Re: [R] detecting any element in a vector of strings, appearing anywhere in any of several character variables in a dataframe
Thanks everyone. John's original solution worked great. And with 27,000 records, 65 alarm.words, and 6 columns to search, it takes only about 15 seconds. That is certainly adequate for my needs. But I will try out the other strategies too. And thanks also for lot's of new R things to learn--grep, grepl, do.call . . . that's always a bonus! --Chris Ryan On Thu, Jul 9, 2015 at 1:52 PM, Bert Gunter bgunter.4...@gmail.com wrote: Yup, that does it. Let grep figure out what's a word rather than doing it manually. Forgot about \b Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Thu, Jul 9, 2015 at 10:30 AM, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote: Just add a word break marker before and after: zz$v5 - grepl( paste0( \\b(, paste0( alarm.words, collapse=| ), )\\b ), do.call( paste, zz[ , 2:3 ] ) ) ) --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On July 9, 2015 10:12:23 AM PDT, Bert Gunter bgunter.4...@gmail.com wrote: Jeff: Well, it would be much better (no loops!) except, I think, for one issue: red would match barred and I don't think that this is what is wanted: the matches should be on whole words not just string patterns. So you would need to fix up the matching pattern to make this work, but it may be a little tricky, as arbitrary whitespace characters, e.g. or \n etc. could be in the strings to be matched separating the words or ending the sentence. I'm sure it can be done, but I'll leave it to you or others to figure it out. Of course, if my diagnosis is wrong or silly, please point this out. Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Thu, Jul 9, 2015 at 9:34 AM, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote: I think grep is better suited to this: zz$v5 - grepl( paste0( alarm.words, collapse=| ), do.call( paste, zz[ , 2:3 ] ) ) ) --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On July 9, 2015 8:51:10 AM PDT, Bert Gunter bgunter.4...@gmail.com wrote: Here's a way to do it that uses %in% (i.e. match() ) and uses only a single, not a double, loop. It should be more efficient. sapply(strsplit(do.call(paste,zz[,2:3]),[[:space:]]+), + function(x)any(x %in% alarm.words)) [1] FALSE FALSE TRUE FALSE FALSE TRUE FALSE FALSE TRUE TRUE The idea is to paste the strings in each row (do.call allows an arbitrary number of columns) into a single string and then use strsplit to break the string into individual words on whitespace. Then the matching is vectorized with the any( %in% ... ) call. Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Thu, Jul 9, 2015 at 6:05 AM, John Fox j...@mcmaster.ca wrote: Dear Chris, If I understand correctly what you want, how about the following? rows - apply(zz[, 2:3], 1, function(x) any(sapply(alarm.words, grepl, x=x))) zz[rows, ] v1 v2v3 v4 3 -1.022329green turtleronald weasley 2 6 0.336599 waffle the hamsterred sparks 1 9 -1.631874 yellow giraffe with a long neck gandalf the white 1 10 1.130622 black bear gandalf the grey 2 I hope this helps, John John Fox, Professor McMaster University Hamilton, Ontario, Canada http://socserv.mcmaster.ca/jfox/ On Wed, 08 Jul 2015 22:23:37 -0400 Christopher W. Ryan cr...@binghamton.edu wrote: Running R 3.1.1 on windows 7 I want to identify as a case any record in a dataframe that contains any of several keywords in any of several variables. Example: # create a dataframe with 4 variables and 10 records v2 - c(white bird, blue bird, green turtle, quick brown
Re: [R] sum some columns for each row
Hi Dawn, Your data are a bit messed up, but try the following: colSums(dat[,grep(ABC,names(dat),fixed=TRUE)],na.rm=TRUE) colSums(dat[,grep(XYZ,names(dat),fixed=TRUE)],na.rm=TRUE) I'm assuming that you want to discard the NA values. Jim On Fri, Jul 10, 2015 at 6:52 AM, Rui Barradas ruipbarra...@sapo.pt wrote: Hello, Please use ?dput to give a data example, like this it's completely unreadable. If your data.frame is named 'dat' use dput(head(dat, 30)) # paste the outut of this in your mail And don't post in html, use plain text only, like the posting guide says. Rui Barradas Em 09-07-2015 18:12, Dawn escreveu: Hi, I have a big dataframe as follows 109ABC109XYZ18ABC18XYZ22XYZ23ABC25ABC 25XYZ 30ABC31XYZ32ABC32XYZ34DCM34XYZ36ABC36SUR 38DCM38XYZ39DCM39SUR41DCM41SUR42DCM42SUR 46SUR52DCM64ABC64XYZ65ABC65XYZ66ABC66XYZ 67XYZ68ABC68SUR70MES70SUR72ABC72XYZ76ABC 76XYZ82ABC85ABCPOV Cluster_1171 310145221112 2TT:61 Cluster_21420 653699610131 4TT:88 Cluster_3336417 1718131719221152185184 79 TT:227 I want to get two columns, i.e, one is to sum columns for all including ABC for each row and the other is to sum columns for all including XYZ for each row. Is there some help? Thank you! Dawn [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] color2D.matplot with anchored color scale
Hi Phong, This is a common problem with using color to represent numeric values. What you want is a reference scale. Whenever you call color2D.matplot, use the cellcolors argument to specify the colors of each cell. You can directly call color.scale in this argument, using the xrange argument of that function to ensure that the colors returned are calculated for the full range: color.scale(...,xrange=c(0,40),...) Look at the second example in the help page for barp to see how this is done. Notice that it doesn't matter that the actual data are in proportions (0 to 1) and the legend is labelled in percentages (0 to 100). The data values are correctly colored for the entire scale, although none of these values are at the endpoints. Jim On Fri, Jul 10, 2015 at 12:22 PM, Phong Nguyen xphon...@gmail.com wrote: Hello Jim, I have a several matrices stored in allGrid - list() I am using: color2D.matplot(grid, extremes = c(green, red), vcol = black, nslices = 60, show.legend=TRUE,axes=FALSE,show.values=TRUE, xlab=Columns,ylab=Rows) for each of grid in allGrid. Each grid is a matrix with element range from 0 to max number of allGrid, say 40. I want to plot many grid with color represents the number (density). But I cannot fix the color scale and anchor the maximum value to a fixed number. I have tried many things but nothing works. Just the extra is: I cannot make the color from green (small number) - yellow (middle number) - red (big number). Sometimes, the plot turns black and white. Please help me. Phong __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
On Fri, 10 Jul 2015, David Winsemius wrote: #Generally one needs to complete a pdf() call with: dev.off() # And an empty file is the symptom os such a failure. David, I did leave that off the example file, but it make no difference. The attached is the compiled example.pdf Rich example.pdf Description: Adobe PDF document __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] sum some columns for each row
Thank you all and sorry for the data messing. It has worked! Best, Dawn On Fri, Jul 10, 2015 at 4:15 AM, Jim Lemon drjimle...@gmail.com wrote: Hi Dawn, Your data are a bit messed up, but try the following: colSums(dat[,grep(ABC,names(dat),fixed=TRUE)],na.rm=TRUE) colSums(dat[,grep(XYZ,names(dat),fixed=TRUE)],na.rm=TRUE) I'm assuming that you want to discard the NA values. Jim On Fri, Jul 10, 2015 at 6:52 AM, Rui Barradas ruipbarra...@sapo.pt wrote: Hello, Please use ?dput to give a data example, like this it's completely unreadable. If your data.frame is named 'dat' use dput(head(dat, 30)) # paste the outut of this in your mail And don't post in html, use plain text only, like the posting guide says. Rui Barradas Em 09-07-2015 18:12, Dawn escreveu: Hi, I have a big dataframe as follows 109ABC109XYZ18ABC18XYZ22XYZ23ABC25ABC 25XYZ 30ABC31XYZ32ABC32XYZ34DCM34XYZ36ABC36SUR 38DCM38XYZ39DCM39SUR41DCM41SUR42DCM42SUR 46SUR52DCM64ABC64XYZ65ABC65XYZ66ABC66XYZ 67XYZ68ABC68SUR70MES70SUR72ABC72XYZ76ABC 76XYZ82ABC85ABCPOV Cluster_1171 310145221112 2TT:61 Cluster_21420 653699610131 4TT:88 Cluster_3336417 1718131719221152185184 79 TT:227 I want to get two columns, i.e, one is to sum columns for all including ABC for each row and the other is to sum columns for all including XYZ for each row. Is there some help? Thank you! Dawn [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
Your LyX example has two problems: 1) We don't have your .RData; 2) You didn't library(reshape) and library(lattice). Hence it is not a self-contained reproducible example. After fixing these two issues, I don't see why lattice graphics can be problematic with knitr. There is no need to print() the plot, and no need to pdf(), either. See the attached PDF I generated. Regards, Yihui -- Yihui Xie xieyi...@gmail.com Web: http://yihui.name On Fri, Jul 10, 2015 at 7:18 PM, Rich Shepard rshep...@appl-ecosys.com wrote: On Fri, 10 Jul 2015, David Winsemius wrote: #Generally one needs to complete a pdf() call with: dev.off() # And an empty file is the symptom os such a failure. David, I did leave that off the example file, but it make no difference. The attached is the compiled example.pdf Rich __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. example.pdf Description: Adobe PDF document __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Time series exercise (was: (no subject)).
On 10/07/15 21:17, Lia LEE wrote: Hello forum members, I am taking this R course which I have to admit that it is beyond my capability. I am asked to analyze the following data(file attached) according to the question provided below: 1. The file [data_13-9.txt] contains a data of length 225, which seems to have some cycle pattern. (1) Fit a suitable model for this data, then report the model equation. (2) Provide the forecast values for 3-steps ahead and 6-steps ahead. I am desperately seeking for your help, since I really don't know where to start.. I have done plot.ts(data.13-6), but not further. Above question is just part of the whole task, but I believe solving this would be very much helpful for me to jump in to the other questions. It would be easier for me to follow if your answer is in R script.. I appreciate your patience and help. Thank you so much in advance! As Bert Gunter said, we don't do homework for people on this list. Notwithstanding I couldn't resist having a crack at analysing your time series, and I found it, uh, challenging to say the least. I think of myself as having at least *some* skill at fitting time series models, and I struggled to find a model that fitted adequately to your data. (I finally managed to get a decent fit, after trying a number of models on a hammer-and-hope basis.) Perhaps I am even more of a thicko than I think I am. Nevertheless it seems to me that your instructor has dropped you in the deep end by setting you this exercise. (Perhaps I am missing something obvious, as is so often the case. Others may wish to chime in with some comments to the effect You idiot Rolf. The *obvious* model is ) At any rate, your first stop should be your instructor. Get him or her to give you some pointers as to how to get started. That is what instructors are for. cheers, Rolf Turner Technical Editor ANZJS Department of Statistics University of Auckland Phone: +64-9-373-7599 ext. 88276 __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
On Jul 10, 2015, at 2:57 PM, Rich Shepard wrote:
On Fri, 10 Jul 2015, Hadley Wickham wrote:
Have you tried explicitly print()ing the lattice graphics in your knitr
doc?
Hadley,
Only now. Had not thought of trying this before.
pdf('carlin-1-descriptive.pdf')
print(xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T))
#Generally one needs to complete a pdf() call with:
dev.off()
# And an empty file is the symptom os such a failure.
David.
No error messages, but no graphic, either. Without specifying the pdf
device, TeX complains it cannot find a graphics device and lists bit-mapped,
ps and svg devices.
Most likely I do not have the correct syntax.
Thanks,
Rich
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius
Alameda, CA, USA
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
I'd recommend starting with a simpler .Rmd or .Rnw file, rather than
using it with lyx. The basic .Rmd file below works for me without any
further adjustments:
# Lattice test
```{r}
library(lattice)
xyplot(mpg ~ wt, data = mtcars)
```
Hadley
On Fri, Jul 10, 2015 at 3:39 PM, Rich Shepard rshep...@appl-ecosys.com wrote:
On Fri, 10 Jul 2015, Hadley Wickham wrote:
You shouldn't be explicitly opening a device in a knitr document.
Hadley,
Didn't think so.
I think maybe you should post a minimal document so we can figure out
what's going wrong.
Agreed. Attached are the raw data (carlin.csv) and a stripped down LyX
document with the knitr chunks.
This is my first attempt to use knitr; I'm reading the knitr book and
that's where I got the impression that lattice graphics are not supported.
Rich
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
http://had.co.nz/
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] (no subject)
I was under the impression that different instructional environments have different standards for ethical conduct, so we list members cannot in general know whether we would be condoning/assisting in cheating. However, if you are taking a class, then the instructor/institution should be providing appropriate resources to assist the student so we should not have to second guess them anyway. Reducing list volume is at best a secondary concern from my perspective. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On July 10, 2015 10:30:41 AM PDT, Bert Gunter bgunter.4...@gmail.com wrote: Sorry Lia. We don't do homework on this list. You can imagine how clogged it would be if we did. Maybe you'll get lucky and someone will answer you privately. Otherwise, seek help from your teachers, fellow students, and/or course homework forums. Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Fri, Jul 10, 2015 at 2:17 AM, Lia LEE ljylia.0...@gmail.com wrote: Hello forum members, I am taking this R course which I have to admit that it is beyond my capability. I am asked to analyze the following data(file attached) according to the question provided below: 1. The file [data_13-9.txt] contains a data of length 225, which seems to have some cycle pattern. (1) Fit a suitable model for this data, then report the model equation. (2) Provide the forecast values for 3-steps ahead and 6-steps ahead. I am desperately seeking for your help, since I really don't know where to start.. I have done plot.ts(data.13-6), but not further. Above question is just part of the whole task, but I believe solving this would be very much helpful for me to jump in to the other questions. It would be easier for me to follow if your answer is in R script.. I appreciate your patience and help. Thank you so much in advance! Cheers, Lia __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Embed fonts in an R graph
On Jul 10, 2015, at 8:45 AM, David Winsemius wrote: On Jul 10, 2015, at 7:40 AM, Edwin Sun wrote: Hello all, I cannot embed a common font type into an R graph. I did it successfully in December 2014 with the previous R version. However, with R 3.2.1 in July 2015, the following sample codes do not work anymore. pdf(file = c:/testA.pdf, family = serif) plot(x = 1:10, y = rnorm(10)) dev.off() embedFonts(file = c:/testA.pdf, outfile = c:/testB.pdf) When you look at ?embedFonts it becomes obvious that this is a process mediated by GhostScript, an external program no under the control of the R Team, but rather a system facility that you are responsible for maintaining on your unspecified (but inferable) operating system. And don't forget to read your News. In this case, there is an item in the very first entry about embedFonts: str(news()) Classes ‘news_db_from_Rd’, ‘news_db’ and 'data.frame': 681 obs. of 4 variables: $ Version : chr 3.1.2 3.1.2 3.1.2 3.1.2 ... $ Date: chr NA NA NA NA ... $ Category: chr NEW FEATURES NEW FEATURES NEW FEATURES NEW FEATURES ... $ Text: chr embedFonts() now defaults to format = \ps2write\ for .ps and .eps\nfiles. This is available in Ghostscript 9.x (since 2010) | __truncated__ For consistency with [dpqr]norm(), [dp]lnorm(sdlog = 0) model a\npoint mass at exp(mulog) rather than return NaN (for an error)| __truncated__ capabilities() now reports if ICU is compiled in for use for\ncollation (it is only actually used if a suitable locale is set f| __truncated__ (OS X only.) Package tcltk checks when loaded if it is linked\nagainst the CRAN X11-based Tcl/Tk and if so that the Tcl/Tk\ncom| __truncated__ ... - attr(*, bad)= logi FALSE FALSE FALSE FALSE FALSE FALSE ... - attr(*, package)= chr R Here's a way to search for any others: newstuff$Text[ grepl(embed, newstuff$Text) ] [1] embedFonts() now defaults to format = \ps2write\ for .ps and .eps\nfiles. This is available in Ghostscript 9.x (since 2010) whereas\nthe previous default, format = \pswrite\, was removed in\nGhostscript 9.10. [2] Error messages from bugs in embedded Sexpr code in Sweave documents\nnow report the source location. [3] read.table(), readLines() and scan() have a new argument to\ninfluence the treatment of embedded nuls. [4] read.table(), readLines() and scan() now warn when an embedded nul\nis found in the input. (Related to PR#15625 which was puzzled by\nthe behaviour in this unsupported case.) As a result, both testA.pdf and testB.pdf cannot embed the fonts into the graph. That sentence did not make sense to me. I would have expected 'testA.pdf to have been altered at all. -- David. Since You are posting through Nabble I'd suggest you read the Posting Guide: R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Specifically, Adobe Acrobt reveals that Times-Roman is substituted by TimesNewRomanPSMT, and ZapfDingbats is substituted by AdobePiStd. Any help is greatly appreciated. Edwin http://r.789695.n4.nabble.com/file/n4709707/Capture.png -- View this message in context: http://r.789695.n4.nabble.com/Embed-fonts-in-an-R-graph-tp4709707.html Sent from the R help mailing list archive at Nabble.com. -- David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Embed fonts in an R graph
Hello all, I cannot embed a common font type into an R graph. I did it successfully in December 2014 with the previous R version. However, with R 3.2.1 in July 2015, the following sample codes do not work anymore. pdf(file = c:/testA.pdf, family = serif) plot(x = 1:10, y = rnorm(10)) dev.off() embedFonts(file = c:/testA.pdf, outfile = c:/testB.pdf) As a result, both testA.pdf and testB.pdf cannot embed the fonts into the graph. Specifically, Adobe Acrobt reveals that Times-Roman is substituted by TimesNewRomanPSMT, and ZapfDingbats is substituted by AdobePiStd. Any help is greatly appreciated. Edwin http://r.789695.n4.nabble.com/file/n4709707/Capture.png -- View this message in context: http://r.789695.n4.nabble.com/Embed-fonts-in-an-R-graph-tp4709707.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Embed fonts in an R graph
On Jul 10, 2015, at 7:40 AM, Edwin Sun wrote: Hello all, I cannot embed a common font type into an R graph. I did it successfully in December 2014 with the previous R version. However, with R 3.2.1 in July 2015, the following sample codes do not work anymore. pdf(file = c:/testA.pdf, family = serif) plot(x = 1:10, y = rnorm(10)) dev.off() embedFonts(file = c:/testA.pdf, outfile = c:/testB.pdf) When you look at ?embedFonts it becomes obvious that this is a process mediated by GhostScript, an external program no under the control of the R Team, but rather a system facility that you are responsible for maintaining on your unspecified (but inferable) operating system. As a result, both testA.pdf and testB.pdf cannot embed the fonts into the graph. That sentence did not make sense to me. I would have expected 'testA.pdf to have been altered at all. -- David. Since You are posting through Nabble I'd suggest you read the Posting Guide: R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Specifically, Adobe Acrobt reveals that Times-Roman is substituted by TimesNewRomanPSMT, and ZapfDingbats is substituted by AdobePiStd. Any help is greatly appreciated. Edwin http://r.789695.n4.nabble.com/file/n4709707/Capture.png -- View this message in context: http://r.789695.n4.nabble.com/Embed-fonts-in-an-R-graph-tp4709707.html Sent from the R help mailing list archive at Nabble.com. -- David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Corrected: approaches tpmatrix multiplication of each layer of 3-d array with different matrix
Strictly speaking, the answer is yes because you can unroll the loop, but that
probably is not what you really want or need to do.
Your example seems about right, but it is not clear how you plan to make 44
conform with 5500.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/BatteriesO.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
---
Sent from my phone. Please excuse my brevity.
On July 10, 2015 6:44:19 AM PDT, Ranjan Maitra maitra.mbox.igno...@inbox.com
wrote:
Hi,
Sorry to post again, but there is a careless error in my first R code
snippet:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:dim(A)[3]) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
The second snippet is correct:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ] %*%
mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, the second is almost twice as long as the first snippet.
Many thanks,
Ranjan
On Fri, 10 Jul 2015 08:23:49 -0500 Ranjan Maitra
maitra.mbox.igno...@inbox.com wrote:
Dear friends,
I have two 3-d arrays of appropriate dimensions. I want to
postmultiply the 2-D matrix layers of the first with the 2-D matrix
layers of the second. Can I do this easily in R avoiding loops?
As an example:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:3) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
So, is there a way to do this without the loop?
Of course, I could abind the arrays and then use apply with an
appropriate function which would be as follows:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ]
%*% mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, this turns out to be slower -- perhaps because of the use of
abind and filling the array inside the function.
I just wanted suggestions to get this operation done more
efficiently.
Many thanks and best wishes,
Ranjan
Publish your photos in seconds for FREE
TRY IM TOOLPACK at http://www.imtoolpack.com/default.aspx?rc=if4
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Corrected: approaches to matrix multiplication of each layer of 3-d array with different matrix
What does it mean to unroll the loop?
Thanks!
Ranjan
On Fri, 10 Jul 2015 07:07:15 -0700 Jeff Newmiller jdnew...@dcn.davis.ca.us
wrote:
Strictly speaking, the answer is yes because you can unroll the loop, but
that probably is not what you really want or need to do.
Your example seems about right, but it is not clear how you plan to make 44
conform with 5500.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/BatteriesO.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
---
Sent from my phone. Please excuse my brevity.
On July 10, 2015 6:44:19 AM PDT, Ranjan Maitra
maitra.mbox.igno...@inbox.com wrote:
Hi,
Sorry to post again, but there is a careless error in my first R code
snippet:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:dim(A)[3]) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
The second snippet is correct:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ] %*%
mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, the second is almost twice as long as the first snippet.
Many thanks,
Ranjan
On Fri, 10 Jul 2015 08:23:49 -0500 Ranjan Maitra
maitra.mbox.igno...@inbox.com wrote:
Dear friends,
I have two 3-d arrays of appropriate dimensions. I want to
postmultiply the 2-D matrix layers of the first with the 2-D matrix
layers of the second. Can I do this easily in R avoiding loops?
As an example:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:3) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
So, is there a way to do this without the loop?
Of course, I could abind the arrays and then use apply with an
appropriate function which would be as follows:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ]
%*% mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, this turns out to be slower -- perhaps because of the use of
abind and filling the array inside the function.
I just wanted suggestions to get this operation done more
efficiently.
Many thanks and best wishes,
Ranjan
Publish your photos in seconds for FREE
TRY IM TOOLPACK at http://www.imtoolpack.com/default.aspx?rc=if4
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Important Notice: This mailbox is ignored: e-mails are set to be deleted on
receipt. Please respond to the mailing list if appropriate. For those needing
to send personal or professional e-mail, please use appropriate addresses.
FREE 3D EARTH SCREENSAVER - Watch the Earth right on your desktop!
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] approaches tpmatrix multiplication of each layer of 3-d array with different matrix
Dear friends,
I have two 3-d arrays of appropriate dimensions. I want to postmultiply the 2-D
matrix layers of the first with the 2-D matrix layers of the second. Can I do
this easily in R avoiding loops?
As an example:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:3) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
So, is there a way to do this without the loop?
Of course, I could abind the arrays and then use apply with an appropriate
function which would be as follows:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ] %*%
mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, this turns out to be slower -- perhaps because of the use of abind and
filling the array inside the function.
I just wanted suggestions to get this operation done more efficiently.
Many thanks and best wishes,
Ranjan
Publish your photos in seconds for FREE
TRY IM TOOLPACK at http://www.imtoolpack.com/default.aspx?rc=if4
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Corrected: approaches tpmatrix multiplication of each layer of 3-d array with different matrix
Hi,
Sorry to post again, but there is a careless error in my first R code snippet:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:dim(A)[3]) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
The second snippet is correct:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ] %*%
mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, the second is almost twice as long as the first snippet.
Many thanks,
Ranjan
On Fri, 10 Jul 2015 08:23:49 -0500 Ranjan Maitra
maitra.mbox.igno...@inbox.com wrote:
Dear friends,
I have two 3-d arrays of appropriate dimensions. I want to postmultiply the
2-D matrix layers of the first with the 2-D matrix layers of the second. Can
I do this easily in R avoiding loops?
As an example:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:3) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
So, is there a way to do this without the loop?
Of course, I could abind the arrays and then use apply with an appropriate
function which would be as follows:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ] %*%
mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, this turns out to be slower -- perhaps because of the use of abind
and filling the array inside the function.
I just wanted suggestions to get this operation done more efficiently.
Many thanks and best wishes,
Ranjan
Publish your photos in seconds for FREE
TRY IM TOOLPACK at http://www.imtoolpack.com/default.aspx?rc=if4
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Important Notice: This mailbox is ignored: e-mails are set to be deleted on
receipt. Please respond to the mailing list if appropriate. For those needing
to send personal or professional e-mail, please use appropriate addresses.
Can't remember your password? Do you need a strong and secure password?
Use Password manager! It stores your passwords protects your account.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] cointegration and VECM, urca package and Eviews
Hello, I estimated a VECM in Eviews and R using urca package's ca.jo(), cajorl() and vec2var() functions. Specifications are 'no trend' in Eviews and 'none' in R (no theory, just testing, feel free to make changes). Results are different, ecm and cointegrating vectors are completely different. R code is: *johcoint=ca.jo(Ydata,type=trace,ecdet=c(none),K=2,spec=transitory) summary(johcoint) vecm.r1=cajorls(johcoint,r=1) vecm.r1 vecm.l=vec2var(johcoint,r=1) ll=irf(vecm.l, impulse = B,response = A, boot = FALSE) plot(ll$irf[[1]])* Data: AB C D 1 8.6469243.9251552.2977372.764267 2 8.6438104.0482152.1407312.769231 3 8.6347324.1171142.0637242.747604 4 8.6033373.9760021.9392902.741640 5 8.6043443.9246971.9282552.732419 6 8.6288873.9215171.8786742.718437 7 8.6531673.9060761.9432362.693620 8 8.6618543.9404682.1077182.670370 9 8.6098393.8727822.0030642.689212 10 8.6140913.9058391.9737192.679186 11 8.6136923.8907971.9393112.659350 12 8.6514884.0524231.9610382.640751 13 8.6544694.1375342.1308732.622611 14 8.6931214.0747532.1084272.595760 15 8.6994353.8724122.0918162.622049 16 8.8087243.8513732.3457402.646252 17 8.8144373.8060482.0571042.728953 18 8.8365293.7430461.8258272.748266 19 8.8268983.6938971.8238803.027604 20 8.8091173.6731262.0200162.820051 21 8.6549723.6529031.5232492.538225 22 8.5159173.6595921.6177342.523293 23 8.5899193.6558221.8276452.371598 24 8.5951933.6459371.8256032.251557 25 8.6153323.6292011.6619462.254364 26 8.6712223.6094641.7330732.145093 27 8.6118823.6121101.7949371.819291 28 8.6884143.5792051.5058881.654666 29 8.6901253.5549581.4265891.731257 30 8.7259323.5332881.5223111.788969 31 8.7432793.5275911.6012611.760313 32 8.6948053.5316111.6340851.732271 33 8.6879833.5273271.6019851.836593 34 8.7169763.5146451.5890351.745653 35 8.7754643.4924271.4715621.699377 36 8.8088983.4710361.4601621.686131 37 8.8428473.4511301.5795471.670513 38 8.8717863.4280021.5972161.618989 39 8.9074253.4238871.6262081.652055 40 8.9247213.4036571.5785761.509779 41 8.9411223.3576451.5212361.607082 42 9.0091123.3140891.5067581.544039 43 9.0298943.2677951.4839681.518783 44 9.0553593.2403971.5173481.517085 45 9.0402783.2354101.5904361.509334 46 8.9937963.2523741.6511061.431041 47 8.9674643.2362651.6720981.338936 48 8.9528593.2359161.6624501.287055 49 9.1214303.2175991.7112921.263948 50 9.1478713.2051941.6766411.211038 Will anyone please help why this might happen? Perhaps I am estimating the models incorrectly? Thank you -- View this message in context: http://r.789695.n4.nabble.com/cointegration-and-VECM-urca-package-and-Eviews-tp4709708.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] [R-pkgs] interplot: a new package for visualizing interactive effects
Dear colleagues, We just published a package, interplot, in CRAN. It can be used to plots the conditional coefficients (marginal effects) of variables included in multiplicative interaction terms for various models. The installation instruction and more details about the package are available in http://cran.r-project.org/web/packages/interplot/vignettes/interplot-vignette.html. Please contact me with any questions, bug reports, and comments. Best, Hu, Yue Ph.D. Student, Political Science, University of Iowa, 313 Schaeffer Hall, 20E Washington St., Iowa City, IA, 52242. [[alternative HTML version deleted]] ___ R-packages mailing list r-packa...@r-project.org https://stat.ethz.ch/mailman/listinfo/r-packages __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] clm funtion and CI
I am using the commands bellow. ## load(file.choose())#dataframe:id3.rda attach(id3) dput(head(id3,10)) structure(list(regiao = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Norte, Nordeste, Sudeste, Sul, Centro-Oeste), class = factor), estado = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c(Rondonia, Acre, Amazonas, Roraima, Para, Amapa, Tocantins, Maranhao, Piaui, Ceara, Rio Grande Do Norte, Paraiba, Pernambuco, Alagoas, Sergipe, Bahia, Minas Gerais, Espirito Santo, Rio De Janeiro, Sao Paulo, Parana, Santa Catarina, Rio Grande Do Sul, Mato Grosso Do Sul, Mato Grosso, Goias, Distrito Federal ), class = factor), cod_mun = c(1200401L, 1200401L, 1200401L, 1200401L, 1200401L, 1200401L, 1200401L, 1200401L, 1200401L, 1200401L ), setor = c(0556, 0556, 0556, 0556, 0556, 0556, 0556, 0556, 0562, 0562 ), cap_int = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c(Interior, Capital), class = factor), idade = c(15L, 15L, 17L, 17L, 18L, 18L, 18L, 19L, 19L, 15L), getario = structure(c(3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L), .Label = c(5 anos, 12 anos, 15 a 19 anos, 35 a 44 anos, 65 a 74 anos), class = factor), sexo = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L ), .Label = c(Male, Female), class = factor), grp_etni = structure(c(1L, 4L, 4L, 4L, 2L, 4L, 4L, 4L, 4L, 4L), .Label = c(Branca, Preta, Amarela, Parda, Indigena, Sem Informacao ), class = factor), quest_01 = c(8L, 2L, 4L, 4L, 3L, 4L, 3L, 3L, 3L, 4L), quest_02 = c(4L, 4L, 2L, 2L, 4L, 1L, 3L, 1L, 3L, 2L), density = c(2, 0.5, 2, 2, 0.75, 4, 1, 3, 1, 2), quest_03 = c(3L, 4L, 6L, 5L, 5L, 3L, 3L, 3L, 6L, 5L), quest_04 = structure(c(2L, 3L, 3L, 4L, NA, 2L, 1L, NA, 3L, 3L), .Label = c(Ate 250, 251 a 500, 501 a 1.500, 1.501 a 2.500, 2.501 a 4.500, 4.501 a 9.500, Mais de 9.500, Nao sabe/Nao respondeu ), class = factor), inc_percapita1 = c(46.875, 500, 250, 500, NA, 93.75, 41.679382324, NA, 333.43505859, 250 ), inc_percapita2 = c(46.875, 500, 250, 500, NA, 93.75, 41.679382324, NA, 333.43505859, 250), inc_sqrt1 = c(132.58251953125, 707.106811523438, 500, 1000, NA, 187.5, 72.1687850952148, NA, 577.350280761719, 500), inc_sqrt2 = c(132.58251953125, 707.106811523438, 500, 1000, NA, 187.5, 72.1687850952148, NA, 577.350280761719, 500), q05 = c(11L, 4L, 12L, 6L, 11L, 10L, 7L, 12L, 8L, 7L), quest_06 = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c(Nao, Sim, Nao se aplica, Nao sabe), class = factor), quest_07 = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L), .Label = c(Nao, Sim, Nao se aplica, Nao sabe), class = factor), quest_08 = c(9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 3L, 9L), quest_09 = structure(c(1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c(Nao, Sim, Nao se aplica, Nao sabe), class = factor), quest_10 = structure(c(5L, 5L, 2L, 3L, 3L, 2L, 2L, 3L, 3L, 3L), .Label = c(Menos de 1 ano, 1 a 2 anos, 3 anos, Outros, Nïa se aplica, Nao sabe ), class = factor), quest_11 = structure(c(5L, 5L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L), .Label = c(Publico, Particular, Plano de Saude/Convenios, Outros, Nao se aplica, Nao sabe ), class = factor), quest_12 = structure(c(6L, 6L, 2L, 4L, 1L, 3L, 1L, 4L, 2L, 1L), .Label = c(Revisao/Prevencao, Dor, Extracao, Tratamento, Outros, Nao se aplica, Nao sabe), class = factor), quest_13 = structure(c(NA, NA, 2L, 3L, 2L, 3L, 2L, 2L, 2L, 2L), .Label = c(Muito bom, Bom, Regular, Ruim, Muito Ruim, Nao se aplica, Nao sabe), class = factor), quest_14 = structure(c(3L, 2L, 3L, 4L, 2L, 2L, 4L, 3L, 4L, 2L), .Label = c(Muito satisfeito, Satisfeito, Nem satisfeito/insatisfeito, Insatisfeito, Muito Insatisfeito, Nao sabe), class = factor), quest_15 = structure(c(1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c(Nao, Sim, Nao se aplica, Nao sabe), class = factor), exame = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1), cpod = c(3L, 0L, 8L, 3L, 3L, 12L, 1L, 6L, 6L, 3L), p_sang = c(0L, 1L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 1L), p_calc = c(0L, 1L, 1L, 0L, 0L, 1L, 0L, 1L, 0L, 0L), cpi_max = structure(c(1L, 3L, 3L, 1L, 1L, 3L, 1L, 3L, 1L, 2L), .Label = c(Higido, Sangramento, Calculo, Bolsa 4-5 mm, Bolsa 6 mm ou +, 4, A, X ), class = factor), dai = c(21L, 32L, 23L, 21L, 19L, 18L, 17L, 23L, 34L, 25L), trauma = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_), n_higido = c(26L, 28L, 24L, 24L, 25L, 17L, 27L, 25L, 24L, 25L), n_cariado = c(3L, 0L, 6L, 2L, 0L, 2L, 1L, 2L, 4L, 3L), n_restcar = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 2L, 1L, 0L), n_restaur = c(0L, 0L, 2L, 0L, 3L, 6L, 0L, 2L, 0L, 0L), n_perdcar = c(0L, 0L, 0L, 1L, 0L, 4L, 0L, 0L, 1L, 0L), n_perdout =
Re: [R] detecting any element in a vector of strings, appearing anywhere in any of several character variables in a dataframe
Yes. This is one of the fundamental challenges in text searching -- defining exactly what text defines a match and what doesn't. So, continuing your example, one might imagine that heroin and heroine might both be matches, but maybe heroines shouldn't be (e.g. if the text contains movie reviews). So what one might want to do is add semantic analysis to searches, à la google, a topic way beyond the simple capabilities discussed, or likely needed, here. Incidentally, Jeff Newmiller's (final) regular expression solution is preferable to mine in all respects, I think. -- Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Fri, Jul 10, 2015 at 10:30 AM, Christopher W Ryan cr...@binghamton.edu wrote: Interesting thoughts about the partial-word matches, and speed On another real data set, about 73,000 records and 6 columns to search through for matches (one column of which contains very long character strings--several paragraphs each), I ran both John's and Bert's solutions. John's was noticeably slower, although still quite tolerable. There were a different number of matches, though: oic.2 oic FALSETRUE Sum FALSE 74939 074939 TRUE274 927 1201 Sum 75213927 76140 where oic is the logical vector generated by John's solution, and oic.2 is the logical vector generated by Bert's solution. Bert's solution detected about 77% of the cases detected by John's. I'm still exploring why that might be. One possible explanation, for at least part of the difference, is the issue of partial-word matches. Substantively, I am searching ambulance run records for words related to opioid overdose, and I've noticed that the medics often spell heroin as heroine So in this context, I like partial-word matches--I want to pick up records that (partially) match heroin because it is contained in the word heroine . There may be other things going on too. Thanks. --Chris On Thu, Jul 9, 2015 at 3:24 PM, John Fox j...@mcmaster.ca wrote: Dear Christopher, My usual orientation to this kind of one-off problem is that I'm looking for a simple correct solution. Computing time is usually much smaller than programming time. That said, Bert Gunter's solution was about 5 times faster in a simple check that I ran with microbenchmark, and Jeff Newmiller's solution was about 10 times faster. Both Bert's and Jeff's (eventual) solution protect against partial (rather than full-word) matches, while mine doesn't (though it could easily be modified to do that). Best, John -Original Message- From: Christopher W Ryan [mailto:cr...@binghamton.edu] Sent: July-09-15 2:49 PM To: Bert Gunter Cc: Jeff Newmiller; R Help; John Fox Subject: Re: [R] detecting any element in a vector of strings, appearing anywhere in any of several character variables in a dataframe Thanks everyone. John's original solution worked great. And with 27,000 records, 65 alarm.words, and 6 columns to search, it takes only about 15 seconds. That is certainly adequate for my needs. But I will try out the other strategies too. And thanks also for lot's of new R things to learn--grep, grepl, do.call . . . that's always a bonus! --Chris Ryan On Thu, Jul 9, 2015 at 1:52 PM, Bert Gunter bgunter.4...@gmail.com wrote: Yup, that does it. Let grep figure out what's a word rather than doing it manually. Forgot about \b Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Thu, Jul 9, 2015 at 10:30 AM, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote: Just add a word break marker before and after: zz$v5 - grepl( paste0( \\b(, paste0( alarm.words, collapse=| ), )\\b ), do.call( paste, zz[ , 2:3 ] ) ) ) - -- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k - -- Sent from my phone. Please excuse my brevity. On July 9, 2015 10:12:23 AM PDT, Bert Gunter bgunter.4...@gmail.com wrote: Jeff: Well, it would be much better (no loops!) except, I think, for one issue: red would match barred and I don't think that this is what is wanted: the matches should be on whole words not just string patterns. So you would need to fix up the matching pattern to make this work, but it may be a little tricky, as arbitrary whitespace characters, e.g. or \n etc.
[R] (no subject)
Hello forum members, I am taking this R course which I have to admit that it is beyond my capability. I am asked to analyze the following data(file attached) according to the question provided below: 1. The file [data_13-9.txt] contains a data of length 225, which seems to have some cycle pattern. (1) Fit a suitable model for this data, then report the model equation. (2) Provide the forecast values for 3-steps ahead and 6-steps ahead. I am desperately seeking for your help, since I really don't know where to start.. I have done plot.ts(data.13-6), but not further. Above question is just part of the whole task, but I believe solving this would be very much helpful for me to jump in to the other questions. It would be easier for me to follow if your answer is in R script.. I appreciate your patience and help. Thank you so much in advance! Cheers, Lia fourth_a.ts 1 -0.0242227774450564 2 0.447778425867187 3 0.0679634009051251 4 0.390085614914361 5 0.249535226083153 6 0.518797872921499 7 -0.0969256279112136 8 0.123337983703432 9 -0.414941322119016 10 -0.27757276812968 11 0.0403939285820523 12 0.494211788018315 13 0.124244228153442 14 0.394493565117432 15 0.188705401390586 16 0.532762644104765 17 -0.10747895472636 18 0.144164346660537 19 -0.336048738751554 20 -0.268668787023198 21 0.0632175364558109 22 0.425890066866375 23 0.129576388534439 24 0.434428059119178 25 0.166373082777172 26 0.500324747168639 27 -0.181757008467706 28 0.111908426500126 29 -0.271053619415509 30 -0.167744715393572 31 -0.0338728333227656 32 0.333625139545928 33 0.0140758980245519 34 0.357007127635719 35 0.117528321727847 36 0.436606929603184 37 -0.281483140210634 38 0.0207127868483681 39 -0.347869271054934 40 -0.173998579595848 41 -0.0799206011874377 42 0.277044216890528 43 -0.114919716596858 44 0.284979270819777 45 -0.0204983858654412 46 0.404494915834395 47 -0.293744301550975 48 0.127254025577103 49 -0.260160101188769 50 -0.0875216627615043 51 -0.0462217977187355 52 0.397719199372734 53 -0.0591056840364732 54 0.367738474710558 55 -0.0152206137909984 56 0.353167727849039 57 -0.312136059481424 58 0.143633095475107 59 -0.171180250675521 60 -0.0465141674925802 61 0.0899046896169316 62 0.598910847300957 63 0.0475490561242251 64 0.358240966214597 65 -0.115970806757625 66 0.322290982770865 67 -0.286140052945316 68 0.0618578078197809 69 -0.212161273189703 70 -0.0454341579685268 71 0.0105666268253198 72 0.581041116690388 73 0.0693941384243427 74 0.261971378607031 75 -0.123479577576325 76 0.367590419177466 77 -0.141235430279281 78 0.116237028180501 79 -0.198695126295741 80 -0.0657961678537194 81 -0.0135147919675166 82 0.64984396453257 83 -0.0167548399541178 84 0.227526983440523 85 -0.299388449116629 86 0.416617177307962 87 -0.203407983560365 88 -0.0023010455436364 89 -0.282560660653303 90 -0.176413766464725 91 -0.0983101390414709 92 0.676705573655853 93 0.0203031107706873 94 0.312294913410111 95 -0.165489563226253 96 0.495102364234008 97 -0.305931623403696 98 0.0254406084608136 99 -0.225414817884392 100 -0.15036962703039 101 -0.112423279517229 102 0.745007684199088 103 0.0255308466866797 104 0.315917556432058 105 -0.303111962111323 106 0.4422161899518 107 -0.369563414156803 108 0.0535188548883159 109 -0.164608441001884 110 -0.156343742785993 111 -0.207438206198236 112 0.689341282064895 113 -0.00226758654004458 114 0.288620788540252 115 -0.400804924124587 116 0.359566102139385 117 -0.321517807983831 118 0.00695988179093469 119 -0.231063555270884 120 -0.0754597599841716 121 -0.217474888732617 122 0.683362779387654 123 -0.00314961139535584 124 0.30330965844177 125 -0.345238161601586 126 0.360311898301801 127 -0.301677126208083 128 0.0752078039771654 129 -0.155192129731062 130 -0.061593861998895 131 -0.219884190719033 132 0.628023504848516 133 -0.0382384606055213 134 0.297499086480709 135 -0.346531677222434 136 0.327798639134225 137 -0.391356801473802 138 0.0491703726922144 139 -0.249887313782597 140 -0.114655677012198 141 -0.220433378749168 142 0.560059582446338 143 -0.196920702930255 144 0.219878996139467 145 -0.373914844022043 146 0.292758745532306 147 -0.471257747874178 148 0.101291169049118 149 -0.177115964022913 150 -0.132451723823155 151 -0.21848909838528 152 0.514021082036989 153 -0.211628524400154 154 0.249156930945686 155 -0.277957223804047 156 0.292060580594635 157 -0.411605289128537 158 0.15610957238629 159 -0.167147715462073 160 -0.116581851584324 161 -0.234964260449157 162 0.526997072058525 163 -0.234040498456114 164 0.193292408158503 165 -0.286173628961541 166 0.329912374179291 167 -0.439242525292821 168 0.12873648130915 169 -0.211483057184516 170 -0.160118716712957 171 -0.168318618554501 172 0.553840105722893 173 -0.184533155434883 174 0.134661753730845 175 -0.264620194457709 176 0.378708889591781 177 -0.400340933892769 178 0.105012175958662 179 -0.28484391241728 180 -0.200352172901001 181 -0.217957678983035 182 0.524658753398018 183 -0.287612226565405 184 0.0883221554409499 185 -0.341060900924494 186 0.263243703023783 187
[R] Reading the non delimited file with no particular patterns in the data to R
I am beginner in R and I want to read a ASCII file to R environment. However, the ASCII file is a non delimited and the data is not continuous (have some blank spaces between the variables) so in order to read the data i have used the below syntax i.e test - read.fwf(D:/R_process/ASCII.txt, width = c(10, 4, 1, 4, 9, 9, 1,1,1,1,1,1,1,3,8)) Now i am able to read it but the data read is wrong. Actually my out put should have only the applicable variables data but not the blank data. Attached is the ASCII data. Please let me know how should i write the syntax to read only the applicable data in the file. Thanks for your help in advance. test.txt http://r.789695.n4.nabble.com/file/n4709699/test.txt -- View this message in context: http://r.789695.n4.nabble.com/Cross-tabulation-with-top-one-variable-and-side-as-multiple-variables-tp4708379p4709699.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] how to embed a 3D plot created by ??rgl?? into gWidgets ggraphics device???
I created some 3D cubes by using rgl package. The next step is to embed the
3D plot(rgl device) into ggraphics device from the gWidgets package, but
I have no idea how to implement it. Is there a way to implement by gWidgets
or other package? Any help? Thank you in advance!
My code:
library(rgl)
library(scatterplot3d)
library(gWidgets)
options(guiToolkit=RGtk2)
df-data.frame(x=c(1,2,3,4),
y=c(2,4,6,8),
z=c(3,6,9,12),
value=c(33,43,75,21))
clr - df$value/max(df$value)
f - colorRamp(c(green, yellow, purple, red))
## 3D PLOT
for(i in 1:length(df$x)){
shade3d(translate3d(scale3d(cube3d(col=rgb(f(clr[i])/255),alpha=0.15 ),
10.0, 10.0, 2.5),df$x[i],df$y[i],df$z[i]))
}
window - gwindow(TEST, width = 800, height= 600, visible = FALSE)
group - ggroup(cont = window, expand = TRUE)
loadBtn - gbutton(display, cont = group)
addHandlerChanged(loadBtn, handler = function(h,...){
sudwin-gwindow(3D,visible = TRUE)
dev - ggraphics(cont=subwin)
DO NOT KNOW HOW TO DO NEXT...
})
visible(window)-TRUE
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to assign value to a variable dynamically constructed
I'll let Bill respond in detail if he cares to(he is both more knowledgable and fluent at this than I), but as a nearly unbreakable rule, get() and assign() should not be used in R. Basically, they represent a macro (script)-oriented strategy for handling R's objects, whereas R is designed to use an object-oriented (everything is an object) and functional (all procedures are functions) approach. Using get() and assign() leads to messy, confusing, error-prone, non-portable code in R, and that's why they should be avoided. For details, you should consult web tutorials, John Chambers's books, and other books on R programming. Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Fri, Jul 10, 2015 at 9:44 AM, Bastien Tran bastien.t...@gmail.com wrote: Dear all, Provided I understood correctly, shouldn't assign() do the trick? Most similar threads seem to include this approach (among others, indeed). Regards, Bastien On Wednesday, July 8, 2015 at 7:30:04 PM UTC+2, William Dunlap wrote: You can use an environment instead of a list using the same [[ syntax. It is like 'get0(..., inherit=FALSE)' on the left side of the - and like 'assign(...)' on the right side. E.g., myData - new.env() varName - v1 myData[[varName]] - 1:10 myData[[varName]][4] - myData[[varName]][4] * 100 myData[[varName]] # [1] 1 2 3 400 5 6 7 8 9 10 names(myData) # [1] v1 (Before R-3.2.0 or so, you had to use objects(myData,all=TRUE) if myData was an environment and names(myData) if it was a list. Now names() works for environments.) It is better to use a dedicated environment (or list) for each set of related variables so that name collisions do not cause problems. Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, Jul 8, 2015 at 10:06 AM, Greg Snow 538...@gmail.com wrote: This is FAQ 7.21. The most important part of the answer in FAQ 7.21 is the last section where it states that it is often easier to use a list rather than messing around with trying to dynamically name global variables. If you tell us what you are trying to accomplish then we may have better advice. The route you are headed down now usually leads to inefficient code and hard to find bugs. On Tue, Jul 7, 2015 at 2:53 PM, Jun Shen jun.shen...@gmail.com wrote: Dear list, Let's say we have a variable (id), whose name is dynamically constructed. This variable represents a vector or data frame with many elements. Now I want to specifically assign a value to one of the elements. I couldn't get it right. test - 'id' # id is dynamically constructed through paste() id - 1:4 # I can get the element by doing get(test)[2] # Now I want to assign a value to the second element of this dynamical variable. get(test)[2] - 5 # doesn't work. Thanks a lot. Jun Shen [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Gregory (Greg) L. Snow Ph.D. 538...@gmail.com __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Reading the non delimited file with no particular patterns in the data to R
Is this what your are expecting? test - read.fwf(test.dat, width = c(10, 4, 1, 4, 9, 12,26,1,1,1,1,1,1,3,8)) test V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13 V14 V15 1 1 2015 1 4 0.766696 1 1 0 0 0 0 0 0 0 10 2 2 2015 1 4 1.458186 1 1 0 0 0 1 0 0 0 20 3 3 2015 1 4 0.185492 1 1 0 0 0 0 0 0 0 15 4 4 2015 1 4 0.961584 1 1 0 0 0 0 0 0 0 3 5 5 2015 1 4 0.650091 2 0 0 0 1 0 0 0 0 NA 6 6 2015 1 4 0.430350 1 1 0 0 0 0 0 0 0 20 7 7 2015 1 4 3.192895 2 1 0 1 1 0 0 0 0 0 8 8 2015 1 4 0.617127 1 1 0 1 0 1 0 0 0 15 9 9 2015 1 4 0.399207 1 1 0 0 0 0 0 0 0 10 Clint Clint BowmanINTERNET: cl...@ecy.wa.gov Air Quality Modeler INTERNET: cl...@math.utah.edu Department of Ecology VOICE: (360) 407-6815 PO Box 47600FAX:(360) 407-7534 Olympia, WA 98504-7600 USPS: PO Box 47600, Olympia, WA 98504-7600 Parcels:300 Desmond Drive, Lacey, WA 98503-1274 On Fri, 10 Jul 2015, jagadishpchary wrote: I am beginner in R and I want to read a ASCII file to R environment. However, the ASCII file is a non delimited and the data is not continuous (have some blank spaces between the variables) so in order to read the data i have used the below syntax i.e test - read.fwf(D:/R_process/ASCII.txt, width = c(10, 4, 1, 4, 9, 9, 1,1,1,1,1,1,1,3,8)) Now i am able to read it but the data read is wrong. Actually my out put should have only the applicable variables data but not the blank data. Attached is the ASCII data. Please let me know how should i write the syntax to read only the applicable data in the file. Thanks for your help in advance. test.txt http://r.789695.n4.nabble.com/file/n4709699/test.txt -- View this message in context: http://r.789695.n4.nabble.com/Cross-tabulation-with-top-one-variable-and-side-as-multiple-variables-tp4708379p4709699.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] predict.poly for multivariate data
A recent stackoverflow post
http://stackoverflow.com/questions/31134985 How do you make R poly()
evaluate (or “predict”) multivariate new data (orthogonal or raw)? made
me look at poly and polym again.
predict.poly doesn't work with multivariate data because for such data
poly calls polym which does not:
a) return an object inheriting from class poly;
b) return the coefficients needed to make predictions;
c) accept coefficients as an argument or include code to make predictions.
This does lead to some wrong answers without warnings. e.g.
## vanilla poly and polym ###
library(datasets)
alm - lm(stack.loss ~ poly(Air.Flow, Water.Temp, degree=3), stackloss)
# correct prediction values [1:10]
alm$fitted.values[1:10]
# predict(alldata)[1:10] gives correct values
predict(alm, stackloss)[1:10]
# predict(partdata) gives wrong values
predict(alm, stackloss[1:10,])
#
I guess - but haven't confirmed - that with multivariate newdata
predict.lm(alm, newdata) calculates new orthogonal polynomials based on
newdata rather than applying the original coefficients.
Below I append versions of:
a) polym edited to address the three points above;
b) poly slightly edited to reflect the changes in polym;
c) predict.poly unaltered, just to get it in the same environment as
polym and poly for testing.
After implementing these the three sets of predictions above all agree.
I'm very ready to believe that I've got the wrong end of the stick
and/or my suggestions can be improved so I welcome correction.
Otherwise, how do I go about getting these changes implemented?
I see stats is maintained by R Core Team. Are they likely to pick it up
from here, or do I need to take any other action?
Best regards
Keith Jewell
### polym ##
polym - function (..., degree = 1, coefs = NULL, raw = FALSE)
# add coefs argument
{
if(is.null(coefs)) {
dots - list(...)
nd - length(dots)
if (nd == 0)
stop(must supply one or more vectors)
if (nd == 1)
return(poly(dots[[1L]], degree, raw = raw))
n - sapply(dots, length)
if (any(n != n[1L]))
stop(arguments must have the same length)
z - do.call(expand.grid, rep.int(list(0:degree), nd))
s - rowSums(z)
ind - (s 0) (s = degree)
z - z[ind, ]
s - s[ind]
aPoly - poly(dots[[1L]], degree, raw = raw) # avoid 2 calcs
res - cbind(1, aPoly)[, 1 + z[, 1]]
# attribute coefs = list of coefs from individual variables
if (!raw) coefs - list(attr(aPoly, coefs))
for (i in 2:nd) {
aPoly - poly(dots[[i]], degree, raw = raw)
res - res * cbind(1, aPoly)[, 1 + z[, i]]
if (!raw) coefs - c(coefs, list(attr(aPoly, coefs)))
}
colnames(res) - apply(z, 1L, function(x) paste(x, collapse = .))
attr(res, degree) - as.vector(s)
if (!raw) attr(res, coefs) - coefs
class(res) - c(poly, matrix) # add poly class
res
}
else
{
nd - length(coefs)# number of variables
newdata - as.data.frame(list(...)) # new data
if (nd != ncol(newdata)) stop(wrong number of columns in newdata)
z - do.call(expand.grid, rep.int(list(0:degree), nd))
s - rowSums(z)
ind - (s 0) (s = degree)
z - z[ind, ]
res - cbind(1, poly(newdata[[1]], degree=degree,
coefs=coefs[[1]]))[, 1 + z[, 1]]
for (i in 2:nd) res - res*cbind(1, poly(newdata[[i]],
degree=degree, coefs=coefs[[i]]))[, 1 + z[, i]]
colnames(res) - apply(z, 1L, function(x) paste(x, collapse = .))
res
}
}
##
poly ##
poly - function (x, ..., degree = 1, coefs = NULL, raw = FALSE)
{
dots - list(...)
if (nd - length(dots)) {
if (nd == 1 length(dots[[1L]]) == 1L)
degree - dots[[1L]]
# pass coefs argument as well
else return(polym(x, ..., degree = degree, coefs=coefs, raw = raw))
}
if (is.matrix(x)) {
m - unclass(as.data.frame(cbind(x, ...)))
# pass coefs argument as well
return(do.call(polym, c(m, degree = degree, raw = raw,
list(coefs=coefs
}
if (degree 1)
stop('degree' must be at least 1)
if (anyNA(x))
stop(missing values are not allowed in 'poly')
n - degree + 1
if (raw) {
Z - outer(x, 1L:degree, ^)
colnames(Z) - 1L:degree
attr(Z, degree) - 1L:degree
class(Z) - c(poly, matrix)
return(Z)
}
if (is.null(coefs)) {
if (degree = length(unique(x)))
stop('degree' must be less than number of unique points)
xbar - mean(x)
x - x - xbar
X - outer(x, seq_len(n) - 1, ^)
QR - qr(X)
if (QR$rank degree)
stop('degree' must be less than number of unique points)
z - QR$qr
z - z * (row(z) == col(z))
raw - qr.qy(QR, z)
norm2 - colSums(raw^2)
alpha - (colSums(x * raw^2)/norm2 + xbar)[1L:degree]
Z - raw/rep(sqrt(norm2), each = length(x))
colnames(Z) - 1L:n - 1L
Z - Z[, -1, drop = FALSE]
attr(Z, degree) - 1L:degree
attr(Z, coefs) - list(alpha = alpha, norm2 = c(1,
Re: [R] How to assign value to a variable dynamically constructed
Dear all, Provided I understood correctly, shouldn't assign() do the trick? Most similar threads seem to include this approach (among others, indeed). Regards, Bastien On Wednesday, July 8, 2015 at 7:30:04 PM UTC+2, William Dunlap wrote: You can use an environment instead of a list using the same [[ syntax. It is like 'get0(..., inherit=FALSE)' on the left side of the - and like 'assign(...)' on the right side. E.g., myData - new.env() varName - v1 myData[[varName]] - 1:10 myData[[varName]][4] - myData[[varName]][4] * 100 myData[[varName]] # [1] 1 2 3 400 5 6 7 8 9 10 names(myData) # [1] v1 (Before R-3.2.0 or so, you had to use objects(myData,all=TRUE) if myData was an environment and names(myData) if it was a list. Now names() works for environments.) It is better to use a dedicated environment (or list) for each set of related variables so that name collisions do not cause problems. Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, Jul 8, 2015 at 10:06 AM, Greg Snow 538...@gmail.com wrote: This is FAQ 7.21. The most important part of the answer in FAQ 7.21 is the last section where it states that it is often easier to use a list rather than messing around with trying to dynamically name global variables. If you tell us what you are trying to accomplish then we may have better advice. The route you are headed down now usually leads to inefficient code and hard to find bugs. On Tue, Jul 7, 2015 at 2:53 PM, Jun Shen jun.shen...@gmail.com wrote: Dear list, Let's say we have a variable (id), whose name is dynamically constructed. This variable represents a vector or data frame with many elements. Now I want to specifically assign a value to one of the elements. I couldn't get it right. test - 'id' # id is dynamically constructed through paste() id - 1:4 # I can get the element by doing get(test)[2] # Now I want to assign a value to the second element of this dynamical variable. get(test)[2] - 5 # doesn't work. Thanks a lot. Jun Shen [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Gregory (Greg) L. Snow Ph.D. 538...@gmail.com __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] (no subject)
Sorry Lia. We don't do homework on this list. You can imagine how clogged it would be if we did. Maybe you'll get lucky and someone will answer you privately. Otherwise, seek help from your teachers, fellow students, and/or course homework forums. Cheers, Bert Bert Gunter Data is not information. Information is not knowledge. And knowledge is certainly not wisdom. -- Clifford Stoll On Fri, Jul 10, 2015 at 2:17 AM, Lia LEE ljylia.0...@gmail.com wrote: Hello forum members, I am taking this R course which I have to admit that it is beyond my capability. I am asked to analyze the following data(file attached) according to the question provided below: 1. The file [data_13-9.txt] contains a data of length 225, which seems to have some cycle pattern. (1) Fit a suitable model for this data, then report the model equation. (2) Provide the forecast values for 3-steps ahead and 6-steps ahead. I am desperately seeking for your help, since I really don't know where to start.. I have done plot.ts(data.13-6), but not further. Above question is just part of the whole task, but I believe solving this would be very much helpful for me to jump in to the other questions. It would be easier for me to follow if your answer is in R script.. I appreciate your patience and help. Thank you so much in advance! Cheers, Lia __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] tcltk2 entry box
Thank you very much, Greg, for the tkwait commands. I am just starting to try out examples on the sciviews web page to get a feel for tcltk in R and the tkwait.variable and tkwait.window seem like they could be very useful to me. I will add these in to my practice scripts and see what I can do with them. Matthew On 7/9/2015 5:31 PM, Greg Snow wrote: If you want you script to wait until you have a value entered then you can use the tkwait.variable or tkwait.window commands to make the script wait before continuing (or you can bind the code to a button so that you enter the value, then click on the button to run the code). On Wed, Jul 8, 2015 at 7:58 PM, Matthew McCormack mccorm...@molbio.mgh.harvard.edu wrote: Wow ! Very nice. Thank you very much, John. This is very helpful and just what I need. Yes, I can see that I should have paid attention to tcltk before going to tcltk2. Matthew On 7/8/2015 8:37 PM, John Fox wrote: Dear Matthew, For file selection, see ?tcltk::tk_choose.files or ?tcltk::tkgetOpenFile . You could enter a number in a tk entry widget, but, depending upon the nature of the number, a slider or other widget might be a better choice. For a variety of helpful tcltk examples see http://www.sciviews.org/_rgui/tcltk/, originally by James Wettenhall but now maintained by Philippe Grosjean (the author of the tcltk2 package). (You probably don't need tcltk2 for the simple operations that you mention, but see ?tk2spinbox for an alternative to a slider.) Best, John --- John Fox, Professor McMaster University Hamilton, Ontario, Canada http://socserv.socsci.mcmaster.ca/jfox/ -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Matthew Sent: July-08-15 8:01 PM To: r-help Subject: [R] tcltk2 entry box Is anyone familiar enough with the tcltk2 package to know if it is possible to have an entry box where a user can enter information (such as a path to a file or a number) and then be able to use the entered information downstream in a R script ? The idea is for someone unfamiliar with R to just start an R script that would take care of all the commands for them so all they have to do is get the script started. However, there is always a couple of pieces of information that will change each time the script is used (for example, a different file will be processed by the script). So, I would like a way for the user to input that information as the script ran. Matthew McCormack __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code. --- This email has been checked for viruses by Avast antivirus software. https://www.avast.com/antivirus __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to embed a 3D plot created by “rgl” into gWidgets ggraphics device“?
On 10/07/2015 8:43 AM, just_rookie wrote:
I created some 3D cubes by using rgl package. The next step is to embed the
3D plot(rgl device) into ggraphics device from the gWidgets package,
but I have no idea how to implement it. Is there a way to implement by
gWidgets or other package? Any help? Thank you in advance!
Is there an existing widget that displays HTML, and can display WebGL?
Then it's probably easiest to use rgl::writeWebGL to create the
Javascript code, and that other widget to display it.
If you want it displayed using native OpenGL code, it's likely a lot
more work. On Windows it's probably easiest; I don't know how hard it
would be to do on other platforms. I would not personally spend any
time on it.
Duncan Murdoch
My code:
library(rgl)
library(scatterplot3d)
library(gWidgets)
options(guiToolkit=RGtk2)
df-data.frame(x=c(1,2,3,4),
y=c(2,4,6,8),
z=c(3,6,9,12),
value=c(33,43,75,21))
clr - df$value/max(df$value)
f - colorRamp(c(green, yellow, purple, red))
## 3D PLOT
for(i in 1:length(df$x)){
shade3d(translate3d(scale3d(cube3d(col=rgb(f(clr[i])/255),alpha=0.15 ),
10.0, 10.0,
2.5),df$x[i],df$y[i],df$z[i]))
}
window - gwindow(TEST, width = 800, height= 600, visible = FALSE)
group - ggroup(cont = window, expand = TRUE)
loadBtn - gbutton(display, cont = group)
addHandlerChanged(loadBtn, handler = function(h,...){
sudwin-gwindow(3D,visible = TRUE)
dev - ggraphics(cont=subwin)
DO NOT KNOW HOW TO DO NEXT...
})
visible(window)-TRUE
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Corrected: approaches to matrix multiplication of each layer of 3-d array with different matrix
EE[,,1] - A[,,1] %*% B[,,1]
EE[,,2] - A[,,2] %*% B[,,2]
EE[,,3] - A[,,3] %*% B[,,3]
etc.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/BatteriesO.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
---
Sent from my phone. Please excuse my brevity.
On July 10, 2015 8:37:37 AM PDT, Ranjan Maitra maitra.mbox.igno...@inbox.com
wrote:
What does it mean to unroll the loop?
Thanks!
Ranjan
On Fri, 10 Jul 2015 07:07:15 -0700 Jeff Newmiller
jdnew...@dcn.davis.ca.us wrote:
Strictly speaking, the answer is yes because you can unroll the loop,
but that probably is not what you really want or need to do.
Your example seems about right, but it is not clear how you plan to
make 44 conform with 5500.
---
Jeff NewmillerThe . . Go
Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live
Go...
Live: OO#.. Dead: OO#..
Playing
Research Engineer (Solar/BatteriesO.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#.
rocks...1k
---
Sent from my phone. Please excuse my brevity.
On July 10, 2015 6:44:19 AM PDT, Ranjan Maitra
maitra.mbox.igno...@inbox.com wrote:
Hi,
Sorry to post again, but there is a careless error in my first R
code
snippet:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:dim(A)[3]) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
The second snippet is correct:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA, ]
%*%
mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, the second is almost twice as long as the first snippet.
Many thanks,
Ranjan
On Fri, 10 Jul 2015 08:23:49 -0500 Ranjan Maitra
maitra.mbox.igno...@inbox.com wrote:
Dear friends,
I have two 3-d arrays of appropriate dimensions. I want to
postmultiply the 2-D matrix layers of the first with the 2-D matrix
layers of the second. Can I do this easily in R avoiding loops?
As an example:
--- begin R code ---
AA - array(1:60, dim = c(5500,44,33))
BB - array(1:60, dim = c(44,44,33))
arraymatprod - function(A, B) {
EE - array(dim=dim(A));
for (i in 1:3) EE[,,i] - A[,,i] %*% B[,,i]
EE
}
system.time(arraymatprod(AA, BB))
--- end R code ---
So, is there a way to do this without the loop?
Of course, I could abind the arrays and then use apply with an
appropriate function which would be as follows:
--- begin R code ---
arraymatrixproduct - function(A, B) {
require(abind)
dA - dim(A)[1]
AB - abind(A, B, along = 1)
array(apply(X = AB, MARGIN = 3, FUN = (function(mat) ((mat[1:dA,
]
%*% mat[(dA+1):(dim(AB)[1]),], dim = dim(A))
}
system.time(arraymatrixproduct(AA, BB))
--- end R code ---
However, this turns out to be slower -- perhaps because of the use
of
abind and filling the array inside the function.
I just wanted suggestions to get this operation done more
efficiently.
Many thanks and best wishes,
Ranjan
Publish your photos in seconds for FREE
TRY IM TOOLPACK at http://www.imtoolpack.com/default.aspx?rc=if4
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Re: [R] How to assign value to a variable dynamically constructed
Yes, assign() and get() can do this, but I think the [[]] syntax is simpler and makes it easier to switch between lists and environments for data organization. E.g., the translation of myData[[varName]][4] - myData[[varName]][4] * 100 where myData is an environment to the get/assign style would be something like tmp - get(varName, envir=myData) tmp[4] - tmp[4] * 100 assign(varName, tmp, envir=myData) Bill Dunlap TIBCO Software wdunlap tibco.com On Fri, Jul 10, 2015 at 9:44 AM, Bastien Tran bastien.t...@gmail.com wrote: Dear all, Provided I understood correctly, shouldn't assign() do the trick? Most similar threads seem to include this approach (among others, indeed). Regards, Bastien On Wednesday, July 8, 2015 at 7:30:04 PM UTC+2, William Dunlap wrote: You can use an environment instead of a list using the same [[ syntax. It is like 'get0(..., inherit=FALSE)' on the left side of the - and like 'assign(...)' on the right side. E.g., myData - new.env() varName - v1 myData[[varName]] - 1:10 myData[[varName]][4] - myData[[varName]][4] * 100 myData[[varName]] # [1] 1 2 3 400 5 6 7 8 9 10 names(myData) # [1] v1 (Before R-3.2.0 or so, you had to use objects(myData,all=TRUE) if myData was an environment and names(myData) if it was a list. Now names() works for environments.) It is better to use a dedicated environment (or list) for each set of related variables so that name collisions do not cause problems. Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, Jul 8, 2015 at 10:06 AM, Greg Snow 538...@gmail.com wrote: This is FAQ 7.21. The most important part of the answer in FAQ 7.21 is the last section where it states that it is often easier to use a list rather than messing around with trying to dynamically name global variables. If you tell us what you are trying to accomplish then we may have better advice. The route you are headed down now usually leads to inefficient code and hard to find bugs. On Tue, Jul 7, 2015 at 2:53 PM, Jun Shen jun.shen...@gmail.com wrote: Dear list, Let's say we have a variable (id), whose name is dynamically constructed. This variable represents a vector or data frame with many elements. Now I want to specifically assign a value to one of the elements. I couldn't get it right. test - 'id' # id is dynamically constructed through paste() id - 1:4 # I can get the element by doing get(test)[2] # Now I want to assign a value to the second element of this dynamical variable. get(test)[2] - 5 # doesn't work. Thanks a lot. Jun Shen [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Gregory (Greg) L. Snow Ph.D. 538...@gmail.com __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
On Fri, 10 Jul 2015, Roy Mendelssohn - NOAA Federal wrote:
Don’t know for certain but might this help:
It's very interesting, but does not appear to resolve the immediate need
to write the R code in a knitr chunk for incorporation into the compiled LyX
document.
The gridGraphics package description notes that both lattice and ggplot2
are built on the grid framework, and the new gridGraphics package will
'echo' either to a grid format for further tweaking. Unless the knitr
package will accept the echoed image ...
It does not. Here is what the compiled document shows (the R code is
included in the document):
pdf('carlin-1-description.pdf')
xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T)
require(gridGraphics)
## Loading required package: gridGraphics
## Loading required package: grid
grid.echo()
## Error in grid.echo.recordedplot(recordPlot(), newpage, prefix): No
## graphics to replay
dev.off()
Rich
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
Have you tried explicitly print()ing the lattice graphics in your knitr doc? Hadley On Friday, July 10, 2015, Rich Shepard rshep...@appl-ecosys.com wrote: Hadley's ggplot2 book is quite old and a new version is in the works, but not yet out. I've been using lattice graphics but the knitr package doesn't support lattice, only basic plots and ggplot2. My Web searches for Trellis plots in ggplot2 equivalent to those in lattice have not been productive. I would appreciate a pointer to a resource that would teach me how to translate from lattice xyplot() to ggplot2 ggplot(). This is one such plot needing translation: xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T) Rich __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- http://had.co.nz/ [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
On Fri, 10 Jul 2015, Hadley Wickham wrote:
Have you tried explicitly print()ing the lattice graphics in your knitr
doc?
Hadley,
Only now. Had not thought of trying this before.
pdf('carlin-1-descriptive.pdf')
print(xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T))
No error messages, but no graphic, either. Without specifying the pdf
device, TeX complains it cannot find a graphics device and lists bit-mapped,
ps and svg devices.
Most likely I do not have the correct syntax.
Thanks,
Rich
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
I don't actually use lattice very much, but I have no difficulty setting up a lattice plot in a knitr/rmarkdown file, and can think of no reason why you might have concluded that knitr does not support lattice. Sorry, not going to translate your non-reproducible example... please go the extra little effort to dput some example data so we can communicate clearly about your problem. [1] [1] http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On July 10, 2015 2:09:45 PM PDT, Rich Shepard rshep...@appl-ecosys.com wrote: Hadley's ggplot2 book is quite old and a new version is in the works, but not yet out. I've been using lattice graphics but the knitr package doesn't support lattice, only basic plots and ggplot2. My Web searches for Trellis plots in ggplot2 equivalent to those in lattice have not been productive. I would appreciate a pointer to a resource that would teach me how to translate from lattice xyplot() to ggplot2 ggplot(). This is one such plot needing translation: xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T) Rich __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
Don’t know for certain but might this help: http://journal.r-project.org/archive/2015-1/murrell.pdf From the latest issue of R Journal. Abstract The gridGraphics package provides a function, grid.echo(), that can be used to convert a plot drawn with the graphics package to a visually identical plot drawn using grid. This conversion provides access to a variety of grid tools for making customisations and additions to the plot that are not possible with the graphics package. -Roy On Jul 10, 2015, at 2:09 PM, Rich Shepard rshep...@appl-ecosys.com wrote: Hadley's ggplot2 book is quite old and a new version is in the works, but not yet out. I've been using lattice graphics but the knitr package doesn't support lattice, only basic plots and ggplot2. My Web searches for Trellis plots in ggplot2 equivalent to those in lattice have not been productive. I would appreciate a pointer to a resource that would teach me how to translate from lattice xyplot() to ggplot2 ggplot(). This is one such plot needing translation: xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T) Rich __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ** The contents of this message do not reflect any position of the U.S. Government or NOAA. ** Roy Mendelssohn Supervisory Operations Research Analyst NOAA/NMFS Environmental Research Division Southwest Fisheries Science Center ***Note new address and phone*** 110 Shaffer Road Santa Cruz, CA 95060 Phone: (831)-420-3666 Fax: (831) 420-3980 e-mail: roy.mendelss...@noaa.gov www: http://www.pfeg.noaa.gov/ Old age and treachery will overcome youth and skill. From those who have been given much, much will be expected the arc of the moral universe is long, but it bends toward justice -MLK Jr. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Trellis Plots: translating lattice xyplot() to ggplot()
Hadley's ggplot2 book is quite old and a new version is in the works, but not yet out. I've been using lattice graphics but the knitr package doesn't support lattice, only basic plots and ggplot2. My Web searches for Trellis plots in ggplot2 equivalent to those in lattice have not been productive. I would appreciate a pointer to a resource that would teach me how to translate from lattice xyplot() to ggplot2 ggplot(). This is one such plot needing translation: xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T) Rich __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
On Fri, 10 Jul 2015, Roy Mendelssohn - NOAA Federal wrote: Don’t know for certain but might this help: http://journal.r-project.org/archive/2015-1/murrell.pdf From the latest issue of R Journal. Roy, Thanks. I'll certainly read that article. Carpe weekend, Rich __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
You shouldn't be explicitly opening a device in a knitr document. I think
maybe you should post a minimal document so we can figure out what's going
wrong.
Hadley
On Friday, July 10, 2015, Rich Shepard rshep...@appl-ecosys.com wrote:
On Fri, 10 Jul 2015, Hadley Wickham wrote:
Have you tried explicitly print()ing the lattice graphics in your knitr
doc?
Hadley,
Only now. Had not thought of trying this before.
pdf('carlin-1-descriptive.pdf')
print(xyplot(value ~ sampdate | variable, data=carlin.1.melt, rm.na = T))
No error messages, but no graphic, either. Without specifying the pdf
device, TeX complains it cannot find a graphics device and lists
bit-mapped,
ps and svg devices.
Most likely I do not have the correct syntax.
Thanks,
Rich
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
http://had.co.nz/
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Trellis Plots: translating lattice xyplot() to ggplot()
On Fri, 10 Jul 2015, Hadley Wickham wrote: You shouldn't be explicitly opening a device in a knitr document. Hadley, Didn't think so. I think maybe you should post a minimal document so we can figure out what's going wrong. Agreed. Attached are the raw data (carlin.csv) and a stripped down LyX document with the knitr chunks. This is my first attempt to use knitr; I'm reading the knitr book and that's where I got the impression that lattice graphics are not supported. Richsiteid,sampdate,Temp.h2o,Temp.air,Disc.cfs,Turb,SC,DO,pH,ANC,HCO3,CO3,Alk,Hard,TDS,TSS,N.tot,N.org,NH4,NO3,NO2,PO4,C,Ca,Mg,Na,K,Cl,SO4,F,Si,As,Ba,Be,Cd,Cr,Co,Cu,Fe,Pb,Mn,Mo,Ni,Ag,Sr,V,Zi,Al,Li,Se,CN,Hg 10321000,1965-10-01,,,98,,490,,8.4,,238,4,,150,,40,12,46,, 10321000,1965-11-01,,,141,,507,,8.3,213,252,4,,170,,50,11,42,, 10321000,1965-12-01,,,128,,564,,8.1,238,290,0,,190,359,56,13,47,6.4,16,37,0.5,40, 10321000,1966-01-01,,,122,,506,,8.2,212,259,0,,170,321,50,11,45,6.1,16,34,0.6,31, 10321000,1966-01-17,,,97,,551,,8.5,241,276,9,,200,,58,13,48,, 10321000,1966-02-01,,,108,,506,,8.2,216,263,0,,180,,52,11,42,, 10321000,1966-03-01,,,384,,516,,7.7,201,245,0,,160,,46,11,46,8, 10321000,1966-03-18,,,701,,628,,8.1,235,286,0,,190,,51,16,61,8.5, 10321000,1966-04-01,,,612,,470,,8,189,231,0,,160,301,43,12,40,6.3,14,37,0.5,34, 10321000,1966-04-11,,,541,,423,,8,172,210,0,,140,,40,10,34,5.4, 10321000,1966-04-18,,,355,,466,,8.1,193,235,0,,160,,43,12,39,5.9, 10321000,1966-05-01,,,167,,498,,8,208,253,0,,170,,46,13,42,6.8, 10321000,1966-05-06,,,260,,420,,8.1,181,221,0,,140,,41,10,33,5.4, 10321000,1966-07-01,,,7,,566,,8,226,275,0,,180,450,47,16,52,96,21,48,0.6,34, 10321000,1966-08-01,,,3.9,,550,,8.1,210,256,0,,170,,40,17,51,9.7, 10321000,1966-09-01,,,4.1,,536,,8.4,208,254,0,,170,,41,17,48,8.9, 10321000,1966-10-01,,,7.7,,546,,8.4,220,260,4,,190,340,48,16,46,8.5,19,43,0.5,27, 10321000,1966-11-01,,,16,,536,,8.4,224,263,5,,180,,49,15,45,7.6, 10321000,1966-12-01,,,31,,533,,8.6,222,248,11,,180,336,50,13,47,7.5,14,37,0.5,34, 10321000,1966-12-16,,,30,,615,,8.6,264,296,13,,210,,60,14,56,8.7, 10321000,1967-01-01,,,43,,517,,8.8,214,228,16,,170,333,50,12,48,7.3,19,40,0.5,28, 10321000,1967-02-01,,,72,,513,,8.7,217,234,15,,180,,51,12,46,6.9, 10321000,1967-02-12,,,113,,474,,8.3,189,230,3,,160,,46,11,41,6.8, 10321000,1967-03-01,,,232,,464,,8.5,174,212,7,,150,,44,10,41,6.6, 10321000,1967-03-25,,,422,,498,,8.5,179,218,6,,160,,48,10,43,6.5, 10321000,1967-04-01,,,333,,448,,8.5,164,200,5,,150,283,42,11,39,5.7,15,40,0.5,26, 10321000,1967-05-01,,,327,,451,,8.5,165,201,6,,150,,43,10,38,5.8, 10321000,1967-05-10,,,406,,371,,8.3,127,155,2,,110,,29,9.5,34,5.7, 10321000,1967-05-14,,,396,,435,,8.3,158,193,2,,160,,45,11,38,6.7, 10321000,1967-05-20,,,844,,365,,8,147,179,0,,150,,45,8.1,25,5.6, 10321000,1967-06-01,,,1560,,443,,8.4,189,230,4,,180,,55,10,35,6.7, 10321000,1967-07-01,,,1340,,386,,8.5,175,213,13,,150,255,47,8.6,27,4.8,7.4,14,0.5,28, 10321000,1967-07-11,,,651,,406,,8.3,187,228,2,,170,,55,9.1,27,5, 10321000,1967-07-21,,,254,,453,,8.2,207,252,0,,190,,58,10,35,6, 10321000,1967-08-01,,,48,,, 10321000,1967-08-01,,,48,,525,,8.2,223,272,0,,190,,53,13,47,7.4, 10321000,1967-09-01,,,18,,508,,8.1,210,256,0,,180,,46,15,45,7.9, 10321000,1967-10-01,,,20,,556,,8.4,221,255,7,,180,322,47,15,45,8.2,16,32,0.6,24, 10321000,1967-10-01,,,7.7,,546,,8.4,213,260,4,,190,340,0.0248,16,46,8.5,19,43,0.5,27, 10321000,1967-10-09,,,27,,612,,8.4,242,281,7,,190,,53,15,57,11, 10321000,1967-10-17,,,23,,586,,8.2,238,290,0,,190,,53,15,49,8.3, 10321000,1967-11-01,,,36,,582,,8.4,238,278,6,,190,,55,14,50,7.8, 10321000,1967-12-01,,,44,,565,,8.2,239,292,0,,170,,50,12,53,8.2,
