php-general Digest 6 Jul 2013 06:58:22 -0000 Issue 8286
php-general Digest 6 Jul 2013 06:58:22 - Issue 8286 Topics (messages 321545 through 321558): Re: strlen ? 321545 by: John Meyer 321546 by: shiplu 321547 by: Jim Giner 321548 by: Matijn Woudt 321549 by: Matijn Woudt 321550 by: Jim Giner 321551 by: Stephen 321552 by: Jim Giner 321554 by: John Meyer 321557 by: Ashley Sheridan 321558 by: Lester Caine Guaranteed Way to Get Error Message Wanted 321553 by: Brian Smither 321556 by: Ken Robinson Find a list of function that clashes? 321555 by: Daniel Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- Jim Giner wrote: Trying to manage line breaks in some output I'm generating and using strlen to measure the lengths of the strings I'm printing. Discovered something strange (to me!) in that strlen is returning +1 more than it should. The strings are from a query of my database - simple name fields. But everyone of them is coming back with a length that is one more than I see. Ex. Mike Hall comes back as 10, not 9 F.B. comes back as 5, not 4. I've looked at my data and counted the chars - there is no extra space at the beginning or end in my table. Anyone have an explanation? Does strlen count the line feed? ---End Message--- ---BeginMessage--- On Fri, Jul 5, 2013 at 11:10 PM, Jim Giner jim.gi...@albanyhandball.comwrote: Mike Hall comes back as 10, not 9 F.B. comes back as 5, not 4. Doesn't work for me. php var_dump(Mike Hall, strlen(Mike Hall)); string(9) Mike Hall int(9) Try trimming it first and then apply strlen. -- Shiplu.Mokadd.im ImgSign.com | A dynamic signature machine Innovation distinguishes between follower and leader ---End Message--- ---BeginMessage--- On 7/5/2013 1:32 PM, shiplu wrote: On Fri, Jul 5, 2013 at 11:10 PM, Jim Giner jim.gi...@albanyhandball.comwrote: Mike Hall comes back as 10, not 9 F.B. comes back as 5, not 4. Doesn't work for me. php var_dump(Mike Hall, strlen(Mike Hall)); string(9) Mike Hall int(9) Try trimming it first and then apply strlen. Why would I need to trim something that I can already see doesn't have any trailing or leading characters? ---End Message--- ---BeginMessage--- On Fri, Jul 5, 2013 at 8:33 PM, Jim Giner jim.gi...@albanyhandball.comwrote: On 7/5/2013 1:32 PM, shiplu wrote: On Fri, Jul 5, 2013 at 11:10 PM, Jim Giner jim.gi...@albanyhandball.com **wrote: Mike Hall comes back as 10, not 9 F.B. comes back as 5, not 4. Doesn't work for me. php var_dump(Mike Hall, strlen(Mike Hall)); string(9) Mike Hall int(9) Try trimming it first and then apply strlen. Why would I need to trim something that I can already see doesn't have any trailing or leading characters? Because there are characters you can't see? ---End Message--- ---BeginMessage--- On Fri, Jul 5, 2013 at 8:39 PM, Jim Giner jim.gi...@albanyhandball.comwrote: I checked them in the db manually. Clicked on the name, selected it, no extra space highlighted. Cursored through the length of the value - no extra movements. That does still not guarantee there are no extra characters. Some characters are just not visible (NUL, CR, LF, ..) On 7/5/2013 2:36 PM, Matijn Woudt wrote: On Fri, Jul 5, 2013 at 8:33 PM, Jim Giner jim.gi...@albanyhandball.comwrote: On 7/5/2013 1:32 PM, shiplu wrote: On Fri, Jul 5, 2013 at 11:10 PM, Jim Giner jim.gi...@albanyhandball.com wrote: Mike Hall comes back as 10, not 9 F.B. comes back as 5, not 4. Doesn't work for me. php var_dump(Mike Hall, strlen(Mike Hall)); string(9) Mike Hall int(9) Try trimming it first and then apply strlen. Why would I need to trim something that I can already see doesn't have any trailing or leading characters? Because there are characters you can't see? ---End Message--- ---BeginMessage--- On 7/5/2013 2:42 PM, Matijn Woudt wrote: On Fri, Jul 5, 2013 at 8:39 PM, Jim Giner jim.gi...@albanyhandball.comwrote: I checked them in the db manually. Clicked on the name, selected it, no extra space highlighted. Cursored through the length of the value - no extra movements. That does still not guarantee there are no extra characters. Some characters are just not visible (NUL, CR, LF, ..) On 7/5/2013 2:36 PM, Matijn Woudt wrote: On Fri, Jul 5, 2013 at 8:33 PM, Jim Giner jim.gi...@albanyhandball.comwrote: On 7/5/2013 1:32 PM, shiplu wrote: On Fri, Jul 5, 2013 at 11:10 PM, Jim Giner jim.gi...@albanyhandball.com wrote: Mike Hall comes back as 10, not 9 F.B. comes back as 5, not 4. Doesn't work for me. php var_dump(Mike Hall, strlen(Mike Hall)); string(9) Mike Hall
php-general Digest 6 Jul 2013 19:14:09 -0000 Issue 8287
php-general Digest 6 Jul 2013 19:14:09 - Issue 8287
Topics (messages 321559 through 321565):
Re: strlen ?
321559 by: Jim Giner
321560 by: Lester Caine
mongo usage
321561 by: Tim Dunphy
321563 by: Thomas Punt
321564 by: Jonathan Sundquist
321565 by: Tim Dunphy
Guaranteed Way to Get Error Message Wanted
321562 by: Brian Smither
Administrivia:
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--
---BeginMessage---
On 7/6/2013 2:59 AM, Lester Caine wrote:
Jim Giner wrote:
And the answer is - yes, there is a LF char at the end of my data in
my whole
table.
Now the question is - how the heck did I put that in there? Certainly
not
intentionally. The data is captured from a d/e screen I wrote and it
simply
grabs the post value and inserts a new record with that value along
with some
other values. And I don't see anything concatenating a LF to my string.
The obvious question that comes to mind is 'What OS'? Having seen this
sort of niggle many times I tend to find it relates to something working
'cross-os' a bit like windows ignoring case in file name and linux then
complaining it can't find a file.
It's probably worth checking the sting length back through your code
just to confirm what added it?
The best I can figure is that I did a preload of many of the names from
a csv file. Apparently when I do that it stores the LF at the end of
the csv line. Have to remember that the next time.
---End Message---
---BeginMessage---
Jim Giner wrote:
It's probably worth checking the sting length back through your code
just to confirm what added it?
The best I can figure is that I did a preload of many of the names from a csv
file. Apparently when I do that it stores the LF at the end of the csv line.
Have to remember that the next time.
AH - I use that to flag the end of line when I pulled the data apart - so it
gets stripped ;)
Then I found fgetcsv() which replaced the manual code and gave just the data as
an array.
--
Lester Caine - G8HFL
-
Contact - http://lsces.co.uk/wiki/?page=contact
L.S.Caine Electronic Services - http://lsces.co.uk
EnquirySolve - http://enquirysolve.com/
Model Engineers Digital Workshop - http://medw.co.uk
Rainbow Digital Media - http://rainbowdigitalmedia.co.uk
---End Message---
---BeginMessage---
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in */var/www/mongomaven/index.php* on
line *36*
*Fatal error*: Call to a member function insert() on a non-object in *
/var/www/mongomaven/index.php* on line *36*
*
*
And here's the code:
html
head
titleMongo Test/title
/head
body
Mongo Test Page
?php
$connection = new Mongo();
$db = $connection-jfdb;
$collection = $db-addresses;
//$adresses = $connection-jfdb-adresses;
$address = array(
'first_name' = 'Peter',
'last_name' = 'Parker',
'address' = '175 Fifth Avenue',
'city' = 'New York',
'state' = 'NY',
'zip' = '10010',);
var_dump($address);
echo 'br /';
$addresses-insert($address);
?
/body
/html
I'd appreciate any advice you might have.
Thanks,
Tim
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
---End Message---
---BeginMessage---
Could the comma after the last element in your array be causing the problem?
Date: Sat, 6 Jul 2013 14:42:07 -0400
From: bluethu...@gmail.com
To: php-gene...@lists.php.net
Subject: [PHP] mongo usage
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in */var/www/mongomaven/index.php*
Re: [PHP] strlen ?
Jim Giner wrote: And the answer is - yes, there is a LF char at the end of my data in my whole table. Now the question is - how the heck did I put that in there? Certainly not intentionally. The data is captured from a d/e screen I wrote and it simply grabs the post value and inserts a new record with that value along with some other values. And I don't see anything concatenating a LF to my string. The obvious question that comes to mind is 'What OS'? Having seen this sort of niggle many times I tend to find it relates to something working 'cross-os' a bit like windows ignoring case in file name and linux then complaining it can't find a file. It's probably worth checking the sting length back through your code just to confirm what added it? -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] strlen ?
On 7/6/2013 2:59 AM, Lester Caine wrote: Jim Giner wrote: And the answer is - yes, there is a LF char at the end of my data in my whole table. Now the question is - how the heck did I put that in there? Certainly not intentionally. The data is captured from a d/e screen I wrote and it simply grabs the post value and inserts a new record with that value along with some other values. And I don't see anything concatenating a LF to my string. The obvious question that comes to mind is 'What OS'? Having seen this sort of niggle many times I tend to find it relates to something working 'cross-os' a bit like windows ignoring case in file name and linux then complaining it can't find a file. It's probably worth checking the sting length back through your code just to confirm what added it? The best I can figure is that I did a preload of many of the names from a csv file. Apparently when I do that it stores the LF at the end of the csv line. Have to remember that the next time. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] strlen ?
Jim Giner wrote: It's probably worth checking the sting length back through your code just to confirm what added it? The best I can figure is that I did a preload of many of the names from a csv file. Apparently when I do that it stores the LF at the end of the csv line. Have to remember that the next time. AH - I use that to flag the end of line when I pulled the data apart - so it gets stripped ;) Then I found fgetcsv() which replaced the manual code and gave just the data as an array. -- Lester Caine - G8HFL - Contact - http://lsces.co.uk/wiki/?page=contact L.S.Caine Electronic Services - http://lsces.co.uk EnquirySolve - http://enquirysolve.com/ Model Engineers Digital Workshop - http://medw.co.uk Rainbow Digital Media - http://rainbowdigitalmedia.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] mongo usage
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in */var/www/mongomaven/index.php* on
line *36*
*Fatal error*: Call to a member function insert() on a non-object in *
/var/www/mongomaven/index.php* on line *36*
*
*
And here's the code:
html
head
titleMongo Test/title
/head
body
Mongo Test Page
?php
$connection = new Mongo();
$db = $connection-jfdb;
$collection = $db-addresses;
//$adresses = $connection-jfdb-adresses;
$address = array(
'first_name' = 'Peter',
'last_name' = 'Parker',
'address' = '175 Fifth Avenue',
'city' = 'New York',
'state' = 'NY',
'zip' = '10010',);
var_dump($address);
echo 'br /';
$addresses-insert($address);
?
/body
/html
I'd appreciate any advice you might have.
Thanks,
Tim
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
[PHP] Guaranteed Way to Get Error Message Wanted
It looks like you are running the thread-safe version with FastCGI, which I understand to be counter to the recommendations. Thank you for the comment. I switched to PHP5.4.17-NTS-VC9, but the application still crashes. And still no clue as to why. So, still looking for that magic method to get PHP to report what's happening on a 500 Internal Server Error when it's (presumably? not sure...) not the server's fault. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] mongo usage
Could the comma after the last element in your array be causing the problem?
Date: Sat, 6 Jul 2013 14:42:07 -0400
From: bluethu...@gmail.com
To: php-general@lists.php.net
Subject: [PHP] mongo usage
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in */var/www/mongomaven/index.php* on
line *36*
*Fatal error*: Call to a member function insert() on a non-object in *
/var/www/mongomaven/index.php* on line *36*
*
*
And here's the code:
html
head
titleMongo Test/title
/head
body
Mongo Test Page
?php
$connection = new Mongo();
$db = $connection-jfdb;
$collection = $db-addresses;
//$adresses = $connection-jfdb-adresses;
$address = array(
'first_name' = 'Peter',
'last_name' = 'Parker',
'address' = '175 Fifth Avenue',
'city' = 'New York',
'state' = 'NY',
'zip' = '10010',);
var_dump($address);
echo 'br /';
$addresses-insert($address);
?
/body
/html
I'd appreciate any advice you might have.
Thanks,
Tim
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
Re: [PHP] mongo usage
You commented out the setting of yhe addresses variable
On Jul 6, 2013 1:42 PM, Tim Dunphy bluethu...@gmail.com wrote:
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in */var/www/mongomaven/index.php*
on
line *36*
*Fatal error*: Call to a member function insert() on a non-object in *
/var/www/mongomaven/index.php* on line *36*
*
*
And here's the code:
html
head
titleMongo Test/title
/head
body
Mongo Test Page
?php
$connection = new Mongo();
$db = $connection-jfdb;
$collection = $db-addresses;
//$adresses = $connection-jfdb-adresses;
$address = array(
'first_name' = 'Peter',
'last_name' = 'Parker',
'address' = '175 Fifth Avenue',
'city' = 'New York',
'state' = 'NY',
'zip' = '10010',);
var_dump($address);
echo 'br /';
$addresses-insert($address);
?
/body
/html
I'd appreciate any advice you might have.
Thanks,
Tim
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
Re: [PHP] mongo usage
| Could the comma after the last element in your array be causing the
problem?
I tried removing it, but there was no change. Thanks for the suggestion!
On Sat, Jul 6, 2013 at 2:55 PM, Thomas Punt unassailable...@hotmail.comwrote:
Could the comma after the last element in your array be causing the
problem?
Date: Sat, 6 Jul 2013 14:42:07 -0400
From: bluethu...@gmail.com
To: php-general@lists.php.net
Subject: [PHP] mongo usage
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in
*/var/www/mongomaven/index.php* on
line *36*
*Fatal error*: Call to a member function insert() on a non-object in *
/var/www/mongomaven/index.php* on line *36*
*
*
And here's the code:
html
head
titleMongo Test/title
/head
body
Mongo Test Page
?php
$connection = new Mongo();
$db = $connection-jfdb;
$collection = $db-addresses;
//$adresses = $connection-jfdb-adresses;
$address = array(
'first_name' = 'Peter',
'last_name' = 'Parker',
'address' = '175 Fifth Avenue',
'city' = 'New York',
'state' = 'NY',
'zip' = '10010', );
var_dump($address);
echo 'br /';
$addresses-insert($address);
?
/body
/html
I'd appreciate any advice you might have.
Thanks,
Tim
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
Re: [PHP] mongo usage
| You commented out the setting of yhe addresses variable
Those were both equivalent ways of stating the same thing. I tried
substituting the other statement but there was no change:
$db = $connection-jfdb;
//$collection = $db-addresses;
$adresses = $connection-jfdb-adresses;
Thanks again!
On Sat, Jul 6, 2013 at 2:57 PM, Jonathan Sundquist jsundqu...@gmail.comwrote:
You commented out the setting of yhe addresses variable
On Jul 6, 2013 1:42 PM, Tim Dunphy bluethu...@gmail.com wrote:
Hey all,
I'm trying to pick up some basic use of MongoDB using PHP.
I seem to have hit an early obstacle that I'd like your opinion on. I try
to pass an array to the mongo insert function, but for some reason the
function does not recognize the array I'm passing. Even though I can
perform a var_dump() on the array and see the contents.
Here's the output I'm seeing (with error):
Mongo Test Page array(6) { [first_name]= string(5) Peter
[last_name]= string(6) Parker [address]= string(16) 175 Fifth
Avenue [city]= string(8) New York [state]= string(2) NY
[zip]= string(5) 10010 }
*Notice*: Undefined variable: addresses in
*/var/www/mongomaven/index.php* on
line *36*
*Fatal error*: Call to a member function insert() on a non-object in *
/var/www/mongomaven/index.php* on line *36*
*
*
And here's the code:
html
head
titleMongo Test/title
/head
body
Mongo Test Page
?php
$connection = new Mongo();
$db = $connection-jfdb;
$collection = $db-addresses;
//$adresses = $connection-jfdb-adresses;
$address = array(
'first_name' = 'Peter',
'last_name' = 'Parker',
'address' = '175 Fifth Avenue',
'city' = 'New York',
'state' = 'NY',
'zip' = '10010',);
var_dump($address);
echo 'br /';
$addresses-insert($address);
?
/body
/html
I'd appreciate any advice you might have.
Thanks,
Tim
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
--
GPG me!!
gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
Re: [PHP] Guaranteed Way to Get Error Message Wanted
On 6 July 2013 19:50, Brian Smither bhsmit...@gmail.com wrote: It looks like you are running the thread-safe version with FastCGI, which I understand to be counter to the recommendations. Thank you for the comment. I switched to PHP5.4.17-NTS-VC9, but the application still crashes. And still no clue as to why. So, still looking for that magic method to get PHP to report what's happening on a 500 Internal Server Error when it's (presumably? not sure...) not the server's fault. Have you got all your extensions updated? Enable display_startup_errors. Try running the command line PHP ... php -r echo 1; With your config. Just to see if there is anything ultra obvious missing. -- Richard Quadling Twitter : @RQuadling
[PHP] Guaranteed Way to Get Error Message Wanted
Have you got all your extensions updated? I would think so. Just to state the required disclaimers: phpinfo.php with ? phpinfo() ? works. Liberally peppering a tracer routine throughout the application shows it is getting executed up until one spot. But there is nothing obviously wrong with the code. Nothing! That's why I need the guaranteed message delivery on why PHP does not like the code. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Guaranteed Way to Get Error Message Wanted
On 6 July 2013 21:45, Brian Smither bhsmit...@gmail.com wrote: Have you got all your extensions updated? I would think so. Just to state the required disclaimers: phpinfo.php with ? phpinfo() ? works. Liberally peppering a tracer routine throughout the application shows it is getting executed up until one spot. But there is nothing obviously wrong with the code. Nothing! That's why I need the guaranteed message delivery on why PHP does not like the code. Turn on all your error reporting/logging. Add a try/catch if appropriate. Turn off any unhandled exception processing. Load in XDebug and get a trace going, what is the code doing prior to failure? -- Richard Quadling Twitter : @RQuadling
Re: [PHP] mongo usage
On Sat, Jul 6, 2013 at 9:16 PM, Tim Dunphy bluethu...@gmail.com wrote: | You commented out the setting of yhe addresses variable Those were both equivalent ways of stating the same thing. I tried substituting the other statement but there was no change: $db = $connection-jfdb; //$collection = $db-addresses; $adresses = $connection-jfdb-adresses; Thanks again! You seem to spell the variable differently (1 'd' vs. 2 'd's)? - Matijn
Re: [PHP] mongo usage
| You seem to spell the variable differently (1 'd' vs. 2 'd's)? Thanks! Fixed the type-o. Still no change. $connection = new Mongo(); $db = $connection-jfdb; //$collection = $db-addresses; $adresses = $connection-jfdb-addresses; Any other suggestions? Appreciated. Tim On Sat, Jul 6, 2013 at 5:39 PM, Matijn Woudt tijn...@gmail.com wrote: On Sat, Jul 6, 2013 at 9:16 PM, Tim Dunphy bluethu...@gmail.com wrote: | You commented out the setting of yhe addresses variable Those were both equivalent ways of stating the same thing. I tried substituting the other statement but there was no change: $db = $connection-jfdb; //$collection = $db-addresses; $adresses = $connection-jfdb-adresses; Thanks again! You seem to spell the variable differently (1 'd' vs. 2 'd's)? - Matijn -- GPG me!! gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
[PHP] Re: mongo usage
On 06 Jul 2013 at 23:27, Tim Dunphy bluethu...@gmail.com wrote: | You seem to spell the variable differently (1 'd' vs. 2 'd's)? Thanks! Fixed the type-o. Still no change. $connection = new Mongo(); $db = $connection-jfdb; //$collection = $db-addresses; $adresses = $connection-jfdb-addresses; ~ Any other suggestions? Appreciated. Fix the other typo. -- Cheers -- Tim -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: mongo usage
Thanks. Sorry to bug you guys with this. That did it. sigh On Sat, Jul 6, 2013 at 6:49 PM, Tim Streater t...@clothears.org.uk wrote: On 06 Jul 2013 at 23:27, Tim Dunphy bluethu...@gmail.com wrote: | You seem to spell the variable differently (1 'd' vs. 2 'd's)? Thanks! Fixed the type-o. Still no change. $connection = new Mongo(); $db = $connection-jfdb; //$collection = $db-addresses; $adresses = $connection-jfdb-addresses; ~ Any other suggestions? Appreciated. Fix the other typo. -- Cheers -- Tim -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- GPG me!! gpg --keyserver pool.sks-keyservers.net --recv-keys F186197B
