Re: help on python regular expression named group
Le mardi 16 juillet 2013 08:55:58 UTC+2, Mohan L a écrit :
Dear All,
Here is my script :
#!/usr/bin/python
import re
# A string.
logs = date=2012-11-28 time=21:14:59
# Match with named groups.
m =
re.match((?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+))),
logs)
# print
print m.groupdict()
Output:
{'date': '2012-11-28', 'datetime': 'date=2012-11-28 time=21:14:59', 'time':
'21:14:59'}
Required output :
==
{'date': '2012-11-28', 'datetime': '2012-11-28 21:14:59', 'time': '21:14:59'}
need help to correct the below regex
(?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+)))
so that It will have : 'datetime': '2012-11-28 21:14:59' instead of
'datetime': 'date=2012-11-28 time=21:14:59'
any help would be greatly appreciated
Thanks
Mohan L
--
Not sure, I'm correct. I took you precise string to
refresh my memory.
import re
tmp = 'date=\d{4}-\d{2}-\d{2}'
DatePattern = '(?PDATEPATTERN' + tmp + ')'
tmp = 'time=\d{2}:\d{2}:\d{2}'
TimePattern = '(?PTIMEPATTERN' + tmp + ')'
pattern = DatePattern + ' ' + TimePattern
pattern
'(?PDATEPATTERNdate=\\d{4}-\\d{2}-\\d{2})
(?PTIMEPATTERNtime=\\d{2}:\\d{2}:\\d{2})'
CompiledPattern = re.compile(pattern)
s = 'date=2012-11-28 time=21:14:59'
mo = CompiledPattern.search(s)
print(mo)
_sre.SRE_Match object at 0x02CD4188
print(mo.groups())
('date=2012-11-28', 'time=21:14:59')
print(mo.groupdict())
{'DATEPATTERN': 'date=2012-11-28', 'TIMEPATTERN': 'time=21:14:59'}
print(mo.group(1), mo.group('DATEPATTERN'))
date=2012-11-28 date=2012-11-28
print(mo.group(2), mo.group('TIMEPATTERN'))
time=21:14:59 time=21:14:59
jmf
--
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Re: help on python regular expression named group
On 17 July 2013 07:15, wxjmfa...@gmail.com wrote: Not sure, I'm correct. I took you precise string to refresh my memory. I'm glad to see you doing something else, but I don't think you understood his problem. Note that his problem has not solution, which a few seconds of Googling has confirmed to me. -- http://mail.python.org/mailman/listinfo/python-list
Re: help on python regular expression named group
Le mercredi 17 juillet 2013 09:46:46 UTC+2, Joshua Landau a écrit : On 17 July 2013 07:15, wxjmfa...@gmail.com wrote: Not sure, I'm correct. I took you precise string to refresh my memory. I'm glad to see you doing something else, but I don't think you understood his problem. Note that his problem has not solution, which a few seconds of Googling has confirmed to me. Right. I did not pay attention to date, time *and* datetime. jmf -- http://mail.python.org/mailman/listinfo/python-list
Re: help on python regular expression named group
On 16 July 2013 07:55, Mohan L l.mohan...@gmail.com wrote:
Dear All,
Here is my script :
#!/usr/bin/python
import re
# A string.
logs = date=2012-11-28 time=21:14:59
# Match with named groups.
m =
re.match((?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+))),
logs)
# print
print m.groupdict()
Output:
{'date': '2012-11-28', 'datetime': 'date=2012-11-28 time=21:14:59', 'time':
'21:14:59'}
Required output :
==
{'date': '2012-11-28', 'datetime': '2012-11-28 21:14:59', 'time':
'21:14:59'}
need help to correct the below regex
(?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+)))
so that It will have : 'datetime': '2012-11-28 21:14:59' instead of
'datetime': 'date=2012-11-28 time=21:14:59'
any help would be greatly appreciated
Why do you need to do this in a single Regex? Can't you just
.join(..) the date and time?
--
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Re: help on python regular expression named group
On Tue, Jul 16, 2013 at 2:12 PM, Joshua Landau jos...@landau.ws wrote:
On 16 July 2013 07:55, Mohan L l.mohan...@gmail.com wrote:
Dear All,
Here is my script :
#!/usr/bin/python
import re
# A string.
logs = date=2012-11-28 time=21:14:59
# Match with named groups.
m =
re.match((?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+))),
logs)
# print
print m.groupdict()
Output:
{'date': '2012-11-28', 'datetime': 'date=2012-11-28 time=21:14:59',
'time':
'21:14:59'}
Required output :
==
{'date': '2012-11-28', 'datetime': '2012-11-28 21:14:59', 'time':
'21:14:59'}
need help to correct the below regex
(?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+)))
so that It will have : 'datetime': '2012-11-28 21:14:59' instead of
'datetime': 'date=2012-11-28 time=21:14:59'
any help would be greatly appreciated
Why do you need to do this in a single Regex? Can't you just
.join(..) the date and time?
I using another third party python script. It takes the regex from
configuration file. I can't write any code. I have to do all this in single
regex.
Thanks
Mohan L
--
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Re: help on python regular expression named group
On 16/07/2013 11:18, Mohan L wrote:
On Tue, Jul 16, 2013 at 2:12 PM, Joshua Landau jos...@landau.ws
mailto:jos...@landau.ws wrote:
On 16 July 2013 07:55, Mohan L l.mohan...@gmail.com
mailto:l.mohan...@gmail.com wrote:
Dear All,
Here is my script :
#!/usr/bin/python
import re
# A string.
logs = date=2012-11-28 time=21:14:59
# Match with named groups.
m =
re.match((?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+))),
logs)
# print
print m.groupdict()
Output:
{'date': '2012-11-28', 'datetime': 'date=2012-11-28
time=21:14:59', 'time':
'21:14:59'}
Required output :
==
{'date': '2012-11-28', 'datetime': '2012-11-28 21:14:59', 'time':
'21:14:59'}
need help to correct the below regex
(?Pdatetime(date=(?Pdate[^\s]+))\s+(time=(?Ptime[^\s]+)))
so that It will have : 'datetime': '2012-11-28 21:14:59' instead of
'datetime': 'date=2012-11-28 time=21:14:59'
any help would be greatly appreciated
Why do you need to do this in a single Regex? Can't you just
.join(..) the date and time?
I using another third party python script. It takes the regex from
configuration file. I can't write any code. I have to do all this in
single regex.
A capture group captures a single substring.
What you're asking is for it to with capture 2 substrings (the date and
the time) and then join them together, or capture 1 substring and then
remove part of it.
I don't know of _any_ regex implementation that lets you do that.
--
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Re: help on python regular expression named group
On 16 July 2013 16:38, MRAB pyt...@mrabarnett.plus.com wrote: On 16/07/2013 11:18, Mohan L wrote: I using another third party python script. It takes the regex from configuration file. I can't write any code. I have to do all this in single regex. A capture group captures a single substring. What you're asking is for it to with capture 2 substrings (the date and the time) and then join them together, or capture 1 substring and then remove part of it. I don't know of _any_ regex implementation that lets you do that. If MRAB is correct, there is one straw-clutching method. If in the configuration you pass a regex *object* rather than a regex string, you could duck-type as a regex object. This might sound far-fetched but it's happened once to me. Otherwise, good luck. -- http://mail.python.org/mailman/listinfo/python-list
