Re: [PHP] Links
:| if i want link 3, $result = mysql_query(SELECT address FROM db.links WHERE link_id=3); $foo = mysql_fetch_assoc($result); echo 'a href='.$foo['address'].'this is link 3/a'; On 3/7/07, StainOnRug [EMAIL PROTECTED] wrote: Hello.. I searched for an answer on the simple quesiton but I am only finding complex answers... I simply just want to add a link in my database so when my results display you can see the information.. and when they click the link it takes them to the webpage of the article. I tried inserting examplesite.com User sees this text but when the results page shows.. it doesnt show the hyperlink.. Thank you all very much! -Darren Thanks again! -- View this message in context: http://www.nabble.com/Links-tf3366303.html#a9365950 Sent from the PHP - General mailing list archive at Nabble.com. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- |~ fedt ~|
Re: [PHP] Launch a seperate process
pcntl_ fork() and pcntl_ wait(), yo On 3/6/07, Brad Fuller [EMAIL PROTECTED] wrote: Is there a way in a php script to launch another script but output something and exit (terminating the original request) before that script finishes? I have a script that accepts data, does some stuff, returns a response and exits. I want that page to accept data, return a response and exit. Then the stuff happens. Make sense? I am STFW right now, but nothing yet. Any advice is much appreciated. Thx, B -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
