[PyMOL] multiple atom selection by atom number

[Lihua Wang]

Dear Pymol users,

I am a new pymol explorer (not a user yet :-) and it seems to me that I am
not able to select multiple atoms by using the atom number (or id, as
pymol call it) in the PDB file. For example, if I would like to
select 100 atoms (of consecutive atom numbers) in a polymerase, how
would I do that? (select myselection, id 1000-1100 gives me an error
message). I know I could use combination of shift+left mouse button and/or
cntl+left mouse button to select a bunch of atoms, but that does not give
the freedom as I would have if I could select using atom numbers.

Thanks for your attention.

Lihua

RE: [PyMOL] multiple atom selection by atom number

[Warren DeLano]

Lihua, 

You're correct: 'id' doesn't currently have the capability of selecting by
range or even using a list.  However, we can probably add that behavior in a
future version.

In the meantime, you could tap Python for the task, but it will be slow:

select myrange, none
for a in range(1000,1101): cmd.select(myrange,myrange or id %d%a)

Can you use residue identifiers instead?

select myrange, resi 100-200

Cheers,
Warren

 -Original Message-
 From: pymol-users-ad...@lists.sourceforge.net 
 [mailto:pymol-users-ad...@lists.sourceforge.net] On Behalf Of 
 Lihua Wang
 Sent: Friday, April 02, 2004 12:23 PM
 To: pymol-users@lists.sourceforge.net
 Subject: [PyMOL] multiple atom selection by atom number
 
 Dear Pymol users,
 
 I am a new pymol explorer (not a user yet :-) and it seems to 
 me that I am not able to select multiple atoms by using the 
 atom number (or id, as pymol call it) in the PDB file. For 
 example, if I would like to select 100 atoms (of consecutive 
 atom numbers) in a polymerase, how would I do that? (select 
 myselection, id 1000-1100 gives me an error message). I know 
 I could use combination of shift+left mouse button and/or
 cntl+left mouse button to select a bunch of atoms, but that does not 
 cntl+give
 the freedom as I would have if I could select using atom numbers.
 
 Thanks for your attention.
 
 Lihua
 
 
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