RE: [PHP] control structure

[admin]

 -Original Message-
 From: Chris Stinemetz [mailto:chrisstinem...@gmail.com]
 Sent: Thursday, August 04, 2011 11:34 PM
 To: PHP General
 Subject: [PHP] control structure
 
 I have a php script with a simple condition. If it is not satisfied I
 want to exit the script otherwise I want to continue. I am having
 difficulties getting it to work. The script is just exiting..
 
 Please excuse my indention. Gmail tends to distort it.
 
 Thank you,
 
 Chris
 
 This is what i have so far:
 
 if (!session_id())
   {
   session_start();
   }
 if($_SESSION['signed_in'] == false | $_SESSION['user_level'] != 1
 || $_SESSION['user_level'] != 2  )
   {
   //the user is not an admin
   echo 'Sorry, you do not have sufficient rights to access this
 page.br/
 You must be a technician or an engineer to create a store
 visit.';
 
 exit;
   }
   else {
   continue;
 
 
 
 If I get it to continue I want to execute the rest of the script, but
 It will only exit. Current user has user_level of 1 so that is not an
 issue.
 
 Rest of script:
 
 $market = isset($_GET['market']) ? $_GET['market'] :
 $_SESSION['market'];
 $type = isset($_GET['type']) ? $_GET['type'] : $_SESSION['type'];
 $store = isset($_GET['store']) ? $_GET['store'] :
 $_SESSION['store'];
 
 $type = str_replace('-', ' ', $type);
 
 if($_SESSION['type'] != $type)
 {
 $_SESSION['type'] = $type;
 $store = '';
   }
 
 if($_SESSION['market'] != $market)
 {
 $type = '';
 $store = '';
 }
 
 $_SESSION['market'] = $market;
 $_SESSION['type'] = $type;
 $_SESSION['store'] = $store;
 
 $market_name = array();
 $market_prefix = array();
 $type_name = array();
 $market_prefix = array();
 $store_name = array();
 
 
 $query = SELECT * FROM marketcode  ;
 $result = mysql_query($query) or die(report($query,__LINE__
 ,__FILE__)); //(Something went wrong);
 
   while($row = mysql_fetch_array($result))
 {
 $market_name[] = $row['market_name'];
 $market_prefix[] = $row['market_prefix'];
 }
 
 $query = SELECT store_type FROM store_type WHERE market_prefix =
 '$market'  ;
 $result = mysql_query($query) or die(report($query,__LINE__
 ,__FILE__));
 
   while($row = mysql_fetch_array($result))
 {
 $type_name[] = $row['store_type'];
 }
 
 $type_name = array_unique($type_name);
 sort($type_name);
 
 if($type == '')
 {
 $type = $type_name[0];
 $_SESSION['type'] = $type;
 }
 
 $query = SELECT store_name FROM store_list WHERE store_type =
 '$type' AND market_prefix = '$market'   ;
 $result = mysql_query($query) or die(report($query,__LINE__
 ,__FILE__));
 
 while($row = mysql_fetch_array($result))
 {
 $store_name[] = $row['store_name'];
 }
  //   include ('includes/closedb.php');
// close dB
 sort($store_name);
  }
 ?
 
 div id=myspan
 form action=index.php method=post
 table
 tr
 th class=marketMarket/th
 th class=typeStore Type/th
 th class=storeStore Name/th
 /tr
 tr
 td
 select name=market
 onchange=javascript:get(this.parentNode);
   option value=Choose.../option
 ?php
 foreach($market_prefix as $key = $value)
 {
 $selected = '';
 if($value == $market)
 {
 $selected = 'selected';
 }
 //echo(option value=$value $selected
 $value : $market_name[$key]);
   echo 'option
value=',
 htmlspecialchars($value), ' ',
 $selected, '', htmlspecialchars($value.' : '.$market_name[$key]),
 '/option';
 }
 ?
 /select
 /td
 td
 select name=type
 onchange=javascript:get(this.parentNode);
   option value=Choose.../option
 ?php
 foreach($type_name as $value)
 {
 $selected = '';
 if($value == $type)
 {
 $selected = 'selected';
 }
 $v = str_replace(' ', '-', $value);
 //echo(option value=$v $selected
 $value

Re: [PHP] control structure

[Chris Stinemetz]

        // This part makes no sense they are not logged in and they have a
 level of 1 or 2 ?

Yes. It might not be the best approach, but I am assigning the user a
value: 1, 2, or 3 while they create an account. This will limit what
they will be able to post. For example I only want users with user
level of 1 or 2 to be able to complete the form in this script. Hence,
the control structure I am trying to include.

        // And you was missing a Pipe after false. It will cause the If
 statement to fail.

Thanks for pointing this out. I quess I have been staring at the
computer way too long!

Chris

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Re: [PHP] PHP control structure

[Richard Quadling]

On 14 July 2011 05:15, Negin Nickparsa nickpa...@gmail.com wrote:
 if the problem is only the assigning it's an example:
 in mysql you can have this one:
 create table store_list(id_markets int auto_increment,store_type int,primary
 key(id_markets));

 and for page this one:

 html

 head
 titleStore/title
 /head
 form method=post
 ?php
 $connection=Mysql_connect('localhost','admin','123');
 Mysql_select_db('net',$connection);
 if(array_key_exists('sub',$_POST))
 if(isset($_POST['store_type']) )
 {
 $Type =$_POST['store_type'];
 $ID=$_POST['id'];
  $sql =update store_list set store_type=$Type where id_markets=$ID;
 $res = mysql_query($sql,$connection);
 }
 ?
 select name='store_type'
 option value=0store typeoption
 option value=1corporateoption
 option value=2standardoption
 /select
 ID:input type='text' name='id'
 input type='submit' name='sub' value='update the type'
 /form
 /html

 also I didn't understand your code that you have 'id_store' and 'id_markets'
 it's confusing for me

 if it wasn't your problem please clarify your question maybe I can help.


I'd do this in the SQL...


SELECT DISTINCT
store_type,
CASE store_type
WHEN 1 THEN 'Corporate'
WHEN 2 THEN 'Standard'
ELSE 'Unknown store_type ' + CAST(store_type AS VARCHAR())
END AS store_type_desc
FROM
store_list
WHERE
id_markets=$_POST[id];

Though for the text, I'd probably have a store_types table so I can
label them there and hold additional data about the store types if
needed.

SELECT DISTINCT
store_type,
COALESCE(store_type_desc, 'Unknown store_type ' + CAST(store_type AS
VARCHAR())) AS store_type_desc
FROM
store_list
LEFT OUTER JOIN
store_types ON store_list.store_type = store_types.store_type
WHERE
id_markets=$_POST[id];


-- 
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Twitter : EE : Zend : PHPDoc
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea

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Re: [PHP] PHP control structure

[Tamara Temple]

On Jul 12, 2011, at 10:11 PM, Chris Stinemetz wrote:


Hey all,

I would like to add an if statement to the following function so that
the value 1 is assigned corporate and the value is 2 assign
standard to it.  Would you show me an example on adding it to the
below function? If there is a better way to reassign the value please
share.

Thank you,

Chris

public function ShowType()
{
$sql = SELECT DISTINCT store_type FROM store_list WHERE
id_markets=$_POST[id];
$res = mysql_query($sql,$this-conn);
$Type = 'option value=0store type.../option';
while($row = mysql_fetch_array($res))
{
$Type .= 'option value=' . $row['id_store'] . 
'' .
$row['store_type'] . '/option';
}
return $Type;
}

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I'm really not at all clear what you want to do here. Where and how  
are the values going to be used? Where is it determined something is  
corporate or standard? What do these things mean in the context of  
your application?



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Re: [PHP] PHP control structure

[Negin Nickparsa]

if the problem is only the assigning it's an example:
in mysql you can have this one:
create table store_list(id_markets int auto_increment,store_type int,primary
key(id_markets));

and for page this one:

html

head
titleStore/title
/head
form method=post
?php
$connection=Mysql_connect('localhost','admin','123');
Mysql_select_db('net',$connection);
if(array_key_exists('sub',$_POST))
if(isset($_POST['store_type']) )
{
$Type =$_POST['store_type'];
$ID=$_POST['id'];
  $sql =update store_list set store_type=$Type where id_markets=$ID;
$res = mysql_query($sql,$connection);
}
?
select name='store_type'
option value=0store typeoption
option value=1corporateoption
option value=2standardoption
/select
ID:input type='text' name='id'
input type='submit' name='sub' value='update the type'
/form
/html

also I didn't understand your code that you have 'id_store' and 'id_markets'
it's confusing for me

if it wasn't your problem please clarify your question maybe I can help.

[PHP] PHP control structure

[Chris Stinemetz]

Hey all,

I would like to add an if statement to the following function so that
the value 1 is assigned corporate and the value is 2 assign
standard to it.  Would you show me an example on adding it to the
below function? If there is a better way to reassign the value please
share.

Thank you,

Chris

public function ShowType()
{
$sql = SELECT DISTINCT store_type FROM store_list WHERE
id_markets=$_POST[id];
$res = mysql_query($sql,$this-conn);
$Type = 'option value=0store type.../option';
while($row = mysql_fetch_array($res))
{
$Type .= 'option value=' . $row['id_store'] . 
'' .
$row['store_type'] . '/option';
}
return $Type;
}

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[PHP] Control structure - easier way than repeating conditions in IF?

[BOOT]

Hello!

Can anyone tell me if there is an easier/shorthand for:

if  (($x == $a) || ($x == $b) || ($x == $c) || ($x == $d) ... ) {;}


I understand the logic of why the following does not work:

if   ($x == ($a || $b || $c || $d)) {;}




Thanks!

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RE: [PHP] Control structure - easier way than repeating conditions in IF?

[Gryffyn, Trevor]

You could do something like this:


$valuesarr = array($a,$b,$c,$d);

If (in_array($x,$valuesarr)) {
# do something
}


Or I guess even:

If (in_array($x,array($a,$b,$c,$d))) {
# do something
}

I don't know if your method or this method have better performance but
it's a little easier to read I guess.

-TG

 -Original Message-
 From: BOOT [mailto:[EMAIL PROTECTED] 
 Sent: Friday, April 30, 2004 11:49 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Control structure - easier way than repeating 
 conditions in IF?
 
 
 Hello!
 
 Can anyone tell me if there is an easier/shorthand for:
 
 if  (($x == $a) || ($x == $b) || ($x == $c) || ($x == $d) 
 ... ) {;}
 
 
 I understand the logic of why the following does not work:
 
 if   ($x == ($a || $b || $c || $d)) {;}
 
 
 
 
 Thanks!
 
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 To unsubscribe, visit: http://www.php.net/unsub.php
 
 

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Re: [PHP] Control structure - easier way than repeating conditions in IF?

[Neil Freeman]

Why not just use a switch?...

switch ($x) {
case $a:
case $b:
case $c:
case $d:
//do whatever you need
break;
default:
//catch any other values here
break;
}
Neil

BOOT wrote:
***
This Email Has Been Virus Swept
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Hello!

Can anyone tell me if there is an easier/shorthand for:

if  (($x == $a) || ($x == $b) || ($x == $c) || ($x == $d) ... ) {;}

I understand the logic of why the following does not work:

if   ($x == ($a || $b || $c || $d)) {;}



Thanks!

--
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Re: [PHP] Control Structure Syntax Question

[Michal Migurski]

$x ? xxx : xxx

But it makes your code less readable IMHO and offers no tangible benefit
whatsoever.

It offers the tangible benefit of evaluating to something:

return (isset($foo) ? $foo : $bar);

$query = select * from foo
 .(isset($bar) ?  where bar = ${bar} : '');

$foo = ((count($bar)  1) ? 'bars' : 'bar);

-
michal migurski- contact info and pgp key:
sf/cahttp://mike.teczno.com/contact.html

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[PHP] Control Structure Syntax Question

[Ahbaid Gaffoor]

Someone had posted a tip for using an abbreviated form of an if.. else 
structure...

It looked something like:

$x : action1 : action2;

I'm trying to shorten having to do the following:

if ($x) {
 action1;
} else {
 action 2;
}
can someone please post the syntax if they know it? I am reading the 
fine documentation but can't find it...

many thanks

Ahbaid

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Re: [PHP] Control Structure Syntax Question

[daniel]

$x ? action1 : action2;


 structure...

 It looked something like:

 $x : action1 : action2;

 I'm trying to shorten having to do the following:

 if ($x) {
  action1;
 } else {
  action 2;
 }

 can someone please post the syntax if they know it? I am reading the
 fine documentation but can't find it...

 many thanks

 Ahbaid

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Re: [PHP] Control Structure Syntax Question

[Richard Davey]

Hello Ahbaid,

Tuesday, March 9, 2004, 11:42:21 PM, you wrote:

AG Someone had posted a tip for using an abbreviated form of an if.. else
AG structure...

AG It looked something like:

AG $x : action1 : action2;

$x ? xxx : xxx

But it makes your code less readable IMHO and offers no tangible
benefit whatsoever.

-- 
Best regards,
 Richard Davey
 http://www.phpcommunity.org/wiki/296.html

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Re: [PHP] Control Structure Syntax Question

[Ahbaid Gaffoor]

Yeah, but if my code is less readable, my job security goes up ;) (Kidding)

Thanks for all your help folks,

that's what I needed.

regards

Ahbaid

Richard Davey wrote:

Hello Ahbaid,

Tuesday, March 9, 2004, 11:42:21 PM, you wrote:

AG Someone had posted a tip for using an abbreviated form of an if.. else
AG structure...
AG It looked something like:

AG $x : action1 : action2;

$x ? xxx : xxx

But it makes your code less readable IMHO and offers no tangible
benefit whatsoever.
 

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Re: [PHP] Control Structure Syntax Question

[Justin Patrin]

Ahbaid Gaffoor wrote:

Yeah, but if my code is less readable, my job security goes up ;) (Kidding)

Thanks for all your help folks,

that's what I needed.

regards

Ahbaid

Richard Davey wrote:

Hello Ahbaid,

Tuesday, March 9, 2004, 11:42:21 PM, you wrote:

AG Someone had posted a tip for using an abbreviated form of an if.. 
else
AG structure...

AG It looked something like:

AG $x : action1 : action2;

$x ? xxx : xxx

But it makes your code less readable IMHO and offers no tangible
benefit whatsoever.
 

Before this thread dies, I'd like to clarify something. This syntax is 
mostly for inline ifs as what it does is return a value. For example:

$apples = 2;
echo 'There are '.$apples.' apple'.($apples == 1 ? '' : 's').'.';
In this case, it returns a string which is then echoed. This *could* be 
used in place of a normal if, but there is probably an added overhead as 
the value of the last statement is returned. Also, you *must* have an 
else when you use this syntax (even if it does nothing), it cannot be 
used for a simple if.

--
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Re: [PHP] Control Structure Syntax Question

[trlists]

On 9 Mar 2004 Richard Davey wrote:

 $x ? xxx : xxx
 
 But it makes your code less readable IMHO and offers no tangible
 benefit whatsoever.

Ah, to each his/her own I guess ... I actually find:

$value = ($condition ? $val1 : $val2);

easier to read than:

if ($condition)
$value = $val1;
else
$value = $val2;

On the other hand for this:

$value = ($var1  ($var2 == 4)  (($var3 == $var7) || ($var9 ==
hello))) ? htmlspecialchars(strstr($string1, $string2) . test) :
NULL;

I would prefer to use:

if ($var1  ($var2 == 4)  (($var3 == $var7) || ($var9 ==
hello)))
$value = htmlspecialchars(strstr($string1, $string2) . test);
else
$value = NULL;

In other words ... IMO you can use the ?: operator to be concise (which 
increases readability) or to be cryptic (which reduces it).

--
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Re: [PHP] Control Structure problem

[David Robley]

In article [EMAIL PROTECTED], 
[EMAIL PROTECTED] says...
 yeah, i really like using cases they work well and especially if you want to
 do something different for different values, i forgot about that, its a good
 way to do it,
 
 does php have case else? cuz that is a really handy thing in VB that people
 often forget...

You mean 'default'

   switch ($var)  {
 case 'TEST-1': case 'TEST-2': case 'TEST-2':
   do_something();
   break;  // to stop falling through to next option

default:  // any other case not above
  do_other_thing();
  break;  //Not really needed as is last statement but good practice 
   }

And default can appear anywhere in the statement, not just as last item.

Cheers
-- 
Quod subigo farinam

A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet?

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RE: [PHP] Control Structure problem

[Jennifer Goodie]

 This doesnt work as expected.

 if ( $var === TEST ONE || TEST TWO || TEST THREE) {

 do something;

 }

 It returns true on all strings.  Ive tried using the or operator
 and the == but these fail as well.  Any Ideas?

It behaves exactly as expected.  Try checking the manual section on control
structures, I believe it explains that the syntax you are using is invalid.

What you are saying is if ( $var === (TEST ONE || TEST TWO || TEST
THREE)) {
(TEST ONE || TEST TWO || TEST THREE) is always going to evaluate as
true.  I think what you want is
if ( $var === TEST ONE || $var ===  TEST TWO ||  $var === TEST THREE)
{

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Re: [PHP] Control Structure problem

[Luke Skywalker]

try

if ( $var == TEST ONE || $var == TEST TWO || $var == TEST THREE) {

do something;

}

luke
- Original Message - 
From: Dan J. Rychlik [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 9:53 AM
Subject: [PHP] Control Structure problem


This doesnt work as expected.

if ( $var === TEST ONE || TEST TWO || TEST THREE) {

do something;

}

It returns true on all strings.  Ive tried using the or operator and the ==
but these fail as well.  Any Ideas?

-Dan

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Re: [PHP] Control Structure problem

[Dan J. Rychlik]

Thank you guys.  I truly know the level of expertise on this mailing list,
and I know that it proves invaluable.

Thank you again.
-Dan

- Original Message -
From: Luke Skywalker [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, September 16, 2003 7:01 PM
Subject: Re: [PHP] Control Structure problem


 try

 if ( $var == TEST ONE || $var == TEST TWO || $var == TEST THREE) {

 do something;

 }

 luke
 - Original Message -
 From: Dan J. Rychlik [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, September 17, 2003 9:53 AM
 Subject: [PHP] Control Structure problem


 This doesnt work as expected.

 if ( $var === TEST ONE || TEST TWO || TEST THREE) {

 do something;

 }

 It returns true on all strings.  Ive tried using the or operator and the
==
 but these fail as well.  Any Ideas?

 -Dan

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[PHP] Control Structure problem

[Dan J. Rychlik]

This doesnt work as expected.  

if ( $var === TEST ONE || TEST TWO || TEST THREE) {

do something;

}

It returns true on all strings.  Ive tried using the or operator and the == but these 
fail as well.  Any Ideas?

-Dan

Re: [PHP] Control Structure problem

[Luke Skywalker]

I think speaking for everyone its great to be able to help, we all started
somwhere :) i remember getting stuck on the same problem in visual basic
ages ago

Luke

- Original Message - 
From: Dan J. Rychlik [EMAIL PROTECTED]
To: Luke Skywalker [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 10:12 AM
Subject: Re: [PHP] Control Structure problem


 Thank you guys.  I truly know the level of expertise on this mailing list,
 and I know that it proves invaluable.

 Thank you again.
 -Dan

 - Original Message -
 From: Luke Skywalker [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Tuesday, September 16, 2003 7:01 PM
 Subject: Re: [PHP] Control Structure problem


  try
 
  if ( $var == TEST ONE || $var == TEST TWO || $var == TEST THREE) {
 
  do something;
 
  }
 
  luke
  - Original Message -
  From: Dan J. Rychlik [EMAIL PROTECTED]
  To: [EMAIL PROTECTED]
  Sent: Wednesday, September 17, 2003 9:53 AM
  Subject: [PHP] Control Structure problem
 
 
  This doesnt work as expected.
 
  if ( $var === TEST ONE || TEST TWO || TEST THREE) {
 
  do something;
 
  }
 
  It returns true on all strings.  Ive tried using the or operator and the
 ==
  but these fail as well.  Any Ideas?
 
  -Dan
 
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RE: [PHP] Control Structure problem

[Chris W. Parker]

Dan J. Rychlik mailto:[EMAIL PROTECTED]
on Tuesday, September 16, 2003 5:12 PM said:

 Thank you guys.  I truly know the level of expertise on this mailing
 list, and I know that it proves invaluable.

lovingjab
If by I truly know the level of expertise on this mailing list you
meant I truly don't know the basics of PHP syntax, then yeah, you'd be
right. ;) !!
/lovingjab

:)

Chris.

p.s. Or maybe it's me that's doesn't know the basics... ??

p.p.s. I totally think that the syntax you presented is logical and
should be available. It makes much more sense to me to do it the way you
did, but alas...

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Re: [PHP] Control Structure problem

[Luke Skywalker]

yeah, it does make more sense to do it that way for some things, but when
you get ands, and ors, it gets complicated

eg.

if ($a == foo  $b == bar || something){
//do something
}

does that mean $a can either = foo or something or $b = bar or
something?

and thats just a simple example :) but i know it would be really nice in
simple logical expressions

Luke
- Original Message - 
From: Chris W. Parker [EMAIL PROTECTED]
To: Dan J. Rychlik [EMAIL PROTECTED]; Luke Skywalker
[EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 10:18 AM
Subject: RE: [PHP] Control Structure problem


Dan J. Rychlik mailto:[EMAIL PROTECTED]
on Tuesday, September 16, 2003 5:12 PM said:

 Thank you guys.  I truly know the level of expertise on this mailing
 list, and I know that it proves invaluable.

lovingjab
If by I truly know the level of expertise on this mailing list you
meant I truly don't know the basics of PHP syntax, then yeah, you'd be
right. ;) !!
/lovingjab

:)

Chris.

p.s. Or maybe it's me that's doesn't know the basics... ??

p.p.s. I totally think that the syntax you presented is logical and
should be available. It makes much more sense to me to do it the way you
did, but alas...

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Re: [PHP] Control Structure problem

[Curt Zirzow]

* Thus wrote Chris W. Parker ([EMAIL PROTECTED]):
 Dan J. Rychlik mailto:[EMAIL PROTECTED]
 on Tuesday, September 16, 2003 5:12 PM said:
 
  Thank you guys.  I truly know the level of expertise on this mailing
  list, and I know that it proves invaluable.
 

 
 p.p.s. I totally think that the syntax you presented is logical and
 should be available. It makes much more sense to me to do it the way you
 did, but alas...

Well technically you can do it like:

  switch ($var)  {
case 'TEST-1': case 'TEST-2': case 'TEST-2':
  do something
  }


Curt
-- 
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Re: [PHP] Control Structure problem

[Luke Skywalker]

yeah, i really like using cases they work well and especially if you want to
do something different for different values, i forgot about that, its a good
way to do it,

does php have case else? cuz that is a really handy thing in VB that people
often forget...

Luke
- Original Message - 
From: Curt Zirzow [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 10:49 AM
Subject: Re: [PHP] Control Structure problem


 * Thus wrote Chris W. Parker ([EMAIL PROTECTED]):
  Dan J. Rychlik mailto:[EMAIL PROTECTED]
  on Tuesday, September 16, 2003 5:12 PM said:
 
   Thank you guys.  I truly know the level of expertise on this mailing
   list, and I know that it proves invaluable.
 

 
  p.p.s. I totally think that the syntax you presented is logical and
  should be available. It makes much more sense to me to do it the way you
  did, but alas...

 Well technically you can do it like:

   switch ($var)  {
 case 'TEST-1': case 'TEST-2': case 'TEST-2':
   do something
   }


 Curt
 -- 
 I used to think I was indecisive, but now I'm not so sure.

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RE: [PHP] Control Structure problem

[Martin Towell]

are you thinking of default: ?

-Original Message-
From: Luke Skywalker [mailto:[EMAIL PROTECTED]
Sent: Wednesday, 17 September 2003 10:51 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Control Structure problem


yeah, i really like using cases they work well and especially if you want to
do something different for different values, i forgot about that, its a good
way to do it,

does php have case else? cuz that is a really handy thing in VB that people
often forget...

Luke
- Original Message - 
From: Curt Zirzow [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 10:49 AM
Subject: Re: [PHP] Control Structure problem


 * Thus wrote Chris W. Parker ([EMAIL PROTECTED]):
  Dan J. Rychlik mailto:[EMAIL PROTECTED]
  on Tuesday, September 16, 2003 5:12 PM said:
 
   Thank you guys.  I truly know the level of expertise on this mailing
   list, and I know that it proves invaluable.
 

 
  p.p.s. I totally think that the syntax you presented is logical and
  should be available. It makes much more sense to me to do it the way you
  did, but alas...

 Well technically you can do it like:

   switch ($var)  {
 case 'TEST-1': case 'TEST-2': case 'TEST-2':
   do something
   }


 Curt
 -- 
 I used to think I was indecisive, but now I'm not so sure.

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Re: [PHP] Control Structure problem

[Luke Skywalker]

Yeah, thats exactly what im thinking, and speaking of it, im going to start
using it a lot more :)

thanks

Luke
- Original Message - 
From: Martin Towell [EMAIL PROTECTED]
To: 'Luke Skywalker' [EMAIL PROTECTED];
[EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 10:51 AM
Subject: RE: [PHP] Control Structure problem


 are you thinking of default: ?

 -Original Message-
 From: Luke Skywalker [mailto:[EMAIL PROTECTED]
 Sent: Wednesday, 17 September 2003 10:51 AM
 To: [EMAIL PROTECTED]
 Subject: Re: [PHP] Control Structure problem


 yeah, i really like using cases they work well and especially if you want
to
 do something different for different values, i forgot about that, its a
good
 way to do it,

 does php have case else? cuz that is a really handy thing in VB that
people
 often forget...

 Luke
 - Original Message - 
 From: Curt Zirzow [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Wednesday, September 17, 2003 10:49 AM
 Subject: Re: [PHP] Control Structure problem


  * Thus wrote Chris W. Parker ([EMAIL PROTECTED]):
   Dan J. Rychlik mailto:[EMAIL PROTECTED]
   on Tuesday, September 16, 2003 5:12 PM said:
  
Thank you guys.  I truly know the level of expertise on this mailing
list, and I know that it proves invaluable.
  
 
  
   p.p.s. I totally think that the syntax you presented is logical and
   should be available. It makes much more sense to me to do it the way
you
   did, but alas...
 
  Well technically you can do it like:
 
switch ($var)  {
  case 'TEST-1': case 'TEST-2': case 'TEST-2':
do something
}
 
 
  Curt
  -- 
  I used to think I was indecisive, but now I'm not so sure.
 
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  To unsubscribe, visit: http://www.php.net/unsub.php
 
 

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Re: [PHP] Control Structure problem

[Eugene Lee]

On Wed, Sep 17, 2003 at 12:49:03AM +, Curt Zirzow wrote:
: 
:   switch ($var)  {
: case 'TEST-1': case 'TEST-2': case 'TEST-2':
:   do something
:   }

The switch statement doesn't do an equivalency test, does it?  So while
this switch statement can be rewritten as:

if (($var == 'TEST-1') || ($var == 'TEST-1') || ($var == 'TEST-1'))
{
do something
}

it doesn't do:

if (($var === 'TEST-1') || ($var === 'TEST-1') || ($var === 'TEST-1'))
{
do something
}

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Re: [PHP] Control Structure problem

[Curt Zirzow]

* Thus wrote Eugene Lee ([EMAIL PROTECTED]):
 On Wed, Sep 17, 2003 at 12:49:03AM +, Curt Zirzow wrote:

 The switch statement doesn't do an equivalency test, does it?  So while
 this switch statement can be rewritten as:
 
   if (($var == 'TEST-1') || ($var == 'TEST-1') || ($var == 'TEST-1'))
   {
   do something
   }
 
 it doesn't do:
 
   if (($var === 'TEST-1') || ($var === 'TEST-1') || ($var === 'TEST-1'))
   {
   do something
   }

Correct. Although in most cases == is a good enough test.



Curt
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Re[2]: [PHP] Control Structure problem

[Tom Rogers]

Hi,

Wednesday, September 17, 2003, 11:47:45 AM, you wrote:
EL On Wed, Sep 17, 2003 at 12:49:03AM +, Curt Zirzow wrote:
EL : 
EL :   switch ($var)  {
EL : case 'TEST-1': case 'TEST-2': case 'TEST-2':
EL :   do something
EL :   }

EL The switch statement doesn't do an equivalency test, does it?  So while
EL this switch statement can be rewritten as:

EL if (($var == 'TEST-1') || ($var == 'TEST-1') || ($var == 'TEST-1'))
EL {
EL do something
EL }

EL it doesn't do:

EL if (($var === 'TEST-1') || ($var === 'TEST-1') || ($var === 'TEST-1'))
EL {
EL do something
EL }


You can do it this way I think :)


switch (true)  {
 case ($var === 'TEST-1')?true:false:
 case ($var === 'TEST-2')?true:false:
 case ($var === 'TEST-2')?true:false:
   do something
}

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Re: [PHP] Control Structure problem

[Eugene Lee]

On Wed, Sep 17, 2003 at 01:29:26PM +1000, Tom Rogers wrote:
: Wednesday, September 17, 2003, 11:47:45 AM, Eugene Lee wrote:
: 
: EL The switch statement doesn't do an equivalency test, does it?
[...]
: EL it doesn't do:
: 
: EL if (($var === 'TEST-1') ||
: EL($var === 'TEST-1') ||
: EL($var === 'TEST-1'))
: EL {
: EL do something
: EL }
: 
: You can do it this way I think :)
: 
: switch (true)  {
:  case ($var === 'TEST-1')?true:false:
:  case ($var === 'TEST-2')?true:false:
:  case ($var === 'TEST-2')?true:false:
:do something
: }

Oh man, that's just sick...

I guess, for the sake of performance and readability, it's probably
easier to do an is_string($var) (or whatever variable type) before
doing a normal switch statement.

Still... that's just sick...

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Re: [PHP] Control Structure problem

[Chris Shiflett]

--- Eugene Lee [EMAIL PROTECTED] wrote:
 : switch (true)  {
 :  case ($var === 'TEST-1')?true:false:
 :  case ($var === 'TEST-2')?true:false:
 :  case ($var === 'TEST-2')?true:false:
 :do something
 : }
 
 Oh man, that's just sick...

Partially because it's unnecessarily complex. This is like saying:

if ($var === 'TEST-1')
{
 $expression = true;
}
else
{
 $expression = false;
}

if ($expression)
{
 ...

While the ternary operator makes this redundancy less obvious, it only adds to
the complexity and lack of readability. Consider the following code as a
substitute for the above example:

if ($var === 'TEST-1')
{
 ...

Hopefully that part is clear. Now, on to the original question. Try this
example:

?
$foo = 'bar';
switch (true)
{
case ($foo === 'notbar'):
echo 'A';
break;
case ($foo === 'bar');
echo 'B';
break;
default:
echo 'C';
break;
}
?

This should output B. You will also notice that it works when you switch on
$foo instead of the boolean true, but this is misleading. PHP converts $foo to
the boolean true when comparing to the expressions, because we set it to the
string bar. To understand this point further, try this example:

?
$foo = 0;
switch ($foo)
{
case ($foo === 'notbar'):
echo 'A';
break;
case ($foo === 0);
echo 'B';
break;
default:
echo 'C';
break;
}
?

This should also output B. That seems to be wrong, but in this case it is
comparing each expression to $foo, which is the integer 0 in this case, so it
evaluates to false. So, you will see A, because ($foo === 'notbar') also
evaluates to false.

Recap:
1. You can switch on anything, including boolean values.
2. Your cases can be expressions to be evaluated.

Hope that helps.

Chris

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Re: Re[2]: [PHP] Control Structure problem

[Chris Shiflett]

--- Tom Rogers [EMAIL PROTECTED] wrote:
 This is why you need this construct
 
 $foo = 0;
 switch (true)

You must have missed example 1. :-)

 which now works as expected

Both examples work as expected, of course.

Chris

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Re: [PHP] control structure question

[Miguel Cruz]

On Tue, 23 Jul 2002, Javier Montserat wrote:
 So refering back, i re-wrote the original example using the switch syntax...
 
 switch (true) {
 case doStep1():
 case doStep2():
 case doStep3():
   error();
   break;
 default:
   valid();
 }
 
 Each case expressions is evaluated, until one of them evaluates to a value 
 equal (==) to the switch expression (in this case a boolean error flag).
 
 The error() code will only be called if one of the doStep() evaluates to 
 false.
 
 And the valid() code will only be evaluated if the switch reached the 
 default, which means that none of the above check returned false
 
 I think for this example the switch syntax is more elegant than using a 
 series of if() statements.

That's pretty clever!

miguel


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[PHP] control structure question

[Javier Montserat]

is there a more programmatically elegant way of saying...

$isError = ;

function main() {

doStep1();

if (!$isError) {
doStep2();
}

if (!$isError) {
doStep3();
}
// etc. etc.
}

function doStep1() {
if ($something) {
$isError = 1;
}
}

function doStep2() {
if ($something) {
$isError = 1;
}
}

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Re: [PHP] control structure question

[Martin Clifford]

For steps and sequences, I always use switches.  Most commonly associated with the 
action variable, it would look like this:

switch($action) {
   default:
  // what to show if no variable exists, or is set to a value
  // that is not acceptable below
   break;
   case add_file:
  // what to do in the even that a file needs to be added
  // to the database.
   break;
   case remove_file:
  // what to do in the even that a file need sto be removed
  // from the database.
   break;
}

Basically, whatever the value of $action, that is what section of code will execute.  
Hope that helps!

Martin Clifford
Homepage: http://www.completesource.net
Developer's Forums: http://www.completesource.net/forums/


 Javier Montserat [EMAIL PROTECTED] 07/23/02 10:03AM 
is there a more programmatically elegant way of saying...

$isError = ;

function main() {

doStep1();

if (!$isError) {
doStep2();
}

if (!$isError) {
doStep3();
}
// etc. etc.
}

function doStep1() {
if ($something) {
$isError = 1;
}
}

function doStep2() {
if ($something) {
$isError = 1;
}
}

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Re: [PHP] control structure question

[Javier Montserat]

So refering back, i re-wrote the original example using the switch syntax...

switch (true) {
case doStep1():
case doStep2():
case doStep3():
  error();
  break;
default:
  valid();
}

Each case expressions is evaluated, until one of them evaluates to a value 
equal (==) to the switch expression (in this case a boolean error flag).

The error() code will only be called if one of the doStep() evaluates to 
false.

And the valid() code will only be evaluated if the switch reached the 
default, which means that none of the above check returned false

I think for this example the switch syntax is more elegant than using a 
series of if() statements.

Thanks,
Javier

For steps and sequences, I always use switches.  Most commonly associated 
with the action variable, it would look like this:

switch($action) {
default:
   // what to show if no variable exists, or is set to a value
   // that is not acceptable below
break;
case add_file:
   // what to do in the even that a file needs to be added
   // to the database.
break;
case remove_file:
   // what to do in the even that a file need sto be removed
   // from the database.
break;
}

Basically, whatever the value of $action, that is what section of code will 
execute.  Hope that helps!

Martin Clifford
Homepage: http://www.completesource.net
Developer's Forums: http://www.completesource.net/forums/


  Javier Montserat [EMAIL PROTECTED] 07/23/02 10:03AM 
is there a more programmatically elegant way of saying...

$isError = ;

function main() {

 doStep1();

 if (!$isError) {
 doStep2();
 }

 if (!$isError) {
 doStep3();
 }
 // etc. etc.
}

function doStep1() {
 if ($something) {
 $isError = 1;
 }
}

function doStep2() {
 if ($something) {
 $isError = 1;
 }
}

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[PHP] Control Structure Problem

[Jeff Oien]

This is driving me nuts. I couldn't sleep much last night trying
to figure this out. 

This code assigns rooms to kids signing up for Sunday school
at a very large church. Each subsequent registration is put into
the next room on the list. It looks up in the MySQL database
 the room the last person in that age category and hour was 
assigned and assigns the current person the next one. If someone 
is the first person they get assigned the first room. However if
they are the first person ${newroom.$x} doesn't get assigned
to anything. But thereafter it works fine. I've had a couple other
problems and am wondering if there is a better way to do this
or if I have any syntax problems. Thanks.
Jeff Oien

$x = 1;
while ($x = $Number_Children) {

if (${category.$x} == 'SS KidZone - Kindergarten') {

if ((${Grade.$x}) == 'K'  (${selection.$x}) == '2nd Hour') {
$sql = SELECT * FROM $table_name WHERE Category = 'SS KidZone - Kindergarten' 
 Element1 = '2nd Hour' ORDER by ID desc;
$result = @mysql_query($sql,$connection) or die(Couldn't execute query);

if ($row = mysql_fetch_array($result)) {
$room = $row['Element2'];

if ($room == 'C143 Pink Check') {
${newroom.$x} = 'C143 Pink Dot';
}
if ($room == 'C143 Pink Dot') {
${newroom.$x} = 'C148 Teal Check';
}
if ($room == 'C148 Teal Check') {
${newroom.$x} = 'C148 Teal Dot';
}
if ($room == 'C148 Teal Dot') {
${newroom.$x} = 'C143 Pink Check';
}
}
else { ${newroom.$x} = 'C143 Pink Check'; }
}

do database insertion

}
$x++;
}

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RE: [PHP] Control Structure Problem

[Jeff Oien]

I forgot to say I deleted tabs so that the width might fit in a 
typical mail reader.
Jeff Oien

 This code assigns rooms to kids signing up for Sunday school
 at a very large church. Each subsequent registration is put into
 the next room on the list. It looks up in the MySQL database
  the room the last person in that age category and hour was 
 assigned and assigns the current person the next one. If someone 
 is the first person they get assigned the first room. However if
 they are the first person ${newroom.$x} doesn't get assigned
 to anything. But thereafter it works fine. I've had a couple other
 problems and am wondering if there is a better way to do this
 or if I have any syntax problems. Thanks.
 Jeff Oien
 
 $x = 1;
 while ($x = $Number_Children) {
 
 if (${category.$x} == 'SS KidZone - Kindergarten') {
   
 if ((${Grade.$x}) == 'K'  (${selection.$x}) == '2nd Hour') {
 $sql = SELECT * FROM $table_name WHERE Category = 'SS KidZone - Kindergarten' 
  Element1 = '2nd Hour' ORDER by ID desc;
 $result = @mysql_query($sql,$connection) or die(Couldn't execute query);
 
 if ($row = mysql_fetch_array($result)) {
 $room = $row['Element2'];
 
 if ($room == 'C143 Pink Check') {
 ${newroom.$x} = 'C143 Pink Dot';
 }
 if ($room == 'C143 Pink Dot') {
 ${newroom.$x} = 'C148 Teal Check';
 }
 if ($room == 'C148 Teal Check') {
 ${newroom.$x} = 'C148 Teal Dot';
 }
 if ($room == 'C148 Teal Dot') {
 ${newroom.$x} = 'C143 Pink Check';
 }
 }
 else { ${newroom.$x} = 'C143 Pink Check'; }
 }
 
 do database insertion
 
 }
 $x++;
 }
 
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