[R] R graphics display window
Hi all: How can the R graphics window be customized programmatically? Either minimized,maximized or change the size of the default that ships with R. Thanks Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Creating an instance of R from MS Access?
Hi all: Does anyone know if it's at all possible to create a connection to R from MS access? For example, if I have a table and want to export it to R,generate a graph in R and import it back to MS access. I can do this with sigmaPlot and other graphic programs but just wondering if it can be done with R. Thanks Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] ggplot2 axis color
Hi: Does anyone have an idea on how to color the axis and labels using ggplot2? This is what I got: library(ggplot2) p - qplot(total_bill, tip, data = tips) NewPlot- p + geom_abline(slope=c(0.1,0.15,0.2), colour=c(red,blue,yellow),size=c(2,5,2)) NewPlot + geom_smooth(colour=green, size=3,linetype=3) NewPlot$background.fill-cornsilk NewPlot$background.colour - blue NewPlot$axis.colour-red ? it doesn't do it Thanks Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] About infinite value
I think that the best thing is to work in logarithmic way, to avoid the limitations of the CPU. If y = 10^400, to do y=400*log(10), to change all you formulate to the logarithmic way and the final result to apply the antilogarithm. Felipe de Mendiburu. Professor of statistic Agrarian National University -La Molina - PERU De: [EMAIL PROTECTED] en nombre de arigado Enviado el: lun 23/07/2007 4:17 Para: r-help@stat.math.ethz.ch Asunto: [R] About infinite value Hi everyone I have a problem about infinite. If I type 10^308, R shows 1e+308 When I type 10^309, R shows Inf So, we know if a value is large than 1.XXXe+308, R will show Inf How can i do let the value, like 10^400 ,typed in R to show the word 1e+400 not Inf -- View this message in context: http://www.nabble.com/About-infinite-value-tf4128557.html#a11740491 Sent from the R help mailing list archive at Nabble.com. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] change text labels on a dendrogram
Dear Marcela. In the data, if column 1 has the names: rownames(data) -data [, 1] data - date [, - 1] now, to make a dendrogram greetings. Felipe de Mendiburu. Professor of statistic Agrarian National University -La Molina - PERU De: [EMAIL PROTECTED] en nombre de Ana Marcela Florez Rueda Enviado el: lun 23/07/2007 9:09 Para: r-help@stat.math.ethz.ch Asunto: [R] change text labels on a dendrogram Hi all: I already made a dendrogram, I want to change the labels; In my data set there is one column with text that I want to set as the labels, any one can tellme how can I do it? Thanks, Ana Marcela [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Saving a dataset permanently in R
HI: I'm still struggling with datasets, the more I read about it the more confussed I get. This is the scenario... In R console|Edit|Data Editor, I can find all the datasets available with the different packages, So to create a new dataset in the R console I use the following commands to create an empty data frame. My_Dataset - data.frame() My_Dataset - edit(My_dataset) The problem is that I can't copy my data into the dataframe. Is there any suggestions as of how I can transfer the data and how it can be saved so everytime I open R the dataset would be available.? Thanks Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] LSD, HSD,...
Dear Adrain, You can see the library agricolae for the functions LSD.test, HSD.test, and Waller.test for Waller-Duncan. The criterion is that LSD is more used for few treatments and HSD for many treatments (more than 5) the test of Waller is Bayes and minimizes the two types of error (I or II). In experiment with clones, we prefer Waller-Duncan. Felipe de Mendiburu Statistician. International Potato Center Lima-Peru -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Adrian J. Montero Calvo Sent: Monday, July 16, 2007 2:52 AM To: r-help@stat.math.ethz.ch Subject: [R] LSD, HSD,... Hi, I'm designing a experiment in order to compare the growing of several clones of a tree specie. It will be a complete randomized block design. How can I decide what model of mean comparision to choose? LSD, HSD,TukeyHSD, Duncan,...? Thanks in advance __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to load a dataset
Hi: Since I didn't get any answers, I'll refresh my question. I have a dataset called Chinook Run saved in Excel and I want it to be loaded everytime R starts, so I can call it with a statement like the one below: qplot(color, Year/Forklength, data = Chinook Run) I wonder how can I do that. I went to the rprofile.site and copied the path to my dataset there and it seems to work but I am wondering if that's how's done. Felipe Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to get weekly Covariance with R
Hi: I am trying to migrate from Systat to R but I am facing my first challenge. While I easily can get weekly co-variance for my data, I can't seem to acomplish this with R ( I can't figure out how is done) If interested in looking a sample of my data, please check the data below. In Systat from Week 28 I get a covariance of 1055 fish. Thanks in advance Fish Passage Week number Weekly Covariance0 26 00 27 00 27 0 27 0 27 0 27 0 27 0 27 0 28 10550 28 71 28 132 28 223 28 224 28 218 28 228 29 224 29 488 29 525 29 80 29 417 29 82 29 413 30 373 30 914 30 213 30 651 30 521 30 979 30 177 31 604 31 824 31 1190 31 926 31 1257 31 1071 31 1709 32 1166 32 704 32 1424 32 2586 32 1163 32 647 32 Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] type III ANOVA for a nested linear model
Dear Carsten In this test, factor B would be representing to a factor of block or repetition according to as the levels of A, B, and C are in the data. Factor C this nested in A, then the model should include: B, A and C nested in A, the difference it is the error. Model: B 1 A 2 C(A)6 Error (2+6)*1 = 8 Total mydata-read.table(mydata.txt,header=T) mydata[,1]- as.factor(mydata[,1]) mydata[,2]- as.factor(mydata[,2]) mydata[,3]- as.factor(mydata[,3]) model - aov(resp ~ B + A + C/A, mydata) summary(model) Df Sum Sq Mean Sq F valuePr(F) B1 915.21 915.21 89.6476 1.274e-05 *** A2 33.12 16.56 1.6223 0.25621 C6 199.50 33.25 3.2570 0.06316 . Residuals8 81.67 10.21 Best regards, Felipe de Mendiburu Statistician -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Carsten Jaeger Sent: Tuesday, July 10, 2007 6:15 AM To: R help list Subject: [R] type III ANOVA for a nested linear model Hello, is it possible to obtain type III sums of squares for a nested model as in the following: lmod - lm(resp ~ A * B + (C %in% A), mydata)) I have tried library(car) Anova(lmod, type=III) but this gives me an error (and I also understand from the documentation of Anova as well as from a previous request (http://finzi.psych.upenn.edu/R/Rhelp02a/archive/64477.html) that it is not possible to specify nested models with car's Anova). anova(lmod) works, of course. My data (given below) is balanced so I expect the results to be similar for both type I and type III sums of squares. But are they *exactly* the same? The editor of the journal which I'm sending my manuscript to requests what he calls conventional type III tests and I'm not sure if can convince him to accept my type I analysis. R mydata A B C resp 1 1 1 1 34.12 2 1 1 2 32.45 3 1 1 3 44.55 4 1 2 1 20.88 5 1 2 2 22.32 6 1 2 3 27.71 7 2 1 6 38.20 8 2 1 7 31.62 9 2 1 8 38.71 102 2 6 18.93 112 2 7 20.57 122 2 8 31.55 133 1 9 40.81 143 1 10 42.23 153 1 11 41.26 163 2 9 28.41 173 2 10 24.07 183 2 11 21.16 Thanks a lot, Carsten __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to get weekly Co-Variance
Hi: I am trying to migrate from Systat to R but I am facing my first challenge. While I easily can get weekly co-variance for my data, I can't seem to acomplish this with R ( I can't figure out how is done) If interested in looking a sample of my data, please check the Excel attachment. In Systat from Week 28 I get a covariance of 1055 fish. Thanks in advance Felipe D. Carrillo Fishery Biologist US Fish Wildlife Service Red Bluff, California 96080 - __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to plot two variables using a secondary Y axis
Date Fo Co6/27/2007 57.1 13.96/28/2007 57.7 14.3 6/29/2007 57.8 14.36/30/2007 57 13.97/1/2007 57.1 13.9 7/2/2007 57.2 14.07/3/2007 57.3 14.17/4/2007 57.6 14.2 7/5/2007 58 14.47/6/2007 58.1 14.57/7/2007 58.2 14.67/8/2007 58.4 14.77/9/200758.7 14.8 Hello all: I am a newbie to R, and I was wondering how can I plot the Temperature values above using Lattice or ggplot2 code. I want Date(X axis), Degrees F(Y axis) and Degrees C( on a secondary Y axis). Thanks - [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to activate the R commands in SciViews
Please help, I have SciViews(svGUI) and Rcmdr but when the SciViews Console opens the R commander menu don't work. Any ideas anybody? - 8:00? 8:25? 8:40? Find a flick in no time [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Call-Tips
Hi: I am brand new to this group ( and To Tinn-R), so I have my first question: How do I turn on the Call-Tips? I went through the help and I have installed the SciViews but still can't get it to work. I would really appreciate your help. - TV dinner still cooling? [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R's Spearman
Dear Ray,
The R's Spearman calculated by R is correct for ties or nonties, which is not
correct is the probability for the case of ties. I send to you formulates it
for the correlation with ties, that is equal to R.
Regards,
Felipe de Mendiburu
Statistician
# Spearman correlation rs with ties or no ties
rs-function(x,y) {
d-rank(x)-rank(y)
tx-as.numeric(table(x))
ty-as.numeric(table(y))
Lx-sum((tx^3-tx)/12)
Ly-sum((ty^3-ty)/12)
N-length(x)
SX2- (N^3-N)/12 - Lx
SY2- (N^3-N)/12 - Ly
rs- (SX2+SY2-sum(d^2))/(2*sqrt(SX2*SY2))
return(rs)
}
# Aplicacion
cor(y[,1],y[,2],method=spearman)
[1] 0.2319084
rs(y[,1],y[,2])
[1] 0.2319084
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Raymond Wan
Sent: Monday, May 28, 2007 10:29 PM
To: r-help@stat.math.ethz.ch
Subject: [R] R's Spearman
Hi all,
I am trying to figure out the formula used by R's Spearman rho (using
cor(method=spearman)) because I can't seem to get the same value as by
calculating by hand. Perhaps I'm using cor wrong, but I don't know
where. Basically, I am running these commands:
y=read.table(file=tmp,header=TRUE,sep=\t)
y
IQ Hours
1 106 7
2 86 0
3 9720
4 11312
5 12012
6 11017
cor(y[1],y[2],method=spearman)
Hours
IQ 0.2319084
[it's an abbreviated example of one I took from Wikipedia]. I
calculated by hand (apologies if the table looks strange when pasted
into e-mail):
IQHoursrank(IQ) rank(hours)diffdiff^2
110673 2 11
2 8601 1 00
3 9720 2 6-416
411312 5 3.5 1.52.25
512012 6 3.5 2.56.25
611017 4 5-11
26.5
rho=0.242857
where rho = (1 - ((6 * 26.5) / 6 * (6^2 - 1))). I kept modifying the
table and realized that the difference in result comes from ties. i.e.,
if I remove the tie in rows 4 and 5, I get the same result from both cor
and calculating by hand. Perhaps I'm handling ties wrong...does anyone
know how R does it or perhaps I need to change how I'm using it?
Thank you!
Ray
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] creating a multivariate set of variables with givenintercorrelations
Dear Dimitri, if you wish single the correlations, can use the following script: a-1:10 b- rnorm(10) c- rbinom(10,8,0.3) d- rpois(10,8) corr-cor( cbind(a,b,c,d) ) round(as.dist(corr),2) # or only as.dist(corr) a b c b 0.07 c 0.19 -0.26 d -0.16 -0.13 -0.41 regards, Felipe Hi! I was wondering if there is a package in R that allows one to create a multivariate data set with pre-specified intercorrelations among variables, e.g., a set of 4 variables (with a length of N each), such that the correlations between variables are: a b c d a 1 r1r2r3 b 1 r4r5 c 1 r6 d 1 Thank you very much! Dimitri Liakhovitski __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] 'substitute' question
Dear Renko To modify the script plot(x,y) r2-summary(lm1)$r.squared*100 # label R2text - substitute(paste(R^2, = ,r2),list(r2=r2)) text(-1,1,R2text, col=red) # To see of the coordinates of the graph. Grettings Felipe -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of remko duursma Sent: Tuesday, March 13, 2007 8:02 AM To: r-help@stat.math.ethz.ch Subject: [R] 'substitute' question # I use this code to label a graph with the R2: # graph x - rnorm(100) y - x + rnorm(100) lm1 - lm(y~x) plot(x,y) # label R2text - substitute(paste(R^2, = ,r2),list(r2=r2)) text(1,-3,R2text, col=red) # i have modified this a bit, so that i have a vector with other labels, each of which # will be labelled on the graph. Example: texts - c(And the R2 is, R2text) x - c(-2,-2) y - c(2,1) for(i in 1:length(texts))text(x[i],y[i],texts[i],pos=4, col=blue) # As you can see the label R2 = 48.7 remains at paste(R^2, = , 48.7) # What to do? Thanks for your help, Remko ..-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~-.-~- Remko Duursma Post-doctoral researcher Dept. Forest Ecology University of Helsinki, Finland _ With tax season right around the corner, make sure to follow these few simple tips. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Package RODBC
Dear Alberto, It is better to assign a name to an area of data and not to use the name of the sheet, because this can have graphs and other data. If you this interested can see: http://tarwi.lamolina.edu.pe/~fmendiburu/Rsolutions.htm I hope that this also helps, Felipe. -Original Message- From: Wolfgang Raffelsberger [mailto:[EMAIL PROTECTED] Sent: Wednesday, March 07, 2007 4:50 AM To: Mendiburu, Felipe (CIP) Cc: Alberto Monteiro; r-help@stat.math.ethz.ch Subject: Re: [R] Package RODBC Dear Alberto, please note that special characters (eg a space character) in the Excel sheet names mess up the simple way of querying provided by sqlFetch. If you have a regular case of all sheets like Sheet1: plan1 - sqlFetch(channel,Sheet1) # should work But if you have Sheet 1 ( similar..) you have to use the command sqlQuery(), which means that you have to write a proper SQL query as 2nd argument that follows proper SQL syntax (starting with SELECT, etc...). If I wanted to combine this with sheet-names already read in variables/vectors I concatenate this into a single stringsimilar to your 2nd code variant ... Of course you could also use grep() to search the position of a given sheet-name (the order of the sheets may be different that within Excel). What you get with plan1[,1] depends on what you're reading. In case that the 1st column is read as string, this is read by default as factor with n levels. You can simply convert it using as.character() ... Hope this helps, Wolfgang Mendiburu, Felipe (CIP) a écrit : Dear Alberto, channel - odbcConnectExcel(test.xls) name1 - tables[1, TABLE_NAME] # the name1 is Sheet1$ it must be: name1 - Sheet1 plan1 - sqlFetch(channel, name1) is ok or plan1 - sqlFetch(channel, Sheet1) Regards, Felipe -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Alberto Monteiro Sent: Tuesday, March 06, 2007 9:37 AM To: r-help@stat.math.ethz.ch Subject: [R] Package RODBC I have some questions about the RODBC package. library(RODBC) # required for those who want to repeat these lines 1st, I noticed that the following sequence does not work: channel - odbcConnextExcel(test.xls) tables - sqlTables(channel) name1 - tables[1, TABLE_NAME] # this should be the name plan1 - sqlFetch(channel, name1) # bang! odbcClose(channel) However, I can circumvent this with: channel - odbcConnextExcel(test.xls) tables - sqlTables(channel) name1 - tables[1, TABLE_NAME] # this should be the name plan1 - sqlQuery(channel, sprintf(select * from [%s], name1)) # ok odbcClose(channel) 2nd, it seems that only pure strings (which are not links to strings) and numerical values are correctly fetched or selected. Is this a bug? 3rd, when do something like plan1[,1] a weird message about Levels appear. What is that? Alberto Monteiro -- . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Wolfgang Raffelsberger, PhD Laboratoire de BioInformatique et Génomique Intégrative IGBMC 1 rue Laurent Fries, 67404 Illkirch Strasbourg, France Tel (+33) 388 65 3300 Fax (+33) 388 65 3276 [EMAIL PROTECTED] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to apply functions to unbalanced data in long format byfactors......cant get by or aggregate to work
Dear Alan, I think that podria to be of utility the function tapply.stat () of the package agricolae. see ?tapply.stat Regards, Felipe. for example: library(agricolae) attach(mydata) set1-tapply.stat(mydata[,2:5],Y,median) set2-tapply.stat(time,Y,function(x) median(x)) set3-tapply.stat(mydata[,c(2,3)],Y,function(x) median(x)) set2 timeY 1 120hr 14.94159 2 24hr 14.81914 set3 time treatmentY 1 120hr control 15.31974 2 120hr trt 14.82851 3 24hr control 15.03627 4 24hr trt 14.70249 From: [EMAIL PROTECTED] on behalf of ALAN SMITH Sent: Wed 3/7/2007 6:25 PM To: r-help@stat.math.ethz.ch Subject: [R] how to apply functions to unbalanced data in long format byfactors..cant get by or aggregate to work Hello R users, Problem...I do not understand how to use aggregate,by, or the appropriate apply to perform a function on data with more than one factor on unbalanced data... I have a data frame in the long format that does not contain balanced data. The ID is a unique identifier corresponding to the experimental unit that will later be examined by ANOVA, T-tests etc. Y is the data generated from the experiment. The factors represent the differences between each sample or run measured. str(mydata) ### sample of table at bottom of email ### 'data.frame': 129982 obs. of 6 variables: $ ID: num 7 7 7 7 7 7 8 8 8 8 ... $ time : Factor w/ 2 levels 120hr,24hr: 1 1 1 1 2 2 2 1 1 1 ... $ treatment: Factor w/ 2 levels control,trt: 1 1 1 2 2 1 1 2 1 1 ... $ expREP : Factor w/ 3 levels expREP1,expREP2,..: 1 1 1 3 1 1 1 1 2 2 ... $ techREP : Factor w/ 3 levels techREP1,techREP2,..: 3 2 1 1 1 3 1 3 3 2 ... $ Y : num 14.4 14.1 14.2 13.8 14.1 ... Could someone please help with doing something like the following 1. I would like to find the median for each unique combination of factors using the data in the long format (like finding the median of a single column of data). 2. Create a new column where the median is repeated for the number of rows of the unique factor combination 3. I would like to learn the most efficient way to do this because I want to avoid recreating the table from scratch with many commands like the series below. I will have to perform this operation on many different data sets some, with many more factors then this example. ### help me learn to use an apply or other command that will do the following # m0-mydata$cpdID[mydata$time==24hr mydata$treatment==control mydata$expREP==expREP1 mydata$techREP==techREP1] m1-mydata$Y[mydata$time==24hr mydata$treatment==control mydata$expREP==expREP1 mydata$techREP==techREP1] m2-median(m1) m3-cbind(ID=m0,time=rep(24hr,length(m1)), treatment=rep(control,length(m1)), expREP=rep(expREP1,length(m1)), techREP=rep(techREP1,length(m1)),Y=m1,Y50=rep(m2,length(m1))) # I would like to avoid writing the above hundreds of times ## I am able to reshape into wide format and then find the column medians. However restacking the data and regenerating the factors becomes very very messy on data sets with 150 columns. I am able to preform this analysis is SAS easily using BY, but I would like to know how to do it in R. I have tried these commands in a number of different variations with no luck and similar error messages test1-aggregate(mydata[,-1], list(mydata$time,mydata$treatment,mydata$expREP,mydata$techREP) ,median, na.rm=T) Error in median.default(X[[1]], ...) : need numeric data ### Y in numeric test1-by(mydata[,-1], list(mydata$time,mydata$treatment,mydata$expREP,mydata$techREP) ,median, na.rm=T) Error in median.default(data[x, ], ...) : need numeric data Thanks Alan winXP R 2.4.1 #Example data frame## mydata-as.data.frame(structure(list(cpdID = c(7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 19, 19, 19, 19, 19, 19, 23, 23, 23, 23, 23, 23, 23, 23, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 33, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 40, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 42, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47, 47), time = structure(as.integer(c(1, 1, 1, 1, 2, 2, 2, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 1, 1, 2, 1, 2, 2, 1, 1, 2, 2, 1, 2, 2, 2, 1, 2, 1, 2, 2, 2, 2, 1, 2, 2, 1, 2, 1, 2, 2, 1, 1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 1, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 1, 2, 1, 1, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 2, 2, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 1, 2, 1, 2, 2, 1, 2, 1, 2, 2, 1, 1, 2, 2, 2, 2, 2
Re: [R] Package RODBC
Dear Alberto, channel - odbcConnectExcel(test.xls) name1 - tables[1, TABLE_NAME] # the name1 is Sheet1$ it must be: name1 - Sheet1 plan1 - sqlFetch(channel, name1) is ok or plan1 - sqlFetch(channel, Sheet1) Regards, Felipe -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Alberto Monteiro Sent: Tuesday, March 06, 2007 9:37 AM To: r-help@stat.math.ethz.ch Subject: [R] Package RODBC I have some questions about the RODBC package. library(RODBC) # required for those who want to repeat these lines 1st, I noticed that the following sequence does not work: channel - odbcConnextExcel(test.xls) tables - sqlTables(channel) name1 - tables[1, TABLE_NAME] # this should be the name plan1 - sqlFetch(channel, name1) # bang! odbcClose(channel) However, I can circumvent this with: channel - odbcConnextExcel(test.xls) tables - sqlTables(channel) name1 - tables[1, TABLE_NAME] # this should be the name plan1 - sqlQuery(channel, sprintf(select * from [%s], name1)) # ok odbcClose(channel) 2nd, it seems that only pure strings (which are not links to strings) and numerical values are correctly fetched or selected. Is this a bug? 3rd, when do something like plan1[,1] a weird message about Levels appear. What is that? Alberto Monteiro __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] lattice histogram
Steve,
it says resp - rnorm(200) must be resp - rnorm(100)
regards
Felipe
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of steve
Sent: Sunday, March 04, 2007 8:58 AM
To: r-help@stat.math.ethz.ch
Subject: Re: [R] lattice histogram
Hi,
When I tried this the groups had sizes 36 30 34 as expected, but
the annotations n = were 68 72 60 - twice as large. I don't
understand why.
Steve
Renaud Lancelot wrote:
Here is an example using the grid package to annotate the graphs:
library(lattice)
library(grid)
resp - rnorm(200)
group - sample(c(G1, G2, G3), replace = TRUE, size = 100)
histogram(~ resp | group,
panel = function(x, ...){
std - round(sd(x), 2)
n - length(x)
m - round(mean(x), 2)
panel.histogram(x, ...)
x1 - unit(1, npc) - unit(2, mm)
y1 - unit(1, npc) - unit(2, mm)
grid.text(label = bquote(n == .(n)), x = x1, y = y1, just = right)
grid.text(label = bquote(hat(m) == .(m)), x = x1, y = y1 - unit(1,
lines), just = right)
grid.text(label = bquote(hat(s) == .(std)), x = x1, y = y1 -
unit(2, lines), just = right)
})
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] significant anova but no distinct groups ?
You can use the LSD.test or waller.test of the package agricolae that less conservatives than tukey. From: [EMAIL PROTECTED] on behalf of Frederic Jean Sent: Fri 3/2/2007 4:52 PM To: [EMAIL PROTECTED] Subject: [R] significant anova but no distinct groups ? Dear all, I am studying a dataset using the aov() function. The independant variable 'cds' is a factor() with 8 levels and here is the result in studying the dependant variable 'rta' with aov() : summary(aov(rta ~ cds)) Df Sum Sq Mean Sq F value Pr(F) cds 7 0.34713 0.04959 2.3807 0.02777 Residuals 92 1.91635 0.02083 The dependant variable 'rta' is normally distributed and variances are homogeneous. But when studying the result with TukeyHSD, no differences in 'rta' are seen among groups of 'cds' : TukeyHSD(aov(rta ~ cds), which=cds) Tukey multiple comparisons of means 95% family-wise confidence level Fit: aov(formula = rta ~ cds) $cds difflwrupr p adj 1-0 -0.1046092796 -0.4331100 0.22389141 0.9751178 2-0 0.0359991860 -0.1371359 0.20913425 0.9980970 3-0 0.0261665235 -0.1348524 0.18718540 0.9996165 4-0 0.0004502442 -0.1805448 0.18144531 1.000 5-0 -0.1438949939 -0.3104752 0.02268526 0.1422670 [...] 7-5 0.0621598639 -0.1027595 0.22707926 0.9386170 7-6 0.0256519274 -0.1757408 0.22704465 0.248 I tried a pairwise.t.test (holm correction) which also was not able to detect differences in 'rta' among groups of 'cds' I've never been confronted to such a situation before : is it just a problem of power of the /a posteriori/ tests used ? Do I miss something important in basic stats or in R ? How to highlight differences among 'cds' groups seen with aov() ? Any help appreciated Thanks in advance, Fred J. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] ordered matrix question
Juan Pablo, X is data.frame or matrix X - X[order(X[,4]),] options see help(order) Felipe de Mendiburu -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Juan Pablo Fededa Sent: Tuesday, February 27, 2007 12:47 PM To: R-help@stat.math.ethz.ch Subject: [R] ordered matrix question Hi all, Is there an easy way to generate an object wich will be the same matrix, but ordered by de cfp value? The data frame consists of numeric columns: BlockXYcfpyfpID 0524244213.417957.184821091 055627065.3839049.5683726612 052831640.7894745.5737321753 0642432135.8173412.401344274 071643034.3591353.9449230775 0894362109.631583.1971603166 095813063.984523.3964520047 05069283.5139319.1054968568 047646491.6749199.1780894149 036442644.139322.06833436410 Thanks in advance, Juan Pablo [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Multiple conditional without if
Dear matthias, newmatrix = oldmatrix[ (oldmatrix[,5]==4 oldmatrix[,6]==1) , ] Felipe -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of bunny , lautloscrew.com Sent: Tuesday, February 27, 2007 1:25 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple conditional without if Dear all, i am stuck with a syntax problem. i have a matrix which has about 500 rows and 6 columns. now i want to kick some data out. i want create a new matrix which is basically the old one except for all entries which have a 4 in the 5 column AND a 1 in the 6th column. i tried the following but couldn´t get a new matrix, just some wierd errors: newmatrix=oldmatrix[,2][oldmatrix[,5]==4]oldmatrix[,2][oldmatrix[,6] ==1] all i get is: numeric(0) does anybody have an idea how to fix this one ? thx in advance matthias [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Multiple conditional without if
Matthias, According to the logic, New matrix which is basically the old one except for all entries which have a 4 in the 5 column AND a 1 in the 6th column newmatrix - oldmatrix[ (oldmatrix[,5]!=4 oldmatrix[,6]!=1) , ] --- newmatrix - oldmatrix[ !(oldmatrix[,5]==4 oldmatrix[,6]==1) , ] by, Felipe -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of bunny , lautloscrew.com Sent: Tuesday, February 27, 2007 1:25 PM To: r-help@stat.math.ethz.ch Subject: [R] Multiple conditional without if Dear all, i am stuck with a syntax problem. i have a matrix which has about 500 rows and 6 columns. now i want to kick some data out. i want create a new matrix which is basically the old one except for all entries which have a 4 in the 5 column AND a 1 in the 6th column. i tried the following but couldn´t get a new matrix, just some wierd errors: newmatrix=oldmatrix[,2][oldmatrix[,5]==4]oldmatrix[,2][oldmatrix[,6] ==1] all i get is: numeric(0) does anybody have an idea how to fix this one ? thx in advance matthias [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] predict.Arima question
Hi,
I am trying to forecast a model using predict.Arima
I found arima model for a data set: x={x1,x2,x3,...,x(t)}
arima_model = arima(x,order=c(1,0,1))
I am forecasting the next N lags using predict:
arima_pred = predict(arima_model,n.ahead = N, se.fit=T)
If I have one more point in my series, let's say x(t+1). I do not want to
recalibrate themodel, I just want to forecast the next N-1 lags using the
same model for x={x1,x2,...x(t)} but without recalibrate arima.
How to do it using arima + predict.Arima ?
My problem is that I am trying to fit arima models by brute force ( trying
lots of combinations for p and q and chosing the best model by AIC and BIC )
I have a big time series and I am running calibration for some sub-sequence
and I trying to forecast some points. I repeat this process for the next
contiguous subsequence and try to forecast again, until the big series end.
Thanks
Felipe
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Pairwise comparison after repeated measures ANOVA
I am analyzing some data obtained after measuring some parameters at different times in samples obtained from many subjects. The model is quite simple: aov(parameter ~ Time + Error(Subject/Time)) Now I want to make a pairwise comparison between the levels of Time. However, I have not find how to do such a thing. I cannot use TukeyHSD or pairwise.t.test, I supposse. Maybe using contrasts? Could you aim me at some kind of information? All I have found is information on ANOVA, but not how to compare the levels of the factors afterwards. Maybe I simply do not understand how this really works, my background is not very deep in statistics. Thank you. Felipe oOo Felipe Martínez Pastor, Ph. D. Ciencia y Tecnología Agroforestal ETSIA-UCLM Av. España s/n 02071-Albacete (Spain) Phone: +34 967 599 200+2581 Fax: +34 967 599 238+2081 Mobile: +34 687 365 362 e-mail: [EMAIL PROTECTED] Jabber: [EMAIL PROTECTED] website: http://www.germplasm.all.at -- Ningún investigador sin contrato. Employment rights for Spanish junior researchers. http://www.precarios.org __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Discriminant analysis to select best treatment
Hi.
I have found stepclass {klaR}, which is similar to what I was looking
for. However, I take note of your advice en stepwise variable selection.
Greetings.
Felipe
Alexandre Santos Aguiar wrote:
Em Dom 12 Fev 2006 16:10, Felipe Martínez-Pastor escreveu:
--apparently-- not variable selection.
About automatic variable selection one should read this:
http://www.pitt.edu/~wpilib/statfaq/regrfaq.html
--
Ningún investigador sin contrato.
Employment rights for Spanish junior researchers.
http://www.precarios.org
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] Discriminant analysis to select best treatment
I am designing an experiment to trial several analytic techniques on
samples submitted to different treatments. It has occurred to me that I
may use discriminant analysis to find out which kind of analysis best
reveals differences between treatments.
I have found the lda {MASS} in R. However, I am not sure if it is
adequate to my case, since it performs linear discriminant analysis but
--apparently-- not variable selection. In SAS I would use the STEPDISC
procedure, whose description is:
uses forward selection, backward elimination, or stepwise selection to
try to find a subset of quantitative variables that best reveals
differences among the classes.
I wonder if I could use lda or other function in that way. Maybe you
could point me to any resource (I am really new in discriminant analysis).
Thank you.
oOo
Felipe Martínez Pastor, Ph. D.
Ciencia y Tecnología Agroforestal
ETSIA-UCLM
Av. España s/n
02071-Albacete (Spain)
Phone: +34 967 599 200+2581
Fax: +34 967 599 238+2081
Mobile: +34 687 365 362
e-mail: [EMAIL PROTECTED]
Jabber: [EMAIL PROTECTED]
--
Ningún investigador sin contrato.
Employment rights for Spanish junior researchers.
http://www.precarios.org
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] from Colombia - help
Hi, my name is Andres Felipe Barrientos, I'm a student of Statistic and don't speak in english. En mi trabajo de grado necesito implementar la funcion smooth.spline y necesito saber con que tipo de spline trabaja (b-splines o naturales). Ademas me gustaria saber cual es la base que se usa para encontrar estos splines, por ejemplo, cosenos, senos, polinomios entre otros Otra pregunta que tengo consiste en saber cual es la relacion que sostiene la funcion smooth.spline y ns Agradeciendo la atencion prestada y esperando una respuesta desde la universidad del valle, quien le escribe. Andres Felipe - 1GB gratis, Antivirus y Antispam Correo Yahoo!, el mejor correo web del mundo Abrí tu cuenta aquí [[alternative HTML version deleted]] __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Are least-squares means useful or appropriate?
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi. My question was just theoric. I was wondering if someone who were using SAS and R could give me their opinion on the topic. I was trying to use least-squares means for comparison in R, but then I found some indications against them, and I wanted to know if they had good basis (as I told earlier, they were not much detailed). Greetings. Felipe Spencer Graves wrote: | Estimado Felipe: | | If you provide a very simple example (as suggested in the posting | guide, www.R-project.org/posting-guide.html), it would allow those of | use who rarely use SAS to respond. Try to think of the simplest | possible toy data set and analysis that shows the difference between the | SAS answer and the answer you get from a certain R function. If you | post something simple of that nature that someone can copy from your | email into R and try other things in a minute or two, it will likely | increase the speed and utility of a reply. | | Buena Suerte, | spencer graves | -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMvzDEACgkQWtdQtNzjBl6NbgCfTg0hPZaSio9tO1iWrKHZY3Os wzEAn3jdHwqqaHxG0OT8KR6kBlSZDPLp =KtTd -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] Use of least-squares means, are they misleading?
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi. Sorry for sending this question twice, but I would really like to know your opinion on this topic. I have been reading about the (in)convenience of using least-squares means (a. k. a. adjusted means) in multiple comparisons (I used to resort to them when using SAS). I even read a post in this list warning against them, but not giving much detail. What is your opinion? Should I avoid using LSmeans for comparison (e.g. after ANOVA)? Greetings. Felipe __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMulV4ACgkQWtdQtNzjBl6QpwCfXYweOQWipAYY2ZZFiDYuAiwJ LQYAnicmypM4yZhzMztRmZvppTZWes1z =696Z -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Use of least-squares means, are they misleading?
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Thank you, I will try there. Felipe Peter Flom wrote: | Felipe | | I doubt you will get much response on this list, although it's an | interesting question. You might try asking it on another list. Some | that often have discussions of such topics are | | SAS-L | EDSTAT-L and | STAT-L | | Regards | | Peter | | Peter L. Flom, PhD | Assistant Director, Statistics and Data Analysis Core | Center for Drug Use and HIV Research | National Development and Research Institutes | 71 W. 23rd St | http://cduhr.ndri.org | www.peterflom.com | New York, NY 10010 | (212) 845-4485 (voice) | (917) 438-0894 (fax) | | | |Felipe [EMAIL PROTECTED] 09/19/05 6:39 AM | | Hi. | Sorry for sending this question twice, but I would really like to know | your opinion on this topic. | | I have been reading about the (in)convenience of using least-squares | means (a. k. a. adjusted means) in multiple comparisons (I used to | resort to them when using SAS). I even read a post in this list warning | against them, but not giving much detail. | | What is your opinion? Should I avoid using LSmeans for comparison (e.g. | after ANOVA)? | | Greetings. | | Felipe | | __ | R-help@stat.math.ethz.ch mailing list | https://stat.ethz.ch/mailman/listinfo/r-help | PLEASE do read the posting guide! | http://www.R-project.org/posting-guide.html | | __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMuxT0ACgkQWtdQtNzjBl7LWACcCddjPgTnZX2+15aDLbxe+qxD rHcAoIdkgW8ke/M8bb7pSlcptTz9K53j =eCEC -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] Problems compiling Hmisc
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi. I am trying to install Hmisc from source on MacOS 10.4.2, using the R for Mac OS X Aqua GUI 1.12. I have installed g77(using Fink). I am using the Package installer provided by the GUI, and this is the output I obtain: * Installing *source* package 'Hmisc' ... ** libs g77 -fno-common -g -O2 -c cidxcn.f -o cidxcn.o g77 -fno-common -g -O2 -c cidxcp.f -o cidxcp.o g77 -fno-common -g -O2 -c hoeffd.f -o hoeffd.o g77 -fno-common -g -O2 -c jacklins.f -o jacklins.o g77 -fno-common -g -O2 -c largrec.f -o largrec.o gcc-3.3 -no-cpp-precomp - -I/Library/Frameworks/R.framework/Resources/include - -I/usr/local/include -fno-common -g -O2 -c ranksort.c -o ranksort.o g77 -fno-common -g -O2 -c rcorr.f -o rcorr.o g77 -fno-common -g -O2 -c wclosest.f -o wclosest.o gcc-3.3 -bundle -flat_namespace -undefined suppress -L/usr/local/lib -o Hmisc.so cidxcn.o cidxcp.o hoeffd.o jacklins.o largrec.o ranksort.o rcorr.o wclosest.o -L/usr/local/lib/gcc/powerpc-apple-darwin6.8/3.4.2 - -lg2c -lSystem -framework R The downloaded packages are in /private/tmp/Rtmpl1pDLj/downloaded_packages ld: can't locate file for: -lg2c make: *** [Hmisc.so] Error 1 ERROR: compilation failed for package 'Hmisc' It seems to be a problem with the linker, but no idea. Do I need to install any library or another Fink package? Thank you. Felipe - --oOo-- Felipe Martínez-Pastor (BSc, PhD) Animal Reproduction and Obstetrics Veterinary Clinic Hospital 24071-León (Spain) Phone: 987 291 430 / 987 291 000 + 5203 Fax: 987 295 203 e-mail: [EMAIL PROTECTED] - --- This message has been electronically signed using GPG, a free system to sign and encrypt documents. If you want to learn more, visit http://www.gnupg.org -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMqkN0ACgkQWtdQtNzjBl5kFACfSBopAnm/S2PTEbSyZGhOt4q0 zeQAn3MajbnFXWWhVd7gT+fQ5fGE85Ro =lssZ -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] Are least-squares means useful or appropriate?
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi. I have been reading about the convenience of using least-squares means (a. k. a. adjusted means) in multiple comparisons (I used to resort to them when using SAS). I even read a post in this list warning against them, but not giving much detail. What do you think about this? Greetings. Felipe -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMqq5gACgkQWtdQtNzjBl4AigCfQJ64O0wrdYK/1iMReW5RtI1d tMIAn3DQSdk+4D7AK7VQGtWo0TElrFG7 =j9EX -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] means comparison in R (post-hoc test)
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi. I have been using SAS for some time, and now I have discovered R. I am very happy with it, but I have not found out how to perform some of the multiple comparisons I was used to do in SAS. With the SAS/STAT, I generally used the MEANS (for comparison of arithmetic means) and the LSMEANS (for adjusted means) statements of the GLM procedure (I think it is equivalent to lm in R). They provided a lot of tests: LSD, Duncan, Tukey-Kramer, Bonferroni, Scheffé, SNK, etc. However, in R I have only discovered Tukey-HSD. I have searched for information about this, but I was not successful. I wonder if anybody knows where I could learn about this. I would like to use these tests in R, and also obtain the adjusted means like these produced by the LSMEANS statement. Thank you. Felipe - --oOo-- Felipe Martínez-Pastor (BSc, PhD) Animal Reproduction and Obstetrics Veterinary Clinic Hospital 24071-León (Spain) Phone: 987 291 430 / 987 291 000 + 5203 Fax: 987 295 203 e-mail: [EMAIL PROTECTED] - --- This message has been electronically signed using GPG, a free system to sign and encrypt documents. If you want to learn more, visit http://www.gnupg.org -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMpUVYACgkQWtdQtNzjBl4rywCePiSxJw8/N6HzdZ7C+YMHf2K6 YSYAniw5GSo0ihrt4+OabHJ4c2PKNHkp =aF38 -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] means comparison in R (post-hoc test)
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Thank you, I think multcomp is very near to what I was looking for. However, I am still looking for a mean to obtain least-squares (adjusted) means and std. errors of these means, and performing comparisons among these means, as the LSMEANS do in SAS. I have read other messages and have looked at car, effects and Design manuals, but I am not sure if this is what I am looking for. Any clue? Felipe Dieter Menne wrote: | Felipe felipe at unileon.es writes: | | |With the SAS/STAT, I generally used the MEANS (for comparison of |arithmetic means) and the LSMEANS (for adjusted means) statements of the |GLM procedure (I think it is equivalent to lm in R). They provided a lot |of tests: LSD, Duncan, Tukey-Kramer, Bonferroni, Scheffé, SNK, etc. |However, in R I have only discovered Tukey-HSD. | | | Package multcomp with the workhorse-function simint comes close to what you | want. | | | Dieter | | __ -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMpo6UACgkQWtdQtNzjBl72rwCcCuw5qxD1BWsensDI71RzhNgL MUcAnA0Iq4tfoKSr/ymIV1nEZHZijvLW =pavA -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Copying from graphics window in OS X
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 I'm using R for Mac OS X Aqua GUI. It allows me to copy graphs directly, simply with command-c. It's pretty nice, you can give it a try. Greetings. Felipe Chris Wiita wrote: | I'm running R from an Xterm window is OSX-Tiger. Graphical windows | appear as they should, but I'm having trouble copying from them--using | cmd+c or the Copy option in the Edit menu won't place the graph in the | clipboard (when I paste into a running OS X app, I get whatever was the | last copied thing from a non-x11 window). Any ideas on how to copy from | a xterm-launched graphical window? I can copy/paste into and out of the | xterm command line, but I can't get anything from a graphical window. | | Thanks! | | __ | R-help@stat.math.ethz.ch mailing list | https://stat.ethz.ch/mailman/listinfo/r-help | PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html | | -BEGIN PGP SIGNATURE- iEYEARECAAYFAkMp1eYACgkQWtdQtNzjBl59JgCfV7JR8kbsbYvMQG6OVt/plNTd 1S8AnRTHe6cRrwr0mxbJJGXmdkRibDvV =Pc3t -END PGP SIGNATURE- __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] Problems plotting time-series with multiple lines
He you checked this example?: z - ts(matrix(rt(200 * 8, df = 3), 200, 8), start = c(1961,1), frequency = 12) z - window(z[, 1:3], end = c(1969, 12)) plot(z, plot.type = single, lty = 1:3, col = 4:2) It is from the help page of plot.ts Felipe Jose Augusto Jr - jamaj - terra [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Dear Sirs, I want to plot a time series with lines, one for each variable. I have a dataset with dates, and the values. How can i plot? I could plot one variable using index plot, bu i want to put the labels on X axis. But i had two problems: 1) The plot function, when i try to plot(x,y), incorectly sort the date (on X axis). My dataset has the date in string format %d/%m/%Y). If i try to converto to date using as.Date(Dataset.dates,%d/%m/%Y) it interprets the %Y incorrectly. 2) I have 187 rows. So i have to plot only some of the dates, not all. Please, help me. Thanks in advance. Best Regards, José Augusto M. de Andrade Jr. Computer games don't affect kids; I mean if Pac-Man affected us as kids, we'd all be running around darkened rooms, munching magic pills and listening to repetitive electronic music. (Kristian Wilson, Nintendo, Inc. 1989) __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html __ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] 3d cube with labels along axes
This may work:
- use option axes=F in persp
- use locator() to get the coordinates where you want to put your new labels
- use text(x,y,...) to write your new labels
It is a little bit tedious, but it should work. Regards,
Felipe
jonne [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi R-users,
I would like to draw a cube with a grid on it and labels along all
three axes. I have trouble printing the labels correctly. My
best attempt is described below.
Can somebody explain me how I can change the 0,20,40,80,100
along the x axis into character vectors like
no, light, intermediate, severe ?
x - seq(0, 100, length=10)
#x - c(no, light, intermediate, severe)
y - x
f - function(x,y) { numeric(length=100) + 5 }
z - outer(x, y, f)
P - persp(x, y, z, theta=30, phi=30, zlim=c(-10,10), ticktype=detailed)
text3d(0, 0, -10, Hello world, P)
Thanks in advance,
Jonne.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
[R] complex expression with plotmath
Hello everyone,
I want to define a function that receives the name of two variables
(may include Greek letters and subscripts) and uses them into the
title of a plot.
My best attempt is the following:
myplot - function(var1, var2) {
v=paste(var1,==1 ,var2,==2);
plot(1:10, main=parse(,,v))
}
But when I call it with something like myplot(Q[i], Delta[j]) I
get (Q_i=1,Delta_j=2) as title when I want to get Q_i=1
Delta_j=2.
Is there any solution within R? (I don't want to use psfrag and Latex
to post-process the plot)
Why R does not have support for full Latex expressions? (as Matlab
f.ex.). IMHO plotmath is not good enough.
Thank you all.
Felipe
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] complex expression with plotmath
Thanks, it worked!
So the cute trick was the call to *quote* inside the function call.
Thanks again,
Felipe
On 8/14/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 8/14/05, Felipe Csaszar [EMAIL PROTECTED] wrote:
Hello everyone,
I want to define a function that receives the name of two variables
(may include Greek letters and subscripts) and uses them into the
title of a plot.
My best attempt is the following:
myplot - function(var1, var2) {
v=paste(var1,==1 ,var2,==2);
plot(1:10, main=parse(,,v))
}
But when I call it with something like myplot(Q[i], Delta[j]) I
get (Q_i=1,Delta_j=2) as title when I want to get Q_i=1
Delta_j=2.
Is there any solution within R? (I don't want to use psfrag and Latex
to post-process the plot)
Why R does not have support for full Latex expressions? (as Matlab
f.ex.). IMHO plotmath is not good enough.
Try this:
myplot - function(var1, var2)
plot(1:10, main = bquote(.(var1) == 1 ~ ~ .(var2) == 2))
myplot(quote(Q[i]), quote(Delta[j]))
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Re: [R] type III Sum Sq in ANOVA table - Howto?
Hi! I have found your comments very interesting, but I feel I am one of
these people that do not understand what the hell they are really
testing :D
Could you (or anybody) suggest me a good web site to gather this kind
of information? Sometimes I cannot fully understand the messages of the
list because I lack some knowledge background.
Thank you.
Felipe
El Viernes, 7 marzo, 2003, a las 01:31 AM, Rolf Turner escribió:
Andy Liaw wrote:
The long(er) answer: think harder about what question(s) you want
answered
(i.e., what hypotheses you really want to test, and test only
those). The
model hierarchy says that a model should not have an interaction term
involving a factor whose main effect is not present in the model.
Seen in
this light, the hypothesis you're trying to test involves a
non-sensical
model.
Not really. The hypothesis being tested by Type III sums of square
may be suspected of not being of ``central interest'', but it is NOT
(as is commonly believed) ``non-sensical''.
Let us think about the 2-way ANOVA case, where one can actually
understand what is going on. Let the population ***cell means*** be
mu_ij (i = 1, ..., m, j = 1, ..., n) and forget about the confusing
and misleading over-parameterized model.
Testing for the significance of the ``row factor'' by Type III
sums of squares (with interaction in the model of course) tests
H_0: mu_{1.}-bar = mu_{2.}-bar = ... = mu_{m.}-bar
I.e. that the means of the population cell means, over columns, are
all equal. I.e. that ``when rows are averaged over columns'' there
is no row effect.
This could, at least conceiveably, be of interest. Note that the
average is not a weighted average, saying that all columns are
equally important. If all columns are NOT equally important (e.g.
if an item randomly drawn from the population is more likely to
``come from'' column 1 than from column 2 etc.) then this hypothesis
is less likely to be of interest.
But it isn't nonsensical.
It is true, however, that most of the time when people test things
using Type III sums of squares they don't understand what they are
really testing. But then (said he cynically) people don't understand
what the hell they are really testing in most situations, not just
in the context of Type III sums of squares.
cheers,
Rolf Turner
__
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
__
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
[R] SAS/SPSS - R migration
Hi! I am starting to use the R system. Till now I have been using SAS and SPSS, as my university and department has licences of them. I would like to know if there is a mail list in Spanish (this is my native language), and if there is some kind of tutorial specially oriented to people used to work with SAS or SPSS who want to migrate to R. Thank you! Felipe __ [EMAIL PROTECTED] mailing list http://www.stat.math.ethz.ch/mailman/listinfo/r-help
