On 9 Feb 2005 at 16:32, [EMAIL PROTECTED] wrote:
Petr,
It works perfectly! But I still have a question;
I have fit the following data;
x,y,z
1,10,11
2,11,15
3,12,21
4,13,29
5,14,39
6,15,51
7,16,65
8,17,81
9,18,99
10,19,119
dat.lm - lm(z~I(x^2)+y, data=dat)
dat.lm
Call:
lm(formula = z ~ I(x^2) + y, data = dat)
Coefficients:
(Intercept) I(x^2)y
1.841e-141.000e+001.000e+00
How do I create the z matrix from dat.lm?? Without having to type
over all the coefficients?
Maybe
expand.grid() and predict()
# new data
x-1:10
y-20:60
new.df-expand.grid(x,y) #make data.frame
names(new.df)-c(x,y) #change to propper names
contour(x,y,matrix(predict(dat.lm, new.df),10,41))
Cheers
Petr
Kind regards, Darius Blaszijk
- Oorspronkelijk bericht
- Onderwerp: Re: Fw: [R] Contour plot Van:
Petr Pikal [EMAIL PROTECTED] Datum: Wo, 9 februari,
2005 11:23 am Aan: [EMAIL PROTECTED]
r-help@stat.math.ethz.ch
--
Hi Darius
On 8 Feb 2005 at 17:43, [EMAIL PROTECTED] wrote:
I understand that I need to have a (in this case) square matrix with
all
the data. But the question now is;
- can the contourplot not interpolate the missing values
or alternatively
- I have fit a model to the z data (z = 100 + 0.5x + 0.5y). How can
I
make from this model a square matrix z to make a contour plot?
Will
x-1:10
y-1:10
z - outer(x,y,function(x,y) 100 + 0.5*x + 0.5*y)
contour(x,y,z)
work as you wish?
Cheers
Petr
Kind regards, Darius Blaszijk
- Original Message -
From: Achim Zeileis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Tuesday, February 08, 2005 1:51 AM
Subject: Re: [R] Contour plot
On Tue, 8 Feb 2005 01:15:06 +0100 [EMAIL PROTECTED] wrote:
Hello,
I would like to make a contourplot of the following data;
x - 1:10
y - 1:10
z - 100:110
By doing contour(x,y,z) I get the following error;
Error in contour.default(x, y, z) : no proper `z' matrix
specified
How do I fix this??
x and y specify a grid and thus z must provide a value for each
combination of the x's and y's! For example:
x - y - 1:10
contour(x, y, outer(x, y))
Also look at
outer(x, y)
and read ?contour.
Z
Kind regards, Datius Blaszijk
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Petr Pikal
[EMAIL PROTECTED]
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Petr Pikal
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