RE: [PHP] unexpected include parse error
On 27 January 2004 05:50, Paul Furman wrote:
Shawn McKenzie wrote:
I've noticed in both of your posts that you aren't terminating the
line before the include with a ;
Yup, thanks!
Then I fixed my global problem without bugging you guys too.
Actually, no you didn't -- you just bypassed it.
Final result:
#call.php
$dirstr= ./;
include 'scandir.php';
scandir('$dirstr');
Becasue single-quoted strings don't do variable interpolation, you are
actually passing the literal string '$dirstr' to the function -- no the
*value* of $dirstr, which is what you want. If you needed to use quotes
here, they should be double ones -- but, actually, you don't need quotes at
all: since what you really you want is the value of $dirstr, this will do
the trick:
scandir($dirstr);
#scandir.php
function scandir($dirstr) {
Well, now this $dirstr will be set to '$dirstr', which clearly isn't a valid
directory path!
global $dirstr; #I HAD TO ADD THIS LINE ALSO
But you've now bypassed that by equivalencing it to the global version of
$dirstr, which, of course, still contains './', so the rest of the function
works. Once you take the quotes off the function call above, you also won't
need this global statement.
$files = array();
$fh = opendir($dirstr);
while (false !== ($filename = readdir($fh))) {
array_push($files, $filename);
}
closedir($fh);
return $files;
}
FYI...
If you use / then you don't have to escape it like // only the \.
Also, instead of .\\ you can use '.\'
Actually, no you can't, because in single quoted strings \' is the sequence
to insert a single quote! So you still ahve ti use '.\\'.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Beckett Park, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP] unexpected include parse error
On 27 January 2004 05:18, Shawn McKenzie wrote: PS I'm on my windows apache server but the forward slash seems to work in php that keeps it portable. I tried it both ways. Yes -- PHP internally translates between / and \ on Windows, precisely for portability reasons. Thus, you can write your code using / and port it easily between Windows and *n*x systems -- this is a boon if, like me, you do development work on a Windows server but have a *n*x server for your live site. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] unexpected include parse error
the \ has to be slashed
.\\;
-Dave
At 11:27 PM 1/26/2004, Paul Furman wrote:
I'm new so probably missing something easy or doing something terribly
wrong but I have spent a lot of time experimenting...
?php
$dirstr= ./
include 'scandir.php';
scandir('$dirstr');
?
parse error, unexpected T_INCLUDE in [the above file]
if I comment out the
$dirstr= ./
above that error goes away and the scandir.php include runs (that's a php5
function that needs to be defined manually in PHP 4.3.4)
#scandir.php
?php
#$dirstr=.\;
function scandir($dirstr) {
$files = array();
$fh = opendir($dirstr);
while (false !== ($filename = readdir($fh))) {
array_push($files, $filename);
}
closedir($fh);
return $files;
}
?
If I set $dirstr=.\; in the function it gives these errors:
Parse error: unexpected $end in scandir.php at? last line
Fatal error: Call to undefined function: scandir() in showdir.php
If I don't set $dirstr at all, it runs the scandir function and fouls up
in expected ways:
Warning: opendir($dirstr): failed to open dir: Invalid argument in scandir.php
Warning: readdir(): supplied argument is not a valid Directory resource in
scandir.php
Warning: closedir(): supplied argument is not a valid Directory resource
in scandir.php
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Re: [PHP] unexpected include parse error
David Obrien wrote:
the \ has to be slashed
.\\;
Ah great, thanks! that fixes most of the errors. The following runs
where I define the $dirstr in the function but if I try to define it in
the page that calls the function, it still gives
Parse error, unexpected T_INCLUDE in [#call]
#call
$dirstr= .// this is where I want to define the directory
include 'scandir.php';
scandir('$dirstr');
#function
function scandir($dirstr) {
$files = array();
#$dirstr=.//;
$fh = opendir($dirstr);
while (false !== ($filename = readdir($fh))) {
array_push($files, $filename);
}
closedir($fh);
return $files;
}
PS I'm on my windows apache server but the forward slash seems to work
in php that keeps it portable. I tried it both ways.
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Re: [PHP] unexpected include parse error
Paul Furman wrote:
PS I'm on my windows apache server but the forward slash seems to work
OK actually, it was the back slash that was causing problems, it only
works with a forward slash!
but... I've still got the include error:
???
Parse error, unexpected T_INCLUDE
#call
$dirstr= ./
include 'scandir.php'; error here
scandir('$dirstr');
#function
function scandir($dirstr) {
$files = array();
$fh = opendir($dirstr);
while (false !== ($filename = readdir($fh))) {
array_push($files, $filename);
}
closedir($fh);
return $files;
}
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Re: [PHP] unexpected include parse error
I've noticed in both of your posts that you aren't terminating the line
before the include with a ;
That would probably help.
FYI... If you use / then you don't have to escape it like // only the \.
Also, instead of .\\ you can use '.\'
-Shawn
Paul Furman [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
David Obrien wrote:
the \ has to be slashed
.\\;
Ah great, thanks! that fixes most of the errors. The following runs
where I define the $dirstr in the function but if I try to define it in
the page that calls the function, it still gives
Parse error, unexpected T_INCLUDE in [#call]
#call
$dirstr= .// this is where I want to define the directory
include 'scandir.php';
scandir('$dirstr');
#function
function scandir($dirstr) {
$files = array();
#$dirstr=.//;
$fh = opendir($dirstr);
while (false !== ($filename = readdir($fh))) {
array_push($files, $filename);
}
closedir($fh);
return $files;
}
PS I'm on my windows apache server but the forward slash seems to work
in php that keeps it portable. I tried it both ways.
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Re: [PHP] unexpected include parse error
Shawn McKenzie wrote:
I've noticed in both of your posts that you aren't terminating the line
before the include with a ;
Yup, thanks!
Then I fixed my global problem without bugging you guys too.
Final result:
#call.php
$dirstr= ./;
include 'scandir.php';
scandir('$dirstr');
#scandir.php
function scandir($dirstr) {
global $dirstr; #I HAD TO ADD THIS LINE ALSO
$files = array();
$fh = opendir($dirstr);
while (false !== ($filename = readdir($fh))) {
array_push($files, $filename);
}
closedir($fh);
return $files;
}
FYI...
If you use / then you don't have to escape it like // only the \.
Also, instead of .\\ you can use '.\'
Ah ha! that explains my confusion :-)
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Re: [PHP] unexpected include parse error
Hi Paul,
Quoting Paul Furman [EMAIL PROTECTED]:
?php
$dirstr= ./
probably because you are missing a ; at the end?
include 'scandir.php';
scandir('$dirstr');
you should also change this to
scandir($dirstr);
?
parse error, unexpected T_INCLUDE in [the above file]
if I comment out the
$dirstr= ./
above that error goes away and the scandir.php include runs (that's a
php5 function that needs to be defined manually in PHP 4.3.4)
HTH
R'twick
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