Cheers N






Two things come to mind.

1) Is their any PHP inside you javascript file that needs to be 
parsed?  And if so, is the new V5 install configured in such a way 
that it parses/processes javascript files? where the old install was 
processing javascript files.  This would be a configuration issue 
from the actual web server POV.  i.e.  Apache, lighttpd, 
etc...   Once reconfigured, make sure you restart your web server.


Yes there is PHP inside the javascript that is being passed. As an 
exorcise  I was just looking at deleting it all out of the code and 
seeing what happens, however it is everywhere.


The Webserver with the V5 PHP is Apache 2.2.4, but I can not really 
see where I would make the changes you are suggesting.


The older server with V4 is Apache 1.34.4

2) Is your code using short tags in php?  This allows the programmer 
to use ? instead of ?php   .   In this case you might want to 
enable short tags in the new version of PHP.  I think php 5 comes 
with short tags disabled and version 4 had it enabled by 
default.  This setting would be found in your php.ini file on the 
server.  If you need to change the setting, make sure you restart 
your httpd server before testing.


Short tags is enabled and working most of the application is short tagged.

Cheers

Neil


Just a couple of thoughts

--
Jim Lucas

   Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them.

Twelfth Night, Act II, Scene V
by William Shakespeare



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