me wrote:
code
I'm new to regexs and trying to get a list of all my C++ methods with balanced
parenthesis as follows.
#find all c++ method prototypes with a '::' in the middle
#upto and including the 1st closing parenthesis
pattern_upto_1st_closed_parenth = re.compile('\w+::\w+\([^)]*\)')
match_upto_1st_closed_parenth=
re.findall(pattern_upto_1st_closed_parenth,txt)
num_of_protos = len(match_upto_1st_closed_parenth)
for i in range (0,num_of_protos-1):
This should actually be range(0, num_of_protos).
num_of_open_parenths = match_upto_1st_closed_parenth[i].count('(')
#expand the pattern to get all of the prototype
#ie upto the last closed parenthesis
#saying something like
pattern = re.compile(\
'match_upto_1st_closed_parenth[i]+\
(([^)]*\)){num_of_open_parenths-1}'\
)
#
#HELP!! I'm not sure how to incorporate:
#1 'match_upto_1st_closed_parenth[i]' into the above extended pattern???
#2 the count 'num_of_open_parenths' instead of a literal ???
#
#===
#if I could do it this sort of this would appear to offer the neatest solution
pattern_upto_last_balanced_parenthesis = re.compile('
(\w+::\w+\([^)]*\))\
([^)]*\)){\1.count('(')-1}
')
#===
Should I be using regexs to do this?
I've only put \ line extensions to separate the pattern components to assist
readability
Thx
/code
Not necessarily the best way, but:
methods = []
# The pattern for the start of the method's header.
start_pattern = re.compile(r'\w+::\w+\([^)]*\)')
# Start at the beginning of the text.
pos = 0
while True:
# Search for the start of the next method's header.
start_match = start_pattern.search(txt, pos)
if not start_match:
break
# Search for the end of the method's header.
end_pattern = re.compile(r'(?:[^)]*\)){%d}' %
start_match.group().count('('))
end_match = end_pattern.search(txt, pos)
methods.append(txt[start_match.start() : end_match.end()])
# Continue the next search from where we left off.
pos = end_match.end()
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