Re: [PHP] php's variables javascript
On Tue, 28 May 2002, burak delice wrote: I want to make a php that include javascript that use a php variable. Code is below: ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ wdth=;$size;echo;; echo /script; ? (I am calling that php file as below) http://localhost/Aksu/web/getimage.php?resim=K00.jpg But explore gives me an javascript error that syntax error. Why? and how can do my purpose? For one thing, wdth is a misspelling of width. What do you see when you view the source that gets sent to the browser? miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] php's variables javascript
hi everyone, I want to make a php that include javascript that use a php variable. Code is below: ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ wdth=;$size;echo;; echo /script; ? (I am calling that php file as below) http://localhost/Aksu/web/getimage.php?resim=K00.jpg But explore gives me an javascript error that syntax error. Why? and how can do my purpose? thanks burak delice -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php's variables javascript
burak delice wrote: hi everyone, I want to make a php that include javascript that use a php variable. Code is below: ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ wdth=;$size;echo;; echo /script; ? I didn't get the third line.. That's no JavaScript.. Isn't this supposed to be something like: ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ echo document.writeln('width=\$size\');; echo /script; ? -- Best Regards, Sagie Maoz [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php's variables javascript
On Tuesday 28 May 2002 05:59, burak delice wrote: I want to make a php that include javascript that use a php variable. Code is below: No need to post twice. ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ wdth=;$size;echo;; echo /script; ? That code looks broken to me. (I am calling that php file as below) http://localhost/Aksu/web/getimage.php?resim=K00.jpg But explore gives me an javascript error that syntax error. Why? and how can do my purpose? Did you use view source (ALT-V, C) to see what is actually in the script ... ... /script ? -- Jason Wong - Gremlins Associates - www.gremlins.com.hk Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * /* The lymbic system in my brain is so electrically active, it qualifies as a third brain. Normal humans have two brains, left and right. - Jeff Merkey */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] php's variables javascript
Try something like that: ? //$size = GetImageSize (images/$resim); $size = 222; echo script language=\JavaScript\; echo width=; echo $size; echo ;; echo /script; ? Cheers, boyan -- Boyan Nedkov [EMAIL PROTECTED] -Original Message- From: burak delice [mailto:[EMAIL PROTECTED]] Sent: Monday, May 27, 2002 11:59 PM To: [EMAIL PROTECTED] Subject: [PHP] php's variables javascript hi everyone, I want to make a php that include javascript that use a php variable. Code is below: ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ wdth=;$size;echo;; echo /script; ? (I am calling that php file as below) http://localhost/Aksu/web/getimage.php? resim=K00.jpg But explore gives me an javascript error that syntax error. Why? and how can do my purpose? thanks burak delice -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php's variables javascript
Or something easier... ? $size = 222; print HTML script language=JavaScript width = $size; /script HTML; ? Just make sure the HTML; bit is all the way on the left margin, regardless of tabstops in your code. cheers, Brad Boyan Nedkov wrote: Try something like that: ? //$size = GetImageSize (images/$resim); $size = 222; echo script language=\JavaScript\; echo width=; echo $size; echo ;; echo /script; ? Cheers, boyan -- Boyan Nedkov [EMAIL PROTECTED] -Original Message- From: burak delice [mailto:[EMAIL PROTECTED]] Sent: Monday, May 27, 2002 11:59 PM To: [EMAIL PROTECTED] Subject: [PHP] php's variables javascript hi everyone, I want to make a php that include javascript that use a php variable. Code is below: ? $size = GetImageSize (images/$resim); echo script language=\JavaScript\ wdth=;$size;echo;; echo /script; ? (I am calling that php file as below) http://localhost/Aksu/web/getimage.php? resim=K00.jpg But explore gives me an javascript error that syntax error. Why? and how can do my purpose? thanks burak delice -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php