[R] R on QNX

2007-07-31 Thread Suresh Krishna

Hi,

Has anyone attempted to compile R on QNX 4.x or 6.x ? It would be  
particularly cool if there is a precompiled version somewhere on the QNX  
software archives.

Thank you very much !!

Suresh

ps. Please cc replies to my address if possible...

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[R] Nonlinear fitting - reparametrization help

2006-09-27 Thread Suresh Krishna

Hi,

I am trying to fit a function of the form:

y = A0 + A1 * exp( -0.5* ( (X - Mu1) / Sigma1 )^2 ) - A2 * exp ( -0.5*  
( (X-Mu2)/Sigma2 )^2 )

i.e. a mean term (A0) + a difference between two gaussians.

The constraints are A1,A2 0, Sigma1,Sigma20, and usually Sigma2Sigma1.  
The plot looks like a Mexican Hat.

I had trouble (poor fits) fitting this function to toy data in Matlab and  
now I am playing with R's nls and optim functions. I keep running into  
singular gradient errors with nls, even with very different starting  
values, and have not yet figured out how to interpret the trace results  
usefully.

Can someone help ? Is there a correct parameterization for this problem ?  
I have appended some R code with sample data to fit.

Thank you !!!

Suresh; please cc [EMAIL PROTECTED] if possible.

~~~
x=seq(-10,10,length=1000)
a0=0;
ae=1;
me=0;
se=1;
ai=0.5;
mi=0;
si=3;
dogy - function(x,a0,ae,me,se,ai,mi,si){
y=a0+ae*exp(-0.5*(((x-me)/se)^2))-ai*exp(-0.5*(((x-mi)/si)^2))
y}
y=dogy(x,a0,ae,me,se,ai,mi,si)
erval=rnorm(length(y),sd=0.02)
y=y+erval
#plot(x,y+erval)

#fit=nls(y~ae*exp((x/se)^2)-ai*exp((x/si)^2),start=c(ae=.8,se=1.1,ai=.2,si=1),trace=TRUE)

#here I tried to unsuccesfully reduce the model by eliminating A0, Mu1,  
and Mu2

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Re: [R] The problem with rcom pakage

2005-11-08 Thread Suresh Krishna

You need the 2.0 beta package available at:

http://sunsite.univie.ac.at/rcom/download/RSrv200beta.exe

Also, there is a rcom mailing list at  
http://mailman.csd.univie.ac.at/mailman/listinfo/rcom-l for more help.

Suresh

On Tue, 08 Nov 2005 06:42:37 -0500, Julia Ivanova [EMAIL PROTECTED] wrote:

 I have the problem with rcom 1.2.2 package. It does't work with R 2.2.0.
 Is there any opportunities to correct the work of this package?
 Thanks for your help.
 Yulia

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[R] MGARCH estimation

2005-09-21 Thread Krishna
Hi R-users

Can the users let me know how to do MGARCH estimate (Bivariate GARCH)
and volatility forecast for 2 variables in R.

thanks and regards

snvk

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[R] minimal hedge variance ratio

2005-09-19 Thread Krishna
Hi all

i have two data sets, spot and futures cash market prices. to estimate
the minimum variance hedge ratio, i first had a glance on the
correlation coefficient of relative price change (ln(St / St-1).
surprizingly the value is just 0.2 compared to actual price
correlation of 0.9. (i did regress the spot change on future change,
co-effi is 0.3, and R2 is only 0.025

a) in such scenario can someone help me in estimating the ratio which
are time varying.
b) is there a way to define the function as the correlation will work
at given level of basis (futures - spot).

thank u for the help and co-operation

rgds

snvk

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Re: [R] significance of spectal peak with spectrum()

2005-09-16 Thread Suresh Krishna

I am very much a naive and interested beginner, so I am not at all sure 
if you will find this reference

http://snipurl.com/hq2j

interesting

S.

Uwe Ligges wrote:
 Sebastian Leuzinger wrote:
 
 
the null hypothesis would be: one particular frequency peak is not 
significantly different from the background noise.
 
 
 So you want to know, e.g., whether there is something going on at 1000 
 Hz? This is difficult: If you are considering the periodogram to be a 
 density, then you do not know the distribution of the value of a single 
 frequency, because it depends on the stuff going on at other frequencies.
 
 Second point is (and already asked): Kind of [background] noise?
 
 The only really easy test is for the Null signal is white noise, hence 
 H1 is at least one non-white-noisy frequency.
 
 [If somebody knows a really good book or papers that cover other cases 
 than the trivial one mentioned above, I am very interested to hear about 
 them, BTW.]
 
 If you have another kind of noise (such as blue or pink noise), things 
 become even worse.
 
 Uwe Ligges
 
 
 
On Friday 16 September 2005 09:28, you wrote:


Sebastian Leuzinger wrote:


Hello, has anybody got a simple recepie to test the significance level of
the peaks after using spectrum() ?

What is you null hypothesis?

- Kind of noise?
- One particular frequency is noisy or all noisy?
- ...

Uwe Ligges



(R-version 2.0.1, linux SuSE9.3)
 
 
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[R] help required on read.table

2005-09-16 Thread Krishna
Hi all

i am facing a peculiar problem for data input using read.table which i
never faced previously.

i have a data file by name abnew.txt with two coloumns data as depicted below.

A B
420 422
314 321

the txt file is created using the excel save as option. i issued the
statement as

 a - read.table(abnew.txt, header=TRUE) 
 a
 X.þS
1  NA
2   2
3   2
4  NA
5   2
6   2
7  NA
8   2
9   2
10 NA

the o/p looks like as copied above. can some one help me on correct
data reading. your earliest response will help me a lot.

thanks and regards

snvk

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[R] problem with read.table

2005-08-25 Thread Krishna
Hi All

recently i faced an unknown problem while reading the data. Can
someone help me in understanding why this happened.

I have .txt file containing X, Y, Z variables. I used the command 

 a - read.table(filename, header=TRUE)
after reading the file i am able to view it by tryping a. but i am
unable to access the variables in a, by giving the command a$X.

 a$X
 NULL

this is the output it was showing. However the same i am able to
access by giving a[[1]]. i tried changing the mode by issuing command
a - as.data.frame(a). But situation remains the same.

look forward for experts suggestion on this.

rgds

snvk

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Re: [R] problem with read.table

2005-08-25 Thread Krishna
Hi  Mr. Pedro

I tried names(a) and it displayed the names as X, Y and Z.

rgds

snvk

On 8/25/05, Pedro J. Aphalo [EMAIL PROTECTED] wrote:
 Hi,
 
 Did you try names(a) so see what are the names of the columns in the
 dataframe?
 
 Hope this helps a little.
 
 Pedro.
 
 Krishna wrote:
  Hi All
 
  recently i faced an unknown problem while reading the data. Can
  someone help me in understanding why this happened.
 
  I have .txt file containing X, Y, Z variables. I used the command
 
 
 a - read.table(filename, header=TRUE)
 
  after reading the file i am able to view it by tryping a. but i am
  unable to access the variables in a, by giving the command a$X.
 
 
 a$X
 NULL
 
 
  this is the output it was showing. However the same i am able to
  access by giving a[[1]]. i tried changing the mode by issuing command
  a - as.data.frame(a). But situation remains the same.
 
  look forward for experts suggestion on this.
 
  rgds
 
  snvk
 
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 --
 ==
 Pedro J. Aphalo
 Department of Biological and Environmental Science
 University of Jyväskylä
 P.O. Box 35, 40351 JYVÄSKYLÄ, Finland
 Phone  +358 14 260 2339
 Mobile +358 50 3721504
 Fax+358 14 260 2321
 mailto:[EMAIL PROTECTED]
 http://www.jyu.fi/~aphalo/   ,,,^..^,,,
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Re: [R] correlation by subset

2005-08-25 Thread Krishna
Hi Mr. Cleland

it worked excellently well, and i believe the same logic or function
by() can be used even for running regressions on subsets of huge
datasets. correct me if iam wrong

thank you for the help

rgds

snvk

On 8/24/05, Krishna [EMAIL PROTECTED] wrote:
 Hi Mr. Cleland
 
 Could you please detail the function.
 
 Thanks and best regards
 
 snvk
 
 On 8/24/05, Chuck Cleland [EMAIL PROTECTED] wrote:
  by(mydata, mydata$GROUPING, function(x) cor(x$x, x$y, use=pair))
 
  ?by
 
  Krishna wrote:
   Hi all
  
   Having searched the available documentation on R, I request for help
   in sorting out the underlying problem.
  
   I have a huge dataset containing 2 variables x and y, which is a daily
   price series.
  
   I would like to observe the quarterly correlations among these two
   variables. Is there anyway where i can calculate cor.coeff by using a
   grouping variable in R.
  
   thanks in advance for the help
  
   rgds
  
   snvk
  
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  --
  Chuck Cleland, Ph.D.
  NDRI, Inc.
  71 West 23rd Street, 8th floor
  New York, NY 10010
  tel: (212) 845-4495 (Tu, Th)
  tel: (732) 452-1424 (M, W, F)
  fax: (917) 438-0894
 


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[R] help on retrieving output from by( ) for regression

2005-08-25 Thread Krishna
Hi all 

I used a function 
 qtrregr - by(AB, AB$qtr, function(AB) lm(AB$X~AB$Y))

objective is to run a regression on quartery subsets in the data set
AB, having variables X and Y, grouped by variable qtr.

Now i retrieved the output using qtrregr, however it only showed the
coefficients (intercept and B) with out significant levels and
residuals for each qtr. Can some on help me on how can retrieve the
detailed regression output.

rgds

snvk

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[R] correlation by subset

2005-08-24 Thread Krishna
Hi all

Having searched the available documentation on R, I request for help
in sorting out the underlying problem.

I have a huge dataset containing 2 variables x and y, which is a daily
price series.

I would like to observe the quarterly correlations among these two
variables. Is there anyway where i can calculate cor.coeff by using a
grouping variable in R.

thanks in advance for the help

rgds

snvk

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Re: [R] correlation by subset

2005-08-24 Thread Krishna
Hi Mr. Cleland

Could you please detail the function.

Thanks and best regards

snvk

On 8/24/05, Chuck Cleland [EMAIL PROTECTED] wrote:
 by(mydata, mydata$GROUPING, function(x) cor(x$x, x$y, use=pair))
 
 ?by
 
 Krishna wrote:
  Hi all
 
  Having searched the available documentation on R, I request for help
  in sorting out the underlying problem.
 
  I have a huge dataset containing 2 variables x and y, which is a daily
  price series.
 
  I would like to observe the quarterly correlations among these two
  variables. Is there anyway where i can calculate cor.coeff by using a
  grouping variable in R.
 
  thanks in advance for the help
 
  rgds
 
  snvk
 
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 --
 Chuck Cleland, Ph.D.
 NDRI, Inc.
 71 West 23rd Street, 8th floor
 New York, NY 10010
 tel: (212) 845-4495 (Tu, Th)
 tel: (732) 452-1424 (M, W, F)
 fax: (917) 438-0894


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[R] optimal hedge variance ratio

2005-08-17 Thread Krishna
Hi All,

I am trying to finding out what could be an optimal hedge variance
ratio between spot and futures markets, between whose the degree of
correlation is highly varying.

For some reasons the hedge time period cannot extend for more than 1
month. So just to get an hint, I have calculated monthly correlation
coefficients which are highly varying. I am copying the frequency
distribution of monthly correlation coefficient values
(karl-pearsons') to indicating the degree of volatility.

Corre 
range   Frequency   
-0.70   0.00%
-0.52   3.08%
-0.33   4.62%
0   7   10.77%
0.3 7   10.77%
0.5 6   9.23%
0.7 16  24.62%
0.9 15  23.08%
1   9   13.85%

Can someone throw light on which model to use and how to approach for
desiging a hedge model (estimate hedge variance ratio) in such a
scenario. Help requested at the earliest.

thanks for the attention and best rgds

snvk

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[R] help on cross hedge optimal hedge variance ratio

2005-08-12 Thread Krishna
Hi everyone

I am trying to estimate the optimal hedge variance ratio for cross
hedging two commodities. the price levels are used (compared to price
change and % price change) and used the OLS with dummy variable for
estimating the co-efficients. the equation looks like this

Y = B + B1*D1 + B2*X + B3*(X*D1)

Where Y = Daily Cash market price
D1 = Dummy variable taking value 1 for period Oct-Mar and 0 for Apr-Sep
X = Daily futures market price on which cross hedging is done.
B,B1,B2,B3 are the slope co-efficients. 

The results look like this 
Regression Statistics
Multiple R  0.948702709
R Square0.900036831
Adjusted R Square   0.89981135
Standard Error  25.52050965
Observations1334


CoefficientsStandard Error  t Stat  P-value
Intercept   53.817  4.375   12.300  0.000
X   0.986   0.012   80.283  0.000
D1  27.399  6.106   4.487   0.000
D1 * X  -0.100  0.017   -5.820  0.000

It is understood the slope co-efficients for different periods are
significant as indicated by t-table value. But I feel suspicious on
the reliability of this values.

I have used 5 years of daily price data for running the regression,
and I feel suscpicious becasue, the monthly correlations (pearson
correlation co-efficient) are highly varying between spot and futures
and some times even negative.

Can someone suggest me 
a) the tests to judge the reliability of hedge-variance values
b) Is there any other better method than described here for estimating
the hedge-variance values

Thank you for the attention and look forward for an early reply

rgds

snvk

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[R] error loading nlme package

2005-08-09 Thread Krishna
Hi everyone

The suggestion I received from Mr. Dimitris Rizopoulos and Mr. Gabor
Grothendieck seems to work well. But unfortunately when I am trying to
load nlme package, the following error message is generated. Please
help me on this, at the earliest.

 library(nlme)
Error in loadNamespace(i, c(lib.loc, .libPaths()), keep.source) : 
There is no package called 'lattice'
In addition: Warning message: 
package 'nlme' was built under R version 2.0.1 
Error in library(nlme) : package/namespace load failed for 'nlme'

Though i am using the version R 2.0.0. A couple of hours back it was
loaded, in the new session this problem is generated.

regards
Krishna

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[R] help on regression by subsets in dataset

2005-08-08 Thread Krishna
Hi Everyone

May I request for a small help while performing the regression analysis.

I would like to know is there any possibility of conducting the
regression for different data subsets (in the same data file),
classified on the basis of grouping variable. The alternative for
this is running the regression for n number of times which you all
know is quite cumbersome.

Thank you for your kind attention and help

rgds

krishna

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Re: [R] [OT] gmail filter for R-help and R-devel lists

2005-07-01 Thread Suresh Krishna

i dont use gmail, but this method *may* run into problems if people are 
replying to a message and r-help is on the cc: line.

thunderbird has a to: or cc: option for this... is gmail's to: field a 
default for to: or cc: ?

-s.

Deepayan Sarkar wrote:
 On 6/30/05, Douglas Bates [EMAIL PROTECTED] wrote:
 
This is slightly off-topic but I would be interested in whether anyone
has succeeded in creating a filter expression for Google's gmail
system that will select messages sent through the R-help and R-devel
lists.  It seems as if it should be easy to select on '[R]' or '[Rd]'
in the subject line but I haven't been able to work out the exact
syntax that would do this and not select messages that have an 'R'
anywhere in the subject.
 
 
 I filter on the To field, which mostly works:
 
 Matches: to:(r-help@stat.math.ethz.ch)
 Do this: Skip Inbox, Apply label r-help
 
 Matches: to:([EMAIL PROTECTED])
 Do this: Skip Inbox, Apply label r-help
 
 Deepayan
 
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Re: [R] cor vs cor.test

2005-05-25 Thread Suresh Krishna


From:

?cor.test

Arguments:

x, y: numeric vectors of data values.  'x' and 'y' must have the
  same length.

-s.

Michael Grant wrote:

Using Windows System, R 2.1.0

d is a data frame, 48 rows, 10 columns
cor(d) works properly providing all pairwise Pearson correlation
coefficients among columns
cor.test(d) gives error message Error in cor.test.default(d) : argument
y is missing, with no default

Why?

Thanks,
MCG

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Re: [R] website reference for building R packages

2005-05-23 Thread Suresh Krishna


it is the first link if you type making packages into the google 
search box here:


http://maths.newcastle.edu.au/~rking/R/

-s.


Laura Holt wrote:

Hi R People:

A few weeks ago, someone put a link to a website for how to for 
building R packages.  It was very nice.


But of course, I have misplaced the link.  Does anyone still have that, 
please?


It was someone from the University of Chicago, I believe.

Thanks in advance.

Sincerely,
Laura Holt
mailto: [EMAIL PROTECTED]

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Re: [R] hello

2005-05-20 Thread Suresh Krishna
http://snipurl.com/f0xh
(leads you to packages 'ade4' and 'MASS')
-s.
Navarre Sabine wrote:
I would like to donc an AFC (factoriel correspondance analysis) and I know that 
on Splus, the function to do that is afc(data). But on R??? is it acm?
That a lot! 
Sabine


-
ils, photos et vidéos !
[[alternative HTML version deleted]]
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Re: [R] R2.1.0: Bug in list.files

2005-05-12 Thread Suresh Krishna
Is that the entire story ? I tried this with yesterday's patched version 
(windows xp) and found:

 list.files(getwd(),*.txt,full=T)
Error in list.files(path, pattern, all.files, full.names, recursive) :
invalid 'pattern' regular expression
 list.files(getwd(),'.txt',full=T)
[1] C:/Documents and Settings/suresh/BDE_SysInfo.txt
[2] C:/Documents and Settings/suresh/dxva_sig.txt
Replacing *.txt with '*.txt' seems to do something.
-s.
Uwe Ligges wrote:
Steve Roberts wrote:
R2.0.1 (MS Windows)

list.files(myloc,*.zip,full=T)

[1] P:/SARsoftware/Rlibraries/gnlm_0.1.zip
[2] P:/SARsoftware/Rlibraries/lms2_0.2.zip
R2.1.0:

list.files(myloc,*.zip,full=T)

Error in list.files(path, pattern, all.files, full.names, recursive) : 
invalid 'pattern' regular expression
 
Bug? or have I missed something

You missed to read the NEWS that tells you:
o   The regular expression code is now based on that in glibc 2.3.3.
It has stricter conformance to POSIX, so metachars such as
{ } + * may need to be escaped where before they did not
(but could have been).
Probably you want
 list.files(pattern = \\.zip$, full.names = TRUE)
Uwe Ligges

Steve.
  Dr Steve Roberts   [EMAIL PROTECTED]
Senior Lecturer in Medical Statistics,
CMMCH NHS Trust and University of Manchester Biostatistics Group,
0161 275 5192/5764 / 0161 276 5785
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Re: [R] R2.1.0: Bug in list.files

2005-05-12 Thread Suresh Krishna
oops, my fault. i missed typing the key '*' character in the second version.
apologies !!!
suresh
Suresh Krishna wrote:
Is that the entire story ? I tried this with yesterday's patched version 
(windows xp) and found:

  list.files(getwd(),*.txt,full=T)
Error in list.files(path, pattern, all.files, full.names, recursive) :
invalid 'pattern' regular expression
  list.files(getwd(),'.txt',full=T)
[1] C:/Documents and Settings/suresh/BDE_SysInfo.txt
[2] C:/Documents and Settings/suresh/dxva_sig.txt
Replacing *.txt with '*.txt' seems to do something.
-s.
Uwe Ligges wrote:
Steve Roberts wrote:
R2.0.1 (MS Windows)

list.files(myloc,*.zip,full=T)

[1] P:/SARsoftware/Rlibraries/gnlm_0.1.zip
[2] P:/SARsoftware/Rlibraries/lms2_0.2.zip
R2.1.0:

list.files(myloc,*.zip,full=T)

Error in list.files(path, pattern, all.files, full.names, recursive) 
: invalid 'pattern' regular expression

 
Bug? or have I missed something

You missed to read the NEWS that tells you:
o   The regular expression code is now based on that in glibc 2.3.3.
It has stricter conformance to POSIX, so metachars such as
{ } + * may need to be escaped where before they did not
(but could have been).
Probably you want
 list.files(pattern = \\.zip$, full.names = TRUE)
Uwe Ligges

Steve.
  Dr Steve Roberts   [EMAIL PROTECTED]
Senior Lecturer in Medical Statistics,
CMMCH NHS Trust and University of Manchester Biostatistics Group,
0161 275 5192/5764 / 0161 276 5785
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Re: [R] density function

2005-05-11 Thread Suresh Krishna
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/20509.html
-s.
Hui Han wrote:
Thank you very much, Professor Ripley.
If possible, could you point me to other packages that you think I 
should look at for estimating a derivative?

Best regards,
Hui
Prof Brian Ripley wrote:
On Tue, 10 May 2005, Hui Han wrote:
I wonder if the function density outputs the gaussian mixture 
formula that is estimated from the input data, assuming a gaussian 
model is used at each data point ?  I want to take the derivative of 
the finally estimated gaussian mixture formula for further analysis.

It is a kernel density estimate: a rather trivial mixture, not 
necessarily Gaussian.  Also, it is not set up to optimally estimate a 
derivative, and you should look at more sophisticated methods in other 
packages if you want to do that.

As to what density outputs: see its help page.
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Re: [R] Multiple IF statements - is there a better alternative?

2005-05-11 Thread Suresh Krishna
are you looking for something like:
InternalMean - mean(data1[,3])
TestValues - c(0,1,2,4,9) #should be in increasing order
TestResults - c(.95, .85, .7, NaN,0)
if (InternalMean==0) IntResult=1 else 
IntResult=TestResults[which(TestValues==max(TestValues[TestValuesInternalMean]))]

-s.
Jones, Glen R wrote:
Hello,
Rather than rely on a set of IF statements (as there could be many -
please see below)), could the following be done in a different/better
way?
InternalMean - mean(data1[,3])
if (InternalMean == 0)
Intresult = 1
if (InternalMean  0  InternalMean  1)
Intresult = .95
if (InternalMean = 1  InternalMean  2)
Intresult = .85
if (InternalMean = 2  InternalMean  4)
Intresult = .70
...
if (InternalMean = 9)
Intresult = .0
Thanks in advance
Glen Jones
Value Analyst
Industry Framework Governance
Telstra Corporation Limited
Tel: (03) 9634 7280
email: [EMAIL PROTECTED]

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Re: [R] Multiple IF statements - is there a better alternative?

2005-05-11 Thread Suresh Krishna
oops, i meant something more like:
TestValues - c(0,1,2,4,9) #should be in increasing order
TestResults - c(.95, .85, .7, NaN,0)
if (InternalMean==0) IntResult=1 else 
IntResult=TestResults[TestValues==max(TestValues[TestValues=InternalMean])]

-s.
Suresh Krishna wrote:
are you looking for something like:
InternalMean - mean(data1[,3])
TestValues - c(0,1,2,4,9) #should be in increasing order
TestResults - c(.95, .85, .7, NaN,0)
if (InternalMean==0) IntResult=1 else 
IntResult=TestResults[which(TestValues==max(TestValues[TestValuesInternalMean]))] 

-s.
Jones, Glen R wrote:
Hello,
Rather than rely on a set of IF statements (as there could be many -
please see below)), could the following be done in a different/better
way?
InternalMean - mean(data1[,3])
if (InternalMean == 0)
Intresult = 1
if (InternalMean  0  InternalMean  1)
Intresult = .95
if (InternalMean = 1  InternalMean  2)
Intresult = .85
if (InternalMean = 2  InternalMean  4)
Intresult = .70
...
if (InternalMean = 9)
Intresult = .0
Thanks in advance
Glen Jones
Value Analyst
Industry Framework Governance
Telstra Corporation Limited
Tel: (03) 9634 7280

email: [EMAIL PROTECTED]

The information contained in this e-mail message may be confidential.
If you are not the intended recipient, any use of, interference with,
disclosure or copying of this material is unauthorised and prohibited.
If you have received this message in error, please notify me by reply
e-mail and then delete the message.

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Re: [R] R Greenhouse-Geiser correction?

2005-05-10 Thread Suresh Krishna
see these threads:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/46512.html
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/15653.html
-suresh
Darren Weber wrote:
Is there a function in R for doing Greenhouse-Geiser correction in ANOVA 
models?

Is it already available in the aov function? How do we use it?
Best, Darren
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[R] Contingency table: logistic regression

2005-03-30 Thread Suresh Krishna
Hi,
I am analyzing a data set with greater than 1000 independent cases 
(collected in an unrestricted manner), where each case has 3 variables 
associated with it: one, a factor variable with 0/1 levels (called XX), 
another factor variable with 8 levels (X) and a third response variable 
with two levels (Y: 0/1). I am trying to see if X1 has an effect on the 
relationship between X2 and the proportion of 1-s in Y.

I have three questions:
a) I have never used glm-s for this or any other sort of analysis before 
today, so am I interpreting the output correctly ?

After setting options(contrasts=c(contr.treatment,contr.poly))
I did:
~~Begin R output~~
Call:
glm(formula = Y ~ X * Fac, family = binomial, data = mat, subset = 
sactype  3  numstim == 16)

Deviance Residuals:
   Min  1Q  Median  3Q Max
-2.232  -0.901   0.416   0.985   1.656
Coefficients:
Estimate Std. Error z value Pr(|z|)
(Intercept)2.405  0.209   11.52   2e-16 ***
X2-2.511  0.293   -8.57   2e-16 ***
X3-3.283  0.286  -11.47   2e-16 ***
X4-2.009  0.302   -6.653e-11 ***
X5-3.098  0.276  -11.22   2e-16 ***
X6-2.580  0.288   -8.97   2e-16 ***
X7-3.484  0.288  -12.09   2e-16 ***
X8-2.811  0.328   -8.56   2e-16 ***
Fac   -1.558  0.721   -2.16  0.03071 *
X2:Fac 2.133  0.9422.26  0.02351 *
X3:Fac 1.848  0.9321.98  0.04748 *
X4:Fac 2.836  0.9822.89  0.00386 **
X5:Fac 3.263  0.9453.45  0.00056 ***
X6:Fac 3.630  0.9713.74  0.00018 ***
X7:Fac 3.256  0.8833.69  0.00023 ***
X8:Fac 3.350  1.0003.35  0.00081 ***
---
Signif. codes:  0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 1619.4  on 1178  degrees of freedom
Residual deviance: 1271.2  on 1163  degrees of freedom
AIC: 1303
Number of Fisher Scoring iterations: 5
End R output~~~
I am reading this like this: each of the X2X8 terms tell me whether 
the proportions associated with those factors at level 0 of Fac, are 
different from the proportion associated with factor X1 for level 0 of 
Fac. And each of the terms associated with Fac (X2:Fac,...X8:Fac) is 
telling me whether the difference between X2...X8 and X1 is different 
for Fac=0 and Fac=1; and this is the same thing as whether the 
proportion associated with X2..X8 are different for the two levels 
of Fac. So these X2...X8:Fac terms are like performing a simple 2x2 
analysis of the effect of Fac on Y, given X2 (X8).

How much of this is incorrect ?
My other two questions are:
b) Is this the right way to approach this analysis in R ? Or am I better 
off reading about multi-way contingency table analyses and using them ?

and
c) How do I incorporate a correction for multiple-testing into the above 
analysis ? The effect of Fac on the relationship between X and Y was 
planned.

I would greatly, and respectfully appreciate all pointers, tips and 
admonitions.

Thank you 
Suresh
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[R] Re: Contingency table: logistic regression

2005-03-30 Thread Suresh Krishna
Oops, I corrected some errors in the first paragraph; sorry for the 
repeated posting.

Suresh
~~
Hi,
I am analyzing a data set with greater than 1000 independent cases
(collected in an unrestricted manner), where each case has 3 variables
associated with it: one, a factor variable with 0/1 levels (called Fac),
another factor variable with 8 levels (X) and a third response variable
with two levels (Y: 0/1). I am trying to see if Fac has an effect on the
relationship between X and the proportion of 1-s in Y.
I have three questions:
a) I have never used glm-s for this or any other sort of analysis before
today, so am I interpreting the output correctly ?
After setting options(contrasts=c(contr.treatment,contr.poly))
I did:
~~Begin R output~~
Call:
glm(formula = Y ~ X * Fac, family = binomial, data = mat, subset =
sactype  3  numstim == 16)
Deviance Residuals:
   Min  1Q  Median  3Q Max
-2.232  -0.901   0.416   0.985   1.656
Coefficients:
Estimate Std. Error z value Pr(|z|)
(Intercept)2.405  0.209   11.52   2e-16 ***
X2-2.511  0.293   -8.57   2e-16 ***
X3-3.283  0.286  -11.47   2e-16 ***
X4-2.009  0.302   -6.653e-11 ***
X5-3.098  0.276  -11.22   2e-16 ***
X6-2.580  0.288   -8.97   2e-16 ***
X7-3.484  0.288  -12.09   2e-16 ***
X8-2.811  0.328   -8.56   2e-16 ***
Fac   -1.558  0.721   -2.16  0.03071 *
X2:Fac 2.133  0.9422.26  0.02351 *
X3:Fac 1.848  0.9321.98  0.04748 *
X4:Fac 2.836  0.9822.89  0.00386 **
X5:Fac 3.263  0.9453.45  0.00056 ***
X6:Fac 3.630  0.9713.74  0.00018 ***
X7:Fac 3.256  0.8833.69  0.00023 ***
X8:Fac 3.350  1.0003.35  0.00081 ***
---
Signif. codes:  0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
(Dispersion parameter for binomial family taken to be 1)
Null deviance: 1619.4  on 1178  degrees of freedom
Residual deviance: 1271.2  on 1163  degrees of freedom
AIC: 1303
Number of Fisher Scoring iterations: 5
End R output~~~
I am reading this like this: each of the X2X8 terms tell me whether
the proportions associated with those factors at level 0 of Fac, are
different from the proportion associated with factor X1 for level 0 of
Fac. And each of the terms associated with Fac (X2:Fac,...X8:Fac) is
telling me whether the difference between X2...X8 and X1 is different
for Fac=0 and Fac=1; and this is the same thing as whether the
proportion associated with X2..X8 are different for the two levels
of Fac. So these X2...X8:Fac terms are like performing a simple 2x2
analysis of the effect of Fac on Y, given X2 (X8).
How much of this is incorrect ?
My other two questions are:
b) Is this the right way to approach this analysis in R ? Or am I better
off reading about multi-way contingency table analyses and using them ?
and
c) How do I incorporate a correction for multiple-testing into the above
analysis ? The effect of Fac on the relationship between X and Y was
planned.
I would greatly, and respectfully appreciate all pointers, tips and
admonitions.
Thank you 
Suresh
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Re: [R] and [ESS] Starting ESS

2005-02-28 Thread B Suresh Krishna
Hi,
Yes, I defined the HOME environment variable as instructed in the 
installation instructions. Also, I can happily switch buffers in Emacs 
(C-x C-b or using C-x C-o) to the R-window and back to the .r file I am 
editing without any problem...

If it matters, I am using Windows XP on a Dell Inspiron 9100 laptop, and 
the latest version of R.

Thanks, Suresh
On Mon, 28 Feb 2005, Vincent Goulet wrote:
Suresh,
Did you define a HOME environment variable for Emacs to use (as instructed in
the installation instructions)? I observed that when the HOME variable is not
defined (or points to a non-existent directory), Emacs will freeze as soon as
one toggles from the Emacs window to another application and back to Emacs.
And of course, I should have written FSF Emacs in my original post, not FSG.
Hope this helps!
Le 26 Février 2005 00:06, Suresh Krishna a écrit :
Prof. Goulet,
I apologize in advance if I shouldnt have been writing to you directly;
but I thought that my problem was simple enough that you could very
quickly say if you knew of a quick fix for this.
Because I am familiar with the Emacs editor, I was happily and
gratefully using your packaged version of FSG Emacs after you suggested
it here on the list (R-help); but I have run into a problem that occurs
when i run:
x=1;
y=1;
par(ask=T)
plot(x,y)
emacs/ess/r now freezes because it is waiting for me to hit enter to see
the next plot, however, when i hit enter, i am not sure R is able to
realize that i hit enter. also, the hit enter to see next plot message
is not displayed in the window with the r process.
If this is a problem that is somehow specific to what I am doing, then
please let me know. I have switched back to JGR and the mouse, until then.
Thanks !!
Suresh
Vincent Goulet wrote:
To answer your question: I don't think it matters.
If you're willing to use FSG Emacs instead of XEmacs, I repackaged Emacs
21.3 for Windows together with recent versions of ESS and AuCTeX for my
students (I personally run Linux). The package and installation
instructions are at:
 http://vgoulet.act.ulaval.ca/download/software/emacs/
(Look for files emacs-21.3-ready.zip, emacs_install_en.txt and perhaps
ess_s-plus_win_en.txt.)
Hope this helps!
Le 23 Février 2005 18:16, Laura Holt a écrit :
Dear R People:
I have finally seen the error of my ways and have decided to use ESS for
R and S + stuff.
However, I have a question right from the beginning.  I'm somewhat
confused by the installation instructions.
Do I install XEMACS or ESS first, please?
Windows XP
R Version 2.0.1
(S + 6.2)
Thanks so much!
Sincerely,
Laura Holt
mailto: [EMAIL PROTECTED]
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--
 Vincent Goulet, Associate Professor
 École d'actuariat
 Université Laval, Québec
 [EMAIL PROTECTED]   http://vgoulet.act.ulaval.ca
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[R] comparing predicted sequence A'(t) to observed sequence A(t)

2005-02-12 Thread Suresh Krishna
Hi,
I have a question that I have not been succesful in finding a definitive 
answer to; and I was hoping someone here could give me some pointers to 
the right place in the literature.

A. We have 4 sets of data, A(t), B(t), C(t), and D(t). Each of these 
consists of a series of counts obtained in sequential time-intervals: so 
 for example, A(t) would be something like:

Count A(t):  25,28,26,   34   ..
Time (ms):  0-10, 10-20, 20-30, 30-40 ...
Each count in the series A(t) is obtained by summing the total number of 
observed counts over multiple (say 50), independent repetitions of that 
time-series. These counts are generally known to be Poisson distributed, 
and the 4 processes A(t), B(t), C(t) and D(t) are independent of each other.

B. It appears on visual observation that the following relationship 
holds; and such a relationship would also be expected on mechanistic 
considerations.

A(t) = B(t) + C(t) - D(t)
We now want to test this hypothesis statistically.
Because successive counts in the sequence are likely to be correlated, 
isnt it true that none of these methods are valid ? Perhaps for other 
reasons as well ?

a)Doing a chi-squared test to see if the predicted curve for A(t) 
deviates significantly from the observed A(t); this also seems to not 
take the variability of the predicted curve into account.

b)Doing a regression of the predicted values of A(t) against the actual 
values of A(t) and checking for deviations of slope from 1 and intercept 
from 0 ? Here, in addition to lack of independence, the fact that 
X-values are not fixed (i.e. are variable) and the fact that X and Y are 
Poisson distributed counts should also be taken into account, right ?

I would be very grateful if someone could point me to methods to handle 
this kind of situation, or where to look for them. Is there something in 
the time-series literature, for instance ?

Thanks !!
Suresh
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Re: [R] comparing predicted sequence A'(t) to observed sequence A(t)

2005-02-12 Thread Suresh Krishna
Hi,
Thanks for your quick response !
By predicted A(t), I meant B(t) + C(t) - D(t). In other words, how well 
does B(t) + C(t) - D(t) approximate A(t) ?

And all the counts are non-negative.
Regards, Suresh
Spencer Graves wrote:
 What do you mean by the following:
 A(t) = B(t) + C(t) - D(t)?
 Since you speak of regressing predicted against actual A(t), I 
gather this is not what you mean.
 Another question:  Do you have numbers -0 for either predicted or 
actual A(t)?  If yes but only a very few, I might replace the 0's by 0.5 
and any negatives by 0.25, take their logarithms, then try acf, pacf, 
ar, arima(..., xreg=A.pred), etc.
 There are doubtless better methods.  However, if I had to have an 
answer today, I think I'd try this, then discuss implications and 
limitations.  If I needed a more sophisticated answer and I had a few 
weeks or months to work on it, I might develop some way to simulate a 
process that seemed to describe what I thought generated these numbers 
and compare simulated results with actual, under a variety of 
hypotheses, obtaining various kinds of p-values, etc.
 hope this helps.  spencer graves

Suresh Krishna wrote:
Hi,
I have a question that I have not been succesful in finding a 
definitive answer to; and I was hoping someone here could give me some 
pointers to the right place in the literature.

A. We have 4 sets of data, A(t), B(t), C(t), and D(t). Each of these 
consists of a series of counts obtained in sequential time-intervals: 
so  for example, A(t) would be something like:

Count A(t):  25,28,26,   34   ..
Time (ms):  0-10, 10-20, 20-30, 30-40 ...
Each count in the series A(t) is obtained by summing the total number 
of observed counts over multiple (say 50), independent repetitions of 
that time-series. These counts are generally known to be Poisson 
distributed, and the 4 processes A(t), B(t), C(t) and D(t) are 
independent of each other.

B. It appears on visual observation that the following relationship 
holds; and such a relationship would also be expected on mechanistic 
considerations.

A(t) = B(t) + C(t) - D(t)
We now want to test this hypothesis statistically.
Because successive counts in the sequence are likely to be correlated, 
isnt it true that none of these methods are valid ? Perhaps for other 
reasons as well ?

a)Doing a chi-squared test to see if the predicted curve for A(t) 
deviates significantly from the observed A(t); this also seems to not 
take the variability of the predicted curve into account.

b)Doing a regression of the predicted values of A(t) against the 
actual values of A(t) and checking for deviations of slope from 1 and 
intercept from 0 ? Here, in addition to lack of independence, the fact 
that X-values are not fixed (i.e. are variable) and the fact that X 
and Y are Poisson distributed counts should also be taken into 
account, right ?

I would be very grateful if someone could point me to methods to 
handle this kind of situation, or where to look for them. Is there 
something in the time-series literature, for instance ?

Thanks !!
Suresh
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[R] locfit confidence intervals

2004-10-12 Thread Suresh Krishna
hi,
after
m=locfit(y~x,..., family=binomial)
plot(m,band=local) gives me a plot of locfit's result with a confidence 
interval around it. i would like to get the actual values that are being 
used to plot the lines in this figure.

i tried using predict, but the standard error it returns when i supply the 
se=T argument, appears not to be the same as the CI produced by plot (it is 
much larger...in my one case).  i have tried all the different type=.. 
options, but none of them matches the CI produced by plot.

i only recently started using both R and local regression methods and am 
still feeling my way around, so even though I have gone through the FAQs 
and the online manuals and the archives of this group and the Loader book, 
I have been unable to make much progress. any help would be very appreciated !!

thanks, suresh
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