Re: [PHP] Avoid object twice
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is not good!!
I would like to run c.php and b.php, then the program, which is Mail()
function, get one email and get Good from b.php
Regards,
Yui
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Re: [PHP] Avoid object twice
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is not good!!
I would like to run c.php and b.php, then the program, which is Mail()
function, get one email and get Good from b.php
Regards,
Yui
--
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Re: [PHP] Avoid object twice
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not good!!
I would like to run c.php and b.php, then the program, which is Mail()
function, get one email and get Good from b.php
Regards,
Yui
You could add a parameter to the buff() method.
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff($sendMail = false){
if ($sendMail) {
mail([EMAIL PROTECTED],test,test);
}
}
}
When executing b.php pass true too the buff() method to send
an email.
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff(true);
?
When executing c.php don't pass a parameter to the buff() method. So
it defaults to false. And will not send an email.
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
--
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RE: [PHP] Avoid object twice
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not
good!!
I would like to run c.php and b.php, then the program, which is Mail()
function, get one email and get Good from b.php
You are not making any sense... if you only want the Mail() function to
run once, then ONLY CALL -BUFF() ONE TIME. It's that simple. You are
mailing twice because you call buff() in two separate places--and buff()
in turn calls Mail(). I don't understand your problem.
$objref = new My(Good);
$obj = new My(Hello);
$obj-buff();
Bam. You get Hello, Good, and it sends one e-mail. Since you are
completely abstracting your code from its real-world application, that's
the best I can do.
Todd Boyd
Web Programmer
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Thank you for your good advice.
I excute c.php I did not get Good from b.php.
How can I get Good from b.php.
Regards,
Yui
2008/6/4 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is not
good!!
I would like to run c.php and b.php, then the program, which is Mail()
function, get one email and get Good from b.php
Regards,
Yui
You could add a parameter to the buff() method.
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff($sendMail = false){
if ($sendMail) {
mail([EMAIL PROTECTED],test,test);
}
}
}
When executing b.php pass true too the buff() method to send
an email.
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff(true);
?
When executing c.php don't pass a parameter to the buff() method. So it
defaults to false. And will not send an email.
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
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Re: [PHP] Avoid object twice
I knew it .
But Hello and Good is different file.
I would like to get Good from b.php.
Please tell me goo advice.
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not
good!!
I would like to run c.php and b.php, then the program, which is Mail()
function, get one email and get Good from b.php
You are not making any sense... if you only want the Mail() function to
run once, then ONLY CALL -BUFF() ONE TIME. It's that simple. You are
mailing twice because you call buff() in two separate places--and buff()
in turn calls Mail(). I don't understand your problem.
$objref = new My(Good);
$obj = new My(Hello);
$obj-buff();
Bam. You get Hello, Good, and it sends one e-mail. Since you are
completely abstracting your code from its real-world application, that's
the best I can do.
Todd Boyd
Web Programmer
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Avoid object twice
I knew it .
But Hello and Good is different file.
I would like to get Good from b.php.
Please tell me goo advice.
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not
good!!
I would like to run c.php and b.php, then the program, which is
Mail()
function, get one email and get Good from b.php
You are not making any sense... if you only want the Mail() function
to
run once, then ONLY CALL -BUFF() ONE TIME. It's that simple. You
are
mailing twice because you call buff() in two separate places--and
buff()
in turn calls Mail(). I don't understand your problem.
$objref = new My(Good);
$obj = new My(Hello);
$obj-buff();
Bam. You get Hello, Good, and it sends one e-mail. Since you are
completely abstracting your code from its real-world application,
that's
the best I can do.
I still don't get it. Please explain to me WHY this is not a solution to
your problem?
===
My.php
===
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
===
b.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
// $objref-buff(); NOTICE HOW THIS IS COMMENTED OUT!!!
?
===
c.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff(); // MAIL() IS EXECUTED HERE
?
If that doesn't work, then here are my questions:
1.) What on earth are you ACTUALLY trying to do?
2.) Does -buff() NEED to be called for each instance of My()?
3.) Are you wanting multiple instances of this class to share data?
4.) If (3), then are you familiar with the STATIC property?
Todd Boyd
Web Programmer
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
My problem is that I would like to share the parameter.
For instance, goolge map key.
There are actually two files.
example,
main.php
?php
$googlemapkey=g8ejeUFEUHEU;// example
mail([EMAIL PROTECTED],test.test);
?
Above is part of code;
I will excute main.php program.
then other.php run
But when other.php run, other.php requre $googlemapkey.
Of couse, I can get $googlemapkey if I use include or require.
But if I use include or require,
mail([EMAIL PROTECTED],test.test) run again.
So this program send twice email. It is NOT GOOD.
I juse send $googlemapkey from mail.php to other.php
Please advice if you have any solution.
Regards,
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
I knew it .
But Hello and Good is different file.
I would like to get Good from b.php.
Please tell me goo advice.
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not
good!!
I would like to run c.php and b.php, then the program, which is
Mail()
function, get one email and get Good from b.php
You are not making any sense... if you only want the Mail() function
to
run once, then ONLY CALL -BUFF() ONE TIME. It's that simple. You
are
mailing twice because you call buff() in two separate places--and
buff()
in turn calls Mail(). I don't understand your problem.
$objref = new My(Good);
$obj = new My(Hello);
$obj-buff();
Bam. You get Hello, Good, and it sends one e-mail. Since you are
completely abstracting your code from its real-world application,
that's
the best I can do.
I still don't get it. Please explain to me WHY this is not a solution to
your problem?
===
My.php
===
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
===
b.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
// $objref-buff(); NOTICE HOW THIS IS COMMENTED OUT!!!
?
===
c.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff(); // MAIL() IS EXECUTED HERE
?
If that doesn't work, then here are my questions:
1.) What on earth are you ACTUALLY trying to do?
2.) Does -buff() NEED to be called for each instance of My()?
3.) Are you wanting multiple instances of this class to share data?
4.) If (3), then are you familiar with the STATIC property?
Todd Boyd
Web Programmer
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Quoting Yui Hiroaki [EMAIL PROTECTED]:
My problem is that I would like to share the parameter.
For instance, goolge map key.
There are actually two files.
example,
main.php
?php
$googlemapkey=g8ejeUFEUHEU;// example
mail([EMAIL PROTECTED],test.test);
?
Above is part of code;
I will excute main.php program.
then other.php run
But when other.php run, other.php requre $googlemapkey.
Of couse, I can get $googlemapkey if I use include or require.
But if I use include or require,
mail([EMAIL PROTECTED],test.test) run again.
So this program send twice email. It is NOT GOOD.
I juse send $googlemapkey from mail.php to other.php
Please advice if you have any solution.
Regards,
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
I knew it .
But Hello and Good is different file.
I would like to get Good from b.php.
Please tell me goo advice.
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not
good!!
I would like to run c.php and b.php, then the program, which is
Mail()
function, get one email and get Good from b.php
You are not making any sense... if you only want the Mail() function
to
run once, then ONLY CALL -BUFF() ONE TIME. It's that simple. You
are
mailing twice because you call buff() in two separate places--and
buff()
in turn calls Mail(). I don't understand your problem.
$objref = new My(Good);
$obj = new My(Hello);
$obj-buff();
Bam. You get Hello, Good, and it sends one e-mail. Since you are
completely abstracting your code from its real-world application,
that's
the best I can do.
I still don't get it. Please explain to me WHY this is not a solution to
your problem?
===
My.php
===
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
===
b.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
// $objref-buff(); NOTICE HOW THIS IS COMMENTED OUT!!!
?
===
c.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff(); // MAIL() IS EXECUTED HERE
?
If that doesn't work, then here are my questions:
1.) What on earth are you ACTUALLY trying to do?
2.) Does -buff() NEED to be called for each instance of My()?
3.) Are you wanting multiple instances of this class to share data?
4.) If (3), then are you familiar with the STATIC property?
Todd Boyd
Web Programmer
I think you are making it way to complicated for yourself.
So you really just need to share settings between files.
That's exactly what include / require are for.
settings.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
Here you include settings.php and are able to use the mapkey variable.
If you want to send an email just call sendMail();
other.php
?php
include settings.php;
// use your google API key any way you want
sendMail(); // sends mail
?
If you don't need the sendMail(); function. then don't call it.
other2.php
?php
include settings.php;
// use your google API key any way you want
?
I think that's about as clear as i can make it.
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Re: [PHP] Avoid object twice
NO!
That is what I do not want!
setting.php need to run mail() function.
also setting.php need $googlemapkey.
other.php just need $googlemapkey.
other .php do not need run mail() function.
If I use include, I will get twice email.
Please do advice how to share the $googlemapkey.
Regards,
Yui
2008/6/4 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
My problem is that I would like to share the parameter.
For instance, goolge map key.
There are actually two files.
example,
main.php
?php
$googlemapkey=g8ejeUFEUHEU;// example
mail([EMAIL PROTECTED],test.test);
?
Above is part of code;
I will excute main.php program.
then other.php run
But when other.php run, other.php requre $googlemapkey.
Of couse, I can get $googlemapkey if I use include or require.
But if I use include or require,
mail([EMAIL PROTECTED],test.test) run again.
So this program send twice email. It is NOT GOOD.
I juse send $googlemapkey from mail.php to other.php
Please advice if you have any solution.
Regards,
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
I knew it .
But Hello and Good is different file.
I would like to get Good from b.php.
Please tell me goo advice.
Yui
2008/6/4 Boyd, Todd M. [EMAIL PROTECTED]:
Thank you for your advice me!
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
That is what I want to try.
When c.php run, Mail() function run // it is OK
When b.php run, it also run Mail() fuction. // it is NOT OK
I would like to run Mail() function one time only from c.php.
However I also get prameter which declare Good in b.php
Now when c.php and b.php run, the program send twice email. That is
not
good!!
I would like to run c.php and b.php, then the program, which is
Mail()
function, get one email and get Good from b.php
You are not making any sense... if you only want the Mail() function
to
run once, then ONLY CALL -BUFF() ONE TIME. It's that simple. You
are
mailing twice because you call buff() in two separate places--and
buff()
in turn calls Mail(). I don't understand your problem.
$objref = new My(Good);
$obj = new My(Hello);
$obj-buff();
Bam. You get Hello, Good, and it sends one e-mail. Since you are
completely abstracting your code from its real-world application,
that's
the best I can do.
I still don't get it. Please explain to me WHY this is not a solution to
your problem?
===
My.php
===
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
mail([EMAIL PROTECTED],test,test);
}
}
?
===
b.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
// $objref-buff(); NOTICE HOW THIS IS COMMENTED OUT!!!
?
===
c.php
===
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff(); // MAIL() IS EXECUTED HERE
?
If that doesn't work, then here are my questions:
1.) What on earth are you ACTUALLY trying to do?
2.) Does -buff() NEED to be called for each instance of My()?
3.) Are you wanting multiple instances of this class to share data?
4.) If (3), then are you familiar with the STATIC property?
Todd Boyd
Web Programmer
I think you are making it way to complicated for yourself.
So you really just need to share settings between files.
That's exactly what include / require are for.
settings.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
Here you include settings.php and are able to use the mapkey variable.
If you want to send an email just call sendMail();
other.php
?php
include settings.php;
// use your google API key any way you want
sendMail(); // sends mail
?
If you don't need the sendMail(); function. then don't call it.
other2.php
?php
include settings.php;
// use your google API key any way you want
?
I think that's about as clear as i can make it.
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PHP
RE: [PHP] Avoid object twice
On 04 June 2008 16:03, Yui Hiroaki advised:
NO!
That is what I do not want!
setting.php need to run mail() function.
also setting.php need $googlemapkey.
other.php just need $googlemapkey.
other .php do not need run mail() function.
If I use include, I will get twice email.
Same answer as Thijs gave, just with the filenames moved around:
google_info.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
setting.php
?php
include google_info.php;
sendMail(); // sends mail
// other stuff using your google API key
?
other.php
?php
include google_info.php;
// use your google API key any way you want
// ... but no call to sendMail()
?
Cheers!
Mike
--
Mike Ford, Electronic Information Developer,
C507, Leeds Metropolitan University, Civic Quarter Campus,
Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 812 4730
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
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RE: [PHP] Avoid object twice
-Original Message-
From: Yui Hiroaki [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2008 10:03 AM
To: Thijs Lensselink
Cc: php-general@lists.php.net
Subject: Re: [PHP] Avoid object twice
NO!
That is what I do not want!
setting.php need to run mail() function.
also setting.php need $googlemapkey.
other.php just need $googlemapkey.
other .php do not need run mail() function.
If I use include, I will get twice email.
Please do advice how to share the $googlemapkey.
I think you are making it way to complicated for yourself.
So you really just need to share settings between files.
That's exactly what include / require are for.
settings.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
Here you include settings.php and are able to use the mapkey
variable.
If you want to send an email just call sendMail();
other.php
?php
include settings.php;
// use your google API key any way you want
sendMail(); // sends mail
?
If you don't need the sendMail(); function. then don't call it.
other2.php
?php
include settings.php;
// use your google API key any way you want
?
I think that's about as clear as i can make it.
For the love of everything good in this world, please take the time to
READ his reply. Most notably, you should pay attention to how he
DECLARES a function in settings.php, rather than EXECUTING a function.
Since it is just a DECLARATION, you can include that file and the
function will not be EXECUTED. You can then EXECUTE the function at a
time of your choosing.
Not everything should run when it is loaded--you built a class (My)...
this is the same idea. Rather than a class, this is a function. Think
about it--member functions of classes don't execute by themselves (save
for the constructor/destructor, etc.)... you have to invoke them. Same
with (most) functions. You build it, and then it just sits there until
you actually tell it to do something. If you don't want your script to
send mail yet, then don't tell it to use the sendMail() function.
Hope this is resolved,
Todd Boyd
Web Programmer
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Re: [PHP] Avoid object twice
Thank you for all!
I try to use script.
But it does not run correctly.
It means that setting.php never call sendMail() from google_info.php.
Are you sure that it is possible to call function from other file?
Best Regards,
Yui
2008/6/5 Boyd, Todd M. [EMAIL PROTECTED]:
-Original Message-
From: Yui Hiroaki [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2008 10:03 AM
To: Thijs Lensselink
Cc: php-general@lists.php.net
Subject: Re: [PHP] Avoid object twice
NO!
That is what I do not want!
setting.php need to run mail() function.
also setting.php need $googlemapkey.
other.php just need $googlemapkey.
other .php do not need run mail() function.
If I use include, I will get twice email.
Please do advice how to share the $googlemapkey.
I think you are making it way to complicated for yourself.
So you really just need to share settings between files.
That's exactly what include / require are for.
settings.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
Here you include settings.php and are able to use the mapkey
variable.
If you want to send an email just call sendMail();
other.php
?php
include settings.php;
// use your google API key any way you want
sendMail(); // sends mail
?
If you don't need the sendMail(); function. then don't call it.
other2.php
?php
include settings.php;
// use your google API key any way you want
?
I think that's about as clear as i can make it.
For the love of everything good in this world, please take the time to
READ his reply. Most notably, you should pay attention to how he
DECLARES a function in settings.php, rather than EXECUTING a function.
Since it is just a DECLARATION, you can include that file and the
function will not be EXECUTED. You can then EXECUTE the function at a
time of your choosing.
Not everything should run when it is loaded--you built a class (My)...
this is the same idea. Rather than a class, this is a function. Think
about it--member functions of classes don't execute by themselves (save
for the constructor/destructor, etc.)... you have to invoke them. Same
with (most) functions. You build it, and then it just sits there until
you actually tell it to do something. If you don't want your script to
send mail yet, then don't tell it to use the sendMail() function.
Hope this is resolved,
Todd Boyd
Web Programmer
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Re: [PHP] Avoid object twice
Uhmm!
It is sure that function can call from other file.
But it is NOT EXECUTE mail() function.
How mail function be execute!
Please do more advice.
You may tire of this mail.
BEST REGARDS,
Yui
2008/6/5 Boyd, Todd M. [EMAIL PROTECTED]:
-Original Message-
From: Yui Hiroaki [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2008 10:03 AM
To: Thijs Lensselink
Cc: php-general@lists.php.net
Subject: Re: [PHP] Avoid object twice
NO!
That is what I do not want!
setting.php need to run mail() function.
also setting.php need $googlemapkey.
other.php just need $googlemapkey.
other .php do not need run mail() function.
If I use include, I will get twice email.
Please do advice how to share the $googlemapkey.
I think you are making it way to complicated for yourself.
So you really just need to share settings between files.
That's exactly what include / require are for.
settings.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
Here you include settings.php and are able to use the mapkey
variable.
If you want to send an email just call sendMail();
other.php
?php
include settings.php;
// use your google API key any way you want
sendMail(); // sends mail
?
If you don't need the sendMail(); function. then don't call it.
other2.php
?php
include settings.php;
// use your google API key any way you want
?
I think that's about as clear as i can make it.
For the love of everything good in this world, please take the time to
READ his reply. Most notably, you should pay attention to how he
DECLARES a function in settings.php, rather than EXECUTING a function.
Since it is just a DECLARATION, you can include that file and the
function will not be EXECUTED. You can then EXECUTE the function at a
time of your choosing.
Not everything should run when it is loaded--you built a class (My)...
this is the same idea. Rather than a class, this is a function. Think
about it--member functions of classes don't execute by themselves (save
for the constructor/destructor, etc.)... you have to invoke them. Same
with (most) functions. You build it, and then it just sits there until
you actually tell it to do something. If you don't want your script to
send mail yet, then don't tell it to use the sendMail() function.
Hope this is resolved,
Todd Boyd
Web Programmer
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Re: [PHP] Avoid object twice
On 6/4/08, Yui Hiroaki [EMAIL PROTECTED] wrote: Uhmm! It is sure that function can call from other file. But it is NOT EXECUTE mail() function. How mail function be execute! Please do more advice. You may tire of this mail. Yes. David -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Thanks you for php developer.
If php can not share the parameter each different
file, it is not reality of my program.
If I use include or requre, php can share the paremeter each file.
But other files call or execute from original file.
setting.php and google_info.php and other.php almost reach
the my goal, I thought.
But google_info.php must execute mail() function.
Or setting.php must have $googlemapkey.
Thank you for a lot.
Regards,
Yui
2008/6/5 Boyd, Todd M. [EMAIL PROTECTED]:
-Original Message-
From: Yui Hiroaki [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 04, 2008 10:03 AM
To: Thijs Lensselink
Cc: php-general@lists.php.net
Subject: Re: [PHP] Avoid object twice
NO!
That is what I do not want!
setting.php need to run mail() function.
also setting.php need $googlemapkey.
other.php just need $googlemapkey.
other .php do not need run mail() function.
If I use include, I will get twice email.
Please do advice how to share the $googlemapkey.
I think you are making it way to complicated for yourself.
So you really just need to share settings between files.
That's exactly what include / require are for.
settings.php
?php
$googlemapkey = g8ejeUFEUHEU;// example
function sendMail() {
mail([EMAIL PROTECTED],test.test);
}
?
Here you include settings.php and are able to use the mapkey
variable.
If you want to send an email just call sendMail();
other.php
?php
include settings.php;
// use your google API key any way you want
sendMail(); // sends mail
?
If you don't need the sendMail(); function. then don't call it.
other2.php
?php
include settings.php;
// use your google API key any way you want
?
I think that's about as clear as i can make it.
For the love of everything good in this world, please take the time to
READ his reply. Most notably, you should pay attention to how he
DECLARES a function in settings.php, rather than EXECUTING a function.
Since it is just a DECLARATION, you can include that file and the
function will not be EXECUTED. You can then EXECUTE the function at a
time of your choosing.
Not everything should run when it is loaded--you built a class (My)...
this is the same idea. Rather than a class, this is a function. Think
about it--member functions of classes don't execute by themselves (save
for the constructor/destructor, etc.)... you have to invoke them. Same
with (most) functions. You build it, and then it just sits there until
you actually tell it to do something. If you don't want your script to
send mail yet, then don't tell it to use the sendMail() function.
Hope this is resolved,
Todd Boyd
Web Programmer
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RE: [PHP] Avoid object twice
-Original Message- From: Yui Hiroaki [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 04, 2008 12:28 PM To: Boyd, Todd M. Cc: php-general@lists.php.net Subject: Re: [PHP] Avoid object twice Thanks you for php developer. If php can not share the parameter each different file, it is not reality of my program. If I use include or requre, php can share the paremeter each file. But other files call or execute from original file. setting.php and google_info.php and other.php almost reach the my goal, I thought. But google_info.php must execute mail() function. Or setting.php must have $googlemapkey. I think it's a fair to assume that no programming language (i.e., PHP) is able to magically determine the contents of another file/script without communicating with it in some way (shared memory, pipes, sockets, the filesystem, middleware, etc.). How is google_info.php structured? Is it on YOUR server, so that you can put a page-include at the top of it? If the code that contains your class (which contains the function to execute mail()) is not included as part of the executed script, then the executed script will have no idea that it even exists--let alone have the knowledge of its member functions. I think you need to take a step back and focus on fundamental programming concepts before trying to tackle playing with a Google API. Todd Boyd Web Developer -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good, when the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED] wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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Re: [PHP] Avoid object twice
I don't see how it's possible for you to get Hello after Good, when the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED] wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
--
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Re: [PHP] Avoid object twice
I suggest you don't put code other than class structures in class files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED] wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good, when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED] wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good, when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
--
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To unsubscribe, visit: http://www.php.net/unsub.php
--
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED] wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good, when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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Re: [PHP] Avoid object twice
Please look at my.php
my.php load
$obj=new My(Hello);
$obj-buff();
so, if a.php load, it absolutely got hello in load b.php
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED] wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good,
when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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If you only want to see Good Then don't run it twice.
Take James's suggestion and try it again:
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
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Re: [PHP] Avoid object twice
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED] wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good, when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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If you only want to see Good Then don't run it twice.
Take James's suggestion and try it again:
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
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Re: [PHP] Avoid object twice
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Please look at my.php
my.php load
$obj=new My(Hello);
$obj-buff();
so, if a.php load, it absolutely got hello in load b.php
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED] wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good,
when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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If you only want to see Good Then don't run it twice.
Take James's suggestion and try it again:
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
I don't think i understand you fully. Or you're trying to make it to
complicated.
You have a class in My.php :
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
And a script that creates an instance of My b.php :
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
The output will be Hellobr/Goodbr/. because you call it two
times. So if you only want to see Good. Then you change b.php to
look like this:
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
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Re: [PHP] Avoid object twice
The code is blelow;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
on website, first it execute My.php , then execute b.php
So it will show blelow;
Hello(when excute My.php)
Hello(when excute from b.php)
Good(when excute from b.php)
I do not need Hello twice
I would get
Hello(when excute My.php)
Good(when excute from b.php)
Please do help me!
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Please look at my.php
my.php load
$obj=new My(Hello);
$obj-buff();
so, if a.php load, it absolutely got hello in load b.php
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class
files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good,
when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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If you only want to see Good Then don't run it twice.
Take James's suggestion and try it again:
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
I don't think i understand you fully. Or you're trying to make it to
complicated.
You have a class in My.php :
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
And a script that creates an instance of My b.php :
Re: [PHP] Avoid object twice
On 3 Jun 2008, at 17:12, Yui Hiroaki wrote:
The code is blelow;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
on website, first it execute My.php , then execute b.php
So it will show blelow;
Hello(when excute My.php)
Hello(when excute from b.php)
Good(when excute from b.php)
I do not need Hello twice
I would get
Hello(when excute My.php)
Good(when excute from b.php)
As you've already been told you should not really mix classes and
procedural code in files. Put the My class into My.php, then have
b.php and c.php where c.php contains the procedural code from My.php
along with the __autoload from b.php.
I don't see why you insist on being able to run My.php. If it
contains a class it should not be run as the main script. Ever!!
-Stut
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Re: [PHP] Avoid object twice
Yui Hiroaki wrote:
The code is blelow;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
on website, first it execute My.php , then execute b.php
So it will show blelow;
Hello(when excute My.php)
Hello(when excute from b.php)
Good(when excute from b.php)
I do not need Hello twice
I would get
Hello(when excute My.php)
Good(when excute from b.php)
Please do help me!
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Please look at my.php
my.php load
$obj=new My(Hello);
$obj-buff();
so, if a.php load, it absolutely got hello in load b.php
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class
files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good,
when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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If you only want to see Good Then don't run it twice.
Take James's suggestion and try it again:
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
I don't think i understand you fully. Or you're trying to make it to
complicated.
You have a class in My.php :
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
And a script that creates an instance of My b.php :
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
The output will be Hellobr/Goodbr/. because you call it two
Re: [PHP] Avoid object twice
Stut wrote: On 3 Jun 2008, at 18:35, Yui Hiroaki wrote: Sorry I still have a problem. Let's take a step back. What are you *actually* trying to do. I'm assuming it's not just printing out Hello and Good. What is the real problem you're trying to solve and what are the constraints that are causing you to be weird in the implementation? -Stut As Stut says, depending upon what you're trying to do there is most likely a much better way. Why If you want to execute a method or retrieve a property from both objects, why do you have them in two separate files? -Shawn -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Thank you for everyone who helps me!
I got a message what I want.
Thank you!
Yui
2008/6/4 Jim Lucas [EMAIL PROTECTED]:
Yui Hiroaki wrote:
The code is blelow;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
on website, first it execute My.php , then execute b.php
So it will show blelow;
Hello(when excute My.php)
Hello(when excute from b.php)
Good(when excute from b.php)
I do not need Hello twice
I would get
Hello(when excute My.php)
Good(when excute from b.php)
Please do help me!
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Please look at my.php
my.php load
$obj=new My(Hello);
$obj-buff();
so, if a.php load, it absolutely got hello in load b.php
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class
files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good,
when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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If you only want to see Good Then don't run it twice.
Take James's suggestion and try it again:
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
I don't think i understand you fully. Or you're trying to make it to
complicated.
You have a class in My.php :
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo
Re: [PHP] Avoid object twice
On 3 Jun 2008, at 18:35, Yui Hiroaki wrote: Sorry I still have a problem. Let's take a step back. What are you *actually* trying to do. I'm assuming it's not just printing out Hello and Good. What is the real problem you're trying to solve and what are the constraints that are causing you to be weird in the implementation? -Stut -- http://stut.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Avoid object twice
Sorry I still have a problem.
I separete files belows;
-My.php---
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
--b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
--c.php--
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
--
First I execute c.php
Then I got Hello
Next I execute b.php
Then I got Good
I would like to get to execute b.php
Then I got Hello and Good -I need
The problem is how to get parameter from c.php to b.php.
Please do help me!
Regards,
Yui
2008/6/4 Jim Lucas [EMAIL PROTECTED]:
Yui Hiroaki wrote:
The code is blelow;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
on website, first it execute My.php , then execute b.php
So it will show blelow;
Hello(when excute My.php)
Hello(when excute from b.php)
Good(when excute from b.php)
I do not need Hello twice
I would get
Hello(when excute My.php)
Good(when excute from b.php)
Please do help me!
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Please look at my.php
my.php load
$obj=new My(Hello);
$obj-buff();
so, if a.php load, it absolutely got hello in load b.php
Regards,
Yui
2008/6/3 Thijs Lensselink [EMAIL PROTECTED]:
Quoting Yui Hiroaki [EMAIL PROTECTED]:
Thank you for a good suggest!
Somehow, I have to execute my.php also.
This program have to run.
1)My.php
2)b.php
My.php show Hello - it is OK,
b.php shows
Hello
Good
it is NOT good. I need to get only Good
Please give me a suggestion.
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I suggest you don't put code other than class structures in class
files.
Also don't execute My.php just execute b.php which though __autoload
includes My.php.
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$obj=new My(Hello);
$obj-buff();
$objref=new My(Good);
$objref-buff();
---
--My.php--
?php
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
/James Dempster
On Tue, Jun 3, 2008 at 9:17 AM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
HI!
I had mistake in code in php.
When I excute My.php, it say Hello
When I excute b.php, it say
Hello
Good
I would like to execute b.php and show
only Good
If you know it ,please teach me!
Here is code below;
-b.php
?php
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new My(Good);
$objref-buff();
?
---
--My.php--
?php
$obj=new My(Hello);
$obj-buff();
Class My{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
}
?
--
Regards,
Yui
2008/6/3 James Dempster [EMAIL PROTECTED]:
I don't see how it's possible for you to get Hello after Good,
when
the
file that cause's Hello is required to do Good
/James
On Mon, Jun 2, 2008 at 2:00 PM, Yui Hiroaki [EMAIL PROTECTED]
wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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PHP General Mailing
RE: [PHP] Avoid object twice
Try removing from a.php the lines:
$obj=new my(Hello);
$obj-buff();
I think this will achieve what you want.
-Original Message-
From: Yui Hiroaki [mailto:[EMAIL PROTECTED]
Sent: Monday, June 02, 2008 11:01 PM
To: php-general@lists.php.net
Subject: [PHP] Avoid object twice
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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Re: [PHP] Avoid object twice
Yui Hiroaki wrote:
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
Just to make sure, you are calling your a.php script my.php in real life right?
If not, this might be part of your problem. When I run the above script, and
change the a.php to my.php, it loads just fine and it only displays one instance
of hello. I am thinking that you calling the class more then once and you don't
realize it.
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them.
Twelfth Night, Act II, Scene V
by William Shakespeare
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Re: [PHP] Avoid object twice
if I delete
$obj=new my(Hello);
$obj-buff();
I can not show Hello.
I would like to see hello one time only.
Regards,
Yui
2008/6/2 Scott McNaught [Synergy 8] [EMAIL PROTECTED]:
Try removing from a.php the lines:
$obj=new my(Hello);
$obj-buff();
I think this will achieve what you want.
-Original Message-
From: Yui Hiroaki [mailto:[EMAIL PROTECTED]
Sent: Monday, June 02, 2008 11:01 PM
To: php-general@lists.php.net
Subject: [PHP] Avoid object twice
Please take a look at code.
a.php
$obj=new my(Hello);
$obj-buff();
Class my{
private $word;
function __construct($getword){
$this-word=$getword;
}
public function buff(){
echo $this-word.br /;
}
--
-b.php---
function __autoload($class_name) {
include_once $class_name . '.php';
}
$objref=new my(Good);
$objref-buff();
I get an Echo;
Good
Hello
Hello
I do not need to get Hello twice.
When I b.php , $obj=new my(Hello) is loaded.
Do you have any adia to avoid load $obj in a.php twice?
Regards,
Yui
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To unsubscribe, visit: http://www.php.net/unsub.php
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