Re: [PHP] Readdir() question
When I need to do 'filesystem' type things I use MySQL to map all of the
files. This offers lot's of versatility in that you could just make a single
folder called filesystem and have all of your files in the root of that
folder - then use mysql to map virtual folders and structures and such.
2008/9/12 Jochem Maas [EMAIL PROTECTED]
Nathan Rixham schreef:
Jochem Maas wrote:
Nathan Rixham schreef:
Stut wrote:
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include
which would give an error on second and subsequent define()s
yet if(!defined... it's already defined so won't be defined subsequent
times :)
my bad
still crap though
yes :-P
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Re: [PHP] Readdir() question
Luke schreef:
When I need to do 'filesystem' type things I use MySQL to map all of the
files. This offers lot's of versatility in that you could just make a single
folder called filesystem and have all of your files in the root of that
folder - then use mysql to map virtual folders and structures and such.
I don't understand what you mean, can you elaborate?
2008/9/12 Jochem Maas [EMAIL PROTECTED]
Nathan Rixham schreef:
Jochem Maas wrote:
Nathan Rixham schreef:
Stut wrote:
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include
which would give an error on second and subsequent define()s
yet if(!defined... it's already defined so won't be defined subsequent
times :)
my bad
still crap though
yes :-P
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Re: [PHP] Readdir() question
Ok,
one folder on your webserver, and put all of the files that you want to
include on your website/system in this folder (also uploading into this
folder); just in the root of that folder, so say you wouldn't have anymore
folders under it.
Make a table called 'Files,' containing:
ID
Name
Type
true_location
virtual_location
(or similar depending on your needs, you might also want a folders table,
perhaps this will increase speed if you are visually displaying the entire
display system.)
the Name, name of the file
Type, type of file, I have this in just so i can easily tell what file it is
and what to do without having to execute more scripts.
true_location, the real location and filename of the file that is placed in
your file
virtual_location, made up location that forms your filesystem
The advantages of mapping real files in a virtual location is that you and
the user can interact with the virtual location like it is really mapped and
keep the versatility of MySQL. Since reading several pieces of
information from MySQL is much faster than reading from files to get it.
For an upload system you would need to write a PHP script on the upload of
the file to add entries to the table. If you are initially placing many
files in there you may want to write a perl/shell/php script to enter all of
the initial file entries for the table for you.
2008/9/12 Jochem Maas [EMAIL PROTECTED]
Luke schreef:
When I need to do 'filesystem' type things I use MySQL to map all of the
files. This offers lot's of versatility in that you could just make a
single
folder called filesystem and have all of your files in the root of that
folder - then use mysql to map virtual folders and structures and such.
I don't understand what you mean, can you elaborate?
2008/9/12 Jochem Maas [EMAIL PROTECTED]
Nathan Rixham schreef:
Jochem Maas wrote:
Nathan Rixham schreef:
Stut wrote:
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include
which would give an error on second and subsequent define()s
yet if(!defined... it's already defined so won't be defined subsequent
times :)
my bad
still crap though
yes :-P
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defiance.bounceme.net/dinosaur/
Re: [PHP] Readdir() question
Luke wrote:
Ok,
one folder on your webserver, and put all of the files that you want to
include on your website/system in this folder (also uploading into this
folder); just in the root of that folder, so say you wouldn't have anymore
folders under it.
Make a table called 'Files,' containing:
ID
Name
Type
true_location
virtual_location
(or similar depending on your needs, you might also want a folders table,
perhaps this will increase speed if you are visually displaying the entire
display system.)
the Name, name of the file
Type, type of file, I have this in just so i can easily tell what file it is
and what to do without having to execute more scripts.
true_location, the real location and filename of the file that is placed in
your file
virtual_location, made up location that forms your filesystem
The advantages of mapping real files in a virtual location is that you and
the user can interact with the virtual location like it is really mapped and
keep the versatility of MySQL. Since reading several pieces of
information from MySQL is much faster than reading from files to get it.
For an upload system you would need to write a PHP script on the upload of
the file to add entries to the table. If you are initially placing many
files in there you may want to write a perl/shell/php script to enter all of
the initial file entries for the table for you.
2008/9/12 Jochem Maas [EMAIL PROTECTED]
Luke schreef:
When I need to do 'filesystem' type things I use MySQL to map all of the
files. This offers lot's of versatility in that you could just make a
single
folder called filesystem and have all of your files in the root of that
folder - then use mysql to map virtual folders and structures and such.
I don't understand what you mean, can you elaborate?
2008/9/12 Jochem Maas [EMAIL PROTECTED]
Nathan Rixham schreef:
Jochem Maas wrote:
Nathan Rixham schreef:
Stut wrote:
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include
which would give an error on second and subsequent define()s
yet if(!defined... it's already defined so won't be defined subsequent
times :)
my bad
still crap though
yes :-P
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i just use DirectoryIterator combined with DOMDocument to create nested
deep directory listing xml files that I can use in any application; i
find the over head v low; and if it was to go high; I'd just cache the
results :p
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RE: [PHP] Readdir() question
-Original Message- From: Luke [mailto:[EMAIL PROTECTED] Sent: Friday, September 12, 2008 7:13 AM To: Jochem Maas Cc: [EMAIL PROTECTED]; php-general@lists.php.net Subject: Re: [PHP] Readdir() question Ok, one folder on your webserver, and put all of the files that you want to include on your website/system in this folder (also uploading into this folder); just in the root of that folder, so say you wouldn't have anymore folders under it. Make a table called 'Files,' containing: ID Name Type true_location virtual_location (or similar depending on your needs, you might also want a folders table, perhaps this will increase speed if you are visually displaying the entire display system.) the Name, name of the file Type, type of file, I have this in just so i can easily tell what file it is and what to do without having to execute more scripts. true_location, the real location and filename of the file that is placed in your file virtual_location, made up location that forms your filesystem The advantages of mapping real files in a virtual location is that you and the user can interact with the virtual location like it is really mapped and keep the versatility of MySQL. Since reading several pieces of information from MySQL is much faster than reading from files to get it. For an upload system you would need to write a PHP script on the upload of the file to add entries to the table. If you are initially placing many files in there you may want to write a perl/shell/php script to enter all of the initial file entries for the table for you. ---8--- snip It would get a bit ugly when you started having files with the same name being stored in that physical directory. Obviously, there are ways to combat this (tack an identifier onto the file name, etc.) but it seems like it's too much work when there is already a methodology in place that works--the underlying filesystem. I guess it would be faster if you cached file attributes (last mod time, owner, etc.) every now and again on some sort of schedule, and read the attributes from the table instead of the file itself... but you've still got to do it in the scheduled job, and your data is stale. Maybe that's okay, maybe that's not. Todd Boyd Web Programmer -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Readdir() question
Hi,
I'm going to make a small browser based file system for ease of small
updates that I make frequently on my Website. First of all I want to loop
all the files on the same directory and to tell PHP read the same directory,
I think I'd need to use the magic constant I think its called, __DIR__ such
as:
?php
$dir=opendir(__DIR__);
while($files=readdir($dir)) {
echo $files;
}
?
But I get a few errors:
*Warning*: opendir(__DIR__) [function.opendir]: failed to open dir: No error
in *C:\wamp\www\Project1\index.php* on line *2*
*Warning*: readdir(): supplied argument is not a valid Directory resource in
*C:\wamp\www\Project1\index.php* on line *3
*Any help in the right direction will be appreciated!
Cheers.
Re: [PHP] Readdir() question
On 11 Sep 2008, at 13:12, Ben Stones wrote:
I'm going to make a small browser based file system for ease of small
updates that I make frequently on my Website. First of all I want
to loop
all the files on the same directory and to tell PHP read the same
directory,
I think I'd need to use the magic constant I think its called,
__DIR__ such
as:
?php
$dir=opendir(__DIR__);
while($files=readdir($dir)) {
echo $files;
}
?
But I get a few errors:
*Warning*: opendir(__DIR__) [function.opendir]: failed to open dir:
No error
in *C:\wamp\www\Project1\index.php* on line *2*
*Warning*: readdir(): supplied argument is not a valid Directory
resource in
*C:\wamp\www\Project1\index.php* on line *3
*Any help in the right direction will be appreciated!
__DIR__ is not a valid constant (yet, I think it may be planned for
5.3/6). You should be developing with notices on - this would have
told you __DIR__ is wrong.
Use dirname(__FILE__) to get what you're after.
-Stut
--
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RE: [PHP] Readdir() question
[snip]
I'm going to make a small browser based file system for ease of small
updates that I make frequently on my Website. First of all I want to
loop
all the files on the same directory and to tell PHP read the same
directory,
I think I'd need to use the magic constant I think its called, __DIR__
such
as:
?php
$dir=opendir(__DIR__);
while($files=readdir($dir)) {
echo $files;
}
?
But I get a few errors:
*Warning*: opendir(__DIR__) [function.opendir]: failed to open dir: No
error
in *C:\wamp\www\Project1\index.php* on line *2*
*Warning*: readdir(): supplied argument is not a valid Directory
resource in
*C:\wamp\www\Project1\index.php* on line *3
*Any help in the right direction will be appreciated!
[/snip]
This really is not the proper use if __DIR__ as it is based on a file
that you are trying to open. This is equivalent to dirname(__FILE__).
which will give you the path of the __FILE__ and hence the directory of
that file. In your case you should specify the file path in $dir
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Re: [PHP] Readdir() question
Ben Stones schreef:
Hi,
I'm going to make a small browser based file system for ease of small
updates that I make frequently on my Website. First of all I want to loop
all the files on the same directory and to tell PHP read the same directory,
I think I'd need to use the magic constant I think its called, __DIR__ such
as:
__DIR__ does not exist unless your using php5.3 ... and your not.
your still not bothering to develop with error_reporting set to 'full'
namely E_ALL | E_STRICT, probably it's set to E_ALL ^ E_NOTICE ... no idea what
I'm talking about?
read this: http://php.net/error_reporting
?php
$dir=opendir(__DIR__);
while($files=readdir($dir)) {
echo $files;
}
?
But I get a few errors:
code you write should check for errors, namely checking to see whether opendir()
failed or not, if it did fail output don't try to loop through the files using
readdir(),
output an error message or something instead.
*Warning*: opendir(__DIR__) [function.opendir]: failed to open dir: No error
in *C:\wamp\www\Project1\index.php* on line *2*
*Warning*: readdir(): supplied argument is not a valid Directory resource in
*C:\wamp\www\Project1\index.php* on line *3
*Any help in the right direction will be appreciated!
Cheers.
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Re: [PHP] Readdir() question
Stut wrote:
On 11 Sep 2008, at 13:12, Ben Stones wrote:
I'm going to make a small browser based file system for ease of small
updates that I make frequently on my Website. First of all I want to loop
all the files on the same directory and to tell PHP read the same
directory,
I think I'd need to use the magic constant I think its called, __DIR__
such
as:
?php
$dir=opendir(__DIR__);
while($files=readdir($dir)) {
echo $files;
}
?
But I get a few errors:
*Warning*: opendir(__DIR__) [function.opendir]: failed to open dir: No
error
in *C:\wamp\www\Project1\index.php* on line *2*
*Warning*: readdir(): supplied argument is not a valid Directory
resource in
*C:\wamp\www\Project1\index.php* on line *3
*Any help in the right direction will be appreciated!
__DIR__ is not a valid constant (yet, I think it may be planned for
5.3/6). You should be developing with notices on - this would have told
you __DIR__ is wrong.
Use dirname(__FILE__) to get what you're after.
-Stut
maybe this is into coding standards and ethics.. but this may be acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include, as it changes on a per directory basis; hence why it'd
/need/ to be a *magic* constant I guess :)
talked myself in and out of that one; but yet still worth a post i fear!
nath
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Re: [PHP] Readdir() question
Nathan Rixham schreef:
Stut wrote:
On 11 Sep 2008, at 13:12, Ben Stones wrote:
I'm going to make a small browser based file system for ease of small
updates that I make frequently on my Website. First of all I want to
loop
all the files on the same directory and to tell PHP read the same
directory,
I think I'd need to use the magic constant I think its called,
__DIR__ such
as:
?php
$dir=opendir(__DIR__);
while($files=readdir($dir)) {
echo $files;
}
?
But I get a few errors:
*Warning*: opendir(__DIR__) [function.opendir]: failed to open dir:
No error
in *C:\wamp\www\Project1\index.php* on line *2*
*Warning*: readdir(): supplied argument is not a valid Directory
resource in
*C:\wamp\www\Project1\index.php* on line *3
*Any help in the right direction will be appreciated!
__DIR__ is not a valid constant (yet, I think it may be planned for
5.3/6). You should be developing with notices on - this would have
told you __DIR__ is wrong.
Use dirname(__FILE__) to get what you're after.
-Stut
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include
which would give an error on second and subsequent define()s
, as it changes on a per directory basis; hence why it'd
/need/ to be a *magic* constant I guess :)
talked myself in and out of that one; but yet still worth a post i fear!
lol
nath
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Re: [PHP] Readdir() question
Jochem Maas wrote:
Nathan Rixham schreef:
Stut wrote:
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto just
in one include
which would give an error on second and subsequent define()s
yet if(!defined... it's already defined so won't be defined subsequent
times :)
still crap though
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Re: [PHP] Readdir() question
Nathan Rixham schreef:
Jochem Maas wrote:
Nathan Rixham schreef:
Stut wrote:
maybe this is into coding standards and ethics.. but this may be
acceptable:
if( !defined('__DIR__') ) {
define('__DIR__' , dirname(__FILE__));
}
however realistically you'd have to do this in every file and nto
just in one include
which would give an error on second and subsequent define()s
yet if(!defined... it's already defined so won't be defined subsequent
times :)
my bad
still crap though
yes :-P
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Re: [PHP] readdir() question
On Tue, August 15, 2006 11:00 pm, John Meyer wrote: Richard Lynch wrote: Do you really mean opendir() or do you mean readdir() ??? readdir(). The point is why do you need to put it as !== vs. != http://us3.php.net/manual/en/language.types.type-juggling.php -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] readdir() question
I have a script to list the files in a directory:
select name=letters
?php
$open = opendir(.);
while ($file = readdir($open) != false) {
?
option value=?=$file??=$file?/option
?php
}
?
/select
/form
And all I am getting are 1s. I think I'm doing it right, what is the
disconnect?
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Re: [PHP] readdir() question
On 15/08/06, John Meyer [EMAIL PROTECTED] wrote:
I have a script to list the files in a directory:
select name=letters
?php
$open = opendir(.);
while ($file = readdir($open) != false) {
?
option value=?=$file??=$file?/option
?php
}
?
/select
/form
And all I am getting are 1s. I think I'm doing it right, what is the
disconnect?
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Straight from the PHP readdir help... http://uk2.php.net/readdir
?php
if ($handle = opendir('.')) {
while (false !== ($file = readdir($handle))) {
if ($file != . $file != ..) {
echo $file\n;
}
}
closedir($handle);
}
?
It does however strip out '.' or '..' but I'm sure you'll get the hang of
it.
HTH
Re: [PHP] readdir() question
On Tue, August 15, 2006 12:04 pm, John Meyer wrote:
I have a script to list the files in a directory:
select name=letters
?php
$open = opendir(.);
while ($file = readdir($open) != false) {
?
option value=?=$file??=$file?/option
?php
}
?
/select
/form
And all I am getting are 1s. I think I'm doing it right, what is
the
disconnect?
It's not a readdir question. It's an Order of Operations question.
:-)
$file = readdir($open) != false
You probably believe that PHP is going to magically know that you
want this bit:
readdir($open) != false
to be done first
But PHP can't read your mind.
It's going to look at the facts of the case.
= and != have equal priority in PHP,
and in case of a tie it will evaluate them left-to-right:
$file = readdir($open)
This gives you the name of the file.
PHP then does the != false bit, comparing the name of a file with false.
Unless your filename starts with one or more '0' characters, and then
has alpha characters for the first non-numeric characters after the
'0's, then it ain't gonna be equal to false, and it will always return
1.
'afile' != false 1
'filename' != false - 1
'000name' != false -- 0
'012name' != false -- 1
You really do need to put the parentheses in there, so PHP does things
in the rigth order, just like the manual says to:
http://php.net/readdir
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Re: [PHP] readdir() question
Richard Lynch wrote:
On Tue, August 15, 2006 12:04 pm, John Meyer wrote:
I have a script to list the files in a directory:
select name=letters
?php
$open = opendir(.);
while ($file = readdir($open) != false) {
?
option value=?=$file??=$file?/option
?php
}
?
/select
/form
And all I am getting are 1s. I think I'm doing it right, what is
the
disconnect?
It's not a readdir question. It's an Order of Operations question.
:-)
$file = readdir($open) != false
You probably believe that PHP is going to magically know that you
want this bit:
readdir($open) != false
to be done first
No, and I fixed that. What I'm wondering about is why this
false !== ($dirhandle = opendir('letters'))
works, but this
($dirhandle = opendir('letters')) != false
does not
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Re: [PHP] readdir() question
On Tue, August 15, 2006 5:56 pm, John Meyer wrote:
Richard Lynch wrote:
On Tue, August 15, 2006 12:04 pm, John Meyer wrote:
I have a script to list the files in a directory:
select name=letters
?php
$open = opendir(.);
while ($file = readdir($open) != false) {
?
option value=?=$file??=$file?/option
?php
}
?
/select
/form
And all I am getting are 1s. I think I'm doing it right, what is
the
disconnect?
It's not a readdir question. It's an Order of Operations question.
:-)
$file = readdir($open) != false
You probably believe that PHP is going to magically know that you
want this bit:
readdir($open) != false
to be done first
No, and I fixed that. What I'm wondering about is why this
false !== ($dirhandle = opendir('letters'))
works, but this
($dirhandle = opendir('letters')) != false
does not
Do you really mean opendir() or do you mean readdir() ???
What value are you getting for $dirhandle?
echo it out and see what it is.
You also have != in one, and !== in the other. Those aren't the same.
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Re: [PHP] readdir() question
Richard Lynch wrote: Do you really mean opendir() or do you mean readdir() ??? readdir(). The point is why do you need to put it as !== vs. != -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] readdir() question
John Meyer wrote: Richard Lynch wrote: Do you really mean opendir() or do you mean readdir() ??? readdir(). The point is why do you need to put it as !== vs. != They mean different things. !== means check the values are not the same AND check their types. != means check the values are not the same. http://www.php.net/manual/en/language.operators.comparison.php -- Postgresql php tutorials http://www.designmagick.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
