Re: About python while statement and pop()
2014年6月12日木曜日 14時43分42秒 UTC+9 Steven D'Aprano: On Wed, 11 Jun 2014 21:56:06 -0700, hito koto wrote: I want to use while statement, for example: def foo(x): ... y = [] ... while x !=[]: ... y.append(x.pop()) ... return y ... print foo(a) [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] a [] but this is empty so,I want to leave a number of previous (a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]]) I wouldn't use a while statement. The easy way is: py a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]] py y = a[::-1] py print y [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] py print a [[1, 2, 3, 4], [5, 6, 7, 8, 9], [10]] If you MUST use a while loop, then you need something like this: def foo(x): y = [] index = 0 while index len(x): y.append(x[i]) i += 1 return y This does not copy in reverse order. To make it copy in reverse order, index should start at len(x) - 1 and end at 0. -- Steven Hi, Steven: Thanks, My goal is to be able to in many ways python Sorry, I was mistake, I want to leave a number of previous (a = [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] ) -- https://mail.python.org/mailman/listinfo/python-list
Re: About python while statement and pop()
2014年6月12日木曜日 14時43分42秒 UTC+9 Steven D'Aprano: On Wed, 11 Jun 2014 21:56:06 -0700, hito koto wrote: I want to use while statement, for example: def foo(x): ... y = [] ... while x !=[]: ... y.append(x.pop()) ... return y ... print foo(a) [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] a [] but this is empty so,I want to leave a number of previous (a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]]) I wouldn't use a while statement. The easy way is: py a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]] py y = a[::-1] py print y [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] py print a [[1, 2, 3, 4], [5, 6, 7, 8, 9], [10]] If you MUST use a while loop, then you need something like this: def foo(x): y = [] index = 0 while index len(x): y.append(x[i]) i += 1 return y This does not copy in reverse order. To make it copy in reverse order, index should start at len(x) - 1 and end at 0. -- Steven Hi, Steven: Thanks, My goal is to be able to in many ways python Sorry, I was mistake, I want to leave a number of previous (a = [[10], [9, 8, 7, 6, 5], [4, 3, 2, 1]] ) -- https://mail.python.org/mailman/listinfo/python-list
Re: About python while statement and pop()
2014年6月12日木曜日 14時43分42秒 UTC+9 Steven D'Aprano: On Wed, 11 Jun 2014 21:56:06 -0700, hito koto wrote: I want to use while statement, for example: def foo(x): ... y = [] ... while x !=[]: ... y.append(x.pop()) ... return y ... print foo(a) [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] a [] but this is empty so,I want to leave a number of previous (a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]]) I wouldn't use a while statement. The easy way is: py a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]] py y = a[::-1] py print y [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] py print a [[1, 2, 3, 4], [5, 6, 7, 8, 9], [10]] If you MUST use a while loop, then you need something like this: def foo(x): y = [] index = 0 while index len(x): y.append(x[i]) i += 1 return y This does not copy in reverse order. To make it copy in reverse order, index should start at len(x) - 1 and end at 0. -- Steven Hi, Thank you! -- https://mail.python.org/mailman/listinfo/python-list
Python deepcopy to while statement
Hi, all I want to make the function use while statement,and without a deepcopy functions. this is my use deepcopy function ｃorrect codes, So, how can i to do a different way and use while statement: def foo(x): if not isinstance(x, list): return x return [foo(y) for y in x] -- https://mail.python.org/mailman/listinfo/python-list
Re: Python deepcopy to while statement
2014年6月13日金曜日 12時47分19秒 UTC+9 hito koto: Hi, all I want to make the function use while statement,and without a deepcopy functions. this is my use deepcopy function ｃorrect codes, So, how can i to do a different way and use while statement: def foo(x): if not isinstance(x, list): return x return [foo(y) for y in x] I write this code but this is not copy: maybe have to write one more the while statements: but i can't. def foo(x): y = [] i = len(x)-1 while i = 0: y.append(x[i]) i -= 1 return y -- https://mail.python.org/mailman/listinfo/python-list
Re: Python deepcopy to while statement
2014年6月13日金曜日 12時47分19秒 UTC+9 hito koto: Hi, all I want to make the function use while statement,and without a deepcopy functions. this is my use deepcopy function ｃorrect codes, So, how can i to do a different way and use while statement: def foo(x): if not isinstance(x, list): return x return [foo(y) for y in x] I write this code but this is not copy: maybe noe more write while statements: but i can't. def foo(x): y = [] i = len(x)-1 while i = 0: y.append(x[i]) i -= 1 return y -- https://mail.python.org/mailman/listinfo/python-list
About python while statement and pop()
Hello,all I'm first time, I want to make a while statement which can function the same x.pop () and without the use of pop、how can i to do? i want to change this is code: def foo(x): y = [] while x !=[]: y.append(x.pop()) return y -- https://mail.python.org/mailman/listinfo/python-list
Re: About python while statement and pop()
2014年6月12日木曜日 12時58分27秒 UTC+9 Chris Angelico: On Thu, Jun 12, 2014 at 1:40 PM, Vincent Vande Vyvre vincent.vandevy...@swing.be wrote: Le 12/06/2014 05:12, hito koto a écrit : Hello,all I'm first time, I want to make a while statement which can function the same x.pop () and without the use of pop、how can i to do? i want to change this is code: def foo(x): y = [] while x !=[]: y.append(x.pop()) return y Something like that : def foo(x): return reversed(x) That doesn't do the same thing, though. Given a list x, the original function will empty that list and return a new list in reverse order, but yours will return a reversed iterator over the original list without changing it. This is more accurate, but still not identical, and probably not what the OP's teacher is looking for: def foo(x): y = x[::-1] x[:] = [] return y If the mutation of x is unimportant, it can simply be: def foo(x): return x[::-1] ChrisA I want to use while statement, for example: def foo(x): ... y = [] ... while x !=[]: ... y.append(x.pop()) ... return y ... print foo(a) [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] a [] but this is empty so,I want to leave a number of previous (a = [[1, 2, 3, 4],[5, 6, 7, 8, 9],[10]]) -- https://mail.python.org/mailman/listinfo/python-list
