Re: [R] Binning the data based on a value
Add the drop = TRUE command to split ?split split(a, cut(a$spending, breaks = (0:5)*100), drop = TRUE) Michael On Mon, Dec 5, 2011 at 4:06 PM, Diviya Smith wrote: > Thank you very much Michael. This is very helpful. However, if there is any > way to exclude zero length bins. Lets imagine that the matrix was as follows > - > > a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), > age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 400, 450, 500)) > > bins <- split(a, cut(a$spending, breaks = (0:5)*100) > > then bins[3] = > $`(200,300]` > [1] patient charges age spending > <0 rows> (or 0-length row.names) > > Is there a way to exclude this? > > Priya > > On Mon, Dec 5, 2011 at 3:43 PM, R. Michael Weylandt > wrote: >> >> Just a clarification: I can't get round to work as I first expected so >> if you want to do bins by 100's you'd probably want: >> >> split(a, cut(a$spending, breaks = (0:5)*100)) >> >> Michael >> >> On Mon, Dec 5, 2011 at 3:41 PM, R. Michael Weylandt >> wrote: >> > I'd so something like >> > >> > split(a, a$spending) >> > >> > and you can include a round(a$spending, -2) or something similar if >> > you want to group by the 100's. >> > >> > Michael >> > >> > On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith >> > wrote: >> >> Hello there, >> >> >> >> I have a matrix with some data and I want to split this matrix based on >> >> the >> >> values in one column. Is there a quick way of doing this? I have looked >> >> at >> >> cut but I am not sure how to exactly use it? >> >> for example: >> >> >> >> I would like to split the matrix "a" based on the spending such that >> >> the >> >> data is binned groups [0..99],[100..199]...and so on. >> >> >> >> a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), >> >> age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 250, 400, 450)) >> >> >> >> Expected output - >> >> bin[1] <- c(10, 60) >> >> bin[2] <- c(110, 200, 250) >> >> bin[3] <- c(400, 450) >> >> >> >> NOTE that the number of data points in each bin is not the same and the >> >> empty bins are removed (since there are no points between [199..299], >> >> bin[3] starts at 400. >> >> >> >> Any help would be most appreciated. Thank you in advance. >> >> >> >> Diviya >> >> >> >> [[alternative HTML version deleted]] >> >> >> >> __ >> >> R-help@r-project.org mailing list >> >> https://stat.ethz.ch/mailman/listinfo/r-help >> >> PLEASE do read the posting guide >> >> http://www.R-project.org/posting-guide.html >> >> and provide commented, minimal, self-contained, reproducible code. > > __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Binning the data based on a value
Thank you very much Michael. This is very helpful. However, if there is any way to exclude zero length bins. Lets imagine that the matrix was as follows - a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 400, 450, 500)) bins <- split(a, cut(a$spending, breaks = (0:5)*100) then bins[3] = $`(200,300]` [1] patient charges age spending <0 rows> (or 0-length row.names) Is there a way to exclude this? Priya On Mon, Dec 5, 2011 at 3:43 PM, R. Michael Weylandt < michael.weyla...@gmail.com> wrote: > Just a clarification: I can't get round to work as I first expected so > if you want to do bins by 100's you'd probably want: > > split(a, cut(a$spending, breaks = (0:5)*100)) > > Michael > > On Mon, Dec 5, 2011 at 3:41 PM, R. Michael Weylandt > wrote: > > I'd so something like > > > > split(a, a$spending) > > > > and you can include a round(a$spending, -2) or something similar if > > you want to group by the 100's. > > > > Michael > > > > On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith > wrote: > >> Hello there, > >> > >> I have a matrix with some data and I want to split this matrix based on > the > >> values in one column. Is there a quick way of doing this? I have looked > at > >> cut but I am not sure how to exactly use it? > >> for example: > >> > >> I would like to split the matrix "a" based on the spending such that the > >> data is binned groups [0..99],[100..199]...and so on. > >> > >> a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), > >> age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 250, 400, 450)) > >> > >> Expected output - > >> bin[1] <- c(10, 60) > >> bin[2] <- c(110, 200, 250) > >> bin[3] <- c(400, 450) > >> > >> NOTE that the number of data points in each bin is not the same and the > >> empty bins are removed (since there are no points between [199..299], > >> bin[3] starts at 400. > >> > >> Any help would be most appreciated. Thank you in advance. > >> > >> Diviya > >> > >>[[alternative HTML version deleted]] > >> > >> __ > >> R-help@r-project.org mailing list > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Binning the data based on a value
Just a clarification: I can't get round to work as I first expected so if you want to do bins by 100's you'd probably want: split(a, cut(a$spending, breaks = (0:5)*100)) Michael On Mon, Dec 5, 2011 at 3:41 PM, R. Michael Weylandt wrote: > I'd so something like > > split(a, a$spending) > > and you can include a round(a$spending, -2) or something similar if > you want to group by the 100's. > > Michael > > On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith wrote: >> Hello there, >> >> I have a matrix with some data and I want to split this matrix based on the >> values in one column. Is there a quick way of doing this? I have looked at >> cut but I am not sure how to exactly use it? >> for example: >> >> I would like to split the matrix "a" based on the spending such that the >> data is binned groups [0..99],[100..199]...and so on. >> >> a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), >> age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 250, 400, 450)) >> >> Expected output - >> bin[1] <- c(10, 60) >> bin[2] <- c(110, 200, 250) >> bin[3] <- c(400, 450) >> >> NOTE that the number of data points in each bin is not the same and the >> empty bins are removed (since there are no points between [199..299], >> bin[3] starts at 400. >> >> Any help would be most appreciated. Thank you in advance. >> >> Diviya >> >> [[alternative HTML version deleted]] >> >> __ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Binning the data based on a value
I'd so something like split(a, a$spending) and you can include a round(a$spending, -2) or something similar if you want to group by the 100's. Michael On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith wrote: > Hello there, > > I have a matrix with some data and I want to split this matrix based on the > values in one column. Is there a quick way of doing this? I have looked at > cut but I am not sure how to exactly use it? > for example: > > I would like to split the matrix "a" based on the spending such that the > data is binned groups [0..99],[100..199]...and so on. > > a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), > age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 250, 400, 450)) > > Expected output - > bin[1] <- c(10, 60) > bin[2] <- c(110, 200, 250) > bin[3] <- c(400, 450) > > NOTE that the number of data points in each bin is not the same and the > empty bins are removed (since there are no points between [199..299], > bin[3] starts at 400. > > Any help would be most appreciated. Thank you in advance. > > Diviya > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Binning the data based on a value
Hello there, I have a matrix with some data and I want to split this matrix based on the values in one column. Is there a quick way of doing this? I have looked at cut but I am not sure how to exactly use it? for example: I would like to split the matrix "a" based on the spending such that the data is binned groups [0..99],[100..199]...and so on. a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 250, 400, 450)) Expected output - bin[1] <- c(10, 60) bin[2] <- c(110, 200, 250) bin[3] <- c(400, 450) NOTE that the number of data points in each bin is not the same and the empty bins are removed (since there are no points between [199..299], bin[3] starts at 400. Any help would be most appreciated. Thank you in advance. Diviya [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
