Re: [PHP] Capturing output of shell script.
- Original Message - From: Brad Hubbard [EMAIL PROTECTED] To: Charles Williams [EMAIL PROTECTED]; Php-General (E-mail) [EMAIL PROTECTED] Sent: Saturday, June 30, 2001 1:12 PM Subject: Re: [PHP] Capturing output of shell script. On Sat, 30 Jun 2001 06:36, Charles Williams wrote: Hello all, I have an .sh shell script being executed from a php4 call. I need to capture the string return and work with that in the php script. The only problem is that the call works but I cannot get the returned string. I've tried using exec, passthru, ``, system, and escapeshellcommand. Nothing seems to work. any ideas? $capture = `script.sh 21`; // redirect standard error to standard output Cheers, Brad Brad, Here is what I am trying to execute: $pass_string = super cadduser -f \.$full_name.\ -u \.$Username.\ -p \.$Password.\ -q \.$Quota.\ -x -d .$top_domain; exec($pass_string, $ary_result); echo Result: ; #var_dump($ary_result); return $ary_result; For some reason it will only continue execution past the 'exec' call rarely. Most of the time the script just stops after the exec call (the echo and below is not executed). When it does go beyond the 'exec' call the var_dump (that I use for testing only. will be gone when working) does show as an array. I have the max_execution_time set to 180 so I know the script isn't timeing out. Any ideas? I have never run into this problem before. thanks chuck -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Capturing output of shell script.
correction below chuck - Original Message - From: Charles Williams [EMAIL PROTECTED] To: [EMAIL PROTECTED]; Php-General (E-mail) [EMAIL PROTECTED] Sent: Monday, July 02, 2001 10:54 PM Subject: Re: [PHP] Capturing output of shell script. - Original Message - From: Brad Hubbard [EMAIL PROTECTED] To: Charles Williams [EMAIL PROTECTED]; Php-General (E-mail) [EMAIL PROTECTED] Sent: Saturday, June 30, 2001 1:12 PM Subject: Re: [PHP] Capturing output of shell script. On Sat, 30 Jun 2001 06:36, Charles Williams wrote: Hello all, I have an .sh shell script being executed from a php4 call. I need to capture the string return and work with that in the php script. The only problem is that the call works but I cannot get the returned string. I've tried using exec, passthru, ``, system, and escapeshellcommand. Nothing seems to work. any ideas? $capture = `script.sh 21`; // redirect standard error to standard output Cheers, Brad Brad, Here is what I am trying to execute: $pass_string = super cadduser -f \.$full_name.\ -u \.$Username.\ -p \.$Password.\ -q \.$Quota.\ -x -d .$top_domain; The above should be one line. exec($pass_string, $ary_result); echo Result: ; #var_dump($ary_result); return $ary_result; For some reason it will only continue execution past the 'exec' call rarely. Most of the time the script just stops after the exec call (the echo and below is not executed). When it does go beyond the 'exec' call the var_dump (that I use for testing only. will be gone when working) does show as an array. I have the max_execution_time set to 180 so I know the script isn't timeing out. Any ideas? I have never run into this problem before. thanks chuck -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Capturing output of shell script.
On 29-Jun-01 Charles Williams wrote:
Hello all,
I have an .sh shell script being executed from a php4 call. I need to
capture the string return and work with that in the php script. The only
problem is that the call works but I cannot get the returned string. I've
tried using exec, passthru, ``, system, and escapeshellcommand. Nothing
seems to work. any ideas?
$cmd='stuff.sh';
$p=popen($cmd, 'r');
if ($p) {
while ($str=fgetss($p,1000)) {
do_foo($str);
}
pclose($p);
} else {
echo Pphsst. bad command: $cmd BR;
}
Regards,
--
Don Read [EMAIL PROTECTED]
-- It's always darkest before the dawn. So if you are going to
steal the neighbor's newspaper, that's the time to do it.
--
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Re: [PHP] Capturing output of shell script.
On Sat, 30 Jun 2001 06:36, Charles Williams wrote: Hello all, I have an .sh shell script being executed from a php4 call. I need to capture the string return and work with that in the php script. The only problem is that the call works but I cannot get the returned string. I've tried using exec, passthru, ``, system, and escapeshellcommand. Nothing seems to work. any ideas? $capture = `script.sh 21`; // redirect standard error to standard output Cheers, Brad -- Brad Hubbard Congo Systems 12 Northgate Drive, Thomastown, Victoria, Australia 3074 Email: [EMAIL PROTECTED] Ph: +61-3-94645981 Fax: +61-3-94645982 Mob: +61-419107559 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
