(Very Newbie) Problems defining a variable
#!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) target = int(input(How much money would you like to earn each year? \n)) interest = 0 i = 0 while interest target: #determine the interest rate to use if bank = : rate = 0.006 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 #Now that we know what interest rate to use, apply it... lastbank = bank#To calculate interest... bank += (bank * rate) #Update earnings... interest = bank - lastbank #And figure out how much interest is made! i += 1 #So we can see which year a calculation represents print(Year %s, at %s rate: %s paid, %s in bank. % (i, rate, interest, bank)) I wrote this expanding off an 'interest' exercise in a tutorial, which was fairly simple (assume %1, calculate for ten years). It's intended to take how much the user has in the bank and determine how long it will be until it generates a certain amount in interest each year. The problem is that rates are not solid, and increase at certain points. I put the rates from the basic account option at my bank in as an example. I'm pretty certain that that is also the problem in the code. I'm pretty sure it's a problem with the 'if' statements', and it looks like it's one of those mistakes that's so simple you look back on it and laugh at yourself. If you put in a bank number = , it fails, saying NameError: name 'rate' is not defined. If you put in one higher, it runs correctly, but thinks that the rate is 0.006 I tried def'ing a function for it, which didn't work any better. I'm having a hard time figuring out exactly why it is those if statements are wrong. -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Dec 12, 5:56 am, Bruno Desthuilliers bruno. 42.desthuilli...@websiteburo.invalid wrote: feb...@gmail.com a écrit : #!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) target = int(input(How much money would you like to earn each year? \n)) interest = 0 i = 0 while interest target: #determine the interest rate to use if bank = : rate = 0.006 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 (snip) I'm pretty certain that that is also the problem in the code. I'm pretty sure it's a problem with the 'if' statements', and it looks like it's one of those mistakes that's so simple you look back on it and laugh at yourself. If you put in a bank number = , it fails, saying NameError: name 'rate' is not defined. If you put in one higher, it runs correctly, but thinks that the rate is 0.006 Indeed. That's what you asked for. If bank is = , then rate will be set to 0.006, and the following tests will be skipped. Else - since you just don't handle the case -, rate is not defined at all. I guess you wanted your first test to be: if bank = : ... FWIW, when using if/elif that way, make sure you always end with a default else clause (even if just to signal you didn't expect to be there...) HTH that's it, thanks! was confused with it being basically in a column of all = *. I replaced it with if bank = 0: print(You're in the red!) quit() elif bank = 1 and bank = : rate = 0.0060 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 else: print(What's this doing here?) which also changes it to keep it from going on forever if you put in a negative amount. Out of curiosity, would you still recommend applying an 'else' clause in this case? I don't see how it could ever be triggered, even if there's an error of some kind -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Fri, 12 Dec 2008 04:05:21 -0800, feba wrote: that's it, thanks! was confused with it being basically in a column of all = *. I replaced it with if bank = 0: print(You're in the red!) quit() elif bank = 1 and bank = : rate = 0.0060 You can replace this with the simpler, easier to read and faster: elif 1 = bank = : rate = 0.0060 elif 1 = bank = 24999: rate = 0.0085 ... elif bank = 10: rate = 0.0173 else: print(What's this doing here?) Change the last two else clauses to this one: else: rate = 0.0173 -- Steven -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Fri, Dec 12, 2008 at 3:42 AM, feb...@gmail.com wrote: #!/usr/bin/python #Py3k, UTF-8 snip #determine the interest rate to use if bank = : rate = 0.006 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 For the love of Benji, reverse the ordering of the clauses so you don't have to keep checking whether the number is also under the next limit! (I'm assuming Bruno's guess about your first test having the operator flipped around the wrong way was right) if bank = 10: rate = 0.0173 elif bank = 5: rate = 0.0149 elif bank = 25000: rate = 0.0124 elif bank = 1: rate = 0.0085 else: rate = 0.006 Note how much simpler that is to read and understand. And switching the default case to the 'else' is just idiomatic. Cheers, Chris -- Follow the path of the Iguana... http://rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
feba: if bank = 0: print(You're in the red!) quit() elif bank = 1 and bank = : rate = 0.0060 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 else: print(What's this doing here?) I think your indents are a little too much large (the soft standard is 4 spaces). The last else can be removed. Does bank == 0 mean being in red? That list of if-elif seems bug-prone. In the future you will learn ways to write that in a less bug-prone (but also probably more complex to read and understand) way. Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
feb...@gmail.com a écrit : #!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) target = int(input(How much money would you like to earn each year? \n)) interest = 0 i = 0 while interest target: #determine the interest rate to use if bank = : rate = 0.006 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 (snip) I'm pretty certain that that is also the problem in the code. I'm pretty sure it's a problem with the 'if' statements', and it looks like it's one of those mistakes that's so simple you look back on it and laugh at yourself. If you put in a bank number = , it fails, saying NameError: name 'rate' is not defined. If you put in one higher, it runs correctly, but thinks that the rate is 0.006 Indeed. That's what you asked for. If bank is = , then rate will be set to 0.006, and the following tests will be skipped. Else - since you just don't handle the case -, rate is not defined at all. I guess you wanted your first test to be: if bank = : ... FWIW, when using if/elif that way, make sure you always end with a default else clause (even if just to signal you didn't expect to be there...) HTH -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
feba a écrit : On Dec 12, 5:56 am, Bruno Desthuilliers bruno. 42.desthuilli...@websiteburo.invalid wrote: (snip) I guess you wanted your first test to be: if bank = : ... (snip) that's it, thanks! was confused with it being basically in a column of all = *. I replaced it with if bank = 0: print(You're in the red!) quit() elif bank = 1 and bank = : rate = 0.0060 elif bank = 1 and bank = 24999: rate = 0.0085 elif bank = 25000 and bank = 4: rate = 0.0124 elif bank = 5 and bank = 9: rate = 0.0149 elif bank = 10: rate = 0.0173 else: print(What's this doing here?) which also changes it to keep it from going on forever if you put in a negative amount. Good point. Out of curiosity, would you still recommend applying an 'else' clause in this case? Yes, but I'd use it as a replacement for the last test: # code here ... elif bank = 5 and bank = 9: rate = 0.0149 else: rate = 0.0173 And finally, I'd simplify the whole damn thing: if bank 1: print(You're in the red!) quit() elif bank 1: rate = 0.0060 elif bank 25000: rate = 0.0085 elif bank 5: rate = 0.0124 elif bank 10: rate = 0.0149 else: rate = 0.0173 I don't see how it could ever be triggered, even if there's an error of some kind It couldn't, indeed. Which FWIW is a clear indication that the previous test ( elif bank = 10:) is redundant !-) HTH -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
Actually, I have gedit set to four spaces per tab. I have no reason why it's showing up that large on copy/paste, but the file itself is fine. Thanks for the advice Chris, Stephen, I can definitely see how those are both far better ways of doing it. I have it as: #!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) if bank =0: print(You need a postive amount to gain interest.) quit() target = int(input(How much money would you like to earn each year? \n)) interest = 0 i = 0 while interest target: #determine the interest rate to use if bank = 10: rate = 0.0173 elif bank = 5: rate = 0.0149 elif bank = 25000: rate = 0.0124 elif bank = 1: rate = 0.0085 else: rate = 0.0060 #Now that we know what interest rate to use, apply it... lastbank = bank#To calculate interest... bank += (bank * rate) #Update earnings... interest = bank - lastbank #And figure out how much interest is made! i += 1 #So we can see which year a calculation represents print(Year %s, at %s rate: %s paid, %s in bank. % (i, rate, interest, bank)) now it checks to make sure the account is positive before moving on, in addition to using your recommendations on readability and efficiency in getting the rate -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Fri, 12 Dec 2008 04:58:36 -0800, feba wrote: Actually, I have gedit set to four spaces per tab. I have no reason why it's showing up that large on copy/paste, but the file itself is fine. The file contains one tab character per indentation level and it depends on the software you use to look at the text how many spaces will be displayed. Better use four real spaces to indent one level so it looks the same everywhere. Ciao, Marc 'BlackJack' Rintsch -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Fri, Dec 12, 2008 at 12:50 PM, Dennis Lee Bieber wlfr...@ix.netcom.comwrote: On Fri, 12 Dec 2008 03:42:55 -0800 (PST), feb...@gmail.com declaimed the following in comp.lang.python: #!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) target = int(input(How much money would you like to earn each year? \n)) Just for my curiosity -- did Python 3.x (besides turning print into a function) also change input() to behave as the old raw_input()? Yes. The above would be very discouraged in Python 2.x... in favor of ... int(raw_input(...)) -- WulfraedDennis Lee Bieber KD6MOG wlfr...@ix.netcom.com wulfr...@bestiaria.com HTTP://wlfraed.home.netcom.com/ (Bestiaria Support Staff: web-a...@bestiaria.com) HTTP://www.bestiaria.com/ -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
Since we all seem to be having a go, here's my take. By pulling the
rates and thresholds into a dictionary I feel I'm getting a step
closer to the real world, where these would presumably be pulled in
from a database and the number of interest bands might vary. But is
there a tidier way to get 'thresholds'? I was a bit surprised that
rates.keys() didn't give me a list directly, so although the 3.0
tutorial says The keys() method of a dictionary object returns a list
of all the keys used in the dictionary, in arbitrary order (if you
want it sorted, just apply the sort() method to ) that's not /quite/
such a given, because the list of keys doesn't seem to be there for
the sorting any more.
Is there a tidy way of making rates and thresholds local to get_rate,
without recalculating each time? I suppose going object oriented is
the proper way.
#Py3k,UTF-8
rates = {0: 0.006, 1: 0.0085, 25000: 0.0124, 5: 0.0149, 10: 0.0173}
thresholds = list(rates.keys())
thresholds.sort()
thresholds.reverse()
def get_rate(balance):
for threshold in thresholds:
if balance = threshold:
return rates[threshold]
else:
return 0.0
balance = int(input(How much money is in your account?\n))
target = int(input(How much money would you like to earn each year?\n))
if balance = 0:
print(You'll never make your fortune that way!\n)
else:
interest = 0
year = 0
while interest target:
rate = get_rate(balance)
interest = balance * rate
balance += interest
year += 1
print(Year %s, at %s rate: %s paid, %s in bank. % (year,
rate, interest, balance))
--
Tim Rowe
--
http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
Tim Rowe wrote:
Since we all seem to be having a go, here's my take. By pulling the
rates and thresholds into a dictionary I feel I'm getting a step
closer to the real world, where these would presumably be pulled in
from a database and the number of interest bands might vary. But is
there a tidier way to get 'thresholds'? I was a bit surprised that
rates.keys() didn't give me a list directly, so although the 3.0
tutorial says The keys() method of a dictionary object returns a list
of all the keys used in the dictionary, in arbitrary order (if you
want it sorted, just apply the sort() method to ) that's not /quite/
such a given, because the list of keys doesn't seem to be there for
the sorting any more.
Is there a tidy way of making rates and thresholds local to get_rate,
without recalculating each time? I suppose going object oriented is
the proper way.
#Py3k,UTF-8
rates = {0: 0.006, 1: 0.0085, 25000: 0.0124, 5: 0.0149, 10: 0.0173}
thresholds = list(rates.keys())
thresholds.sort()
thresholds.reverse()
Why are you putting them into a dict at all? Surely a list of tuples is
better?
# I could've just written the list in descending order here!
rates = [(0, 0.006), (1, 0.0085), (25000, 0.0124), (5, 0.0149),
(10, 0.0173)]
thresholds.sort(reversed=True)
def get_rate(balance):
for threshold in thresholds:
if balance = threshold:
return rates[threshold]
else:
return 0.0
def get_rate(balance):
for threshold, rate in thresholds:
if balance = threshold:
return rate
return 0.0
balance = int(input(How much money is in your account?\n))
target = int(input(How much money would you like to earn each year?\n))
if balance = 0:
print(You'll never make your fortune that way!\n)
else:
interest = 0
year = 0
while interest target:
rate = get_rate(balance)
interest = balance * rate
balance += interest
year += 1
print(Year %s, at %s rate: %s paid, %s in bank. % (year,
rate, interest, balance))
--
http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
At 2008-12-12T18:12:39Z, Tim Rowe digi...@gmail.com writes:
Is there a tidy way of making rates and thresholds local to get_rate,
without recalculating each time? I suppose going object oriented is
the proper way.
#Py3k,UTF-8
rates = {0: 0.006, 1: 0.0085, 25000: 0.0124, 5: 0.0149, 10:
0.0173}
thresholds = list(rates.keys())
thresholds.sort()
thresholds.reverse()
def get_rate(balance):
for threshold in thresholds:
if balance = threshold:
return rates[threshold]
else:
return 0.0
How 'bout:
def get_rate(balance):
for threshold, rate in ((10, .0173),
(5, .0149),
(25000, .0124),
(1, .0085),
(0, .006)):
if balance threshold:
return rate
return .0
--
Kirk Strauser
The Day Companies
--
http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Dec 13, 4:50 am, Dennis Lee Bieber wlfr...@ix.netcom.com wrote: On Fri, 12 Dec 2008 03:42:55 -0800 (PST), feb...@gmail.com declaimed the following in comp.lang.python: #!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) target = int(input(How much money would you like to earn each year? \n)) Just for my curiosity -- did Python 3.x (besides turning print into a function) also change input() to behave as the old raw_input()? Yup. There've been some other tectonic plate shift effects, e.g.: xrange() - range(); range() - list(range()) dict.iteritems() - dict.items(); dict.items() - list(dict.items()) halfassci() - repr(); repr() - ascii() -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
2008/12/12 Kirk Strauser k...@daycos.com: def get_rate(balance): for threshold, rate in ((10, .0173), (5, .0149), (25000, .0124), (1, .0085), (0, .006)): if balance threshold: return rate return .0 Yes, once it's changed from a dictionary to tuples it becomes easier, doesn't it? D'oh! -- Tim Rowe -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Dec 13, 5:18 am, Kirk Strauser k...@daycos.com wrote:
At 2008-12-12T18:12:39Z, Tim Rowe digi...@gmail.com writes:
Is there a tidy way of making rates and thresholds local to get_rate,
without recalculating each time? I suppose going object oriented is
the proper way.
#Py3k,UTF-8
rates = {0: 0.006, 1: 0.0085, 25000: 0.0124, 5: 0.0149, 10:
0.0173}
thresholds = list(rates.keys())
thresholds.sort()
thresholds.reverse()
def get_rate(balance):
for threshold in thresholds:
if balance = threshold:
return rates[threshold]
else:
return 0.0
How 'bout:
def get_rate(balance):
for threshold, rate in ((10, .0173),
(5, .0149),
(25000, .0124),
(1, .0085),
(0, .006)):
if balance threshold:
return rate
return .0
(1) you meant if balance threshold:
(2) sequential search can be very fast if the sequence is in
descending order of probability of occurence ... you might like to
consider reversing the order
(3) for a much longer table, binary search using a function from the
bisect module could be considered
(4) in practice, the default action would not be return 0.0;
perhaps something along these lines:
if balance -overdraft_limit:
raise Exception(...)
return HUGE
--
http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
2008/12/12 John Machin sjmac...@lexicon.net: (2) sequential search can be very fast if the sequence is in descending order of probability of occurence ... you might like to consider reversing the order I find it hard to imagine a bank with so many interest rate thresholds that the search of the table is likely to be a significant contribution to the run time! (3) for a much longer table, binary search using a function from the bisect module could be considered (4) in practice, the default action would not be return 0.0; perhaps something along these lines: if balance -overdraft_limit: raise Exception(...) That's more likely to be in the withdrawal routine (and is probably best not handled as an exception, because it's pretty much normal flow). If a bank provided a service such as the one implemented by this program, there'd be no need for it to know about overdraft limits because it's not making actual transactions. Why would they increase coupling unneccesarily? -- Tim Rowe -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
At 2008-12-12T19:20:52Z, John Machin sjmac...@lexicon.net writes: (1) you meant if balance threshold: balance = threshold. We both mistyped. :-) (2) sequential search can be very fast if the sequence is in descending order of probability of occurence ... you might like to consider reversing the order Actually, I just wanted to point out a simplified version of the exact same algorithm. Given enough RAM and if the speed was indeed critical, you could turn that into a tuple of interest rates and jump straight to rate[balance] in O(1). -- Kirk Strauser The Day Companies -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Dec 13, 6:49 am, Tim Rowe digi...@gmail.com wrote: 2008/12/12 John Machin sjmac...@lexicon.net: (4) in practice, the default action would not be return 0.0; perhaps something along these lines: if balance -overdraft_limit: raise Exception(...) That's more likely to be in the withdrawal routine You'd certainly hope that this test would appear in the withdrawal routine. (and is probably best not handled as an exception, because it's pretty much normal flow). If a bank provided a service such as the one implemented by this program, there'd be no need for it to know about overdraft limits because it's not making actual transactions. Why would they increase coupling unneccesarily? Yeah, you're right, much easier to return 0% interest on a negative balance [customers happy; no wear and tear on the call centre] and hope that anomalies are checked somewhere else *and* that somebody #1 is tasked with actioning the anomaly reports and that somebody #2 is keeping an eye on somebody #1. -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
Tim Rowe a écrit : 2008/12/12 Kirk Strauser k...@daycos.com: def get_rate(balance): for threshold, rate in ((10, .0173), (5, .0149), (25000, .0124), (1, .0085), (0, .006)): if balance threshold: return rate return .0 Yes, once it's changed from a dictionary to tuples it becomes easier, doesn't it? D'oh! comment A sequence of pairs and a dict are _almost_ interchangeable (mmm... is that the correct word ?) representations of a same data set[1] - the main difference being ordering. If ordering matters, choose a sequence of pairs as main representation - you can easily build a dict from it if/when you need it. [1] d = dict(a=1, b=2, c=3) dict(d.items()) == d True /comment -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Fri, 12 Dec 2008 04:58:36 -0800, feba wrote: Actually, I have gedit set to four spaces per tab. I have no reason why it's showing up that large on copy/paste, but the file itself is fine. You've set gedit to _show tabs_ as four spaces, but not to substitute tabs with four spaces. Go to gedit's preference where you change how many spaces is used to display tabs, right below it is Insert spaces instead of tabs. -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
On Fri, 12 Dec 2008 09:50:43 -0800, Dennis Lee Bieber wrote: On Fri, 12 Dec 2008 03:42:55 -0800 (PST), feb...@gmail.com declaimed the following in comp.lang.python: #!/usr/bin/python #Py3k, UTF-8 bank = int(input(How much money is in your account?\n)) target = int(input(How much money would you like to earn each year? \n)) Just for my curiosity -- did Python 3.x (besides turning print into a function) also change input() to behave as the old raw_input()? The above would be very discouraged in Python 2.x... in favor of ... int(raw_input(...)) Actually, that's the first thing I wanted to bark on, before seeing the little note above it: #Py3k, UTF-8. I wonder though, there is a potential problem if someone (users) is running this py3k code in a python2.x. The code is a perfectly legal and correct python 2.x code, but uses input() instead of raw_input(), we all know the evil of 2.x's input (). -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
Kirk Strauser: def get_rate(balance): for threshold, rate in ((10, .0173), (5, .0149), (25000, .0124), (1, .0085), (0, .006)): if balance threshold: return rate return .0 Nice code. This operation, of choosing an item in a sorted list of intervals that has no holes, is common enough. But something like an interval dict is overkill here. I suggest to put a zero before all those points, to improve readability and avoid some possible errors: it's easy to not see a small leading point. Bruno Desthuilliers: A sequence of pairs and a dict are _almost_ interchangeable (mmm... is that the correct word ?) representations of a same data set[1] - the main difference being ordering. If ordering matters, choose a sequence of pairs as main representation - you can easily build a dict from it if/when you need it. Generally(*) it's better to use the simpler data structure that does the job. Here a list/tuple of tuples is good. Very often programs get translated to other languages, so keeping things as simple as possible helps that too. - (*) I have used 'generally' because there's a compromise to be taken here. In C and other related languages you often use structs or records, so if you have pairs you give a name to the fields, for example x and y for the two coordinates of a 2D Point. In Python in such situation you can create a Point class, but often you instead use a (x, y) or [x, y]. In some situations you need to access the fields, so you use [0] and [1]. This is (was) a case where Python looks lower-lever than the C language. In Python3/Python2.6+ you can use a NamedTuple too. Is it better to give and take a list of points to/from as a list of [x,y] lists or as a list of Point2D? Probably a Java programmer thinks that using Point2D is safer and is a way to document what the function takes/returns too. Extending the list of pairs to 3D points is a little simpler if they are represented as tuples/lists. That's an example where you may not choose the simpler data structure (that in Python is a list of pairs) and use a list of NamedTuple to make code safer even if the data structure is a little more complex. Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list
Re: (Very Newbie) Problems defining a variable
feb...@gmail.com wrote: ... elif bank = 1 and bank = 24999: rate = 0.0085 ... Also, (although not useful here as others have pointed out), note that particular code means the same thing as: ... elif 1 = bank = 24999: rate = 0.0085 ... --Scott David Daniels scott.dani...@acm.org -- http://mail.python.org/mailman/listinfo/python-list
