RE: [PHP] Problem with arrays
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Hi,
I have 2 arrays:
Array (
[0] = Array (
[0] = 28
[1] = Music
)
[1] = Array (
[0] = 5
[1] = Books
)
)
and
Array (
[0] = aaa
[1] = bbb
)
I want to join this two array and the result must be loke this:
Array (
[0] = Array (
[0] = 28
[1] = Music
[2] = aaa
)
[1] = Array (
[0] = 5
[1] = Books
[2] = bbb
)
)
Thanks in advance for your help
In this specific example, I think this would work:
?
for ($i = 0; $i count($second_array); $i++) {
array_push($first_array[$i], $second_array[$i]);
}
?
That's not terribly flexible, though. Is this used in a more generalized
sense, or is it just this specific instance?
--
Mike Johnson Smarter Living, Inc.
Web Developerwww.smartertravel.com
[EMAIL PROTECTED] (617) 886-5539
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with arrays
Mike Johnson wrote:
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Hi,
I have 2 arrays:
Array (
[0] = Array (
[0] = 28
[1] = Music
)
[1] = Array (
[0] = 5
[1] = Books
)
)
and
Array (
[0] = aaa
[1] = bbb
)
I want to join this two array and the result must be loke this:
Array (
[0] = Array (
[0] = 28
[1] = Music
[2] = aaa
)
[1] = Array (
[0] = 5
[1] = Books
[2] = bbb
)
)
Thanks in advance for your help
In this specific example, I think this would work:
?
for ($i = 0; $i count($second_array); $i++) {
array_push($first_array[$i], $second_array[$i]);
}
?
That's not terribly flexible, though. Is this used in a more generalized
sense, or is it just this specific instance?
This variation of Mike's solution will allow the array keys to be non-numeric and/or non-incrementing.
?php
foreach($second_array as $key=$value) {
if(array_key_exists($key, $first_array)) {
array_push($first_array[$key], $value);
} else {
print 'ERROR: Key '.$key.' does not exist in array $first_array.\n';
// or alternatively to add a new sub-array to $first_array
// $first_array[$key] = array($value);
}
}
?
--Bob
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with arrays
for ($i = 0; $i count($array1); i++) $array1[$i][] = $array2[$i]; from kevin l'huillier -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with arrays
On 24/06/05, Josh Olson [EMAIL PROTECTED] wrote: for ($i = 0; $i count($array1); i++) $array1[$i][] = $array2[$i]; from kevin l'huillier That's basically what Mike wrote (only with array_push instead of []), and Bob improved upon. And they didn't mix the arrays up. I was only making the point that the solution was simple with a quick comment in IRC. I had not intended for it to be posted to the list. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Problem with arrays
[snip] form action=products.php method=post input name=position[pos][$value] type=text id=position[pos][$value] value=number 1 input name=position[pos][$value] type=text id=position[pos][$value] value=number 2 input name=position[pos][$value] type=text id=position[pos][$value] value=number 3 /form Note that $value from position[pos][$value] is different in all 3 fields. For each element of the array i want to update the value in the database. For example, for each value of the position[pos][$value] i want to update the database with the specific number. Something like this: $query = UPDATE table SET value = 'number 1' WHERE id='$value'; [/snip] On Good Friday, when traffic is really slow, we have someone who wants to post their problem over and over again.cool Lets start simply, shall we? http://www.php.net/print_r -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with Arrays?
At 13:46 22.02.2003, Patrick Teague said:
[snip]
here's what I had that didn't print anything other than 3 blank lines for
this section of code -
$byteSize[0] = bytes;
$byteSize[1] = kb;
$byteSize[2] = mb;
function getMaxSize( $maxSize )
{
echo $byteSize[0] . br/\n;
echo $byteSize[1] . br/\n;
echo $byteSize[2] . br/\n;
}
[snip]
if you declare $bytesize global within the function it will work:
function getMaxSize( $maxSize )
{
global $bytesize;
echo $byteSize[0] . br/\n;
}
You'd be still better off passing the array as variable:
function getMaxSize( $bytesize, $maxSize )
{
echo $byteSize[0] . br/\n;
}
And lastly, for performance issues, pass it as a reference:
function getMaxSize( $bytesize, $maxSize )
{
echo $byteSize[0] . br/\n;
}
Without a reference, the array is copied to the function. By passing a
reference the function is working on the original array, no copy overhead.
Note: When passed as reference, any modification on the array within the
function will effect the original array (same is true if declared global).
Without reference the original array remains unchanged.
--
O Ernest E. Vogelsinger
(\)ICQ #13394035
^ http://www.vogelsinger.at/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Problem with Arrays?
on 22/02/03 11:46 PM, Patrick Teague ([EMAIL PROTECTED]) wrote:
I ran into something interesting the only thing I can figure out is that
functions won't use any variables other than globals, those past to the
function, or those created inside the function?
exactly :)
you bring the array or variable into the scope of the function
?
$byteSize[0] = bytes;
$byteSize[1] = kb;
$byteSize[2] = mb;
function getMaxSize( $maxSize )
{
global $byteSize;
echo $byteSize[0] . br/\n;
echo $byteSize[1] . br/\n;
echo $byteSize[2] . br/\n;
}
?
Justin French
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
