Re: [PHP] Dazed and Confused
On Wed, 30 Oct 2002, PHP List wrote: > So are you saying there really is no array pointer? > Lets say I have an array with several different values like: > $myarray["a"] = "s"; > $myarray[3] = "d"; > $myarray["sdf"] = "y"; > There is no way of saying give me the value in the array at position 2? > Since the size of the array is returned as 3, should there not be a way of > doing this? There is an array pointer. It is manipulated using the various iteration functions. reset($myarray); echo next($myarray); would give you the value at the second position. -Rasmus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Dazed and Confused
So are you saying there really is no array pointer?
Lets say I have an array with several different values like:
$myarray["a"] = "s";
$myarray[3] = "d";
$myarray["sdf"] = "y";
There is no way of saying give me the value in the array at position 2?
Since the size of the array is returned as 3, should there not be a way of
doing this?
Like I said, I seem to be blanking on arrays.
> Because you haven't put anything in array index 0. The only array index
> that has anything is "test". There is no difference between numeric and
> string indices. You seem to be assuming that somehow the first element in
> an array can always be accessed as index 0 which is not the case and never
> has been.
>
> -Rasmus
>
> On Wed, 30 Oct 2002, PHP List wrote:
>
> > For some reason my brain is not operating within normal parameters this
week.
> >
> > $myarray["test"] = "sd";
> > echo $myarray[0];
> >
> > Why will nothing echo? Do I somehow have to initialize indexing on the
array $myarray?
> > php says that $myarray is an array, but I can't access it with numeric
indexes.
> >
> > I know if I do this:
> > $myarray = array("test"=>"sd");
> > that I can now echo $myarray[0] and get the value of sd returned.
> >
> >
>
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Re: [PHP] Dazed and Confused
Hello,
"PHP List" <[EMAIL PROTECTED]> wrote:
> For some reason my brain is not operating within normal parameters
> this week.
>
> $myarray["test"] = "sd";
> echo $myarray[0];
>
> Why will nothing echo? Do I somehow have to initialize indexing on
> the array $myarray?
> php says that $myarray is an array, but I can't access it with numeric
> indexes.
That's because your $myarray was set using strings...
> I know if I do this:
> $myarray = array("test"=>"sd");
> that I can now echo $myarray[0] and get the value of sd returned.
Are you sure? Try it :)
- E
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Re: [PHP] Dazed and Confused
Because you haven't put anything in array index 0. The only array index
that has anything is "test". There is no difference between numeric and
string indices. You seem to be assuming that somehow the first element in
an array can always be accessed as index 0 which is not the case and never
has been.
-Rasmus
On Wed, 30 Oct 2002, PHP List wrote:
> For some reason my brain is not operating within normal parameters this week.
>
> $myarray["test"] = "sd";
> echo $myarray[0];
>
> Why will nothing echo? Do I somehow have to initialize indexing on the array
>$myarray?
> php says that $myarray is an array, but I can't access it with numeric indexes.
>
> I know if I do this:
> $myarray = array("test"=>"sd");
> that I can now echo $myarray[0] and get the value of sd returned.
>
>
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[PHP] Dazed and Confused
For some reason my brain is not operating within normal parameters this week.
$myarray["test"] = "sd";
echo $myarray[0];
Why will nothing echo? Do I somehow have to initialize indexing on the array $myarray?
php says that $myarray is an array, but I can't access it with numeric indexes.
I know if I do this:
$myarray = array("test"=>"sd");
that I can now echo $myarray[0] and get the value of sd returned.
