Re: [PHP] regular expression question
But how? The +[a-z]{2,} seems to allow at least two a-z clusters, but it
doesn't include a period. /ml
Almost correct. The plus belongs to whatever comes before it, not after.
So what you're referring to as matching two or more characters but not
the period, is this:
[a-z]{2,}
And this will match one or more subdomains:
([-a-z0-9]+\.)+
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[PHP] regular expression question
Hello:
I've adapted this regular expression script from a book, but I'm not
clear why it works.
$email = [EMAIL PROTECTED];
$pattern = /[EMAIL PROTECTED]@([-a-z0-9]+\.)+[a-z]{2,}/;
___
if ( preg_match($pattern,$email) )
{
print yes! . $email . matches!;
}
else { print no match; }
___
When I run this script, I get the yes! [EMAIL PROTECTED]
matches! statement.
But I don't understand why the second half of the regular expression
works. I'm talking about this part:
@([-a-z0-9]+\.)+[a-z]{2,}/;
why is it able to detect repeated sections of the email address after
@ that are separated by periods? like @email.alaska.com . It
looks to me like it's only looking for one example of that pattern.
Does the () allow an unlimited number of patterns to pass?
thanks for any and all guidance
Matthew
Matthew Lasar || llfcc.net
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Re: [PHP] regular expression question
Matthew Lasar wrote:
But I don't understand why the second half of the regular expression
works. I'm talking about this part:
@([-a-z0-9]+\.)+[a-z]{2,}/;
why is it able to detect repeated sections of the email address after
@ that are separated by periods? like @email.alaska.com . It
looks to me like it's only looking for one example of that pattern.
Does the () allow an unlimited number of patterns to pass?
No, but the following '+' does.
/Per Jessen, Zürich
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Re: [PHP] regular expression question
At 11:32 AM 8/31/2007, Per Jessen wrote:
Matthew Lasar wrote:
But I don't understand why the second half of the regular expression
works. I'm talking about this part:
@([-a-z0-9]+\.)+[a-z]{2,}/;
why is it able to detect repeated sections of the email address after
@ that are separated by periods? like @email.alaska.com . It
looks to me like it's only looking for one example of that pattern.
Does the () allow an unlimited number of patterns to pass?
No, but the following '+' does.
But how? The +[a-z]{2,} seems to allow at least
two a-z clusters, but it doesn't include a period. /ml
/Per Jessen, Zürich
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Re: [PHP] regular expression question
Matthew Lasar wrote:
At 11:32 AM 8/31/2007, Per Jessen wrote:
Matthew Lasar wrote:
But I don't understand why the second half of the regular
expression works. I'm talking about this part:
@([-a-z0-9]+\.)+[a-z]{2,}/;
why is it able to detect repeated sections of the email address
after @ that are separated by periods? like @email.alaska.com .
It looks to me like it's only looking for one example of that
pattern. Does the () allow an unlimited number of patterns to
pass?
No, but the following '+' does.
But how? The +[a-z]{2,} seems to allow at least
two a-z clusters, but it doesn't include a period. /ml
That plus applies to the grouping () before it:
([-a-z0-9]+\.)+ one or more sequences of -a-z0-9 followed by a period
/Per Jessen, Zürich
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Re: [PHP] Regular expression question
On 8/11/05, Leon Vismer [EMAIL PROTECTED] wrote: Hi Robin Many thanks for this, how would one extend this to support the following: $str = insert into userComment (userID, userName, userSurname) values (0, 'Leon', 'mcDonald'); one does not want $str = insert into user_comment (user_id, user_name, user_surname) values (0, 'Leon', 'mc_donald'); $match = '/(?=[a-z])(?![Mm]c|[Mm]ac)([A-Z]+)/e'; Should make exceptions for McDonald, mcDonald, MacDonald and macDonald. With luck you don't have any tables called something like appleMacUsers. unfortunately lookbehind assertions does not support non-fixed length chars so /(?=(?!')[a-z])([A-Z]+)/e will work for 'mDonald' but the following will not work. True, lookbehind assertions must be a fixed length - but unlike in perl, they can have alternates which are different fixed lengths: This is illegal, because the length isn't fixed: (?![Mm]a?c) This is fine, because each alternate is fixed even though they are diffferent lengths: (?![Mm]c|[Mm]ac) -robin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Regular expression question
Hi I would like to convert from one naming convention within a sql statement to another. I have the following, code $str = insert into userComment (userID, userName, userSurname) values (0, 'Leon', 'Vismer'); $match = array( /([a-z]+)(ID)/, /([a-z]+)([A-Z])/ ); $replace = array( \$1_id, \$1_\$2 ); $nstr = preg_replace($match, $replace, $str); echo $nstr .\n; /code the above gets me to insert into user_Comment (user_id, user_Name, user_Surname) values (0, 'Leon', 'Vismer') however I want to get to insert into user_comment (user_id, user_name, user_surname) values (0, 'Leon', 'Vismer') Some help from the regex experts ;-) Many thanks -- Leon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regular expression question
n Thu, 11 Aug 2005, Leon Vismer wrote:
Hi
I would like to convert from one naming convention within a sql statement to
another.
I have the following,
code
$str = insert into userComment (userID, userName, userSurname) values (0,
'Leon', 'Vismer');
$match = array(
/([a-z]+)(ID)/,
/([a-z]+)([A-Z])/
);
$replace = array(
\$1_id,
\$1_\$2
);
$nstr = preg_replace($match, $replace, $str);
echo $nstr .\n;
/code
the above gets me to
insert into user_Comment (user_id, user_Name, user_Surname) values (0, 'Leon',
'Vismer')
however I want to get to
insert into user_comment (user_id, user_name, user_surname) values (0, 'Leon',
'Vismer')
Some help from the regex experts ;-)
Just a quick note; why dont' you search on user since it's the constant and
replace 'user[A-Z]' with 'user_[a-z]' or in the case of userID 'user[A-Z]{2}'
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Re: [PHP] Regular expression question
Hi
Just a quick note; why dont' you search on user since it's the constant
and replace 'user[A-Z]' with 'user_[a-z]' or in the case of userID
'user[A-Z]{2}'
This is part of my problem user will not always be constant, I basically want
to be able to change between two naming conventions.
Example:
userID becomes user_id
clientID becomes client_id
tableName becomes table_name
anotherTableName becomes another_table_name
etc.
Thanks
--
Leon
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Re: [PHP] Regular expression question
On 8/11/05, Leon Vismer [EMAIL PROTECTED] wrote: Hi I would like to convert from one naming convention within a sql statement to another. I have the following, code $str = insert into userComment (userID, userName, userSurname) values (0, 'Leon', 'Vismer'); $match = array( /([a-z]+)(ID)/, /([a-z]+)([A-Z])/ ); $replace = array( \$1_id, \$1_\$2 ); ?php $str = insert into userComment (userID, userName, userSurname) values (0, 'Leon', 'Vismer'); $match = '/(?=[a-z])([A-Z]+)/e'; $replace = 'strtolower(_$1)'; print preg_replace($match, $replace, $str); ? insert into user_comment (user_id, user_name, user_surname) values (0, 'Leon', 'Vismer') -robin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regular expression question
Hi Robin Many thanks for this, how would one extend this to support the following: $str = insert into userComment (userID, userName, userSurname) values (0, 'Leon', 'mcDonald'); one does not want $str = insert into user_comment (user_id, user_name, user_surname) values (0, 'Leon', 'mc_donald'); unfortunately lookbehind assertions does not support non-fixed length chars so /(?=(?!')[a-z])([A-Z]+)/e will work for 'mDonald' but the following will not work. /(?=(?!')([a-z]+))([A-Z]+)/e Any ideas? Many thanks -- Leon ?php $str = insert into userComment (userID, userName, userSurname) values (0, 'Leon', 'Vismer'); $match = '/(?=[a-z])([A-Z]+)/e'; $replace = 'strtolower(_$1)'; print preg_replace($match, $replace, $str); ? insert into user_comment (user_id, user_name, user_surname) values (0, 'Leon', 'Vismer') -robin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Regular expression question
So I'm trying to implement a simple wiki-like syntax for hyperlinking. Basically I want to match stuff like [this], where the word 'this' gets turned into a hyperlink. I have that working, but I want to be able to escape the opening bracket, so that it's possible to do \[that] without having it match as a link. Here's what I've got: // Matches fine, but without escaping $pattern = / \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; // Throws an unmatched bracket warning $pattern = / [^\\] # Don't match if a backslash precedes \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; // Ignores escaping: \[example] still matches $pattern = / [^\\\] # Don't match if a backslash precedes \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; Nothing seems to change if I keep adding backslashes to that first matching thingy (i.e. the escaping still doesn't work). Any ideas? Thanks much, -Dan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regular expression question
On Thu, May 27, 2004 at 09:59:05AM -0700, Dan Phiffer wrote: So I'm trying to implement a simple wiki-like syntax for hyperlinking. Basically I want to match stuff like [this], where the word 'this' gets turned into a hyperlink. I have that working, but I want to be able to escape the opening bracket, so that it's possible to do \[that] without having it match as a link. Here's what I've got: // Matches fine, but without escaping $pattern = / \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; // Throws an unmatched bracket warning $pattern = / [^\\] # Don't match if a backslash precedes \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; // Ignores escaping: \[example] still matches $pattern = / [^\\\] # Don't match if a backslash precedes \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; Nothing seems to change if I keep adding backslashes to that first matching thingy (i.e. the escaping still doesn't work). Any ideas? Try negative lookbehinds... $pattern = ' / (?!) \[# open [ not preceded by a backslash (.*?) # ungreedy match anything (?!) \]# close ] not preceded by a backslash /x '; - Rob -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regular expression question
Rob Ellis wrote: On Thu, May 27, 2004 at 09:59:05AM -0700, Dan Phiffer wrote: So I'm trying to implement a simple wiki-like syntax for hyperlinking. Basically I want to match stuff like [this], where the word 'this' gets turned into a hyperlink. I have that working, but I want to be able to escape the opening bracket, so that it's possible to do \[that] without having it match as a link. Here's what I've got: // Matches fine, but without escaping $pattern = / \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; // Throws an unmatched bracket warning $pattern = / [^\\] # Don't match if a backslash precedes \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; // Ignores escaping: \[example] still matches $pattern = / [^\\\] # Don't match if a backslash precedes \[ # Open bracket ([^\]]+?) # Text, including whitespace \] # Close bracket /x ; Nothing seems to change if I keep adding backslashes to that first matching thingy (i.e. the escaping still doesn't work). Any ideas? Try negative lookbehinds... $pattern = ' / (?!) \[# open [ not preceded by a backslash (.*?) # ungreedy match anything (?!) \]# close ] not preceded by a backslash /x '; - Rob BTW, instead of un-greedy maych anything (.*?) You could use a negative groupof course to deal with \] as well you have to do alittle more: ([^\]]|[\]])* -- paperCrane Justin Patrin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Regular expression question
So I want to grab the attributes out of an HTML element. The following works, except in the case that the attribute's value includes the character : if (preg_match_all(/tag([^]*)/i, $subject, $matches)) print_r($matches); A $subject of tag attr=\value\ gives: Array ( [0] = Array ( [0] = ) [1] = Array ( [0] = attr=value ) ) A $subject of tag attr=\\ gives: Array ( [0] = Array ( [0] = Thanks for any help, -Dan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regular expression question
well, first off '' should not be allowed as a value of an attr= pair anyways. You should convert it to gt; or lt; this will solve that problem. Jim Lucas - Original Message - From: Dan Phiffer [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, August 04, 2003 4:03 PM Subject: [PHP] Regular expression question So I want to grab the attributes out of an HTML element. The following works, except in the case that the attribute's value includes the character : if (preg_match_all(/tag([^]*)/i, $subject, $matches)) print_r($matches); A $subject of tag attr=\value\ gives: Array ( [0] = Array ( [0] = ) [1] = Array ( [0] = attr=value ) ) A $subject of tag attr=\\ gives: Array ( [0] = Array ( [0] = Thanks for any help, -Dan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Regular expression question
Actually, this is for a general purpose templating that might use and or [ and ] (i.e. [element attribute=value]), but I suppose the same character entity requirement could be applied to other boundary characters. Somehow it didn't occur to me. Thanks for the response, -Dan Jim Lucas [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] well, first off '' should not be allowed as a value of an attr= pair anyways. You should convert it to gt; or lt; this will solve that problem. Jim Lucas - Original Message - From: Dan Phiffer [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, August 04, 2003 4:03 PM Subject: [PHP] Regular expression question So I want to grab the attributes out of an HTML element. The following works, except in the case that the attribute's value includes the character : if (preg_match_all(/tag([^]*)/i, $subject, $matches)) print_r($matches); A $subject of tag attr=\value\ gives: Array ( [0] = Array ( [0] = ) [1] = Array ( [0] = attr=value ) ) A $subject of tag attr=\\ gives: Array ( [0] = Array ( [0] = Thanks for any help, -Dan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] regular expression question
I've got a regexp:
(EV[0-9]{2})!([0-9]{4}-[0-9]{2}-[0-9]{2})!(GR[0-9]{2}).txt
My question is, will it match this:
EV01!2002-11-09!VR01!GR01.txt
And anything formatted like this: (EV02, and so forth).
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Re: [PHP] regular expression question
It might, you should test it to find out.
John Meyer wrote:
I've got a regexp:
(EV[0-9]{2})!([0-9]{4}-[0-9]{2}-[0-9]{2})!(GR[0-9]{2}).txt
My question is, will it match this:
EV01!2002-11-09!VR01!GR01.txt
And anything formatted like this: (EV02, and so forth).
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[PHP] Regular expression question
Is there a regular expression that will remove 1, L, I, O, 0 and the lowercase equivilants from a varialbe? I am not horribly well versed in regular expressions...so I'm basically asking someone to help :) Say I have a string like this jeD1GLal I want to remove any of the chracters that be confusing ... Jeff -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Regular expression question
Hello, I have a little question regarding regular expressions... I want to check for the pattern $num:: But, $num may not be started with another number (assume the number will be 51 , 1 will also match (the pattern 1:: is available in 51::) ... Currently, my regular expression is: eregi(([^0-9]$num::), $string); But that doesn't seem to work... The other option, the start of a line or a : also didn't work: eregi(([^|:]$sess_id::), $string); Anyone can help me with this? Thanks in advance, Leon Mergen -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Regular expression question
What is $num going to be? A number? So how do you determine where that number ends and where there shouldn't be another number in front of it...are there any restrictions on the size of $num? say $num is 51 then you're saying that you want to match 51:: but not 151:: however, what if $num is 151? see what i mean? - Original Message - From: Leon Mergen [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, November 09, 2001 1:53 PM Subject: [PHP] Regular expression question Hello, I have a little question regarding regular expressions... I want to check for the pattern $num:: But, $num may not be started with another number (assume the number will be 51 , 1 will also match (the pattern 1:: is available in 51::) ... Currently, my regular expression is: eregi(([^0-9]$num::), $string); But that doesn't seem to work... The other option, the start of a line or a : also didn't work: eregi(([^|:]$sess_id::), $string); Anyone can help me with this? Thanks in advance, Leon Mergen -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Regular Expression Question
I want to replace a string like this 1B335-2G with this B335. So for all the strings I want to remove the first character and the last three characters. I'm not sure which replace function to use or how to go about it. Thanks. Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Regular Expression Question
since you know exactly which 4 characters you want to keep you can use a simple string trimming routine. $newstring = substr($string,1,5); No need for complicated regular expressions! - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 21:47 To: PHP Subject: [PHP] Regular Expression Question I want to replace a string like this 1B335-2G with this B335. So for all the strings I want to remove the first character and the last three characters. I'm not sure which replace function to use or how to go about it. Thanks. Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Regular Expression Question correction
$newstring = substr($string,1,4); FOUR, not FIVE. Doh. -Original Message- From: Seb Frost [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 22:03 To: [EMAIL PROTECTED]; PHP Subject: RE: [PHP] Regular Expression Question since you know exactly which 4 characters you want to keep you can use a simple string trimming routine. $newstring = substr($string,1,5); No need for complicated regular expressions! - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 21:47 To: PHP Subject: [PHP] Regular Expression Question I want to replace a string like this 1B335-2G with this B335. So for all the strings I want to remove the first character and the last three characters. I'm not sure which replace function to use or how to go about it. Thanks. Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Regular Expression Question
Aren't the trims just for white space? Jeff Oien since you know exactly which 4 characters you want to keep you can use a simple string trimming routine. I forget the name of the function in php but it's there and it'll be something like trimstring($string,1,5); or something like that. No need for complicated regular expressions either way. - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 21:47 To: PHP Subject: [PHP] Regular Expression Question I want to replace a string like this 1B335-2G with this B335. So for all the strings I want to remove the first character and the last three characters. I'm not sure which replace function to use or how to go about it. Thanks. Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Regular Expression Question
I hope my later message clarifys what I mean. - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 22:05 To: PHP Subject: RE: [PHP] Regular Expression Question Aren't the trims just for white space? Jeff Oien since you know exactly which 4 characters you want to keep you can use a simple string trimming routine. I forget the name of the function in php but it's there and it'll be something like trimstring($string,1,5); or something like that. No need for complicated regular expressions either way. - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 21:47 To: PHP Subject: [PHP] Regular Expression Question I want to replace a string like this 1B335-2G with this B335. So for all the strings I want to remove the first character and the last three characters. I'm not sure which replace function to use or how to go about it. Thanks. Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Regular Expression Question
http://www.php.net/manual/en/function.substr.php string substr (string string, int start [, int length]) Substr returns the portion of string specified by the start and length parameters. If start is positive, the returned string will start at the start'th position in string, counting from zero. For instance, in the string 'abcdef', the character at position 0 is 'a', the character at position 2 is 'c', and so forth. Examples: $rest = substr (abcdef, 1);// returns bcdef $rest = substr (abcdef, 1, 3); // returns bcd -Original Message- From: Seb Frost [mailto:[EMAIL PROTECTED]] Sent: Wednesday, July 25, 2001 5:09 PM To: [EMAIL PROTECTED]; PHP Subject: RE: [PHP] Regular Expression Question I hope my later message clarifys what I mean. - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 22:05 To: PHP Subject: RE: [PHP] Regular Expression Question Aren't the trims just for white space? Jeff Oien since you know exactly which 4 characters you want to keep you can use a simple string trimming routine. I forget the name of the function in php but it's there and it'll be something like trimstring($string,1,5); or something like that. No need for complicated regular expressions either way. - seb -Original Message- From: Jeff Oien [mailto:[EMAIL PROTECTED]] Sent: 25 July 2001 21:47 To: PHP Subject: [PHP] Regular Expression Question I want to replace a string like this 1B335-2G with this B335. So for all the strings I want to remove the first character and the last three characters. I'm not sure which replace function to use or how to go about it. Thanks. Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Regular Expression Question
Hello, I was wondering if there is a way to match a pattern, then delete the entire line containing the pattern. I.E. (if I was searching for pattern in a file containing pattern:info:info:info pattern2:info:info:info pattern3:info:info:info is there a way to delete the entire, and only the first line?) or is there an easier way to just remove a line from a file? thank you Dylan Finney www.healthcoast.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
