Re: [R] split a factor into single elements
Note:
> levels(factor(c(0,0,1))) ## just gives you the levels attribute
[1] "0" "1"
> as.character(factor(c(0,0,1))) ## gives you the level of each value in
the vector
[1] "0" "0" "1"
Does that answer your question or have I misunderstood.
Cheers,
Bert
On Tue, Apr 2, 2024 at 12:00 AM Kimmo Elo wrote:
> Hi,
>
> why would this simple procedure not work?
>
> --- snip ---
> mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0),
> rainfall_value= 55)
>
> mydf$string_data <- as.factor(mydf$string_data)
>
> values<-as.integer(levels(mydf$string_data))
>
> for (i in 1:length(values)) {
> assign(paste("VAR_", i, sep=""), values[i])
> }
>
> --- snip ---
>
> Best,
>
> Kimmo
>
> to, 2024-03-28 kello 14:17 +, Ebert,Timothy Aaron kirjoitti:
> > Here are some pieces of working code. I assume you want the second one or
> > the third one that is functionally the same but all in one statement. I
> > do not understand why it is a factor, but I will assume that there is a
> > current and future reason for that. This means I cannot alter the
> > string_data variable, or you can simplify by not making the variable a
> > factor only to turn it back into character.
> >
> > mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0),
> > rainfall_value= 55)
> > mydf$string_data <- as.factor(mydf$string_data)
> >
> > mydf <- data.frame(id_station = 1234, string_data = "2024, 12, 1, 0, 0",
> > rainfall_value= 55)
> > mydf$string_data <- as.factor(mydf$string_data)
> >
> > mydf <- data.frame(id_station = 1234, string_data = as.factor("2024, 12,
> > 1, 0, 0"), rainfall_value= 55)
> >
> > mydf <- data.frame(id_station = 1234, string_data = as.factor("2024, 12,
> > 1, 0, 0"), rainfall_value= 55)
> > mydf$string_data2 <- as.character(mydf$string_data)
> >
> > #I assume there are many records in the data frame and your example is
> > for demonstration only.
> > #I cannot assume that all records are the same, though you may be able to
> > simplify if that is true.
> > #Split the string based on commas.
> > split_values <- strsplit(mydf$string_data2, ",")
> >
> > # find the maximum string length
> > max_length <- max(lengths(split_values))
> >
> > # Add new variables to the data frame
> > for (i in 1:max_length) {
> > new_var_name <- paste0("VAR_", i)
> > mydf[[new_var_name]] <- sapply(split_values, function(x)
> > ifelse(length(x) >= i, x[i], NA))
> > }
> >
> > # Convert to numeric
> > for (i in 1:max_length) {
> >new_var_name <- paste0("VAR_", i)
> >mydf[[new_var_name]] <- as.numeric(mydf[[new_var_name]])
> > }
> > # remove trash
> > mydf <- mydf[,-4]
> > # Provide more useful names
> > colnames(mydf) <- c("id_station", "string_data", "rainfall_mm", "Year",
> > "Month", "Day", "hour", "minute")
> >
> > Regards,
> > Tim
> >
> > -Original Message-
> > From: R-help On Behalf Of Stefano Sofia
> > Sent: Thursday, March 28, 2024 7:48 AM
> > To: Fabio D'Agostino ; r-help@R-project.org
> > Subject: Re: [R] split a factor into single elements
> >
> > [External Email]
> >
> > Sorry for my hurry.
> >
> > The correct reproducible code is different from the initial one. The
> > correct example is
> >
> >
> > mydf <- data.frame(id_station = 1234, string_data = as.factor(2024, 12,
> > 1, 0, 0), rainfall_value= 55)
> >
> >
> > In this case mydf$string_data is a factor, but of length 1 (and not 5
> > like in the initial example).
> >
> > Therefore the suggestion offered by Fabio does not work.
> >
> >
> > Any suggestion?
> >
> > Sorry again for my mistake
> >
> > Stefano
> >
> >
> >
> > (oo)
> > --oOO--( )--OOo--
> > Stefano Sofia PhD
> > Civil Protection - Marche Region - Italy Meteo Section Snow Section Via
> > del Colle Ameno 5
> > 60126 Torrette di Ancona, Ancona (AN)
> > Uff: +39 071 806 7743
> > E-mail: stefano.so...@regione.marche.it
> > ---Oo-oO
> >
> >
> >
> > Da: Fabio D'Agostino
> > Inviato: gioved 28 marzo 2024 12:2
Re: [R] split a factor into single elements
Using levels rather than length might cause problems. 2024 1, 1, 0, 0 will have
a different number of levels than 2024, 3, 8, 0, 0 and I cannot assume that the
two tailing zeros are zero for all records. The code can be simplified if you
can assume more. It might require more work if I have assumed too much. Maybe
there is another data set where the string is something like 2, 2, 2024, 0, 0?
Then you need code to figure out the order of values in the string, reorganize
it into a common format before trying to merge the data.
The other thing is that values of the string are now different rows. You will
need a bit more code to reshape mydf from long to wide. If all of the last two
elements of the string are zero, I would remove these from the data first
before reshaping.
-Original Message-
From: R-help On Behalf Of Kimmo Elo
Sent: Tuesday, April 2, 2024 3:00 AM
To: r-help@r-project.org
Subject: Re: [R] split a factor into single elements
[External Email]
Hi,
why would this simple procedure not work?
--- snip ---
mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0),
rainfall_value= 55)
mydf$string_data <- as.factor(mydf$string_data)
values<-as.integer(levels(mydf$string_data))
for (i in 1:length(values)) {
assign(paste("VAR_", i, sep=""), values[i]) }
--- snip ---
Best,
Kimmo
to, 2024-03-28 kello 14:17 +, Ebert,Timothy Aaron kirjoitti:
> Here are some pieces of working code. I assume you want the second one
> or the third one that is functionally the same but all in one
> statement. I do not understand why it is a factor, but I will assume
> that there is a current and future reason for that. This means I
> cannot alter the string_data variable, or you can simplify by not
> making the variable a factor only to turn it back into character.
>
> mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0,
> 0), rainfall_value= 55) mydf$string_data <-
> as.factor(mydf$string_data)
>
> mydf <- data.frame(id_station = 1234, string_data = "2024, 12, 1, 0,
> 0", rainfall_value= 55) mydf$string_data <-
> as.factor(mydf$string_data)
>
> mydf <- data.frame(id_station = 1234, string_data = as.factor("2024,
> 12, 1, 0, 0"), rainfall_value= 55)
>
> mydf <- data.frame(id_station = 1234, string_data = as.factor("2024,
> 12, 1, 0, 0"), rainfall_value= 55)
> mydf$string_data2 <- as.character(mydf$string_data)
>
> #I assume there are many records in the data frame and your example is
> for demonstration only.
> #I cannot assume that all records are the same, though you may be able
> to simplify if that is true.
> #Split the string based on commas.
> split_values <- strsplit(mydf$string_data2, ",")
>
> # find the maximum string length
> max_length <- max(lengths(split_values))
>
> # Add new variables to the data frame
> for (i in 1:max_length) {
> new_var_name <- paste0("VAR_", i)
> mydf[[new_var_name]] <- sapply(split_values, function(x)
> ifelse(length(x) >= i, x[i], NA))
> }
>
> # Convert to numeric
> for (i in 1:max_length) {
>new_var_name <- paste0("VAR_", i)
>mydf[[new_var_name]] <- as.numeric(mydf[[new_var_name]]) } #
> remove trash mydf <- mydf[,-4] # Provide more useful names
> colnames(mydf) <- c("id_station", "string_data", "rainfall_mm",
> "Year", "Month", "Day", "hour", "minute")
>
> Regards,
> Tim
>
> -Original Message-
> From: R-help On Behalf Of Stefano Sofia
> Sent: Thursday, March 28, 2024 7:48 AM
> To: Fabio D'Agostino ; r-help@R-project.org
> Subject: Re: [R] split a factor into single elements
>
> [External Email]
>
> Sorry for my hurry.
>
> The correct reproducible code is different from the initial one. The
> correct example is
>
>
> mydf <- data.frame(id_station = 1234, string_data = as.factor(2024,
> 12, 1, 0, 0), rainfall_value= 55)
>
>
> In this case mydf$string_data is a factor, but of length 1 (and not 5
> like in the initial example).
>
> Therefore the suggestion offered by Fabio does not work.
>
>
> Any suggestion?
>
> Sorry again for my mistake
>
> Stefano
>
>
>
> (oo)
> --oOO--( )--OOo----------------------
> Stefano Sofia PhD
> Civil Protection - Marche Region - Italy Meteo Section Snow Section
> Via del Colle Ameno 5
> 60126 Torrette di Ancona, Ancona (AN)
> Uff: +39 071 806 7743
> E-mail: stefano.so...@regione.marche.it
> ---Oo-oO
>
>
>
> Da: Fabio D'Agostino
> Inviato: gioved 28 marzo 202
Re: [R] split a factor into single elements
Hi,
why would this simple procedure not work?
--- snip ---
mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0),
rainfall_value= 55)
mydf$string_data <- as.factor(mydf$string_data)
values<-as.integer(levels(mydf$string_data))
for (i in 1:length(values)) {
assign(paste("VAR_", i, sep=""), values[i])
}
--- snip ---
Best,
Kimmo
to, 2024-03-28 kello 14:17 +, Ebert,Timothy Aaron kirjoitti:
> Here are some pieces of working code. I assume you want the second one or
> the third one that is functionally the same but all in one statement. I
> do not understand why it is a factor, but I will assume that there is a
> current and future reason for that. This means I cannot alter the
> string_data variable, or you can simplify by not making the variable a
> factor only to turn it back into character.
>
> mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0),
> rainfall_value= 55)
> mydf$string_data <- as.factor(mydf$string_data)
>
> mydf <- data.frame(id_station = 1234, string_data = "2024, 12, 1, 0, 0",
> rainfall_value= 55)
> mydf$string_data <- as.factor(mydf$string_data)
>
> mydf <- data.frame(id_station = 1234, string_data = as.factor("2024, 12,
> 1, 0, 0"), rainfall_value= 55)
>
> mydf <- data.frame(id_station = 1234, string_data = as.factor("2024, 12,
> 1, 0, 0"), rainfall_value= 55)
> mydf$string_data2 <- as.character(mydf$string_data)
>
> #I assume there are many records in the data frame and your example is
> for demonstration only.
> #I cannot assume that all records are the same, though you may be able to
> simplify if that is true.
> #Split the string based on commas.
> split_values <- strsplit(mydf$string_data2, ",")
>
> # find the maximum string length
> max_length <- max(lengths(split_values))
>
> # Add new variables to the data frame
> for (i in 1:max_length) {
> new_var_name <- paste0("VAR_", i)
> mydf[[new_var_name]] <- sapply(split_values, function(x)
> ifelse(length(x) >= i, x[i], NA))
> }
>
> # Convert to numeric
> for (i in 1:max_length) {
> new_var_name <- paste0("VAR_", i)
> mydf[[new_var_name]] <- as.numeric(mydf[[new_var_name]])
> }
> # remove trash
> mydf <- mydf[,-4]
> # Provide more useful names
> colnames(mydf) <- c("id_station", "string_data", "rainfall_mm", "Year",
> "Month", "Day", "hour", "minute")
>
> Regards,
> Tim
>
> -Original Message-
> From: R-help On Behalf Of Stefano Sofia
> Sent: Thursday, March 28, 2024 7:48 AM
> To: Fabio D'Agostino ; r-help@R-project.org
> Subject: Re: [R] split a factor into single elements
>
> [External Email]
>
> Sorry for my hurry.
>
> The correct reproducible code is different from the initial one. The
> correct example is
>
>
> mydf <- data.frame(id_station = 1234, string_data = as.factor(2024, 12,
> 1, 0, 0), rainfall_value= 55)
>
>
> In this case mydf$string_data is a factor, but of length 1 (and not 5
> like in the initial example).
>
> Therefore the suggestion offered by Fabio does not work.
>
>
> Any suggestion?
>
> Sorry again for my mistake
>
> Stefano
>
>
>
> (oo)
> --oOO--( )--OOo--------------
> Stefano Sofia PhD
> Civil Protection - Marche Region - Italy Meteo Section Snow Section Via
> del Colle Ameno 5
> 60126 Torrette di Ancona, Ancona (AN)
> Uff: +39 071 806 7743
> E-mail: stefano.so...@regione.marche.it
> ---Oo-oO
>
>
>
> Da: Fabio D'Agostino
> Inviato: gioved 28 marzo 2024 12:20
> A: Stefano Sofia; r-help@R-project.org
> Oggetto: Re: [R] split a factor into single elements
>
>
> Non si ricevono spesso messaggi di posta elettronica da
> dagostinof...@gmail.com. Informazioni sul perch
> importante<https://aka.ms/LearnAboutSenderIdentification>
>
> Hi Stefano,
> maybe something like this can help you?
>
> myfactor <- as.factor(c(2024, 2, 1, 0, 0))
>
> # Convert factor values to integers
> first_element <- as.integer(as.character(myfactor)[1])
> second_element <- as.integer(as.character(myfactor)[2])
> third_element <- as.integer(as.character(myfactor)[3])
>
> # Print the results
> first_element
> [1] 2024
> second_element
> [1] 2
> third_element
> [1] 1
>
> # Check the type of the object
> typeof(first_element)
> [1] "integer"
>
> Fabio
>
> Il giorno gio 28 mar 2024 alle
Re: [R] split a factor into single elements
Here are some pieces of working code. I assume you want the second one or the
third one that is functionally the same but all in one statement. I do not
understand why it is a factor, but I will assume that there is a current and
future reason for that. This means I cannot alter the string_data variable, or
you can simplify by not making the variable a factor only to turn it back into
character.
mydf <- data.frame(id_station = 1234, string_data = c(2024, 12, 1, 0, 0),
rainfall_value= 55)
mydf$string_data <- as.factor(mydf$string_data)
mydf <- data.frame(id_station = 1234, string_data = "2024, 12, 1, 0, 0",
rainfall_value= 55)
mydf$string_data <- as.factor(mydf$string_data)
mydf <- data.frame(id_station = 1234, string_data = as.factor("2024, 12, 1, 0,
0"), rainfall_value= 55)
mydf <- data.frame(id_station = 1234, string_data = as.factor("2024, 12, 1, 0,
0"), rainfall_value= 55)
mydf$string_data2 <- as.character(mydf$string_data)
#I assume there are many records in the data frame and your example is for
demonstration only.
#I cannot assume that all records are the same, though you may be able to
simplify if that is true.
#Split the string based on commas.
split_values <- strsplit(mydf$string_data2, ",")
# find the maximum string length
max_length <- max(lengths(split_values))
# Add new variables to the data frame
for (i in 1:max_length) {
new_var_name <- paste0("VAR_", i)
mydf[[new_var_name]] <- sapply(split_values, function(x) ifelse(length(x) >=
i, x[i], NA))
}
# Convert to numeric
for (i in 1:max_length) {
new_var_name <- paste0("VAR_", i)
mydf[[new_var_name]] <- as.numeric(mydf[[new_var_name]])
}
# remove trash
mydf <- mydf[,-4]
# Provide more useful names
colnames(mydf) <- c("id_station", "string_data", "rainfall_mm", "Year",
"Month", "Day", "hour", "minute")
Regards,
Tim
-Original Message-
From: R-help On Behalf Of Stefano Sofia
Sent: Thursday, March 28, 2024 7:48 AM
To: Fabio D'Agostino ; r-help@R-project.org
Subject: Re: [R] split a factor into single elements
[External Email]
Sorry for my hurry.
The correct reproducible code is different from the initial one. The correct
example is
mydf <- data.frame(id_station = 1234, string_data = as.factor(2024, 12, 1, 0,
0), rainfall_value= 55)
In this case mydf$string_data is a factor, but of length 1 (and not 5 like in
the initial example).
Therefore the suggestion offered by Fabio does not work.
Any suggestion?
Sorry again for my mistake
Stefano
(oo)
--oOO--( )--OOo--
Stefano Sofia PhD
Civil Protection - Marche Region - Italy Meteo Section Snow Section Via del
Colle Ameno 5
60126 Torrette di Ancona, Ancona (AN)
Uff: +39 071 806 7743
E-mail: stefano.so...@regione.marche.it
---Oo---------oO------------
Da: Fabio D'Agostino
Inviato: gioved 28 marzo 2024 12:20
A: Stefano Sofia; r-help@R-project.org
Oggetto: Re: [R] split a factor into single elements
Non si ricevono spesso messaggi di posta elettronica da
dagostinof...@gmail.com. Informazioni sul perch
importante<https://aka.ms/LearnAboutSenderIdentification>
Hi Stefano,
maybe something like this can help you?
myfactor <- as.factor(c(2024, 2, 1, 0, 0))
# Convert factor values to integers
first_element <- as.integer(as.character(myfactor)[1])
second_element <- as.integer(as.character(myfactor)[2])
third_element <- as.integer(as.character(myfactor)[3])
# Print the results
first_element
[1] 2024
second_element
[1] 2
third_element
[1] 1
# Check the type of the object
typeof(first_element)
[1] "integer"
Fabio
Il giorno gio 28 mar 2024 alle ore 11:29 Stefano Sofia
mailto:stefano.so...@regione.marche.it>> ha
scritto:
Dear R-list users,
forgive me for this silly question, I did my best to find a solution with no
success.
Suppose I have a factor type like
myfactor <- as.factor(2024, 2, 1, 0, 0)
There are no characters (and therefore strsplit for eample does not work).
I need to store separately the 1st, 2nd and 3rd elements as integers. How can I
do?
Thank you for your help
Stefano
(oo)
--oOO--( )--OOo--
Stefano Sofia PhD
Civil Protection - Marche Region - Italy Meteo Section Snow Section Via del
Colle Ameno 5
60126 Torrette di Ancona, Ancona (AN)
Uff: +39 071 806 7743
E-mail: stefano.so...@regione.marche.it<mailto:stefano.so...@regione.marche.it>
---Oo-oO
AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu contenere
informazioni confidenziali, pertanto destinato solo a persone autorizzate
alla ricezione. I messaggi di posta elettronica per i clie
Re: [R] split a factor into single elements
On 28/03/2024 7:48 a.m., Stefano Sofia wrote: as.factor(2024, 12, 1, 0, 0) That doesn't work. You need to put the numbers in a single vector as Fabio did, or you'll see this: Error in as.factor(2024, 12, 1, 0, 0) : unused arguments (12, 1, 0, 0) Duncan Murdoch __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] split a factor into single elements
Sorry for my hurry. The correct reproducible code is different from the initial one. The correct example is mydf <- data.frame(id_station = 1234, string_data = as.factor(2024, 12, 1, 0, 0), rainfall_value= 55) In this case mydf$string_data is a factor, but of length 1 (and not 5 like in the initial example). Therefore the suggestion offered by Fabio does not work. Any suggestion? Sorry again for my mistake Stefano (oo) --oOO--( )--OOo-- Stefano Sofia PhD Civil Protection - Marche Region - Italy Meteo Section Snow Section Via del Colle Ameno 5 60126 Torrette di Ancona, Ancona (AN) Uff: +39 071 806 7743 E-mail: stefano.so...@regione.marche.it ---Oo-oO Da: Fabio D'Agostino Inviato: gioved� 28 marzo 2024 12:20 A: Stefano Sofia; r-help@R-project.org Oggetto: Re: [R] split a factor into single elements Non si ricevono spesso messaggi di posta elettronica da dagostinof...@gmail.com. Informazioni sul perch� � importante<https://aka.ms/LearnAboutSenderIdentification> Hi Stefano, maybe something like this can help you? myfactor <- as.factor(c(2024, 2, 1, 0, 0)) # Convert factor values to integers first_element <- as.integer(as.character(myfactor)[1]) second_element <- as.integer(as.character(myfactor)[2]) third_element <- as.integer(as.character(myfactor)[3]) # Print the results first_element [1] 2024 second_element [1] 2 third_element [1] 1 # Check the type of the object typeof(first_element) [1] "integer" Fabio Il giorno gio 28 mar 2024 alle ore 11:29 Stefano Sofia mailto:stefano.so...@regione.marche.it>> ha scritto: Dear R-list users, forgive me for this silly question, I did my best to find a solution with no success. Suppose I have a factor type like myfactor <- as.factor(2024, 2, 1, 0, 0) There are no characters (and therefore strsplit for eample does not work). I need to store separately the 1st, 2nd and 3rd elements as integers. How can I do? Thank you for your help Stefano (oo) --oOO--( )--OOo-- Stefano Sofia PhD Civil Protection - Marche Region - Italy Meteo Section Snow Section Via del Colle Ameno 5 60126 Torrette di Ancona, Ancona (AN) Uff: +39 071 806 7743 E-mail: stefano.so...@regione.marche.it<mailto:stefano.so...@regione.marche.it> ---Oo-oO AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu� contenere informazioni confidenziali, pertanto � destinato solo a persone autorizzate alla ricezione. I messaggi di posta elettronica per i client di Regione Marche possono contenere informazioni confidenziali e con privilegi legali. Se non si � il destinatario specificato, non leggere, copiare, inoltrare o archiviare questo messaggio. Se si � ricevuto questo messaggio per errore, inoltrarlo al mittente ed eliminarlo completamente dal sistema del proprio computer. Ai sensi dell'art. 6 della DGR n. 1394/2008 si segnala che, in caso di necessit� ed urgenza, la risposta al presente messaggio di posta elettronica pu� essere visionata da persone estranee al destinatario. IMPORTANT NOTICE: This e-mail message is intended to be received only by persons entitled to receive the confidential information it may contain. E-mail messages to clients of Regione Marche may contain information that is confidential and legally privileged. Please do not read, copy, forward, or store this message unless you are an intended recipient of it. If you have received this message in error, please forward it to the sender and delete it completely from your computer system. [[alternative HTML version deleted]] __ R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help<https://eur02.safelinks.protection.outlook.com/?url=https%3A%2F%2Fstat.ethz.ch%2Fmailman%2Flistinfo%2Fr-help=05%7C02%7Cstefano.sofia%40regione.marche.it%7Cbdac99e047dc4e07d0d508dc4f19093d%7C295eaa1431a14b09bfe65a338b679f60%7C0%7C0%7C638472216145063263%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C0%7C%7C%7C=9KrZWiZG0YnRgIlfzNgVoeo3viH1Sqtq%2BkcrEXa1kv0%3D=0> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html<https://eur02.safelinks.protection.outlook.com/?url=http%3A%2F%2Fwww.r-project.org%2Fposting-guide.html=05%7C02%7Cstefano.sofia%40regione.marche.it%7Cbdac99e047dc4e07d0d508dc4f19093d%7C295eaa1431a14b09bfe65a338b679f60%7C0%7C0%7C638472216145063263%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C0%7C%7C%7C=PKViM4DWqRNrcOiMaEtWYZb3dHfIV2r9nP%2B%2FE5KpZwM%3D=0> and provide commented, minimal, self-contained, reproducible code. __
Re: [R] split a factor into single elements
Thank you Fabio. So easy and straighforward! Stefano (oo) --oOO--( )--OOo-- Stefano Sofia PhD Civil Protection - Marche Region - Italy Meteo Section Snow Section Via del Colle Ameno 5 60126 Torrette di Ancona, Ancona (AN) Uff: +39 071 806 7743 E-mail: stefano.so...@regione.marche.it ---Oo-oO Da: Fabio D'Agostino Inviato: gioved� 28 marzo 2024 12:20 A: Stefano Sofia; r-help@R-project.org Oggetto: Re: [R] split a factor into single elements Non si ricevono spesso messaggi di posta elettronica da dagostinof...@gmail.com. Informazioni sul perch� � importante<https://aka.ms/LearnAboutSenderIdentification> Hi Stefano, maybe something like this can help you? myfactor <- as.factor(c(2024, 2, 1, 0, 0)) # Convert factor values to integers first_element <- as.integer(as.character(myfactor)[1]) second_element <- as.integer(as.character(myfactor)[2]) third_element <- as.integer(as.character(myfactor)[3]) # Print the results first_element [1] 2024 second_element [1] 2 third_element [1] 1 # Check the type of the object typeof(first_element) [1] "integer" Fabio Il giorno gio 28 mar 2024 alle ore 11:29 Stefano Sofia mailto:stefano.so...@regione.marche.it>> ha scritto: Dear R-list users, forgive me for this silly question, I did my best to find a solution with no success. Suppose I have a factor type like myfactor <- as.factor(2024, 2, 1, 0, 0) There are no characters (and therefore strsplit for eample does not work). I need to store separately the 1st, 2nd and 3rd elements as integers. How can I do? Thank you for your help Stefano (oo) --oOO--( )--OOo-- Stefano Sofia PhD Civil Protection - Marche Region - Italy Meteo Section Snow Section Via del Colle Ameno 5 60126 Torrette di Ancona, Ancona (AN) Uff: +39 071 806 7743 E-mail: stefano.so...@regione.marche.it<mailto:stefano.so...@regione.marche.it> ---Oo-oO AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu� contenere informazioni confidenziali, pertanto � destinato solo a persone autorizzate alla ricezione. I messaggi di posta elettronica per i client di Regione Marche possono contenere informazioni confidenziali e con privilegi legali. Se non si � il destinatario specificato, non leggere, copiare, inoltrare o archiviare questo messaggio. Se si � ricevuto questo messaggio per errore, inoltrarlo al mittente ed eliminarlo completamente dal sistema del proprio computer. Ai sensi dell'art. 6 della DGR n. 1394/2008 si segnala che, in caso di necessit� ed urgenza, la risposta al presente messaggio di posta elettronica pu� essere visionata da persone estranee al destinatario. IMPORTANT NOTICE: This e-mail message is intended to be received only by persons entitled to receive the confidential information it may contain. E-mail messages to clients of Regione Marche may contain information that is confidential and legally privileged. Please do not read, copy, forward, or store this message unless you are an intended recipient of it. If you have received this message in error, please forward it to the sender and delete it completely from your computer system. [[alternative HTML version deleted]] __ R-help@r-project.org<mailto:R-help@r-project.org> mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help<https://eur02.safelinks.protection.outlook.com/?url=https%3A%2F%2Fstat.ethz.ch%2Fmailman%2Flistinfo%2Fr-help=05%7C02%7Cstefano.sofia%40regione.marche.it%7Cbdac99e047dc4e07d0d508dc4f19093d%7C295eaa1431a14b09bfe65a338b679f60%7C0%7C0%7C638472216145063263%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C0%7C%7C%7C=9KrZWiZG0YnRgIlfzNgVoeo3viH1Sqtq%2BkcrEXa1kv0%3D=0> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html<https://eur02.safelinks.protection.outlook.com/?url=http%3A%2F%2Fwww.r-project.org%2Fposting-guide.html=05%7C02%7Cstefano.sofia%40regione.marche.it%7Cbdac99e047dc4e07d0d508dc4f19093d%7C295eaa1431a14b09bfe65a338b679f60%7C0%7C0%7C638472216145063263%7CUnknown%7CTWFpbGZsb3d8eyJWIjoiMC4wLjAwMDAiLCJQIjoiV2luMzIiLCJBTiI6Ik1haWwiLCJXVCI6Mn0%3D%7C0%7C%7C%7C=PKViM4DWqRNrcOiMaEtWYZb3dHfIV2r9nP%2B%2FE5KpZwM%3D=0> and provide commented, minimal, self-contained, reproducible code. AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu� contenere informazioni confidenziali, pertanto � destinato solo a persone autorizzate alla ricezione. I messaggi di posta elettronica per i client di Regione Marche possono contenere informazioni confidenziali e con privilegi legali. Se non si � il destinatario specificato, non leggere, copiar
Re: [R] split a factor into single elements
Hi Stefano, maybe something like this can help you? myfactor <- as.factor(c(2024, 2, 1, 0, 0)) # Convert factor values to integers first_element <- as.integer(as.character(myfactor)[1]) second_element <- as.integer(as.character(myfactor)[2]) third_element <- as.integer(as.character(myfactor)[3]) # Print the results first_element [1] 2024 second_element [1] 2 third_element [1] 1 # Check the type of the object typeof(first_element) [1] "integer" Fabio Il giorno gio 28 mar 2024 alle ore 11:29 Stefano Sofia < stefano.so...@regione.marche.it> ha scritto: > Dear R-list users, > > forgive me for this silly question, I did my best to find a solution with > no success. > > Suppose I have a factor type like > > > myfactor <- as.factor(2024, 2, 1, 0, 0) > > > There are no characters (and therefore strsplit for eample does not work). > > I need to store separately the 1st, 2nd and 3rd elements as integers. How > can I do? > > > Thank you for your help > > Stefano > > > (oo) > --oOO--( )--OOo-- > Stefano Sofia PhD > Civil Protection - Marche Region - Italy > Meteo Section > Snow Section > Via del Colle Ameno 5 > 60126 Torrette di Ancona, Ancona (AN) > Uff: +39 071 806 7743 > E-mail: stefano.so...@regione.marche.it > ---Oo-oO > > > > AVVISO IMPORTANTE: Questo messaggio di posta elettronica può contenere > informazioni confidenziali, pertanto è destinato solo a persone autorizzate > alla ricezione. I messaggi di posta elettronica per i client di Regione > Marche possono contenere informazioni confidenziali e con privilegi legali. > Se non si è il destinatario specificato, non leggere, copiare, inoltrare o > archiviare questo messaggio. Se si è ricevuto questo messaggio per errore, > inoltrarlo al mittente ed eliminarlo completamente dal sistema del proprio > computer. Ai sensi dell'art. 6 della DGR n. 1394/2008 si segnala che, in > caso di necessità ed urgenza, la risposta al presente messaggio di posta > elettronica può essere visionata da persone estranee al destinatario. > IMPORTANT NOTICE: This e-mail message is intended to be received only by > persons entitled to receive the confidential information it may contain. > E-mail messages to clients of Regione Marche may contain information that > is confidential and legally privileged. Please do not read, copy, forward, > or store this message unless you are an intended recipient of it. If you > have received this message in error, please forward it to the sender and > delete it completely from your computer system. > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
